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Filtering an array of objects that contain arrays
What is the most efficient way to deep clone an object in JavaScript?How do I remove a property from a JavaScript object?How do I check if an array includes an object in JavaScript?How to append something to an array?Sort array of objects by string property valueHow to check whether a string contains a substring in JavaScript?Loop through an array in JavaScriptHow to check if an object is an array?How do I remove a particular element from an array in JavaScript?For-each over an array in JavaScript?
This is a smaller version of the array i have but it has the same structure
with const arr below, i want to create 2 new arrays with unique values that are sorted in ascending order
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
const finalTags = [];
const finalWeight = [];
// TODO: find a better way to do this
arr.forEach(v =>
if (finalWeight.indexOf(v.weight) === -1) finalWeight.push(v.weight);
v.tags.forEach(val =>
if (finalTags.indexOf(val) === -1) finalTags.push(val);
);
);
// Ascending order
finalTags.sort();
finalWeight.sort();what i have above works, but seems a bit messy and was wandering if there was a better/tidier way of doing this
javascript arrays sorting ecmascript-6
edited Mar 8 at 5:16
Aniket G
2,4211528
asked Mar 8 at 5:05
ace2caseace2case
415
add a comment |
This is a smaller version of the array i have but it has the same structure
with const arr below, i want to create 2 new arrays with unique values that are sorted in ascending order
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
const finalTags = [];
const finalWeight = [];
// TODO: find a better way to do this
arr.forEach(v =>
if (finalWeight.indexOf(v.weight) === -1) finalWeight.push(v.weight);
v.tags.forEach(val =>
if (finalTags.indexOf(val) === -1) finalTags.push(val);
);
);
// Ascending order
finalTags.sort();
finalWeight.sort();what i have above works, but seems a bit messy and was wandering if there was a better/tidier way of doing this
javascript arrays sorting ecmascript-6
edited Mar 8 at 5:16
Aniket G
2,4211528
asked Mar 8 at 5:05
ace2caseace2case
415
Might this be better off on codereview.stackexchange.com?
– rh16
Mar 8 at 5:18
add a comment |
This is a smaller version of the array i have but it has the same structure
with const arr below, i want to create 2 new arrays with unique values that are sorted in ascending order
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
const finalTags = [];
const finalWeight = [];
// TODO: find a better way to do this
arr.forEach(v =>
if (finalWeight.indexOf(v.weight) === -1) finalWeight.push(v.weight);
v.tags.forEach(val =>
if (finalTags.indexOf(val) === -1) finalTags.push(val);
);
);
// Ascending order
finalTags.sort();
finalWeight.sort();what i have above works, but seems a bit messy and was wandering if there was a better/tidier way of doing this
javascript arrays sorting ecmascript-6
edited Mar 8 at 5:16
Aniket G
2,4211528
asked Mar 8 at 5:05
ace2caseace2case
415
This is a smaller version of the array i have but it has the same structure
with const arr below, i want to create 2 new arrays with unique values that are sorted in ascending order
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
const finalTags = [];
const finalWeight = [];
// TODO: find a better way to do this
arr.forEach(v =>
if (finalWeight.indexOf(v.weight) === -1) finalWeight.push(v.weight);
v.tags.forEach(val =>
if (finalTags.indexOf(val) === -1) finalTags.push(val);
);
);
// Ascending order
finalTags.sort();
finalWeight.sort();what i have above works, but seems a bit messy and was wandering if there was a better/tidier way of doing this
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
const finalTags = [];
const finalWeight = [];
// TODO: find a better way to do this
arr.forEach(v =>
if (finalWeight.indexOf(v.weight) === -1) finalWeight.push(v.weight);
v.tags.forEach(val =>
if (finalTags.indexOf(val) === -1) finalTags.push(val);
);
);
// Ascending order
finalTags.sort();
finalWeight.sort();const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
const finalTags = [];
const finalWeight = [];
// TODO: find a better way to do this
arr.forEach(v =>
if (finalWeight.indexOf(v.weight) === -1) finalWeight.push(v.weight);
v.tags.forEach(val =>
if (finalTags.indexOf(val) === -1) finalTags.push(val);
);
);
// Ascending order
finalTags.sort();
finalWeight.sort();javascript arrays sorting ecmascript-6
javascript arrays sorting ecmascript-6
edited Mar 8 at 5:16
Aniket G
2,4211528
asked Mar 8 at 5:05
ace2caseace2case
415
edited Mar 8 at 5:16
Aniket G
2,4211528
asked Mar 8 at 5:05
ace2caseace2case
415
edited Mar 8 at 5:16
Aniket G
2,4211528
edited Mar 8 at 5:16
Aniket G
2,4211528
edited Mar 8 at 5:16
Aniket G
2,4211528
2,4211528
asked Mar 8 at 5:05
ace2caseace2case
415
asked Mar 8 at 5:05
ace2caseace2case
415
asked Mar 8 at 5:05
ace2caseace2case
415
415
Might this be better off on codereview.stackexchange.com?
– rh16
Mar 8 at 5:18
add a comment |
Might this be better off on codereview.stackexchange.com?
– rh16
Mar 8 at 5:18
Might this be better off on codereview.stackexchange.com?
– rh16
Mar 8 at 5:18
Might this be better off on codereview.stackexchange.com?
– rh16
Mar 8 at 5:18
add a comment |
3 Answers
3
active
oldest
votes
You can use Array.prototype.reduce() combined with Set in order to get an object with the sorted arrays tags: [], weights: []:
const arr = [tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf',tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd',tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh',tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'];
const obj = arr.reduce((a, tags, weight) =>
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
, tags: [], weights: []);
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper max-height: 100% !important; top: 0; answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
1
I will vote you up because you had a similar idea to mine and was first. However, it will be nice to see some explanation too.
– Shidersz
Mar 8 at 6:07
Thank you for your comment @Shidersz. I have added a better description and you also have my up..
– Yosvel Quintero
Mar 8 at 6:34
much nicer than my version, thanks for all your answers
– ace2case
Mar 8 at 22:26
add a comment |
One solution is to use Array.reduce() to create two sets, one with the tags and other with the weights. After this you can transform the sets to arrays and use Array.sort() on they:
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let res = arr.reduce((acc, tags, weight) =>
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
, tags: new Set(), weights: new Set());
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console background-color:black !important; color:lime;
.as-console-wrapper max-height:100% !important; top:0;answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
add a comment |
You could use the following code. This basically splits arr up into finalTags and finalWeights.
.flat() flattens the array ([1, [2, [3]]] would become [1, 2, 3])
finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort(); remove's the duplicates.
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let finalTags = arr.map(e => e.tags);
finalTags = finalTags.flat();
finalTags = finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort();
let finalWeight = arr.map(e => e.weight);
finalWeight = finalWeight.filter((item, index) => finalWeight.indexOf(item) >= index).sort();
console.log(finalTags);
console.log(finalWeight);Sources:
Removing duplicates: https://gomakethings.com/removing-duplicates-from-an-array-with-vanilla-javascript/
answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use Array.prototype.reduce() combined with Set in order to get an object with the sorted arrays tags: [], weights: []:
const arr = [tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf',tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd',tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh',tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'];
const obj = arr.reduce((a, tags, weight) =>
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
, tags: [], weights: []);
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper max-height: 100% !important; top: 0; answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
1
I will vote you up because you had a similar idea to mine and was first. However, it will be nice to see some explanation too.
– Shidersz
Mar 8 at 6:07
Thank you for your comment @Shidersz. I have added a better description and you also have my up..
– Yosvel Quintero
Mar 8 at 6:34
much nicer than my version, thanks for all your answers
– ace2case
Mar 8 at 22:26
add a comment |
You can use Array.prototype.reduce() combined with Set in order to get an object with the sorted arrays tags: [], weights: []:
const arr = [tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf',tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd',tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh',tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'];
const obj = arr.reduce((a, tags, weight) =>
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
, tags: [], weights: []);
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper max-height: 100% !important; top: 0; answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
1
I will vote you up because you had a similar idea to mine and was first. However, it will be nice to see some explanation too.
– Shidersz
Mar 8 at 6:07
Thank you for your comment @Shidersz. I have added a better description and you also have my up..
– Yosvel Quintero
Mar 8 at 6:34
much nicer than my version, thanks for all your answers
– ace2case
Mar 8 at 22:26
add a comment |
You can use Array.prototype.reduce() combined with Set in order to get an object with the sorted arrays tags: [], weights: []:
const arr = [tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf',tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd',tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh',tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'];
const obj = arr.reduce((a, tags, weight) =>
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
, tags: [], weights: []);
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper max-height: 100% !important; top: 0; answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
You can use Array.prototype.reduce() combined with Set in order to get an object with the sorted arrays tags: [], weights: []:
const arr = [tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf',tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd',tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh',tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'];
const obj = arr.reduce((a, tags, weight) =>
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
, tags: [], weights: []);
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper max-height: 100% !important; top: 0; const arr = [tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf',tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd',tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh',tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'];
const obj = arr.reduce((a, tags, weight) =>
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
, tags: [], weights: []);
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper max-height: 100% !important; top: 0; const arr = [tags: ['f', 'b', 'd'],weight: 7,something: 'sdfsdf',tags: ['a', 'b', 'c', 'd', 'e'],weight: 6,something: 'frddd',tags: ['f', 'c', 'e', 'a'],weight: 7,something: 'ththh',tags: ['a', 'c', 'g', 'e'],weight: 5,something: 'ghjghj'];
const obj = arr.reduce((a, tags, weight) =>
a.tags = [...new Set(a.tags.concat(tags))];
a.weights = [...new Set(a.weights.concat(weight))];
return a;
, tags: [], weights: []);
// final result i want
console.log('finalTags:', obj.tags.sort()); // ['a', 'b', 'c', 'd', 'e', 'f', 'g'];
console.log('finalWeight:', obj.weights.sort()); // [5, 6, 7];.as-console-wrapper max-height: 100% !important; top: 0; answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
edited Mar 9 at 1:41
answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
answered Mar 8 at 5:16
Yosvel QuinteroYosvel Quintero
11.8k42531
11.8k42531
1
I will vote you up because you had a similar idea to mine and was first. However, it will be nice to see some explanation too.
– Shidersz
Mar 8 at 6:07
Thank you for your comment @Shidersz. I have added a better description and you also have my up..
– Yosvel Quintero
Mar 8 at 6:34
much nicer than my version, thanks for all your answers
– ace2case
Mar 8 at 22:26
add a comment |
1
I will vote you up because you had a similar idea to mine and was first. However, it will be nice to see some explanation too.
– Shidersz
Mar 8 at 6:07
Thank you for your comment @Shidersz. I have added a better description and you also have my up..
– Yosvel Quintero
Mar 8 at 6:34
much nicer than my version, thanks for all your answers
– ace2case
Mar 8 at 22:26
1
1
I will vote you up because you had a similar idea to mine and was first. However, it will be nice to see some explanation too.
– Shidersz
Mar 8 at 6:07
I will vote you up because you had a similar idea to mine and was first. However, it will be nice to see some explanation too.
– Shidersz
Mar 8 at 6:07
Thank you for your comment @Shidersz. I have added a better description and you also have my up..
– Yosvel Quintero
Mar 8 at 6:34
Thank you for your comment @Shidersz. I have added a better description and you also have my up..
– Yosvel Quintero
Mar 8 at 6:34
much nicer than my version, thanks for all your answers
– ace2case
Mar 8 at 22:26
much nicer than my version, thanks for all your answers
– ace2case
Mar 8 at 22:26
add a comment |
One solution is to use Array.reduce() to create two sets, one with the tags and other with the weights. After this you can transform the sets to arrays and use Array.sort() on they:
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let res = arr.reduce((acc, tags, weight) =>
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
, tags: new Set(), weights: new Set());
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console background-color:black !important; color:lime;
.as-console-wrapper max-height:100% !important; top:0;answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
add a comment |
One solution is to use Array.reduce() to create two sets, one with the tags and other with the weights. After this you can transform the sets to arrays and use Array.sort() on they:
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let res = arr.reduce((acc, tags, weight) =>
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
, tags: new Set(), weights: new Set());
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console background-color:black !important; color:lime;
.as-console-wrapper max-height:100% !important; top:0;answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
add a comment |
One solution is to use Array.reduce() to create two sets, one with the tags and other with the weights. After this you can transform the sets to arrays and use Array.sort() on they:
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let res = arr.reduce((acc, tags, weight) =>
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
, tags: new Set(), weights: new Set());
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console background-color:black !important; color:lime;
.as-console-wrapper max-height:100% !important; top:0;answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
One solution is to use Array.reduce() to create two sets, one with the tags and other with the weights. After this you can transform the sets to arrays and use Array.sort() on they:
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let res = arr.reduce((acc, tags, weight) =>
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
, tags: new Set(), weights: new Set());
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console background-color:black !important; color:lime;
.as-console-wrapper max-height:100% !important; top:0;const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let res = arr.reduce((acc, tags, weight) =>
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
, tags: new Set(), weights: new Set());
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console background-color:black !important; color:lime;
.as-console-wrapper max-height:100% !important; top:0;const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let res = arr.reduce((acc, tags, weight) =>
acc.tags = new Set([...acc.tags, ...tags]);
acc.weights.add(weight);
return acc;
, tags: new Set(), weights: new Set());
let sortedWeigths = [...res.weights].sort();
let sortedTags = [...res.tags].sort((a, b) => a.localeCompare(b));
console.log("weights: ", sortedWeigths, "tags: ", sortedTags);.as-console background-color:black !important; color:lime;
.as-console-wrapper max-height:100% !important; top:0;answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
answered Mar 8 at 5:21
ShiderszShidersz
9,1212833
9,1212833
add a comment |
add a comment |
You could use the following code. This basically splits arr up into finalTags and finalWeights.
.flat() flattens the array ([1, [2, [3]]] would become [1, 2, 3])
finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort(); remove's the duplicates.
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let finalTags = arr.map(e => e.tags);
finalTags = finalTags.flat();
finalTags = finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort();
let finalWeight = arr.map(e => e.weight);
finalWeight = finalWeight.filter((item, index) => finalWeight.indexOf(item) >= index).sort();
console.log(finalTags);
console.log(finalWeight);Sources:
Removing duplicates: https://gomakethings.com/removing-duplicates-from-an-array-with-vanilla-javascript/
answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
add a comment |
You could use the following code. This basically splits arr up into finalTags and finalWeights.
.flat() flattens the array ([1, [2, [3]]] would become [1, 2, 3])
finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort(); remove's the duplicates.
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let finalTags = arr.map(e => e.tags);
finalTags = finalTags.flat();
finalTags = finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort();
let finalWeight = arr.map(e => e.weight);
finalWeight = finalWeight.filter((item, index) => finalWeight.indexOf(item) >= index).sort();
console.log(finalTags);
console.log(finalWeight);Sources:
Removing duplicates: https://gomakethings.com/removing-duplicates-from-an-array-with-vanilla-javascript/
answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
add a comment |
You could use the following code. This basically splits arr up into finalTags and finalWeights.
.flat() flattens the array ([1, [2, [3]]] would become [1, 2, 3])
finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort(); remove's the duplicates.
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let finalTags = arr.map(e => e.tags);
finalTags = finalTags.flat();
finalTags = finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort();
let finalWeight = arr.map(e => e.weight);
finalWeight = finalWeight.filter((item, index) => finalWeight.indexOf(item) >= index).sort();
console.log(finalTags);
console.log(finalWeight);Sources:
Removing duplicates: https://gomakethings.com/removing-duplicates-from-an-array-with-vanilla-javascript/
answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
You could use the following code. This basically splits arr up into finalTags and finalWeights.
.flat() flattens the array ([1, [2, [3]]] would become [1, 2, 3])
finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort(); remove's the duplicates.
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let finalTags = arr.map(e => e.tags);
finalTags = finalTags.flat();
finalTags = finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort();
let finalWeight = arr.map(e => e.weight);
finalWeight = finalWeight.filter((item, index) => finalWeight.indexOf(item) >= index).sort();
console.log(finalTags);
console.log(finalWeight);Sources:
Removing duplicates: https://gomakethings.com/removing-duplicates-from-an-array-with-vanilla-javascript/
const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let finalTags = arr.map(e => e.tags);
finalTags = finalTags.flat();
finalTags = finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort();
let finalWeight = arr.map(e => e.weight);
finalWeight = finalWeight.filter((item, index) => finalWeight.indexOf(item) >= index).sort();
console.log(finalTags);
console.log(finalWeight);const arr = [
tags: ['f', 'b', 'd'],
weight: 7,
something: 'sdfsdf'
,
tags: ['a', 'b', 'c', 'd', 'e'],
weight: 6,
something: 'frddd'
,
tags: ['f', 'c', 'e', 'a'],
weight: 7,
something: 'ththh'
,
tags: ['a', 'c', 'g', 'e'],
weight: 5,
something: 'ghjghj'
];
let finalTags = arr.map(e => e.tags);
finalTags = finalTags.flat();
finalTags = finalTags.filter((item, index) => finalTags.indexOf(item) >= index).sort();
let finalWeight = arr.map(e => e.weight);
finalWeight = finalWeight.filter((item, index) => finalWeight.indexOf(item) >= index).sort();
console.log(finalTags);
console.log(finalWeight);answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
edited Mar 8 at 5:30
answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
answered Mar 8 at 5:23
Aniket GAniket G
2,4211528
2,4211528
add a comment |
add a comment |
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Might this be better off on codereview.stackexchange.com?
– rh16
Mar 8 at 5:18