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Force open ZIP file and the break out of loop after extraction
The Next CEO of Stack OverflowC# loop - break vs. continueHow to break out of multiple loops in Python?Breaking out of nested loopsHow do I break out of nested loops in Java?Looping through the content of a file in BashHow to break out of jQuery each LoopLooping through array and removing items, without breaking for loopSelective extracting and opening for zipfile in pythonPython zipfile library fixAttributeError: 'str' object has no attribute 'extractall' extracting zip from brute force
Here is my task:
Sample Alien Zip file found at /tmp/alien-zip-2092.zip is password protected
We have worked out they are using three digit code
Brute force the Zip file to extract to /tmp
My code so far:
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
How do I break out of the loop after the password and extraction is successful.
python loops
asked Mar 8 at 13:12
TNoTNo
633320
add a comment |
Here is my task:
Sample Alien Zip file found at /tmp/alien-zip-2092.zip is password protected
We have worked out they are using three digit code
Brute force the Zip file to extract to /tmp
My code so far:
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
How do I break out of the loop after the password and extraction is successful.
python loops
asked Mar 8 at 13:12
TNoTNo
633320
2
Are you asking how to break out of a loop, or how to tell if the extraction was successful?
– Scott Hunter
Mar 8 at 13:14
add a comment |
Here is my task:
Sample Alien Zip file found at /tmp/alien-zip-2092.zip is password protected
We have worked out they are using three digit code
Brute force the Zip file to extract to /tmp
My code so far:
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
How do I break out of the loop after the password and extraction is successful.
python loops
asked Mar 8 at 13:12
TNoTNo
633320
Here is my task:
Sample Alien Zip file found at /tmp/alien-zip-2092.zip is password protected
We have worked out they are using three digit code
Brute force the Zip file to extract to /tmp
My code so far:
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
How do I break out of the loop after the password and extraction is successful.
python loops
python loops
asked Mar 8 at 13:12
TNoTNo
633320
asked Mar 8 at 13:12
TNoTNo
633320
asked Mar 8 at 13:12
TNoTNo
633320
asked Mar 8 at 13:12
TNoTNo
633320
asked Mar 8 at 13:12
TNoTNo
633320
633320
2
Are you asking how to break out of a loop, or how to tell if the extraction was successful?
– Scott Hunter
Mar 8 at 13:14
add a comment |
2
Are you asking how to break out of a loop, or how to tell if the extraction was successful?
– Scott Hunter
Mar 8 at 13:14
2
2
Are you asking how to break out of a loop, or how to tell if the extraction was successful?
– Scott Hunter
Mar 8 at 13:14
Are you asking how to break out of a loop, or how to tell if the extraction was successful?
– Scott Hunter
Mar 8 at 13:14
add a comment |
2 Answers
2
active
oldest
votes
Entering a wrong password raises a ValueError (documentation)
So you can put the unzip in a try block, pass over the exception if the password is bad, and break out of the loop when extraction was successful.
from zipfile import ZipFile
zf = ZipFile('/tmp/alien-zip-2092.zip')
for i in range(0,999):
try:
zf.extractall(pwd = str(i).encode())
print("Password: " + str(i))
break
except Exception:
pass
I tested this code, note that the password has to be encoded as a byte string.
If you print out the exception it reads:
Bad password for file [and some file info]
answered Mar 8 at 13:42
J.D.J.D.
1,282229
How do I extract to a specific file?
– TNo
Mar 8 at 15:21
check right above in the same documentation. Instead ofextractall(), you can useextract()to provide a filename to extract just that file:zf.extract(member='file.txt', pwd = str(i).encode())
– J.D.
Mar 8 at 15:38
add a comment |
try to use break to break out of a loop.
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
break
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Entering a wrong password raises a ValueError (documentation)
So you can put the unzip in a try block, pass over the exception if the password is bad, and break out of the loop when extraction was successful.
from zipfile import ZipFile
zf = ZipFile('/tmp/alien-zip-2092.zip')
for i in range(0,999):
try:
zf.extractall(pwd = str(i).encode())
print("Password: " + str(i))
break
except Exception:
pass
I tested this code, note that the password has to be encoded as a byte string.
If you print out the exception it reads:
Bad password for file [and some file info]
answered Mar 8 at 13:42
J.D.J.D.
1,282229
How do I extract to a specific file?
– TNo
Mar 8 at 15:21
check right above in the same documentation. Instead ofextractall(), you can useextract()to provide a filename to extract just that file:zf.extract(member='file.txt', pwd = str(i).encode())
– J.D.
Mar 8 at 15:38
add a comment |
Entering a wrong password raises a ValueError (documentation)
So you can put the unzip in a try block, pass over the exception if the password is bad, and break out of the loop when extraction was successful.
from zipfile import ZipFile
zf = ZipFile('/tmp/alien-zip-2092.zip')
for i in range(0,999):
try:
zf.extractall(pwd = str(i).encode())
print("Password: " + str(i))
break
except Exception:
pass
I tested this code, note that the password has to be encoded as a byte string.
If you print out the exception it reads:
Bad password for file [and some file info]
answered Mar 8 at 13:42
J.D.J.D.
1,282229
How do I extract to a specific file?
– TNo
Mar 8 at 15:21
check right above in the same documentation. Instead ofextractall(), you can useextract()to provide a filename to extract just that file:zf.extract(member='file.txt', pwd = str(i).encode())
– J.D.
Mar 8 at 15:38
add a comment |
Entering a wrong password raises a ValueError (documentation)
So you can put the unzip in a try block, pass over the exception if the password is bad, and break out of the loop when extraction was successful.
from zipfile import ZipFile
zf = ZipFile('/tmp/alien-zip-2092.zip')
for i in range(0,999):
try:
zf.extractall(pwd = str(i).encode())
print("Password: " + str(i))
break
except Exception:
pass
I tested this code, note that the password has to be encoded as a byte string.
If you print out the exception it reads:
Bad password for file [and some file info]
answered Mar 8 at 13:42
J.D.J.D.
1,282229
Entering a wrong password raises a ValueError (documentation)
So you can put the unzip in a try block, pass over the exception if the password is bad, and break out of the loop when extraction was successful.
from zipfile import ZipFile
zf = ZipFile('/tmp/alien-zip-2092.zip')
for i in range(0,999):
try:
zf.extractall(pwd = str(i).encode())
print("Password: " + str(i))
break
except Exception:
pass
I tested this code, note that the password has to be encoded as a byte string.
If you print out the exception it reads:
Bad password for file [and some file info]
answered Mar 8 at 13:42
J.D.J.D.
1,282229
edited Mar 8 at 13:48
answered Mar 8 at 13:42
J.D.J.D.
1,282229
answered Mar 8 at 13:42
J.D.J.D.
1,282229
answered Mar 8 at 13:42
J.D.J.D.
1,282229
1,282229
How do I extract to a specific file?
– TNo
Mar 8 at 15:21
check right above in the same documentation. Instead ofextractall(), you can useextract()to provide a filename to extract just that file:zf.extract(member='file.txt', pwd = str(i).encode())
– J.D.
Mar 8 at 15:38
add a comment |
How do I extract to a specific file?
– TNo
Mar 8 at 15:21
check right above in the same documentation. Instead ofextractall(), you can useextract()to provide a filename to extract just that file:zf.extract(member='file.txt', pwd = str(i).encode())
– J.D.
Mar 8 at 15:38
How do I extract to a specific file?
– TNo
Mar 8 at 15:21
How do I extract to a specific file?
– TNo
Mar 8 at 15:21
check right above in the same documentation. Instead of
extractall(), you can use extract() to provide a filename to extract just that file: zf.extract(member='file.txt', pwd = str(i).encode())– J.D.
Mar 8 at 15:38
check right above in the same documentation. Instead of
extractall(), you can use extract() to provide a filename to extract just that file: zf.extract(member='file.txt', pwd = str(i).encode())– J.D.
Mar 8 at 15:38
add a comment |
try to use break to break out of a loop.
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
break
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
add a comment |
try to use break to break out of a loop.
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
break
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
add a comment |
try to use break to break out of a loop.
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
break
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
try to use break to break out of a loop.
from zipfile import ZipFile
for i in range(0,999):
with ZipFile('/tmp/alien-zip-2092.zip') as zf:
zf.extractall(pwd = i)
break
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
answered Mar 8 at 13:15
pbuzulanpbuzulan
416
416
add a comment |
add a comment |
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2
Are you asking how to break out of a loop, or how to tell if the extraction was successful?
– Scott Hunter
Mar 8 at 13:14