how answer a phone call with python through serial port? The Next CEO of Stack OverflowCalling an external command in PythonHow do I copy a file in Python?How can I safely create a nested directory in Python?How can I remove a trailing newline in Python?How do I parse a string to a float or int in Python?How to get the current time in PythonHow can I make a time delay in Python?How do I get the number of elements in a list in Python?How do I concatenate two lists in Python?How do I lowercase a string in Python?
Cannot shrink btrfs filesystem although there is still data and metadata space left : ERROR: unable to resize '/home': No space left on device
Which one is the true statement?
Aggressive Under-Indexing and no data for missing index
Audio Conversion With ADS1243
(How) Could a medieval fantasy world survive a magic-induced "nuclear winter"?
How did Beeri the Hittite come up with naming his daughter Yehudit?
Does Germany produce more waste than the US?
From jafe to El-Guest
Man transported from Alternate World into ours by a Neutrino Detector
Is there a way to save my career from absolute disaster?
Is a distribution that is normal, but highly skewed, considered Gaussian?
TikZ: How to fill area with a special pattern?
How to avoid supervisors with prejudiced views?
Yu-Gi-Oh cards in Python 3
Traveling with my 5 year old daughter (as the father) without the mother from Germany to Mexico
How to get the last not-null value in an ordered column of a huge table?
Calculate the Mean mean of two numbers
What is the process for purifying your home if you believe it may have been previously used for pagan worship?
What day is it again?
IC has pull-down resistors on SMBus lines?
What are the unusually-enlarged wing sections on this P-38 Lightning?
Could a dragon use its wings to swim?
What is the difference between "hamstring tendon" and "common hamstring tendon"?
Does higher Oxidation/ reduction potential translate to higher energy storage in battery?
how answer a phone call with python through serial port?
The Next CEO of Stack OverflowCalling an external command in PythonHow do I copy a file in Python?How can I safely create a nested directory in Python?How can I remove a trailing newline in Python?How do I parse a string to a float or int in Python?How to get the current time in PythonHow can I make a time delay in Python?How do I get the number of elements in a list in Python?How do I concatenate two lists in Python?How do I lowercase a string in Python?
I've been trying to answer a phone call using a serial port, but i only get 'RINGrn' and after a while 'NO CARRIER'. is there any command to answer a call?
import serial
ser = serial.Serial()
ser.port='COM3'
ser.baudrate=9600
ser.open()
while True:
lectura = ser.readline()
if lectura == "RING": ser.write("OK") # To answer the call.
python phone-call
edited Mar 20 '18 at 23:04
Simon
5,60762946
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
add a comment |
I've been trying to answer a phone call using a serial port, but i only get 'RINGrn' and after a while 'NO CARRIER'. is there any command to answer a call?
import serial
ser = serial.Serial()
ser.port='COM3'
ser.baudrate=9600
ser.open()
while True:
lectura = ser.readline()
if lectura == "RING": ser.write("OK") # To answer the call.
python phone-call
edited Mar 20 '18 at 23:04
Simon
5,60762946
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
1
import serial ser = serial.Serial() ser.port='COM3' ser.baudrate=9600 ser.open() while True: lectura = ser.readline() if lectura == "RING": ser.write("OK") # To answer the call.
– Javier Esquivel
Mar 20 '18 at 22:57
I proved using a phone and when i answer a call, it generate the string 'OK'. I've tried search a kind of protocol for it, but i have nothing yet
– Javier Esquivel
Mar 20 '18 at 23:03
add a comment |
I've been trying to answer a phone call using a serial port, but i only get 'RINGrn' and after a while 'NO CARRIER'. is there any command to answer a call?
import serial
ser = serial.Serial()
ser.port='COM3'
ser.baudrate=9600
ser.open()
while True:
lectura = ser.readline()
if lectura == "RING": ser.write("OK") # To answer the call.
python phone-call
edited Mar 20 '18 at 23:04
Simon
5,60762946
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
I've been trying to answer a phone call using a serial port, but i only get 'RINGrn' and after a while 'NO CARRIER'. is there any command to answer a call?
import serial
ser = serial.Serial()
ser.port='COM3'
ser.baudrate=9600
ser.open()
while True:
lectura = ser.readline()
if lectura == "RING": ser.write("OK") # To answer the call.
python phone-call
python phone-call
edited Mar 20 '18 at 23:04
Simon
5,60762946
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
edited Mar 20 '18 at 23:04
Simon
5,60762946
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
edited Mar 20 '18 at 23:04
Simon
5,60762946
edited Mar 20 '18 at 23:04
Simon
5,60762946
edited Mar 20 '18 at 23:04
Simon
5,60762946
5,60762946
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
asked Mar 20 '18 at 22:11
Javier EsquivelJavier Esquivel
111
111
1
import serial ser = serial.Serial() ser.port='COM3' ser.baudrate=9600 ser.open() while True: lectura = ser.readline() if lectura == "RING": ser.write("OK") # To answer the call.
– Javier Esquivel
Mar 20 '18 at 22:57
I proved using a phone and when i answer a call, it generate the string 'OK'. I've tried search a kind of protocol for it, but i have nothing yet
– Javier Esquivel
Mar 20 '18 at 23:03
add a comment |
1
import serial ser = serial.Serial() ser.port='COM3' ser.baudrate=9600 ser.open() while True: lectura = ser.readline() if lectura == "RING": ser.write("OK") # To answer the call.
– Javier Esquivel
Mar 20 '18 at 22:57
I proved using a phone and when i answer a call, it generate the string 'OK'. I've tried search a kind of protocol for it, but i have nothing yet
– Javier Esquivel
Mar 20 '18 at 23:03
1
1
import serial ser = serial.Serial() ser.port='COM3' ser.baudrate=9600 ser.open() while True: lectura = ser.readline() if lectura == "RING": ser.write("OK") # To answer the call.– Javier Esquivel
Mar 20 '18 at 22:57
import serial ser = serial.Serial() ser.port='COM3' ser.baudrate=9600 ser.open() while True: lectura = ser.readline() if lectura == "RING": ser.write("OK") # To answer the call.– Javier Esquivel
Mar 20 '18 at 22:57
I proved using a phone and when i answer a call, it generate the string 'OK'. I've tried search a kind of protocol for it, but i have nothing yet
– Javier Esquivel
Mar 20 '18 at 23:03
I proved using a phone and when i answer a call, it generate the string 'OK'. I've tried search a kind of protocol for it, but i have nothing yet
– Javier Esquivel
Mar 20 '18 at 23:03
add a comment |
1 Answer
1
active
oldest
votes
You just have to send the ACK character.
ser.write(b'x06')
edited Mar 10 at 16:40
bdesham
9,61785396
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
Please include the code in your answer as text, not as an image. This will make it easier for others to see and work with.
– bdesham
Mar 8 at 17:22
It's because is a character ascii and in that way shows sublime text. The original code iscodeser.write('')code
– Javier Esquivel
Mar 9 at 22:52
add a comment |
StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f49394978%2fhow-answer-a-phone-call-with-python-through-serial-port%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You just have to send the ACK character.
ser.write(b'x06')
edited Mar 10 at 16:40
bdesham
9,61785396
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
Please include the code in your answer as text, not as an image. This will make it easier for others to see and work with.
– bdesham
Mar 8 at 17:22
It's because is a character ascii and in that way shows sublime text. The original code iscodeser.write('')code
– Javier Esquivel
Mar 9 at 22:52
add a comment |
You just have to send the ACK character.
ser.write(b'x06')
edited Mar 10 at 16:40
bdesham
9,61785396
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
Please include the code in your answer as text, not as an image. This will make it easier for others to see and work with.
– bdesham
Mar 8 at 17:22
It's because is a character ascii and in that way shows sublime text. The original code iscodeser.write('')code
– Javier Esquivel
Mar 9 at 22:52
add a comment |
You just have to send the ACK character.
ser.write(b'x06')
edited Mar 10 at 16:40
bdesham
9,61785396
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
You just have to send the ACK character.
ser.write(b'x06')
edited Mar 10 at 16:40
bdesham
9,61785396
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
edited Mar 10 at 16:40
bdesham
9,61785396
edited Mar 10 at 16:40
bdesham
9,61785396
edited Mar 10 at 16:40
bdesham
9,61785396
9,61785396
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
answered Mar 8 at 17:19
Javier EsquivelJavier Esquivel
111
111
Please include the code in your answer as text, not as an image. This will make it easier for others to see and work with.
– bdesham
Mar 8 at 17:22
It's because is a character ascii and in that way shows sublime text. The original code iscodeser.write('')code
– Javier Esquivel
Mar 9 at 22:52
add a comment |
Please include the code in your answer as text, not as an image. This will make it easier for others to see and work with.
– bdesham
Mar 8 at 17:22
It's because is a character ascii and in that way shows sublime text. The original code iscodeser.write('')code
– Javier Esquivel
Mar 9 at 22:52
Please include the code in your answer as text, not as an image. This will make it easier for others to see and work with.
– bdesham
Mar 8 at 17:22
Please include the code in your answer as text, not as an image. This will make it easier for others to see and work with.
– bdesham
Mar 8 at 17:22
It's because is a character ascii and in that way shows sublime text. The original code is
code ser.write('') code– Javier Esquivel
Mar 9 at 22:52
It's because is a character ascii and in that way shows sublime text. The original code is
code ser.write('') code– Javier Esquivel
Mar 9 at 22:52
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f49394978%2fhow-answer-a-phone-call-with-python-through-serial-port%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
import serial ser = serial.Serial() ser.port='COM3' ser.baudrate=9600 ser.open() while True: lectura = ser.readline() if lectura == "RING": ser.write("OK") # To answer the call.– Javier Esquivel
Mar 20 '18 at 22:57
I proved using a phone and when i answer a call, it generate the string 'OK'. I've tried search a kind of protocol for it, but i have nothing yet
– Javier Esquivel
Mar 20 '18 at 23:03