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Kotlin Type Mismatch : Required Long found Unit
2019 Community Moderator ElectionJackson with JSON: Unrecognized field, not marked as ignorableError: Could not find or load main classJsonMappingException: No suitable constructor found for type [simple type, class ]: can not instantiate from JSON objectCan't start Eclipse - Java was started but returned exit code=13Kotlin-android: unresolved reference databindingHow to implement Builder pattern in Kotlin?Kotlin parameter type mismatchIs the JDK required for Kotlin?Kotlin type mismatchCan we pass java method to to kotlin function of type () -> Unit?
I have a pojo class in java as below
public class Pojo
@SerializedName("notificationTime")
private long notificationTime;
public long getNotificationTime()
return notificationTime;
Now i am trying this notificationTime in kotlin as below
var notifTime:Long = Pojo.notificationTime
It is showing compiltime error as mentioned . Please help. I am new to kotlin.
java
android kotlin asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
add a comment |
I have a pojo class in java as below
public class Pojo
@SerializedName("notificationTime")
private long notificationTime;
public long getNotificationTime()
return notificationTime;
Now i am trying this notificationTime in kotlin as below
var notifTime:Long = Pojo.notificationTime
It is showing compiltime error as mentioned . Please help. I am new to kotlin.
java
android kotlin asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
4
Do you instantiate your Pojo?
– Nikita Khlebushkin
Mar 7 at 14:07
as you are "new to Kotlin", please have a look at: Kotlin reference... the same link will also lead you to some tutorials...
– Roland
Mar 7 at 14:58
add a comment |
I have a pojo class in java as below
public class Pojo
@SerializedName("notificationTime")
private long notificationTime;
public long getNotificationTime()
return notificationTime;
Now i am trying this notificationTime in kotlin as below
var notifTime:Long = Pojo.notificationTime
It is showing compiltime error as mentioned . Please help. I am new to kotlin.
java
android kotlin asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
I have a pojo class in java as below
public class Pojo
@SerializedName("notificationTime")
private long notificationTime;
public long getNotificationTime()
return notificationTime;
Now i am trying this notificationTime in kotlin as below
var notifTime:Long = Pojo.notificationTime
It is showing compiltime error as mentioned . Please help. I am new to kotlin.
java
android kotlin java
android kotlin asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
asked Mar 7 at 13:59
New Android DeveloperNew Android Developer
32
32
4
Do you instantiate your Pojo?
– Nikita Khlebushkin
Mar 7 at 14:07
as you are "new to Kotlin", please have a look at: Kotlin reference... the same link will also lead you to some tutorials...
– Roland
Mar 7 at 14:58
add a comment |
4
Do you instantiate your Pojo?
– Nikita Khlebushkin
Mar 7 at 14:07
as you are "new to Kotlin", please have a look at: Kotlin reference... the same link will also lead you to some tutorials...
– Roland
Mar 7 at 14:58
4
4
Do you instantiate your Pojo?
– Nikita Khlebushkin
Mar 7 at 14:07
Do you instantiate your Pojo?
– Nikita Khlebushkin
Mar 7 at 14:07
as you are "new to Kotlin", please have a look at: Kotlin reference... the same link will also lead you to some tutorials...
– Roland
Mar 7 at 14:58
as you are "new to Kotlin", please have a look at: Kotlin reference... the same link will also lead you to some tutorials...
– Roland
Mar 7 at 14:58
add a comment |
1 Answer
1
active
oldest
votes
Without an instance, Pojo.notificationTime tries to call a static method. Which is not what your code exposes.
So init your object, then gets its notificationTime:
val pojo = Pojo()
val notifTime = pojo.notificationTime // actually calls `getNotificationTime()` as an implicit getter
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
add a comment |
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Without an instance, Pojo.notificationTime tries to call a static method. Which is not what your code exposes.
So init your object, then gets its notificationTime:
val pojo = Pojo()
val notifTime = pojo.notificationTime // actually calls `getNotificationTime()` as an implicit getter
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
add a comment |
Without an instance, Pojo.notificationTime tries to call a static method. Which is not what your code exposes.
So init your object, then gets its notificationTime:
val pojo = Pojo()
val notifTime = pojo.notificationTime // actually calls `getNotificationTime()` as an implicit getter
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
add a comment |
Without an instance, Pojo.notificationTime tries to call a static method. Which is not what your code exposes.
So init your object, then gets its notificationTime:
val pojo = Pojo()
val notifTime = pojo.notificationTime // actually calls `getNotificationTime()` as an implicit getter
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
Without an instance, Pojo.notificationTime tries to call a static method. Which is not what your code exposes.
So init your object, then gets its notificationTime:
val pojo = Pojo()
val notifTime = pojo.notificationTime // actually calls `getNotificationTime()` as an implicit getter
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
answered Mar 7 at 14:17
shkschneidershkschneider
11.1k114396
11.1k114396
add a comment |
add a comment |
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4
Do you instantiate your Pojo?
– Nikita Khlebushkin
Mar 7 at 14:07
as you are "new to Kotlin", please have a look at: Kotlin reference... the same link will also lead you to some tutorials...
– Roland
Mar 7 at 14:58