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Converting C# Regular Expression To Java matcher issue
C# / .NET equivalent for Java Matcher.find and Matcher.groupIs there a regular expression to detect a valid regular expression?How to validate an email address using a regular expression?Fastest way to determine if an integer's square root is an integerHow do I read / convert an InputStream into a String in Java?Regular Expression for alphanumeric and underscoresRegular expression to match a line that doesn't contain a word?How do you access the matched groups in a JavaScript regular expression?Regular Expressions: Is there an AND operator?How do you use a variable in a regular expression?How do I convert a String to an int in Java?
public static String ReturnBetween(String heap, String startEx, String endEx, boolean include)
int startPos = 0;
int endPos = heap.length();
String starts = "";
String ends = "";
if (!startEx.equals("^"))
Pattern regexStart = Pattern.compile(startEx, Pattern.CASE_INSENSITIVE
if (startPos == -1)
return "";
if (!endEx.equals("$"))
Pattern regexEnd = Pattern.compile(endEx, Pattern.CASE_INSENSITIVE
if (endPos == -1)
return "";
if (!include)
startPos += starts.length();
if (include)
endPos += ends.length();
String result = heap.substring(startPos, endPos);
return result;
This was a c# function for getting a string between two variables i am trying to convert it to java function most the part have been already converted to java code.
i have managed to convert this function . except this part :
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
java regex matcher
asked Mar 8 at 11:23
az favaz fav
257
add a comment |
public static String ReturnBetween(String heap, String startEx, String endEx, boolean include)
int startPos = 0;
int endPos = heap.length();
String starts = "";
String ends = "";
if (!startEx.equals("^"))
Pattern regexStart = Pattern.compile(startEx, Pattern.CASE_INSENSITIVE
if (startPos == -1)
return "";
if (!endEx.equals("$"))
Pattern regexEnd = Pattern.compile(endEx, Pattern.CASE_INSENSITIVE
if (endPos == -1)
return "";
if (!include)
startPos += starts.length();
if (include)
endPos += ends.length();
String result = heap.substring(startPos, endPos);
return result;
This was a c# function for getting a string between two variables i am trying to convert it to java function most the part have been already converted to java code.
i have managed to convert this function . except this part :
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
java regex matcher
asked Mar 8 at 11:23
az favaz fav
257
Refer to this question: stackoverflow.com/questions/37136376/… to address your issue.
– Rahul Sharma
Mar 8 at 11:42
@Wiktor Stribiżew Upvoted and thanks about the tip.
– az fav
Mar 13 at 8:41
add a comment |
public static String ReturnBetween(String heap, String startEx, String endEx, boolean include)
int startPos = 0;
int endPos = heap.length();
String starts = "";
String ends = "";
if (!startEx.equals("^"))
Pattern regexStart = Pattern.compile(startEx, Pattern.CASE_INSENSITIVE
if (startPos == -1)
return "";
if (!endEx.equals("$"))
Pattern regexEnd = Pattern.compile(endEx, Pattern.CASE_INSENSITIVE
if (endPos == -1)
return "";
if (!include)
startPos += starts.length();
if (include)
endPos += ends.length();
String result = heap.substring(startPos, endPos);
return result;
This was a c# function for getting a string between two variables i am trying to convert it to java function most the part have been already converted to java code.
i have managed to convert this function . except this part :
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
java regex matcher
asked Mar 8 at 11:23
az favaz fav
257
public static String ReturnBetween(String heap, String startEx, String endEx, boolean include)
int startPos = 0;
int endPos = heap.length();
String starts = "";
String ends = "";
if (!startEx.equals("^"))
Pattern regexStart = Pattern.compile(startEx, Pattern.CASE_INSENSITIVE
if (startPos == -1)
return "";
if (!endEx.equals("$"))
Pattern regexEnd = Pattern.compile(endEx, Pattern.CASE_INSENSITIVE
if (endPos == -1)
return "";
if (!include)
startPos += starts.length();
if (include)
endPos += ends.length();
String result = heap.substring(startPos, endPos);
return result;
This was a c# function for getting a string between two variables i am trying to convert it to java function most the part have been already converted to java code.
i have managed to convert this function . except this part :
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
java regex matcher
java regex matcher
asked Mar 8 at 11:23
az favaz fav
257
asked Mar 8 at 11:23
az favaz fav
257
asked Mar 8 at 11:23
az favaz fav
257
asked Mar 8 at 11:23
az favaz fav
257
asked Mar 8 at 11:23
az favaz fav
257
257
Refer to this question: stackoverflow.com/questions/37136376/… to address your issue.
– Rahul Sharma
Mar 8 at 11:42
@Wiktor Stribiżew Upvoted and thanks about the tip.
– az fav
Mar 13 at 8:41
add a comment |
Refer to this question: stackoverflow.com/questions/37136376/… to address your issue.
– Rahul Sharma
Mar 8 at 11:42
@Wiktor Stribiżew Upvoted and thanks about the tip.
– az fav
Mar 13 at 8:41
Refer to this question: stackoverflow.com/questions/37136376/… to address your issue.
– Rahul Sharma
Mar 8 at 11:42
Refer to this question: stackoverflow.com/questions/37136376/… to address your issue.
– Rahul Sharma
Mar 8 at 11:42
@Wiktor Stribiżew Upvoted and thanks about the tip.
– az fav
Mar 13 at 8:41
@Wiktor Stribiżew Upvoted and thanks about the tip.
– az fav
Mar 13 at 8:41
add a comment |
1 Answer
1
active
oldest
votes
You should replace
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
with
Matcher m = regexEnd.matcher(heap);
if (m.find(startPos + starts.length()))
ends = m.group();
The point is that you need to declare a matcher and instantiate it with the input string (heap) from a Pattern that you already have (regexEnd).
Then, you execute the matcher using .find(index) where index is the start position to search from. If there is a match, m.group() contains the match value.
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You should replace
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
with
Matcher m = regexEnd.matcher(heap);
if (m.find(startPos + starts.length()))
ends = m.group();
The point is that you need to declare a matcher and instantiate it with the input string (heap) from a Pattern that you already have (regexEnd).
Then, you execute the matcher using .find(index) where index is the start position to search from. If there is a match, m.group() contains the match value.
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
add a comment |
You should replace
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
with
Matcher m = regexEnd.matcher(heap);
if (m.find(startPos + starts.length()))
ends = m.group();
The point is that you need to declare a matcher and instantiate it with the input string (heap) from a Pattern that you already have (regexEnd).
Then, you execute the matcher using .find(index) where index is the start position to search from. If there is a match, m.group() contains the match value.
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
add a comment |
You should replace
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
with
Matcher m = regexEnd.matcher(heap);
if (m.find(startPos + starts.length()))
ends = m.group();
The point is that you need to declare a matcher and instantiate it with the input string (heap) from a Pattern that you already have (regexEnd).
Then, you execute the matcher using .find(index) where index is the start position to search from. If there is a match, m.group() contains the match value.
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
You should replace
ends = regexEnd.Match(heap, startPos + starts.length()).toString();
with
Matcher m = regexEnd.matcher(heap);
if (m.find(startPos + starts.length()))
ends = m.group();
The point is that you need to declare a matcher and instantiate it with the input string (heap) from a Pattern that you already have (regexEnd).
Then, you execute the matcher using .find(index) where index is the start position to search from. If there is a match, m.group() contains the match value.
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
answered Mar 8 at 12:55
Wiktor StribiżewWiktor Stribiżew
326k16147226
326k16147226
add a comment |
add a comment |
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Refer to this question: stackoverflow.com/questions/37136376/… to address your issue.
– Rahul Sharma
Mar 8 at 11:42
@Wiktor Stribiżew Upvoted and thanks about the tip.
– az fav
Mar 13 at 8:41