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Input string was not in a correct format
The Next CEO of Stack OverflowHow to resolve “Input string was not in a correct format.” error?What is “'System.FormatException' occurred in mscorlib.dll but was not handled in user code”?Input string was not in a correct format in c#? Getting the exception as System.formatexception?An unhandled exception of type 'System.FormatException' Additional information: Input string was not in a correct formatThe input string was not in a correct formatInput String is not in Correct Format when reading DataTable valuesSubtraction from one Textfield to another got an errorError: Input string was not in the correct formatToInt32 throwing weird resultsDeleting row gives error “Input string was not in a correct format.”What is the difference between String and string in C#?What are the correct version numbers for C#?Case insensitive 'Contains(string)'manually input in textbox and connected to the serverDataset.GetChanges(DataRowState.Modified) return nullHow does a method in a winform listen to an event/delegate in App_Code, and not get a null event?C# from socket to mail slot in windowsC# How use sign from another window?Renaming a Field name by accepting values from textboxes…It shows "Unclosed quotation mark after the character string ''C# Directx App crashes in Release
I'm new with C#, I have some basic knowledge in Java but I can't get this code to run properly.
It's just a basic calculator, but when I run the program VS2008 gives me this error:
I did almost the same program but in java using JSwing and it worked perfectly.
Here's the form of c#:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace calculadorac
{
public partial class Form1 : Form
int a, b, c;
String resultado;
public Form1()
InitializeComponent();
a = Int32.Parse(textBox1.Text);
b = Int32.Parse(textBox2.Text);
private void button1_Click(object sender, EventArgs e)
add();
result();
private void button2_Click(object sender, EventArgs e)
substract();
result();
private void button3_Click(object sender, EventArgs e)
clear();
private void add()
c = a + b;
resultado = Convert.ToString(c);
private void substract()
c = a - b;
resultado = Convert.ToString(c);
private void result()
label1.Text = resultado;
private void clear()
label1.Text = "";
textBox1.Text = "";
textBox2.Text = "";
What can be the problem? Is there a way to solve it?
PS: I also tried
a = Convert.ToInt32(textBox1.text);
b = Convert.ToInt32(textBox2.text);
and it didn't work.
c# exception formatexception
add a comment |
I'm new with C#, I have some basic knowledge in Java but I can't get this code to run properly.
It's just a basic calculator, but when I run the program VS2008 gives me this error:
I did almost the same program but in java using JSwing and it worked perfectly.
Here's the form of c#:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace calculadorac
{
public partial class Form1 : Form
int a, b, c;
String resultado;
public Form1()
InitializeComponent();
a = Int32.Parse(textBox1.Text);
b = Int32.Parse(textBox2.Text);
private void button1_Click(object sender, EventArgs e)
add();
result();
private void button2_Click(object sender, EventArgs e)
substract();
result();
private void button3_Click(object sender, EventArgs e)
clear();
private void add()
c = a + b;
resultado = Convert.ToString(c);
private void substract()
c = a - b;
resultado = Convert.ToString(c);
private void result()
label1.Text = resultado;
private void clear()
label1.Text = "";
textBox1.Text = "";
textBox2.Text = "";
What can be the problem? Is there a way to solve it?
PS: I also tried
a = Convert.ToInt32(textBox1.text);
b = Convert.ToInt32(textBox2.text);
and it didn't work.
c# exception formatexception
add a comment |
I'm new with C#, I have some basic knowledge in Java but I can't get this code to run properly.
It's just a basic calculator, but when I run the program VS2008 gives me this error:
I did almost the same program but in java using JSwing and it worked perfectly.
Here's the form of c#:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace calculadorac
{
public partial class Form1 : Form
int a, b, c;
String resultado;
public Form1()
InitializeComponent();
a = Int32.Parse(textBox1.Text);
b = Int32.Parse(textBox2.Text);
private void button1_Click(object sender, EventArgs e)
add();
result();
private void button2_Click(object sender, EventArgs e)
substract();
result();
private void button3_Click(object sender, EventArgs e)
clear();
private void add()
c = a + b;
resultado = Convert.ToString(c);
private void substract()
c = a - b;
resultado = Convert.ToString(c);
private void result()
label1.Text = resultado;
private void clear()
label1.Text = "";
textBox1.Text = "";
textBox2.Text = "";
What can be the problem? Is there a way to solve it?
PS: I also tried
a = Convert.ToInt32(textBox1.text);
b = Convert.ToInt32(textBox2.text);
and it didn't work.
c# exception formatexception
I'm new with C#, I have some basic knowledge in Java but I can't get this code to run properly.
It's just a basic calculator, but when I run the program VS2008 gives me this error:
I did almost the same program but in java using JSwing and it worked perfectly.
Here's the form of c#:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace calculadorac
{
public partial class Form1 : Form
int a, b, c;
String resultado;
public Form1()
InitializeComponent();
a = Int32.Parse(textBox1.Text);
b = Int32.Parse(textBox2.Text);
private void button1_Click(object sender, EventArgs e)
add();
result();
private void button2_Click(object sender, EventArgs e)
substract();
result();
private void button3_Click(object sender, EventArgs e)
clear();
private void add()
c = a + b;
resultado = Convert.ToString(c);
private void substract()
c = a - b;
resultado = Convert.ToString(c);
private void result()
label1.Text = resultado;
private void clear()
label1.Text = "";
textBox1.Text = "";
textBox2.Text = "";
What can be the problem? Is there a way to solve it?
PS: I also tried
a = Convert.ToInt32(textBox1.text);
b = Convert.ToInt32(textBox2.text);
and it didn't work.
c# exception formatexception
c# exception formatexception
edited Oct 11 '13 at 14:50
Ian R. O'Brien
3,86873667
3,86873667
asked Nov 30 '11 at 5:22
kustomrtrkustomrtr
5021612
5021612
add a comment |
add a comment |
8 Answers
8
active
oldest
votes
The error means that the string you're trying to parse an integer from doesn't actually contain a valid integer.
It's extremely unlikely that the text boxes will contain a valid integer immediately when the form is created - which is where you're getting the integer values. It would make much more sense to update a
and b
in the button click events (in the same way that you are in the constructor). Also, check out the Int.TryParse
method - it's much easier to use if the string might not actually contain an integer - it doesn't throw an exception so it's easier to recover from.
This error message could be thrown also when try to Convert.ToDouble input comming from user with different cultureinfo, so you could use Convert.ToDouble (String, IFormatProvider) instead of just Convert.ToDouble (String). It is hard to debug, because program will work on you system, but will throw error on some of its users, this is why I have a method to log errors on my server and I found out for the problem fastly.
– vinsa
Apr 7 '18 at 14:24
add a comment |
I ran into this exact exception, except it had nothing to do with parsing numerical inputs. So this isn't an answer to the OP's question, but I think it's acceptable to share the knowledge.
I'd declared a string and was formatting it for use with JQTree which requires curly braces (). You have to use doubled curly braces for it to be accepted as a properly formatted string:
string measurements = string.empty;
measurements += string.Format(@"
label: 'Measurement Name: 0',
children: [
label: 'Measured Value: 1',
label: 'Min: 2',
label: 'Max: 3',
label: 'Measured String: 4',
label: 'Expected String: 5',
]
,",
drv["MeasurementName"] == null ? "NULL" : drv["MeasurementName"],
drv["MeasuredValue"] == null ? "NULL" : drv["MeasuredValue"],
drv["Min"] == null ? "NULL" : drv["Min"],
drv["Max"] == null ? "NULL" : drv["Max"],
drv["MeasuredString"] == null ? "NULL" : drv["MeasuredString"],
drv["ExpectedString"] == null ? "NULL" : drv["ExpectedString"]);
Hopefully this will help other folks who find this question but aren't parsing numerical data.
add a comment |
If you are not validating explicitly for numbers in the text field, in any case its better to use
int result=0;
if(int.TryParse(textBox1.Text,out result))
Now if the result is success then you can proceed with your calculations.
9
Typicallyresult
doesn't need to be initialized.
– yazanpro
Feb 10 '15 at 21:05
add a comment |
Problems
There are some possible cases why the error occurs:
Because
textBox1.Text
contains only number, but the number is too big/too smallBecause
textBox1.Text
contains:- a) non-number (except
space
in the beginning/end,-
in the beginning) and/or - b) thousand separators in the applied culture for your code without specifying
NumberStyles.AllowThousands
or you specifyNumberStyles.AllowThousands
but put wrongthousand separator
in the culture and/or - c) decimal separator (which should not exist in
int
parsing)
- a) non-number (except
NOT OK Examples:
Case 1
a = Int32.Parse("5000000000"); //5 billions, too large
b = Int32.Parse("-5000000000"); //-5 billions, too small
//The limit for int (32-bit integer) is only from -2,147,483,648 to 2,147,483,647
Case 2 a)
a = Int32.Parse("a189"); //having a
a = Int32.Parse("1-89"); //having - but not in the beginning
a = Int32.Parse("18 9"); //having space, but not in the beginning or end
Case 2 b)
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189"); //not OK, no NumberStyles.AllowThousands
b = Int32.Parse("1,189", styles, new CultureInfo("fr-FR")); //not OK, having NumberStyles.AllowThousands but the culture specified use different thousand separator
Case 2 c)
NumberStyles styles = NumberStyles.AllowDecimalPoint;
a = Int32.Parse("1.189", styles); //wrong, int parse cannot parse decimal point at all!
Seemingly NOT OK, but actually OK Examples:
Case 2 a) OK
a = Int32.Parse("-189"); //having - but in the beginning
b = Int32.Parse(" 189 "); //having space, but in the beginning or end
Case 2 b) OK
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189", styles); //ok, having NumberStyles.AllowThousands in the correct culture
b = Int32.Parse("1 189", styles, new CultureInfo("fr-FR")); //ok, having NumberStyles.AllowThousands and correct thousand separator is used for "fr-FR" culture
Solutions
In all cases, please check the value of textBox1.Text
with your Visual Studio debugger and make sure that it has purely-acceptable numerical format for int
range. Something like this:
1234
Also, you may consider of
- using
TryParse
instead ofParse
to ensure that the non-parsed number does not cause you exception problem. check the result of
TryParse
and handle it if nottrue
int val;
bool result = int.TryParse(textbox1.Text, out val);
if (!result)
return; //something has gone wrong
//OK, continue using val
add a comment |
You have not mentioned if your textbox have values in design time or now. When form initializes text box may not hae value if you have not put it in textbox when during form design. you can put int value in form design by setting text property in desgin and this should work.
add a comment |
In my case I forgot to put double curly brace to escape. myobject
add a comment |
it was my problem too ..
in my case i changed the PERSIAN number to LATIN number and it worked.
AND also trime your string before converting.
PersianCalendar pc = new PersianCalendar();
char[] seperator ='/';
string[] date = txtSaleDate.Text.Split(seperator);
int a = Convert.ToInt32(Persia.Number.ConvertToLatin(date[0]).Trim());
add a comment |
I had a similar problem that I solved with the following technique:
The exception was thrown at the following line of code (see the text decorated with ** below):
static void Main(string[] args)
double number = 0;
string numberStr = string.Format("0:C2", 100);
**number = Double.Parse(numberStr);**
Console.WriteLine("The number is 0", number);
After a bit of investigating, I realized that the problem was that the formatted string included a dollar sign ($) that the Parse/TryParse methods cannot resolve (i.e. - strip off). So using the Remove(...) method of the string object I changed the line to:
number = Double.Parse(numberStr.Remove(0, 1)); // Remove the "$" from the number
At that point the Parse(...) method worked as expected.
add a comment |
protected by Community♦ Sep 27 '17 at 16:25
Thank you for your interest in this question.
Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).
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8 Answers
8
active
oldest
votes
8 Answers
8
active
oldest
votes
active
oldest
votes
active
oldest
votes
The error means that the string you're trying to parse an integer from doesn't actually contain a valid integer.
It's extremely unlikely that the text boxes will contain a valid integer immediately when the form is created - which is where you're getting the integer values. It would make much more sense to update a
and b
in the button click events (in the same way that you are in the constructor). Also, check out the Int.TryParse
method - it's much easier to use if the string might not actually contain an integer - it doesn't throw an exception so it's easier to recover from.
This error message could be thrown also when try to Convert.ToDouble input comming from user with different cultureinfo, so you could use Convert.ToDouble (String, IFormatProvider) instead of just Convert.ToDouble (String). It is hard to debug, because program will work on you system, but will throw error on some of its users, this is why I have a method to log errors on my server and I found out for the problem fastly.
– vinsa
Apr 7 '18 at 14:24
add a comment |
The error means that the string you're trying to parse an integer from doesn't actually contain a valid integer.
It's extremely unlikely that the text boxes will contain a valid integer immediately when the form is created - which is where you're getting the integer values. It would make much more sense to update a
and b
in the button click events (in the same way that you are in the constructor). Also, check out the Int.TryParse
method - it's much easier to use if the string might not actually contain an integer - it doesn't throw an exception so it's easier to recover from.
This error message could be thrown also when try to Convert.ToDouble input comming from user with different cultureinfo, so you could use Convert.ToDouble (String, IFormatProvider) instead of just Convert.ToDouble (String). It is hard to debug, because program will work on you system, but will throw error on some of its users, this is why I have a method to log errors on my server and I found out for the problem fastly.
– vinsa
Apr 7 '18 at 14:24
add a comment |
The error means that the string you're trying to parse an integer from doesn't actually contain a valid integer.
It's extremely unlikely that the text boxes will contain a valid integer immediately when the form is created - which is where you're getting the integer values. It would make much more sense to update a
and b
in the button click events (in the same way that you are in the constructor). Also, check out the Int.TryParse
method - it's much easier to use if the string might not actually contain an integer - it doesn't throw an exception so it's easier to recover from.
The error means that the string you're trying to parse an integer from doesn't actually contain a valid integer.
It's extremely unlikely that the text boxes will contain a valid integer immediately when the form is created - which is where you're getting the integer values. It would make much more sense to update a
and b
in the button click events (in the same way that you are in the constructor). Also, check out the Int.TryParse
method - it's much easier to use if the string might not actually contain an integer - it doesn't throw an exception so it's easier to recover from.
answered Nov 30 '11 at 5:24
JonJon
12.9k64453
12.9k64453
This error message could be thrown also when try to Convert.ToDouble input comming from user with different cultureinfo, so you could use Convert.ToDouble (String, IFormatProvider) instead of just Convert.ToDouble (String). It is hard to debug, because program will work on you system, but will throw error on some of its users, this is why I have a method to log errors on my server and I found out for the problem fastly.
– vinsa
Apr 7 '18 at 14:24
add a comment |
This error message could be thrown also when try to Convert.ToDouble input comming from user with different cultureinfo, so you could use Convert.ToDouble (String, IFormatProvider) instead of just Convert.ToDouble (String). It is hard to debug, because program will work on you system, but will throw error on some of its users, this is why I have a method to log errors on my server and I found out for the problem fastly.
– vinsa
Apr 7 '18 at 14:24
This error message could be thrown also when try to Convert.ToDouble input comming from user with different cultureinfo, so you could use Convert.ToDouble (String, IFormatProvider) instead of just Convert.ToDouble (String). It is hard to debug, because program will work on you system, but will throw error on some of its users, this is why I have a method to log errors on my server and I found out for the problem fastly.
– vinsa
Apr 7 '18 at 14:24
This error message could be thrown also when try to Convert.ToDouble input comming from user with different cultureinfo, so you could use Convert.ToDouble (String, IFormatProvider) instead of just Convert.ToDouble (String). It is hard to debug, because program will work on you system, but will throw error on some of its users, this is why I have a method to log errors on my server and I found out for the problem fastly.
– vinsa
Apr 7 '18 at 14:24
add a comment |
I ran into this exact exception, except it had nothing to do with parsing numerical inputs. So this isn't an answer to the OP's question, but I think it's acceptable to share the knowledge.
I'd declared a string and was formatting it for use with JQTree which requires curly braces (). You have to use doubled curly braces for it to be accepted as a properly formatted string:
string measurements = string.empty;
measurements += string.Format(@"
label: 'Measurement Name: 0',
children: [
label: 'Measured Value: 1',
label: 'Min: 2',
label: 'Max: 3',
label: 'Measured String: 4',
label: 'Expected String: 5',
]
,",
drv["MeasurementName"] == null ? "NULL" : drv["MeasurementName"],
drv["MeasuredValue"] == null ? "NULL" : drv["MeasuredValue"],
drv["Min"] == null ? "NULL" : drv["Min"],
drv["Max"] == null ? "NULL" : drv["Max"],
drv["MeasuredString"] == null ? "NULL" : drv["MeasuredString"],
drv["ExpectedString"] == null ? "NULL" : drv["ExpectedString"]);
Hopefully this will help other folks who find this question but aren't parsing numerical data.
add a comment |
I ran into this exact exception, except it had nothing to do with parsing numerical inputs. So this isn't an answer to the OP's question, but I think it's acceptable to share the knowledge.
I'd declared a string and was formatting it for use with JQTree which requires curly braces (). You have to use doubled curly braces for it to be accepted as a properly formatted string:
string measurements = string.empty;
measurements += string.Format(@"
label: 'Measurement Name: 0',
children: [
label: 'Measured Value: 1',
label: 'Min: 2',
label: 'Max: 3',
label: 'Measured String: 4',
label: 'Expected String: 5',
]
,",
drv["MeasurementName"] == null ? "NULL" : drv["MeasurementName"],
drv["MeasuredValue"] == null ? "NULL" : drv["MeasuredValue"],
drv["Min"] == null ? "NULL" : drv["Min"],
drv["Max"] == null ? "NULL" : drv["Max"],
drv["MeasuredString"] == null ? "NULL" : drv["MeasuredString"],
drv["ExpectedString"] == null ? "NULL" : drv["ExpectedString"]);
Hopefully this will help other folks who find this question but aren't parsing numerical data.
add a comment |
I ran into this exact exception, except it had nothing to do with parsing numerical inputs. So this isn't an answer to the OP's question, but I think it's acceptable to share the knowledge.
I'd declared a string and was formatting it for use with JQTree which requires curly braces (). You have to use doubled curly braces for it to be accepted as a properly formatted string:
string measurements = string.empty;
measurements += string.Format(@"
label: 'Measurement Name: 0',
children: [
label: 'Measured Value: 1',
label: 'Min: 2',
label: 'Max: 3',
label: 'Measured String: 4',
label: 'Expected String: 5',
]
,",
drv["MeasurementName"] == null ? "NULL" : drv["MeasurementName"],
drv["MeasuredValue"] == null ? "NULL" : drv["MeasuredValue"],
drv["Min"] == null ? "NULL" : drv["Min"],
drv["Max"] == null ? "NULL" : drv["Max"],
drv["MeasuredString"] == null ? "NULL" : drv["MeasuredString"],
drv["ExpectedString"] == null ? "NULL" : drv["ExpectedString"]);
Hopefully this will help other folks who find this question but aren't parsing numerical data.
I ran into this exact exception, except it had nothing to do with parsing numerical inputs. So this isn't an answer to the OP's question, but I think it's acceptable to share the knowledge.
I'd declared a string and was formatting it for use with JQTree which requires curly braces (). You have to use doubled curly braces for it to be accepted as a properly formatted string:
string measurements = string.empty;
measurements += string.Format(@"
label: 'Measurement Name: 0',
children: [
label: 'Measured Value: 1',
label: 'Min: 2',
label: 'Max: 3',
label: 'Measured String: 4',
label: 'Expected String: 5',
]
,",
drv["MeasurementName"] == null ? "NULL" : drv["MeasurementName"],
drv["MeasuredValue"] == null ? "NULL" : drv["MeasuredValue"],
drv["Min"] == null ? "NULL" : drv["Min"],
drv["Max"] == null ? "NULL" : drv["Max"],
drv["MeasuredString"] == null ? "NULL" : drv["MeasuredString"],
drv["ExpectedString"] == null ? "NULL" : drv["ExpectedString"]);
Hopefully this will help other folks who find this question but aren't parsing numerical data.
answered Oct 23 '14 at 16:01
delliottgdelliottg
2,39012641
2,39012641
add a comment |
add a comment |
If you are not validating explicitly for numbers in the text field, in any case its better to use
int result=0;
if(int.TryParse(textBox1.Text,out result))
Now if the result is success then you can proceed with your calculations.
9
Typicallyresult
doesn't need to be initialized.
– yazanpro
Feb 10 '15 at 21:05
add a comment |
If you are not validating explicitly for numbers in the text field, in any case its better to use
int result=0;
if(int.TryParse(textBox1.Text,out result))
Now if the result is success then you can proceed with your calculations.
9
Typicallyresult
doesn't need to be initialized.
– yazanpro
Feb 10 '15 at 21:05
add a comment |
If you are not validating explicitly for numbers in the text field, in any case its better to use
int result=0;
if(int.TryParse(textBox1.Text,out result))
Now if the result is success then you can proceed with your calculations.
If you are not validating explicitly for numbers in the text field, in any case its better to use
int result=0;
if(int.TryParse(textBox1.Text,out result))
Now if the result is success then you can proceed with your calculations.
answered Nov 30 '11 at 5:30
V4VendettaV4Vendetta
29k66477
29k66477
9
Typicallyresult
doesn't need to be initialized.
– yazanpro
Feb 10 '15 at 21:05
add a comment |
9
Typicallyresult
doesn't need to be initialized.
– yazanpro
Feb 10 '15 at 21:05
9
9
Typically
result
doesn't need to be initialized.– yazanpro
Feb 10 '15 at 21:05
Typically
result
doesn't need to be initialized.– yazanpro
Feb 10 '15 at 21:05
add a comment |
Problems
There are some possible cases why the error occurs:
Because
textBox1.Text
contains only number, but the number is too big/too smallBecause
textBox1.Text
contains:- a) non-number (except
space
in the beginning/end,-
in the beginning) and/or - b) thousand separators in the applied culture for your code without specifying
NumberStyles.AllowThousands
or you specifyNumberStyles.AllowThousands
but put wrongthousand separator
in the culture and/or - c) decimal separator (which should not exist in
int
parsing)
- a) non-number (except
NOT OK Examples:
Case 1
a = Int32.Parse("5000000000"); //5 billions, too large
b = Int32.Parse("-5000000000"); //-5 billions, too small
//The limit for int (32-bit integer) is only from -2,147,483,648 to 2,147,483,647
Case 2 a)
a = Int32.Parse("a189"); //having a
a = Int32.Parse("1-89"); //having - but not in the beginning
a = Int32.Parse("18 9"); //having space, but not in the beginning or end
Case 2 b)
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189"); //not OK, no NumberStyles.AllowThousands
b = Int32.Parse("1,189", styles, new CultureInfo("fr-FR")); //not OK, having NumberStyles.AllowThousands but the culture specified use different thousand separator
Case 2 c)
NumberStyles styles = NumberStyles.AllowDecimalPoint;
a = Int32.Parse("1.189", styles); //wrong, int parse cannot parse decimal point at all!
Seemingly NOT OK, but actually OK Examples:
Case 2 a) OK
a = Int32.Parse("-189"); //having - but in the beginning
b = Int32.Parse(" 189 "); //having space, but in the beginning or end
Case 2 b) OK
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189", styles); //ok, having NumberStyles.AllowThousands in the correct culture
b = Int32.Parse("1 189", styles, new CultureInfo("fr-FR")); //ok, having NumberStyles.AllowThousands and correct thousand separator is used for "fr-FR" culture
Solutions
In all cases, please check the value of textBox1.Text
with your Visual Studio debugger and make sure that it has purely-acceptable numerical format for int
range. Something like this:
1234
Also, you may consider of
- using
TryParse
instead ofParse
to ensure that the non-parsed number does not cause you exception problem. check the result of
TryParse
and handle it if nottrue
int val;
bool result = int.TryParse(textbox1.Text, out val);
if (!result)
return; //something has gone wrong
//OK, continue using val
add a comment |
Problems
There are some possible cases why the error occurs:
Because
textBox1.Text
contains only number, but the number is too big/too smallBecause
textBox1.Text
contains:- a) non-number (except
space
in the beginning/end,-
in the beginning) and/or - b) thousand separators in the applied culture for your code without specifying
NumberStyles.AllowThousands
or you specifyNumberStyles.AllowThousands
but put wrongthousand separator
in the culture and/or - c) decimal separator (which should not exist in
int
parsing)
- a) non-number (except
NOT OK Examples:
Case 1
a = Int32.Parse("5000000000"); //5 billions, too large
b = Int32.Parse("-5000000000"); //-5 billions, too small
//The limit for int (32-bit integer) is only from -2,147,483,648 to 2,147,483,647
Case 2 a)
a = Int32.Parse("a189"); //having a
a = Int32.Parse("1-89"); //having - but not in the beginning
a = Int32.Parse("18 9"); //having space, but not in the beginning or end
Case 2 b)
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189"); //not OK, no NumberStyles.AllowThousands
b = Int32.Parse("1,189", styles, new CultureInfo("fr-FR")); //not OK, having NumberStyles.AllowThousands but the culture specified use different thousand separator
Case 2 c)
NumberStyles styles = NumberStyles.AllowDecimalPoint;
a = Int32.Parse("1.189", styles); //wrong, int parse cannot parse decimal point at all!
Seemingly NOT OK, but actually OK Examples:
Case 2 a) OK
a = Int32.Parse("-189"); //having - but in the beginning
b = Int32.Parse(" 189 "); //having space, but in the beginning or end
Case 2 b) OK
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189", styles); //ok, having NumberStyles.AllowThousands in the correct culture
b = Int32.Parse("1 189", styles, new CultureInfo("fr-FR")); //ok, having NumberStyles.AllowThousands and correct thousand separator is used for "fr-FR" culture
Solutions
In all cases, please check the value of textBox1.Text
with your Visual Studio debugger and make sure that it has purely-acceptable numerical format for int
range. Something like this:
1234
Also, you may consider of
- using
TryParse
instead ofParse
to ensure that the non-parsed number does not cause you exception problem. check the result of
TryParse
and handle it if nottrue
int val;
bool result = int.TryParse(textbox1.Text, out val);
if (!result)
return; //something has gone wrong
//OK, continue using val
add a comment |
Problems
There are some possible cases why the error occurs:
Because
textBox1.Text
contains only number, but the number is too big/too smallBecause
textBox1.Text
contains:- a) non-number (except
space
in the beginning/end,-
in the beginning) and/or - b) thousand separators in the applied culture for your code without specifying
NumberStyles.AllowThousands
or you specifyNumberStyles.AllowThousands
but put wrongthousand separator
in the culture and/or - c) decimal separator (which should not exist in
int
parsing)
- a) non-number (except
NOT OK Examples:
Case 1
a = Int32.Parse("5000000000"); //5 billions, too large
b = Int32.Parse("-5000000000"); //-5 billions, too small
//The limit for int (32-bit integer) is only from -2,147,483,648 to 2,147,483,647
Case 2 a)
a = Int32.Parse("a189"); //having a
a = Int32.Parse("1-89"); //having - but not in the beginning
a = Int32.Parse("18 9"); //having space, but not in the beginning or end
Case 2 b)
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189"); //not OK, no NumberStyles.AllowThousands
b = Int32.Parse("1,189", styles, new CultureInfo("fr-FR")); //not OK, having NumberStyles.AllowThousands but the culture specified use different thousand separator
Case 2 c)
NumberStyles styles = NumberStyles.AllowDecimalPoint;
a = Int32.Parse("1.189", styles); //wrong, int parse cannot parse decimal point at all!
Seemingly NOT OK, but actually OK Examples:
Case 2 a) OK
a = Int32.Parse("-189"); //having - but in the beginning
b = Int32.Parse(" 189 "); //having space, but in the beginning or end
Case 2 b) OK
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189", styles); //ok, having NumberStyles.AllowThousands in the correct culture
b = Int32.Parse("1 189", styles, new CultureInfo("fr-FR")); //ok, having NumberStyles.AllowThousands and correct thousand separator is used for "fr-FR" culture
Solutions
In all cases, please check the value of textBox1.Text
with your Visual Studio debugger and make sure that it has purely-acceptable numerical format for int
range. Something like this:
1234
Also, you may consider of
- using
TryParse
instead ofParse
to ensure that the non-parsed number does not cause you exception problem. check the result of
TryParse
and handle it if nottrue
int val;
bool result = int.TryParse(textbox1.Text, out val);
if (!result)
return; //something has gone wrong
//OK, continue using val
Problems
There are some possible cases why the error occurs:
Because
textBox1.Text
contains only number, but the number is too big/too smallBecause
textBox1.Text
contains:- a) non-number (except
space
in the beginning/end,-
in the beginning) and/or - b) thousand separators in the applied culture for your code without specifying
NumberStyles.AllowThousands
or you specifyNumberStyles.AllowThousands
but put wrongthousand separator
in the culture and/or - c) decimal separator (which should not exist in
int
parsing)
- a) non-number (except
NOT OK Examples:
Case 1
a = Int32.Parse("5000000000"); //5 billions, too large
b = Int32.Parse("-5000000000"); //-5 billions, too small
//The limit for int (32-bit integer) is only from -2,147,483,648 to 2,147,483,647
Case 2 a)
a = Int32.Parse("a189"); //having a
a = Int32.Parse("1-89"); //having - but not in the beginning
a = Int32.Parse("18 9"); //having space, but not in the beginning or end
Case 2 b)
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189"); //not OK, no NumberStyles.AllowThousands
b = Int32.Parse("1,189", styles, new CultureInfo("fr-FR")); //not OK, having NumberStyles.AllowThousands but the culture specified use different thousand separator
Case 2 c)
NumberStyles styles = NumberStyles.AllowDecimalPoint;
a = Int32.Parse("1.189", styles); //wrong, int parse cannot parse decimal point at all!
Seemingly NOT OK, but actually OK Examples:
Case 2 a) OK
a = Int32.Parse("-189"); //having - but in the beginning
b = Int32.Parse(" 189 "); //having space, but in the beginning or end
Case 2 b) OK
NumberStyles styles = NumberStyles.AllowThousands;
a = Int32.Parse("1,189", styles); //ok, having NumberStyles.AllowThousands in the correct culture
b = Int32.Parse("1 189", styles, new CultureInfo("fr-FR")); //ok, having NumberStyles.AllowThousands and correct thousand separator is used for "fr-FR" culture
Solutions
In all cases, please check the value of textBox1.Text
with your Visual Studio debugger and make sure that it has purely-acceptable numerical format for int
range. Something like this:
1234
Also, you may consider of
- using
TryParse
instead ofParse
to ensure that the non-parsed number does not cause you exception problem. check the result of
TryParse
and handle it if nottrue
int val;
bool result = int.TryParse(textbox1.Text, out val);
if (!result)
return; //something has gone wrong
//OK, continue using val
edited May 23 '17 at 12:10
Community♦
11
11
answered Apr 19 '16 at 8:21
IanIan
25.4k144978
25.4k144978
add a comment |
add a comment |
You have not mentioned if your textbox have values in design time or now. When form initializes text box may not hae value if you have not put it in textbox when during form design. you can put int value in form design by setting text property in desgin and this should work.
add a comment |
You have not mentioned if your textbox have values in design time or now. When form initializes text box may not hae value if you have not put it in textbox when during form design. you can put int value in form design by setting text property in desgin and this should work.
add a comment |
You have not mentioned if your textbox have values in design time or now. When form initializes text box may not hae value if you have not put it in textbox when during form design. you can put int value in form design by setting text property in desgin and this should work.
You have not mentioned if your textbox have values in design time or now. When form initializes text box may not hae value if you have not put it in textbox when during form design. you can put int value in form design by setting text property in desgin and this should work.
answered Nov 30 '11 at 5:29
Kirtan PandyaKirtan Pandya
1336
1336
add a comment |
add a comment |
In my case I forgot to put double curly brace to escape. myobject
add a comment |
In my case I forgot to put double curly brace to escape. myobject
add a comment |
In my case I forgot to put double curly brace to escape. myobject
In my case I forgot to put double curly brace to escape. myobject
answered Jan 23 '18 at 14:25
zawhtutzawhtut
6,29043967
6,29043967
add a comment |
add a comment |
it was my problem too ..
in my case i changed the PERSIAN number to LATIN number and it worked.
AND also trime your string before converting.
PersianCalendar pc = new PersianCalendar();
char[] seperator ='/';
string[] date = txtSaleDate.Text.Split(seperator);
int a = Convert.ToInt32(Persia.Number.ConvertToLatin(date[0]).Trim());
add a comment |
it was my problem too ..
in my case i changed the PERSIAN number to LATIN number and it worked.
AND also trime your string before converting.
PersianCalendar pc = new PersianCalendar();
char[] seperator ='/';
string[] date = txtSaleDate.Text.Split(seperator);
int a = Convert.ToInt32(Persia.Number.ConvertToLatin(date[0]).Trim());
add a comment |
it was my problem too ..
in my case i changed the PERSIAN number to LATIN number and it worked.
AND also trime your string before converting.
PersianCalendar pc = new PersianCalendar();
char[] seperator ='/';
string[] date = txtSaleDate.Text.Split(seperator);
int a = Convert.ToInt32(Persia.Number.ConvertToLatin(date[0]).Trim());
it was my problem too ..
in my case i changed the PERSIAN number to LATIN number and it worked.
AND also trime your string before converting.
PersianCalendar pc = new PersianCalendar();
char[] seperator ='/';
string[] date = txtSaleDate.Text.Split(seperator);
int a = Convert.ToInt32(Persia.Number.ConvertToLatin(date[0]).Trim());
answered Dec 10 '15 at 14:54
afshinafshin
2629
2629
add a comment |
add a comment |
I had a similar problem that I solved with the following technique:
The exception was thrown at the following line of code (see the text decorated with ** below):
static void Main(string[] args)
double number = 0;
string numberStr = string.Format("0:C2", 100);
**number = Double.Parse(numberStr);**
Console.WriteLine("The number is 0", number);
After a bit of investigating, I realized that the problem was that the formatted string included a dollar sign ($) that the Parse/TryParse methods cannot resolve (i.e. - strip off). So using the Remove(...) method of the string object I changed the line to:
number = Double.Parse(numberStr.Remove(0, 1)); // Remove the "$" from the number
At that point the Parse(...) method worked as expected.
add a comment |
I had a similar problem that I solved with the following technique:
The exception was thrown at the following line of code (see the text decorated with ** below):
static void Main(string[] args)
double number = 0;
string numberStr = string.Format("0:C2", 100);
**number = Double.Parse(numberStr);**
Console.WriteLine("The number is 0", number);
After a bit of investigating, I realized that the problem was that the formatted string included a dollar sign ($) that the Parse/TryParse methods cannot resolve (i.e. - strip off). So using the Remove(...) method of the string object I changed the line to:
number = Double.Parse(numberStr.Remove(0, 1)); // Remove the "$" from the number
At that point the Parse(...) method worked as expected.
add a comment |
I had a similar problem that I solved with the following technique:
The exception was thrown at the following line of code (see the text decorated with ** below):
static void Main(string[] args)
double number = 0;
string numberStr = string.Format("0:C2", 100);
**number = Double.Parse(numberStr);**
Console.WriteLine("The number is 0", number);
After a bit of investigating, I realized that the problem was that the formatted string included a dollar sign ($) that the Parse/TryParse methods cannot resolve (i.e. - strip off). So using the Remove(...) method of the string object I changed the line to:
number = Double.Parse(numberStr.Remove(0, 1)); // Remove the "$" from the number
At that point the Parse(...) method worked as expected.
I had a similar problem that I solved with the following technique:
The exception was thrown at the following line of code (see the text decorated with ** below):
static void Main(string[] args)
double number = 0;
string numberStr = string.Format("0:C2", 100);
**number = Double.Parse(numberStr);**
Console.WriteLine("The number is 0", number);
After a bit of investigating, I realized that the problem was that the formatted string included a dollar sign ($) that the Parse/TryParse methods cannot resolve (i.e. - strip off). So using the Remove(...) method of the string object I changed the line to:
number = Double.Parse(numberStr.Remove(0, 1)); // Remove the "$" from the number
At that point the Parse(...) method worked as expected.
answered Jun 7 '18 at 16:51
astevens009astevens009
103
103
add a comment |
add a comment |
protected by Community♦ Sep 27 '17 at 16:25
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