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Problem not restarting the function keydown in ajax
2019 Community Moderator ElectionHow can I get jQuery to perform a synchronous, rather than asynchronous, Ajax request?How to manage a redirect request after a jQuery Ajax callAbort Ajax requests using jQueryjQuery AJAX submit formjQuery Ajax File UploadJquery problem with IEHow to make an AJAX call without jQuery?Is Safari on iOS 6 caching $.ajax results?codeigniter:how to check user name and password$_POSt returns unexpected array
I use Ajax to update my data in database,when I Enter input this function is Called
my code is here:
<input type="hidden" value="$cart->id" id="cartId">
<input type="text" class="input" value="$cart->count" id="changeCount">
$("#changeCount").keydown(function (e)
if (e.keyCode == 13)
e.preventDefault();
var cartId = $(this).parent().children('#cartId').val();
var count = $('#changeCount').val();
clearTimeout(timer);
timer = setTimeout(function()
$.ajax(
url: '/changeCount',
type: 'post',
dataType: 'json',
data:
cartId: cartId,
count: count,
_token: $('input[name=_token]').val()
)
.then(function (response)
document.getElementById("carts").innerHTML
=response.html;
)
,250)
)
My Problem, is here that when I want to update count for second I get this Error:
How I can solved this Error?
ajax
asked Mar 7 at 14:10
haniehanie
12619
add a comment |
I use Ajax to update my data in database,when I Enter input this function is Called
my code is here:
<input type="hidden" value="$cart->id" id="cartId">
<input type="text" class="input" value="$cart->count" id="changeCount">
$("#changeCount").keydown(function (e)
if (e.keyCode == 13)
e.preventDefault();
var cartId = $(this).parent().children('#cartId').val();
var count = $('#changeCount').val();
clearTimeout(timer);
timer = setTimeout(function()
$.ajax(
url: '/changeCount',
type: 'post',
dataType: 'json',
data:
cartId: cartId,
count: count,
_token: $('input[name=_token]').val()
)
.then(function (response)
document.getElementById("carts").innerHTML
=response.html;
)
,250)
)
My Problem, is here that when I want to update count for second I get this Error:
How I can solved this Error?
ajax
asked Mar 7 at 14:10
haniehanie
12619
add a comment |
I use Ajax to update my data in database,when I Enter input this function is Called
my code is here:
<input type="hidden" value="$cart->id" id="cartId">
<input type="text" class="input" value="$cart->count" id="changeCount">
$("#changeCount").keydown(function (e)
if (e.keyCode == 13)
e.preventDefault();
var cartId = $(this).parent().children('#cartId').val();
var count = $('#changeCount').val();
clearTimeout(timer);
timer = setTimeout(function()
$.ajax(
url: '/changeCount',
type: 'post',
dataType: 'json',
data:
cartId: cartId,
count: count,
_token: $('input[name=_token]').val()
)
.then(function (response)
document.getElementById("carts").innerHTML
=response.html;
)
,250)
)
My Problem, is here that when I want to update count for second I get this Error:
How I can solved this Error?
ajax
asked Mar 7 at 14:10
haniehanie
12619
I use Ajax to update my data in database,when I Enter input this function is Called
my code is here:
<input type="hidden" value="$cart->id" id="cartId">
<input type="text" class="input" value="$cart->count" id="changeCount">
$("#changeCount").keydown(function (e)
if (e.keyCode == 13)
e.preventDefault();
var cartId = $(this).parent().children('#cartId').val();
var count = $('#changeCount').val();
clearTimeout(timer);
timer = setTimeout(function()
$.ajax(
url: '/changeCount',
type: 'post',
dataType: 'json',
data:
cartId: cartId,
count: count,
_token: $('input[name=_token]').val()
)
.then(function (response)
document.getElementById("carts").innerHTML
=response.html;
)
,250)
)
My Problem, is here that when I want to update count for second I get this Error:
How I can solved this Error?
ajax
ajax
asked Mar 7 at 14:10
haniehanie
12619
asked Mar 7 at 14:10
haniehanie
12619
asked Mar 7 at 14:10
haniehanie
12619
asked Mar 7 at 14:10
haniehanie
12619
asked Mar 7 at 14:10
haniehanie
12619
12619
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I solved,My problem with use this code:
.then(function (response)
$('div[id=carts]').html(response.html))
answered Mar 7 at 14:16
haniehanie
12619
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I solved,My problem with use this code:
.then(function (response)
$('div[id=carts]').html(response.html))
answered Mar 7 at 14:16
haniehanie
12619
add a comment |
I solved,My problem with use this code:
.then(function (response)
$('div[id=carts]').html(response.html))
answered Mar 7 at 14:16
haniehanie
12619
add a comment |
I solved,My problem with use this code:
.then(function (response)
$('div[id=carts]').html(response.html))
answered Mar 7 at 14:16
haniehanie
12619
I solved,My problem with use this code:
.then(function (response)
$('div[id=carts]').html(response.html))
answered Mar 7 at 14:16
haniehanie
12619
answered Mar 7 at 14:16
haniehanie
12619
answered Mar 7 at 14:16
haniehanie
12619
answered Mar 7 at 14:16
haniehanie
12619
12619
add a comment |
add a comment |
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