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Result separation with regex



2019 Community Moderator ElectionList of all special characters that need to be escaped in a regexA comprehensive regex for phone number validationHow to negate specific word in regex?RegEx match open tags except XHTML self-contained tagsJava RegEx with lookahead failingWhy is subtracting these two times (in 1927) giving a strange result?Getting regex dataJava - Parsing strings - String.split() versus Pattern & MatcherRegex pattern to convert comma separated StringC# .NET Regex matching too muchWhen use java regular-expression pattern.matcher(), source does not match regex.But, my hope result is ,source matches regex










0















I wrote a parser that reads a file line by line and parses it with a regex statement. (Regex below)



case "countries":
pattern = "\"(.+?)\"(\s+)?(\((.+?)\))?(\s+)?(\(.+?)\(\#(.+?)\)\)?(\s+)?(.+)";
substitution = "$1, $4, $7, $8, $10";
break;


This outputs a list with all the groups I want and each group separated by a comma. (through the result.split(",");)
Now lets say I don't want to use a comma but instead an | or an *. Changing the comma to any other string doesn't seem to change anything. What am I missing?



try (CSVWriter csvWriter = new CSVWriter(new FileWriter(myLocalPath + "CSV/" + choice.toLowerCase() + ".csv")))

Pattern r = Pattern.compile(pattern);

while (br.readLine() != null)

String nextLine = br.readLine();

Matcher matcher = r.matcher(nextLine);

String result = matcher.replaceAll(substitution);

String[] line = result.split("lorem");

csvWriter.writeNext(line, false);

catch(Exception e)
System.out.println(e);
System.out.println("Parsing done!");










share|improve this question



















  • 1





    Try escaping \| and \* because both are meta-characters in regex.

    – Rahul
    Jan 19 '18 at 13:01












  • Escaping the character didnt work (java should escape characters immediately regardless if it detects its regex right?)

    – Marco Geertsma
    Jan 19 '18 at 13:09











  • Does your input consistently have that pattern ? Your provided input as lorem. What exactly is your input ? Also check this answer.

    – Rahul
    Jan 19 '18 at 13:10












  • do you have an example?

    – Maurice Perry
    Jan 19 '18 at 13:13











  • regex101.com/r/Cv4tPE/1

    – Marco Geertsma
    Jan 19 '18 at 13:22















0















I wrote a parser that reads a file line by line and parses it with a regex statement. (Regex below)



case "countries":
pattern = "\"(.+?)\"(\s+)?(\((.+?)\))?(\s+)?(\(.+?)\(\#(.+?)\)\)?(\s+)?(.+)";
substitution = "$1, $4, $7, $8, $10";
break;


This outputs a list with all the groups I want and each group separated by a comma. (through the result.split(",");)
Now lets say I don't want to use a comma but instead an | or an *. Changing the comma to any other string doesn't seem to change anything. What am I missing?



try (CSVWriter csvWriter = new CSVWriter(new FileWriter(myLocalPath + "CSV/" + choice.toLowerCase() + ".csv")))

Pattern r = Pattern.compile(pattern);

while (br.readLine() != null)

String nextLine = br.readLine();

Matcher matcher = r.matcher(nextLine);

String result = matcher.replaceAll(substitution);

String[] line = result.split("lorem");

csvWriter.writeNext(line, false);

catch(Exception e)
System.out.println(e);
System.out.println("Parsing done!");










share|improve this question



















  • 1





    Try escaping \| and \* because both are meta-characters in regex.

    – Rahul
    Jan 19 '18 at 13:01












  • Escaping the character didnt work (java should escape characters immediately regardless if it detects its regex right?)

    – Marco Geertsma
    Jan 19 '18 at 13:09











  • Does your input consistently have that pattern ? Your provided input as lorem. What exactly is your input ? Also check this answer.

    – Rahul
    Jan 19 '18 at 13:10












  • do you have an example?

    – Maurice Perry
    Jan 19 '18 at 13:13











  • regex101.com/r/Cv4tPE/1

    – Marco Geertsma
    Jan 19 '18 at 13:22













0












0








0








I wrote a parser that reads a file line by line and parses it with a regex statement. (Regex below)



case "countries":
pattern = "\"(.+?)\"(\s+)?(\((.+?)\))?(\s+)?(\(.+?)\(\#(.+?)\)\)?(\s+)?(.+)";
substitution = "$1, $4, $7, $8, $10";
break;


This outputs a list with all the groups I want and each group separated by a comma. (through the result.split(",");)
Now lets say I don't want to use a comma but instead an | or an *. Changing the comma to any other string doesn't seem to change anything. What am I missing?



try (CSVWriter csvWriter = new CSVWriter(new FileWriter(myLocalPath + "CSV/" + choice.toLowerCase() + ".csv")))

Pattern r = Pattern.compile(pattern);

while (br.readLine() != null)

String nextLine = br.readLine();

Matcher matcher = r.matcher(nextLine);

String result = matcher.replaceAll(substitution);

String[] line = result.split("lorem");

csvWriter.writeNext(line, false);

catch(Exception e)
System.out.println(e);
System.out.println("Parsing done!");










share|improve this question
















I wrote a parser that reads a file line by line and parses it with a regex statement. (Regex below)



case "countries":
pattern = "\"(.+?)\"(\s+)?(\((.+?)\))?(\s+)?(\(.+?)\(\#(.+?)\)\)?(\s+)?(.+)";
substitution = "$1, $4, $7, $8, $10";
break;


This outputs a list with all the groups I want and each group separated by a comma. (through the result.split(",");)
Now lets say I don't want to use a comma but instead an | or an *. Changing the comma to any other string doesn't seem to change anything. What am I missing?



try (CSVWriter csvWriter = new CSVWriter(new FileWriter(myLocalPath + "CSV/" + choice.toLowerCase() + ".csv")))

Pattern r = Pattern.compile(pattern);

while (br.readLine() != null)

String nextLine = br.readLine();

Matcher matcher = r.matcher(nextLine);

String result = matcher.replaceAll(substitution);

String[] line = result.split("lorem");

csvWriter.writeNext(line, false);

catch(Exception e)
System.out.println(e);
System.out.println("Parsing done!");







java regex parsing






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 7 at 14:03









Cœur

18.9k9110153




18.9k9110153










asked Jan 19 '18 at 13:00









Marco GeertsmaMarco Geertsma

4561523




4561523







  • 1





    Try escaping \| and \* because both are meta-characters in regex.

    – Rahul
    Jan 19 '18 at 13:01












  • Escaping the character didnt work (java should escape characters immediately regardless if it detects its regex right?)

    – Marco Geertsma
    Jan 19 '18 at 13:09











  • Does your input consistently have that pattern ? Your provided input as lorem. What exactly is your input ? Also check this answer.

    – Rahul
    Jan 19 '18 at 13:10












  • do you have an example?

    – Maurice Perry
    Jan 19 '18 at 13:13











  • regex101.com/r/Cv4tPE/1

    – Marco Geertsma
    Jan 19 '18 at 13:22












  • 1





    Try escaping \| and \* because both are meta-characters in regex.

    – Rahul
    Jan 19 '18 at 13:01












  • Escaping the character didnt work (java should escape characters immediately regardless if it detects its regex right?)

    – Marco Geertsma
    Jan 19 '18 at 13:09











  • Does your input consistently have that pattern ? Your provided input as lorem. What exactly is your input ? Also check this answer.

    – Rahul
    Jan 19 '18 at 13:10












  • do you have an example?

    – Maurice Perry
    Jan 19 '18 at 13:13











  • regex101.com/r/Cv4tPE/1

    – Marco Geertsma
    Jan 19 '18 at 13:22







1




1





Try escaping \| and \* because both are meta-characters in regex.

– Rahul
Jan 19 '18 at 13:01






Try escaping \| and \* because both are meta-characters in regex.

– Rahul
Jan 19 '18 at 13:01














Escaping the character didnt work (java should escape characters immediately regardless if it detects its regex right?)

– Marco Geertsma
Jan 19 '18 at 13:09





Escaping the character didnt work (java should escape characters immediately regardless if it detects its regex right?)

– Marco Geertsma
Jan 19 '18 at 13:09













Does your input consistently have that pattern ? Your provided input as lorem. What exactly is your input ? Also check this answer.

– Rahul
Jan 19 '18 at 13:10






Does your input consistently have that pattern ? Your provided input as lorem. What exactly is your input ? Also check this answer.

– Rahul
Jan 19 '18 at 13:10














do you have an example?

– Maurice Perry
Jan 19 '18 at 13:13





do you have an example?

– Maurice Perry
Jan 19 '18 at 13:13













regex101.com/r/Cv4tPE/1

– Marco Geertsma
Jan 19 '18 at 13:22





regex101.com/r/Cv4tPE/1

– Marco Geertsma
Jan 19 '18 at 13:22












1 Answer
1






active

oldest

votes


















0














seems what you're missing is Pattern.quote, if argument must be read literally, indeed split argument is a regex.



String[] line = result.split(Pattern.quote("..."));





share|improve this answer

























  • Cool, i didnt know about the Pattern.quote part. Really neat to know however i dont think this is usefull for my application since my regex statement already performed as it should. Im already getting the results i want and in the groups i want. I just want to change the comma that gets added between each seperator to any other character. Still gonna look more at Pattern.quote though!

    – Marco Geertsma
    Jan 19 '18 at 13:40











  • about the choice of separator, in a csv it is generally , or ; however if this caracter can appear in a field it must be escaped, commonly within enclosing quotes, it may be changed in CSVWriter settings

    – Nahuel Fouilleul
    Jan 19 '18 at 13:44











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














seems what you're missing is Pattern.quote, if argument must be read literally, indeed split argument is a regex.



String[] line = result.split(Pattern.quote("..."));





share|improve this answer

























  • Cool, i didnt know about the Pattern.quote part. Really neat to know however i dont think this is usefull for my application since my regex statement already performed as it should. Im already getting the results i want and in the groups i want. I just want to change the comma that gets added between each seperator to any other character. Still gonna look more at Pattern.quote though!

    – Marco Geertsma
    Jan 19 '18 at 13:40











  • about the choice of separator, in a csv it is generally , or ; however if this caracter can appear in a field it must be escaped, commonly within enclosing quotes, it may be changed in CSVWriter settings

    – Nahuel Fouilleul
    Jan 19 '18 at 13:44
















0














seems what you're missing is Pattern.quote, if argument must be read literally, indeed split argument is a regex.



String[] line = result.split(Pattern.quote("..."));





share|improve this answer

























  • Cool, i didnt know about the Pattern.quote part. Really neat to know however i dont think this is usefull for my application since my regex statement already performed as it should. Im already getting the results i want and in the groups i want. I just want to change the comma that gets added between each seperator to any other character. Still gonna look more at Pattern.quote though!

    – Marco Geertsma
    Jan 19 '18 at 13:40











  • about the choice of separator, in a csv it is generally , or ; however if this caracter can appear in a field it must be escaped, commonly within enclosing quotes, it may be changed in CSVWriter settings

    – Nahuel Fouilleul
    Jan 19 '18 at 13:44














0












0








0







seems what you're missing is Pattern.quote, if argument must be read literally, indeed split argument is a regex.



String[] line = result.split(Pattern.quote("..."));





share|improve this answer















seems what you're missing is Pattern.quote, if argument must be read literally, indeed split argument is a regex.



String[] line = result.split(Pattern.quote("..."));






share|improve this answer














share|improve this answer



share|improve this answer








edited Jan 19 '18 at 13:32









Valentin Michalak

1,222723




1,222723










answered Jan 19 '18 at 13:29









Nahuel FouilleulNahuel Fouilleul

14.5k11626




14.5k11626












  • Cool, i didnt know about the Pattern.quote part. Really neat to know however i dont think this is usefull for my application since my regex statement already performed as it should. Im already getting the results i want and in the groups i want. I just want to change the comma that gets added between each seperator to any other character. Still gonna look more at Pattern.quote though!

    – Marco Geertsma
    Jan 19 '18 at 13:40











  • about the choice of separator, in a csv it is generally , or ; however if this caracter can appear in a field it must be escaped, commonly within enclosing quotes, it may be changed in CSVWriter settings

    – Nahuel Fouilleul
    Jan 19 '18 at 13:44


















  • Cool, i didnt know about the Pattern.quote part. Really neat to know however i dont think this is usefull for my application since my regex statement already performed as it should. Im already getting the results i want and in the groups i want. I just want to change the comma that gets added between each seperator to any other character. Still gonna look more at Pattern.quote though!

    – Marco Geertsma
    Jan 19 '18 at 13:40











  • about the choice of separator, in a csv it is generally , or ; however if this caracter can appear in a field it must be escaped, commonly within enclosing quotes, it may be changed in CSVWriter settings

    – Nahuel Fouilleul
    Jan 19 '18 at 13:44

















Cool, i didnt know about the Pattern.quote part. Really neat to know however i dont think this is usefull for my application since my regex statement already performed as it should. Im already getting the results i want and in the groups i want. I just want to change the comma that gets added between each seperator to any other character. Still gonna look more at Pattern.quote though!

– Marco Geertsma
Jan 19 '18 at 13:40





Cool, i didnt know about the Pattern.quote part. Really neat to know however i dont think this is usefull for my application since my regex statement already performed as it should. Im already getting the results i want and in the groups i want. I just want to change the comma that gets added between each seperator to any other character. Still gonna look more at Pattern.quote though!

– Marco Geertsma
Jan 19 '18 at 13:40













about the choice of separator, in a csv it is generally , or ; however if this caracter can appear in a field it must be escaped, commonly within enclosing quotes, it may be changed in CSVWriter settings

– Nahuel Fouilleul
Jan 19 '18 at 13:44






about the choice of separator, in a csv it is generally , or ; however if this caracter can appear in a field it must be escaped, commonly within enclosing quotes, it may be changed in CSVWriter settings

– Nahuel Fouilleul
Jan 19 '18 at 13:44




















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