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Realtime monitoring using Django
What is a “slug” in Django?How to combine 2 or more querysets in a Django view?How do I do a not equal in Django queryset filtering?Does Django scale?How to debug in Django, the good way?What's the difference between django OneToOneField and ForeignKey?Need a minimal Django file upload exampleHow to check Django versiondifferentiate null=True, blank=True in djangoDjango local server stopped working
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I want to monitor some network devices using Django.
Lets say I have three PC in three different locations.
PC1= city1
PC2= city2
PC3= city3
Something like this:
example
what is the best way to make a realtime monitoring application in Django.
I already know that I can use snmp or ping to get the status of these PC's. (using views). And I know a bit about mapbox or Java to get an interactive map.
So! how can I have a webpage that automatically update the status of these PC's for example every 10 seconds?
django django-models django-rest-framework django-views
asked Mar 8 at 23:32
shami shamishami shami
31
add a comment |
I want to monitor some network devices using Django.
Lets say I have three PC in three different locations.
PC1= city1
PC2= city2
PC3= city3
Something like this:
example
what is the best way to make a realtime monitoring application in Django.
I already know that I can use snmp or ping to get the status of these PC's. (using views). And I know a bit about mapbox or Java to get an interactive map.
So! how can I have a webpage that automatically update the status of these PC's for example every 10 seconds?
django django-models django-rest-framework django-views
asked Mar 8 at 23:32
shami shamishami shami
31
add a comment |
I want to monitor some network devices using Django.
Lets say I have three PC in three different locations.
PC1= city1
PC2= city2
PC3= city3
Something like this:
example
what is the best way to make a realtime monitoring application in Django.
I already know that I can use snmp or ping to get the status of these PC's. (using views). And I know a bit about mapbox or Java to get an interactive map.
So! how can I have a webpage that automatically update the status of these PC's for example every 10 seconds?
django django-models django-rest-framework django-views
asked Mar 8 at 23:32
shami shamishami shami
31
I want to monitor some network devices using Django.
Lets say I have three PC in three different locations.
PC1= city1
PC2= city2
PC3= city3
Something like this:
example
what is the best way to make a realtime monitoring application in Django.
I already know that I can use snmp or ping to get the status of these PC's. (using views). And I know a bit about mapbox or Java to get an interactive map.
So! how can I have a webpage that automatically update the status of these PC's for example every 10 seconds?
django django-models django-rest-framework django-views
django django-models django-rest-framework django-views
asked Mar 8 at 23:32
shami shamishami shami
31
asked Mar 8 at 23:32
shami shamishami shami
31
asked Mar 8 at 23:32
shami shamishami shami
31
asked Mar 8 at 23:32
shami shamishami shami
31
asked Mar 8 at 23:32
shami shamishami shami
31
31
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You have two ways to do this. The first is a page with some JS that has a setTimeout code which runs every 10 seconds, this timeout will do an ajax call to your server which will execute your "get status" commands and returns a JSON result which you can update the data on your browser page with.
The other solution is to have an open websocket with your server, and then have a a Celery worker which runs a periodic task every 10 seconds that executes your "get status" commands and returns the result to your open websocket(s) which then updates your browser page.
Hope this helps!
answered Mar 9 at 0:43
devdobdevdob
56639
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You have two ways to do this. The first is a page with some JS that has a setTimeout code which runs every 10 seconds, this timeout will do an ajax call to your server which will execute your "get status" commands and returns a JSON result which you can update the data on your browser page with.
The other solution is to have an open websocket with your server, and then have a a Celery worker which runs a periodic task every 10 seconds that executes your "get status" commands and returns the result to your open websocket(s) which then updates your browser page.
Hope this helps!
answered Mar 9 at 0:43
devdobdevdob
56639
add a comment |
You have two ways to do this. The first is a page with some JS that has a setTimeout code which runs every 10 seconds, this timeout will do an ajax call to your server which will execute your "get status" commands and returns a JSON result which you can update the data on your browser page with.
The other solution is to have an open websocket with your server, and then have a a Celery worker which runs a periodic task every 10 seconds that executes your "get status" commands and returns the result to your open websocket(s) which then updates your browser page.
Hope this helps!
answered Mar 9 at 0:43
devdobdevdob
56639
add a comment |
You have two ways to do this. The first is a page with some JS that has a setTimeout code which runs every 10 seconds, this timeout will do an ajax call to your server which will execute your "get status" commands and returns a JSON result which you can update the data on your browser page with.
The other solution is to have an open websocket with your server, and then have a a Celery worker which runs a periodic task every 10 seconds that executes your "get status" commands and returns the result to your open websocket(s) which then updates your browser page.
Hope this helps!
answered Mar 9 at 0:43
devdobdevdob
56639
You have two ways to do this. The first is a page with some JS that has a setTimeout code which runs every 10 seconds, this timeout will do an ajax call to your server which will execute your "get status" commands and returns a JSON result which you can update the data on your browser page with.
The other solution is to have an open websocket with your server, and then have a a Celery worker which runs a periodic task every 10 seconds that executes your "get status" commands and returns the result to your open websocket(s) which then updates your browser page.
Hope this helps!
answered Mar 9 at 0:43
devdobdevdob
56639
answered Mar 9 at 0:43
devdobdevdob
56639
answered Mar 9 at 0:43
devdobdevdob
56639
answered Mar 9 at 0:43
devdobdevdob
56639
56639
add a comment |
add a comment |
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