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UDP send always end ups in the catch
The Next CEO of Stack OverflowDoes a finally block always get executed in Java?Can I catch multiple Java exceptions in the same catch clause?Place cursor at the end of text in EditTextIs there a way to monitor what process sends UDP packets (source/dest IP and port) in Windows?Unable to receive UDP packet on Android ServerUDP multi-clientsSending UDP packet from Android to Arduino“Address already in use” DataramSocket in receive datagramSending UDP from one computer to another in pythonSwift - UDP Receive & Send
fab.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View view)
try
String host = "192.168.4.1";
int port = 2390;
byte[] message = "Som tu".getBytes();
InetAddress address = InetAddress.getByName(host);
DatagramPacket packet = new DatagramPacket(message, message.length, address, port);
DatagramSocket dSocket = new DatagramSocket();
dSocket.send(packet);
dSocket.close();
catch(Exception e)
speak("error");
Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,
RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS,3);
mySpeechRecognizer.startListening(intent);
);
Im trying to create android app that will send text via udp when buttuon is pressed but it always end up in the catch .. any thoughts why ? I also get Error: E/HAL: load: id=gralloc != hmi->id=gralloc but I dont know how to fix it.
Is there any permission that Im forgetting about ? Im using only (RECORD_AUDIO,INTERNET)
java android udp
add a comment |
fab.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View view)
try
String host = "192.168.4.1";
int port = 2390;
byte[] message = "Som tu".getBytes();
InetAddress address = InetAddress.getByName(host);
DatagramPacket packet = new DatagramPacket(message, message.length, address, port);
DatagramSocket dSocket = new DatagramSocket();
dSocket.send(packet);
dSocket.close();
catch(Exception e)
speak("error");
Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,
RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS,3);
mySpeechRecognizer.startListening(intent);
);
Im trying to create android app that will send text via udp when buttuon is pressed but it always end up in the catch .. any thoughts why ? I also get Error: E/HAL: load: id=gralloc != hmi->id=gralloc but I dont know how to fix it.
Is there any permission that Im forgetting about ? Im using only (RECORD_AUDIO,INTERNET)
java android udp
If you throw away the exception information (speak("error");
) we can only guess what the problem is. Print out the exception stacktrace and show it to us. Better still, read it first. The exception name and message will probably sufficient to tell you what the problem is without you needing to ask.
– Stephen C
Mar 8 at 13:14
add a comment |
fab.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View view)
try
String host = "192.168.4.1";
int port = 2390;
byte[] message = "Som tu".getBytes();
InetAddress address = InetAddress.getByName(host);
DatagramPacket packet = new DatagramPacket(message, message.length, address, port);
DatagramSocket dSocket = new DatagramSocket();
dSocket.send(packet);
dSocket.close();
catch(Exception e)
speak("error");
Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,
RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS,3);
mySpeechRecognizer.startListening(intent);
);
Im trying to create android app that will send text via udp when buttuon is pressed but it always end up in the catch .. any thoughts why ? I also get Error: E/HAL: load: id=gralloc != hmi->id=gralloc but I dont know how to fix it.
Is there any permission that Im forgetting about ? Im using only (RECORD_AUDIO,INTERNET)
java android udp
fab.setOnClickListener(new View.OnClickListener()
@Override
public void onClick(View view)
try
String host = "192.168.4.1";
int port = 2390;
byte[] message = "Som tu".getBytes();
InetAddress address = InetAddress.getByName(host);
DatagramPacket packet = new DatagramPacket(message, message.length, address, port);
DatagramSocket dSocket = new DatagramSocket();
dSocket.send(packet);
dSocket.close();
catch(Exception e)
speak("error");
Intent intent = new Intent(RecognizerIntent.ACTION_RECOGNIZE_SPEECH);
intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL,
RecognizerIntent.LANGUAGE_MODEL_FREE_FORM);
intent.putExtra(RecognizerIntent.EXTRA_MAX_RESULTS,3);
mySpeechRecognizer.startListening(intent);
);
Im trying to create android app that will send text via udp when buttuon is pressed but it always end up in the catch .. any thoughts why ? I also get Error: E/HAL: load: id=gralloc != hmi->id=gralloc but I dont know how to fix it.
Is there any permission that Im forgetting about ? Im using only (RECORD_AUDIO,INTERNET)
java android udp
java android udp
asked Mar 8 at 12:55
MagematixMagematix
346
346
If you throw away the exception information (speak("error");
) we can only guess what the problem is. Print out the exception stacktrace and show it to us. Better still, read it first. The exception name and message will probably sufficient to tell you what the problem is without you needing to ask.
– Stephen C
Mar 8 at 13:14
add a comment |
If you throw away the exception information (speak("error");
) we can only guess what the problem is. Print out the exception stacktrace and show it to us. Better still, read it first. The exception name and message will probably sufficient to tell you what the problem is without you needing to ask.
– Stephen C
Mar 8 at 13:14
If you throw away the exception information (
speak("error");
) we can only guess what the problem is. Print out the exception stacktrace and show it to us. Better still, read it first. The exception name and message will probably sufficient to tell you what the problem is without you needing to ask.– Stephen C
Mar 8 at 13:14
If you throw away the exception information (
speak("error");
) we can only guess what the problem is. Print out the exception stacktrace and show it to us. Better still, read it first. The exception name and message will probably sufficient to tell you what the problem is without you needing to ask.– Stephen C
Mar 8 at 13:14
add a comment |
1 Answer
1
active
oldest
votes
Looking at your code, I assume you´re getting a NetworkOnMainThreadException
. Android does not allow network activity on its main thread in order to keep an app responsive. To avoid this error, start a new thread inside your onClick
method and perform the network activity there
Thanks man, wouldnt ever think of that
– Magematix
Mar 8 at 13:11
1
I would like to advice to always log your exception to have a better understanding of what goes wrong. In this case you are catching almost each and every exception and it is not logged, so there are numerous things that could have failed. You can, for example, addLog.e("CRASH", "Exception occurred: ", e)
to your catch, to have your error logged and get more information about what goes wrong
– 0xDEADC0DE
Mar 8 at 13:17
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Looking at your code, I assume you´re getting a NetworkOnMainThreadException
. Android does not allow network activity on its main thread in order to keep an app responsive. To avoid this error, start a new thread inside your onClick
method and perform the network activity there
Thanks man, wouldnt ever think of that
– Magematix
Mar 8 at 13:11
1
I would like to advice to always log your exception to have a better understanding of what goes wrong. In this case you are catching almost each and every exception and it is not logged, so there are numerous things that could have failed. You can, for example, addLog.e("CRASH", "Exception occurred: ", e)
to your catch, to have your error logged and get more information about what goes wrong
– 0xDEADC0DE
Mar 8 at 13:17
add a comment |
Looking at your code, I assume you´re getting a NetworkOnMainThreadException
. Android does not allow network activity on its main thread in order to keep an app responsive. To avoid this error, start a new thread inside your onClick
method and perform the network activity there
Thanks man, wouldnt ever think of that
– Magematix
Mar 8 at 13:11
1
I would like to advice to always log your exception to have a better understanding of what goes wrong. In this case you are catching almost each and every exception and it is not logged, so there are numerous things that could have failed. You can, for example, addLog.e("CRASH", "Exception occurred: ", e)
to your catch, to have your error logged and get more information about what goes wrong
– 0xDEADC0DE
Mar 8 at 13:17
add a comment |
Looking at your code, I assume you´re getting a NetworkOnMainThreadException
. Android does not allow network activity on its main thread in order to keep an app responsive. To avoid this error, start a new thread inside your onClick
method and perform the network activity there
Looking at your code, I assume you´re getting a NetworkOnMainThreadException
. Android does not allow network activity on its main thread in order to keep an app responsive. To avoid this error, start a new thread inside your onClick
method and perform the network activity there
answered Mar 8 at 13:08
0xDEADC0DE0xDEADC0DE
2,23111321
2,23111321
Thanks man, wouldnt ever think of that
– Magematix
Mar 8 at 13:11
1
I would like to advice to always log your exception to have a better understanding of what goes wrong. In this case you are catching almost each and every exception and it is not logged, so there are numerous things that could have failed. You can, for example, addLog.e("CRASH", "Exception occurred: ", e)
to your catch, to have your error logged and get more information about what goes wrong
– 0xDEADC0DE
Mar 8 at 13:17
add a comment |
Thanks man, wouldnt ever think of that
– Magematix
Mar 8 at 13:11
1
I would like to advice to always log your exception to have a better understanding of what goes wrong. In this case you are catching almost each and every exception and it is not logged, so there are numerous things that could have failed. You can, for example, addLog.e("CRASH", "Exception occurred: ", e)
to your catch, to have your error logged and get more information about what goes wrong
– 0xDEADC0DE
Mar 8 at 13:17
Thanks man, wouldnt ever think of that
– Magematix
Mar 8 at 13:11
Thanks man, wouldnt ever think of that
– Magematix
Mar 8 at 13:11
1
1
I would like to advice to always log your exception to have a better understanding of what goes wrong. In this case you are catching almost each and every exception and it is not logged, so there are numerous things that could have failed. You can, for example, add
Log.e("CRASH", "Exception occurred: ", e)
to your catch, to have your error logged and get more information about what goes wrong– 0xDEADC0DE
Mar 8 at 13:17
I would like to advice to always log your exception to have a better understanding of what goes wrong. In this case you are catching almost each and every exception and it is not logged, so there are numerous things that could have failed. You can, for example, add
Log.e("CRASH", "Exception occurred: ", e)
to your catch, to have your error logged and get more information about what goes wrong– 0xDEADC0DE
Mar 8 at 13:17
add a comment |
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If you throw away the exception information (
speak("error");
) we can only guess what the problem is. Print out the exception stacktrace and show it to us. Better still, read it first. The exception name and message will probably sufficient to tell you what the problem is without you needing to ask.– Stephen C
Mar 8 at 13:14