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js-datepicker mutiple inputs with the same class
How to change an element's class with JavaScript?How can I select an element with multiple classes in jQuery?Disable/enable an input with jQuery?Disable same origin policy in ChromeJQueryUI DatePicker replacing invalid input with minDateExtending jQuery UI components ( Overriding jQuery Datepicker to prevent wrong input)UI-Bootstrap datepicker with input maskAngular 2 with javascript and datepickerDon't display datepicker popup in mobile devices for input type=dateJquery UI datepicker add “Unknown” option value to input
I'm using this js-datepicker plugin (https://www.npmjs.com/package/js-datepicker). The problem is I have a lot of fields I want to apply the same type of date picker so presumed I could just give them all a class of say 'year', however it only assigns it to the first input field with that class. Is there a way to apply to all inputs with that class?
my code:
const year = datepicker('.year',
/* formatter: (input, date, instance) =>
const value = date.toLocaleDateString()
input.value = value // => '1/1/2099'
*/
);
javascript npm jsdatepick
asked Mar 8 at 11:22
karlkarl
467
add a comment |
I'm using this js-datepicker plugin (https://www.npmjs.com/package/js-datepicker). The problem is I have a lot of fields I want to apply the same type of date picker so presumed I could just give them all a class of say 'year', however it only assigns it to the first input field with that class. Is there a way to apply to all inputs with that class?
my code:
const year = datepicker('.year',
/* formatter: (input, date, instance) =>
const value = date.toLocaleDateString()
input.value = value // => '1/1/2099'
*/
);
javascript npm jsdatepick
asked Mar 8 at 11:22
karlkarl
467
1
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
– 04FS
Mar 8 at 11:29
They would all be assigned to same const variable, that's why it is appended only to the first element. You'd have to create an array of const and possibly differentiate the DOM elements by something more specific like an id value
– Davide Vitali
Mar 8 at 11:29
add a comment |
I'm using this js-datepicker plugin (https://www.npmjs.com/package/js-datepicker). The problem is I have a lot of fields I want to apply the same type of date picker so presumed I could just give them all a class of say 'year', however it only assigns it to the first input field with that class. Is there a way to apply to all inputs with that class?
my code:
const year = datepicker('.year',
/* formatter: (input, date, instance) =>
const value = date.toLocaleDateString()
input.value = value // => '1/1/2099'
*/
);
javascript npm jsdatepick
asked Mar 8 at 11:22
karlkarl
467
I'm using this js-datepicker plugin (https://www.npmjs.com/package/js-datepicker). The problem is I have a lot of fields I want to apply the same type of date picker so presumed I could just give them all a class of say 'year', however it only assigns it to the first input field with that class. Is there a way to apply to all inputs with that class?
my code:
const year = datepicker('.year',
/* formatter: (input, date, instance) =>
const value = date.toLocaleDateString()
input.value = value // => '1/1/2099'
*/
);
javascript npm jsdatepick
javascript npm jsdatepick
asked Mar 8 at 11:22
karlkarl
467
asked Mar 8 at 11:22
karlkarl
467
asked Mar 8 at 11:22
karlkarl
467
asked Mar 8 at 11:22
karlkarl
467
asked Mar 8 at 11:22
karlkarl
467
467
1
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
– 04FS
Mar 8 at 11:29
They would all be assigned to same const variable, that's why it is appended only to the first element. You'd have to create an array of const and possibly differentiate the DOM elements by something more specific like an id value
– Davide Vitali
Mar 8 at 11:29
add a comment |
1
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
– 04FS
Mar 8 at 11:29
They would all be assigned to same const variable, that's why it is appended only to the first element. You'd have to create an array of const and possibly differentiate the DOM elements by something more specific like an id value
– Davide Vitali
Mar 8 at 11:29
1
1
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
– 04FS
Mar 8 at 11:29
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
– 04FS
Mar 8 at 11:29
They would all be assigned to same const variable, that's why it is appended only to the first element. You'd have to create an array of const and possibly differentiate the DOM elements by something more specific like an id value
– Davide Vitali
Mar 8 at 11:29
They would all be assigned to same const variable, that's why it is appended only to the first element. You'd have to create an array of const and possibly differentiate the DOM elements by something more specific like an id value
– Davide Vitali
Mar 8 at 11:29
add a comment |
2 Answers
2
active
oldest
votes
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
Basically something simple like this should do,
var fields = document.querySelectorAll('.year');
fields.forEach(function(e)
datepicker(e, )
);
If you need the references to the datepicker instances to be able to modify options later on or something like that, you could add them to an array inside the loop.
answered Mar 8 at 11:32
04FS04FS
1,3241314
awesome, looks like the best solution cheers!
– karl
Mar 8 at 12:12
add a comment |
Maybe you can simply use input type "date" to have a quick working solution.
Advantage: Format is chosen based on the current settings of the user, no need to format anything.
<input type="date" value="2019-01-01">answered Mar 8 at 11:30
AaronAaron
13
Hi Aaron, yes this is how I first wanted to do it but unfortunately there's no way of customising the output, it has to go into a specific date format which is likely different to the browser preference.
– karl
Mar 8 at 12:14
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
Basically something simple like this should do,
var fields = document.querySelectorAll('.year');
fields.forEach(function(e)
datepicker(e, )
);
If you need the references to the datepicker instances to be able to modify options later on or something like that, you could add them to an array inside the loop.
answered Mar 8 at 11:32
04FS04FS
1,3241314
awesome, looks like the best solution cheers!
– karl
Mar 8 at 12:12
add a comment |
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
Basically something simple like this should do,
var fields = document.querySelectorAll('.year');
fields.forEach(function(e)
datepicker(e, )
);
If you need the references to the datepicker instances to be able to modify options later on or something like that, you could add them to an array inside the loop.
answered Mar 8 at 11:32
04FS04FS
1,3241314
awesome, looks like the best solution cheers!
– karl
Mar 8 at 12:12
add a comment |
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
Basically something simple like this should do,
var fields = document.querySelectorAll('.year');
fields.forEach(function(e)
datepicker(e, )
);
If you need the references to the datepicker instances to be able to modify options later on or something like that, you could add them to an array inside the loop.
answered Mar 8 at 11:32
04FS04FS
1,3241314
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
Basically something simple like this should do,
var fields = document.querySelectorAll('.year');
fields.forEach(function(e)
datepicker(e, )
);
If you need the references to the datepicker instances to be able to modify options later on or something like that, you could add them to an array inside the loop.
answered Mar 8 at 11:32
04FS04FS
1,3241314
answered Mar 8 at 11:32
04FS04FS
1,3241314
answered Mar 8 at 11:32
04FS04FS
1,3241314
answered Mar 8 at 11:32
04FS04FS
1,3241314
1,3241314
awesome, looks like the best solution cheers!
– karl
Mar 8 at 12:12
add a comment |
awesome, looks like the best solution cheers!
– karl
Mar 8 at 12:12
awesome, looks like the best solution cheers!
– karl
Mar 8 at 12:12
awesome, looks like the best solution cheers!
– karl
Mar 8 at 12:12
add a comment |
Maybe you can simply use input type "date" to have a quick working solution.
Advantage: Format is chosen based on the current settings of the user, no need to format anything.
<input type="date" value="2019-01-01">answered Mar 8 at 11:30
AaronAaron
13
Hi Aaron, yes this is how I first wanted to do it but unfortunately there's no way of customising the output, it has to go into a specific date format which is likely different to the browser preference.
– karl
Mar 8 at 12:14
add a comment |
Maybe you can simply use input type "date" to have a quick working solution.
Advantage: Format is chosen based on the current settings of the user, no need to format anything.
<input type="date" value="2019-01-01">answered Mar 8 at 11:30
AaronAaron
13
Hi Aaron, yes this is how I first wanted to do it but unfortunately there's no way of customising the output, it has to go into a specific date format which is likely different to the browser preference.
– karl
Mar 8 at 12:14
add a comment |
Maybe you can simply use input type "date" to have a quick working solution.
Advantage: Format is chosen based on the current settings of the user, no need to format anything.
<input type="date" value="2019-01-01">answered Mar 8 at 11:30
AaronAaron
13
Maybe you can simply use input type "date" to have a quick working solution.
Advantage: Format is chosen based on the current settings of the user, no need to format anything.
<input type="date" value="2019-01-01"><input type="date" value="2019-01-01"><input type="date" value="2019-01-01">answered Mar 8 at 11:30
AaronAaron
13
answered Mar 8 at 11:30
AaronAaron
13
answered Mar 8 at 11:30
AaronAaron
13
answered Mar 8 at 11:30
AaronAaron
13
13
Hi Aaron, yes this is how I first wanted to do it but unfortunately there's no way of customising the output, it has to go into a specific date format which is likely different to the browser preference.
– karl
Mar 8 at 12:14
add a comment |
Hi Aaron, yes this is how I first wanted to do it but unfortunately there's no way of customising the output, it has to go into a specific date format which is likely different to the browser preference.
– karl
Mar 8 at 12:14
Hi Aaron, yes this is how I first wanted to do it but unfortunately there's no way of customising the output, it has to go into a specific date format which is likely different to the browser preference.
– karl
Mar 8 at 12:14
Hi Aaron, yes this is how I first wanted to do it but unfortunately there's no way of customising the output, it has to go into a specific date format which is likely different to the browser preference.
– karl
Mar 8 at 12:14
add a comment |
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1
Looks like this wants to initialize for one element at a time only, so you will need to select all your .year elements and loop over them, and then call the datepicker function for each one individually.
– 04FS
Mar 8 at 11:29
They would all be assigned to same const variable, that's why it is appended only to the first element. You'd have to create an array of const and possibly differentiate the DOM elements by something more specific like an id value
– Davide Vitali
Mar 8 at 11:29