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adding flask expression using url_for dynamically in javascript to display a img element


How can I merge properties of two JavaScript objects dynamically?Event binding on dynamically created elements?Remove empty elements from an array in JavascriptHow do you access the matched groups in a JavaScript regular expression?Deleting array elements in JavaScript - delete vs spliceHow can I display a JavaScript object?How do I remove a particular element from an array in JavaScript?Create dynamic URLs in Flask with url_for()How can I add new array elements at the beginning of an array in Javascript?Cannot display HTML string













0















I am trying to append a img element in ajax POST request success for my flask application as below:



$.ajax({
type: "POST",
url: "/image",
contentType: 'application/json; charset=utf-8',
data: JSON.stringify(pred_path),
success: function()
$('span#predimage').append("<img src=' url_for('new_send') ' width='1140' height='700'>");

error: function(request,status,message)
//alert("Errorn"+message);

);


The element is called correctly and the output in HTML element looks like below:



<span id="predimage"><img src=" url_for(" new_send')="" '="" height="700" width="1140"></span>


Because of which the image is not getting displayed on the webpage. can someone please help me here as i couldn't find any proper solution . Reference for the above is taken from https://www.reddit.com/r/flask/comments/6di61d/url_for_and_jqueryjavascript/ which says the similar usage worked. But i cannot understand why it is not working here.










share|improve this question




























    0















    I am trying to append a img element in ajax POST request success for my flask application as below:



    $.ajax({
    type: "POST",
    url: "/image",
    contentType: 'application/json; charset=utf-8',
    data: JSON.stringify(pred_path),
    success: function()
    $('span#predimage').append("<img src=' url_for('new_send') ' width='1140' height='700'>");

    error: function(request,status,message)
    //alert("Errorn"+message);

    );


    The element is called correctly and the output in HTML element looks like below:



    <span id="predimage"><img src=" url_for(" new_send')="" '="" height="700" width="1140"></span>


    Because of which the image is not getting displayed on the webpage. can someone please help me here as i couldn't find any proper solution . Reference for the above is taken from https://www.reddit.com/r/flask/comments/6di61d/url_for_and_jqueryjavascript/ which says the similar usage worked. But i cannot understand why it is not working here.










    share|improve this question


























      0












      0








      0








      I am trying to append a img element in ajax POST request success for my flask application as below:



      $.ajax({
      type: "POST",
      url: "/image",
      contentType: 'application/json; charset=utf-8',
      data: JSON.stringify(pred_path),
      success: function()
      $('span#predimage').append("<img src=' url_for('new_send') ' width='1140' height='700'>");

      error: function(request,status,message)
      //alert("Errorn"+message);

      );


      The element is called correctly and the output in HTML element looks like below:



      <span id="predimage"><img src=" url_for(" new_send')="" '="" height="700" width="1140"></span>


      Because of which the image is not getting displayed on the webpage. can someone please help me here as i couldn't find any proper solution . Reference for the above is taken from https://www.reddit.com/r/flask/comments/6di61d/url_for_and_jqueryjavascript/ which says the similar usage worked. But i cannot understand why it is not working here.










      share|improve this question
















      I am trying to append a img element in ajax POST request success for my flask application as below:



      $.ajax({
      type: "POST",
      url: "/image",
      contentType: 'application/json; charset=utf-8',
      data: JSON.stringify(pred_path),
      success: function()
      $('span#predimage').append("<img src=' url_for('new_send') ' width='1140' height='700'>");

      error: function(request,status,message)
      //alert("Errorn"+message);

      );


      The element is called correctly and the output in HTML element looks like below:



      <span id="predimage"><img src=" url_for(" new_send')="" '="" height="700" width="1140"></span>


      Because of which the image is not getting displayed on the webpage. can someone please help me here as i couldn't find any proper solution . Reference for the above is taken from https://www.reddit.com/r/flask/comments/6di61d/url_for_and_jqueryjavascript/ which says the similar usage worked. But i cannot understand why it is not working here.







      javascript python flask






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 7 at 20:29









      davidism

      65.4k12175189




      65.4k12175189










      asked Mar 7 at 20:25









      HimaHima

      11




      11






















          1 Answer
          1






          active

          oldest

          votes


















          0














          You need to understand that flask is a Backend framework.

          This means that when a Client makes a request for a page, flask will take care of rendering such page and returning it to the client.

          Functions like "url_for" are pretty useful to personalize your page when it is rendering.



          With this said, after flask returns the rendered page, he has no way of changing anything on it.

          When you add the "url_for" on JavaScript your are adding it on an already rendered page. This happens in client-side and flask is not aware of this.






          share|improve this answer























          • Thanks very much for above asergio. In that case, when I'm trying to give SRC="file:///programming/......" On the HTML page, image is not getting rendered as well. But the same path mentioned above opens the image when given in webpage. Please help me as I m new to flask and web development.

            – Hima
            Mar 7 at 22:44











          • This really depends on you are trying to do. Anyway, you should start by making flask serve static files. Make sure you have the image you want inside the static folder on your project and test if flask is serving it to you by requesting its path "localhost:5000/static/myimage.jpg". If it works, you simply have to use this path on the SRC of your image.

            – asergio
            Mar 7 at 22:55












          • Sorry for trouble but I don't want to serve from static folder. Yes, my application worked with static but I have absolute paths of images located in a shared server. I want to access those files from my flask application.

            – Hima
            Mar 7 at 23:22











          • I am having trouble to understand clearly your situation. I think this problem deserves a new question where you share the code you have right now and the tree of your project files.

            – asergio
            Mar 7 at 23:40










          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          You need to understand that flask is a Backend framework.

          This means that when a Client makes a request for a page, flask will take care of rendering such page and returning it to the client.

          Functions like "url_for" are pretty useful to personalize your page when it is rendering.



          With this said, after flask returns the rendered page, he has no way of changing anything on it.

          When you add the "url_for" on JavaScript your are adding it on an already rendered page. This happens in client-side and flask is not aware of this.






          share|improve this answer























          • Thanks very much for above asergio. In that case, when I'm trying to give SRC="file:///programming/......" On the HTML page, image is not getting rendered as well. But the same path mentioned above opens the image when given in webpage. Please help me as I m new to flask and web development.

            – Hima
            Mar 7 at 22:44











          • This really depends on you are trying to do. Anyway, you should start by making flask serve static files. Make sure you have the image you want inside the static folder on your project and test if flask is serving it to you by requesting its path "localhost:5000/static/myimage.jpg". If it works, you simply have to use this path on the SRC of your image.

            – asergio
            Mar 7 at 22:55












          • Sorry for trouble but I don't want to serve from static folder. Yes, my application worked with static but I have absolute paths of images located in a shared server. I want to access those files from my flask application.

            – Hima
            Mar 7 at 23:22











          • I am having trouble to understand clearly your situation. I think this problem deserves a new question where you share the code you have right now and the tree of your project files.

            – asergio
            Mar 7 at 23:40















          0














          You need to understand that flask is a Backend framework.

          This means that when a Client makes a request for a page, flask will take care of rendering such page and returning it to the client.

          Functions like "url_for" are pretty useful to personalize your page when it is rendering.



          With this said, after flask returns the rendered page, he has no way of changing anything on it.

          When you add the "url_for" on JavaScript your are adding it on an already rendered page. This happens in client-side and flask is not aware of this.






          share|improve this answer























          • Thanks very much for above asergio. In that case, when I'm trying to give SRC="file:///programming/......" On the HTML page, image is not getting rendered as well. But the same path mentioned above opens the image when given in webpage. Please help me as I m new to flask and web development.

            – Hima
            Mar 7 at 22:44











          • This really depends on you are trying to do. Anyway, you should start by making flask serve static files. Make sure you have the image you want inside the static folder on your project and test if flask is serving it to you by requesting its path "localhost:5000/static/myimage.jpg". If it works, you simply have to use this path on the SRC of your image.

            – asergio
            Mar 7 at 22:55












          • Sorry for trouble but I don't want to serve from static folder. Yes, my application worked with static but I have absolute paths of images located in a shared server. I want to access those files from my flask application.

            – Hima
            Mar 7 at 23:22











          • I am having trouble to understand clearly your situation. I think this problem deserves a new question where you share the code you have right now and the tree of your project files.

            – asergio
            Mar 7 at 23:40













          0












          0








          0







          You need to understand that flask is a Backend framework.

          This means that when a Client makes a request for a page, flask will take care of rendering such page and returning it to the client.

          Functions like "url_for" are pretty useful to personalize your page when it is rendering.



          With this said, after flask returns the rendered page, he has no way of changing anything on it.

          When you add the "url_for" on JavaScript your are adding it on an already rendered page. This happens in client-side and flask is not aware of this.






          share|improve this answer













          You need to understand that flask is a Backend framework.

          This means that when a Client makes a request for a page, flask will take care of rendering such page and returning it to the client.

          Functions like "url_for" are pretty useful to personalize your page when it is rendering.



          With this said, after flask returns the rendered page, he has no way of changing anything on it.

          When you add the "url_for" on JavaScript your are adding it on an already rendered page. This happens in client-side and flask is not aware of this.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 7 at 21:25









          asergioasergio

          863




          863












          • Thanks very much for above asergio. In that case, when I'm trying to give SRC="file:///programming/......" On the HTML page, image is not getting rendered as well. But the same path mentioned above opens the image when given in webpage. Please help me as I m new to flask and web development.

            – Hima
            Mar 7 at 22:44











          • This really depends on you are trying to do. Anyway, you should start by making flask serve static files. Make sure you have the image you want inside the static folder on your project and test if flask is serving it to you by requesting its path "localhost:5000/static/myimage.jpg". If it works, you simply have to use this path on the SRC of your image.

            – asergio
            Mar 7 at 22:55












          • Sorry for trouble but I don't want to serve from static folder. Yes, my application worked with static but I have absolute paths of images located in a shared server. I want to access those files from my flask application.

            – Hima
            Mar 7 at 23:22











          • I am having trouble to understand clearly your situation. I think this problem deserves a new question where you share the code you have right now and the tree of your project files.

            – asergio
            Mar 7 at 23:40

















          • Thanks very much for above asergio. In that case, when I'm trying to give SRC="file:///programming/......" On the HTML page, image is not getting rendered as well. But the same path mentioned above opens the image when given in webpage. Please help me as I m new to flask and web development.

            – Hima
            Mar 7 at 22:44











          • This really depends on you are trying to do. Anyway, you should start by making flask serve static files. Make sure you have the image you want inside the static folder on your project and test if flask is serving it to you by requesting its path "localhost:5000/static/myimage.jpg". If it works, you simply have to use this path on the SRC of your image.

            – asergio
            Mar 7 at 22:55












          • Sorry for trouble but I don't want to serve from static folder. Yes, my application worked with static but I have absolute paths of images located in a shared server. I want to access those files from my flask application.

            – Hima
            Mar 7 at 23:22











          • I am having trouble to understand clearly your situation. I think this problem deserves a new question where you share the code you have right now and the tree of your project files.

            – asergio
            Mar 7 at 23:40
















          Thanks very much for above asergio. In that case, when I'm trying to give SRC="file:///programming/......" On the HTML page, image is not getting rendered as well. But the same path mentioned above opens the image when given in webpage. Please help me as I m new to flask and web development.

          – Hima
          Mar 7 at 22:44





          Thanks very much for above asergio. In that case, when I'm trying to give SRC="file:///programming/......" On the HTML page, image is not getting rendered as well. But the same path mentioned above opens the image when given in webpage. Please help me as I m new to flask and web development.

          – Hima
          Mar 7 at 22:44













          This really depends on you are trying to do. Anyway, you should start by making flask serve static files. Make sure you have the image you want inside the static folder on your project and test if flask is serving it to you by requesting its path "localhost:5000/static/myimage.jpg". If it works, you simply have to use this path on the SRC of your image.

          – asergio
          Mar 7 at 22:55






          This really depends on you are trying to do. Anyway, you should start by making flask serve static files. Make sure you have the image you want inside the static folder on your project and test if flask is serving it to you by requesting its path "localhost:5000/static/myimage.jpg". If it works, you simply have to use this path on the SRC of your image.

          – asergio
          Mar 7 at 22:55














          Sorry for trouble but I don't want to serve from static folder. Yes, my application worked with static but I have absolute paths of images located in a shared server. I want to access those files from my flask application.

          – Hima
          Mar 7 at 23:22





          Sorry for trouble but I don't want to serve from static folder. Yes, my application worked with static but I have absolute paths of images located in a shared server. I want to access those files from my flask application.

          – Hima
          Mar 7 at 23:22













          I am having trouble to understand clearly your situation. I think this problem deserves a new question where you share the code you have right now and the tree of your project files.

          – asergio
          Mar 7 at 23:40





          I am having trouble to understand clearly your situation. I think this problem deserves a new question where you share the code you have right now and the tree of your project files.

          – asergio
          Mar 7 at 23:40



















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