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Array push only works inside the callback
The Next CEO of Stack OverflowCreate ArrayList from arrayHow do I check if an array includes an object in JavaScript?How to append something to an array?PHP: Delete an element from an arrayHow to insert an item into an array at a specific index (JavaScript)?How do I empty an array in JavaScript?Loop through an array in JavaScriptHow to check if an object is an array?How do I remove a particular element from an array in JavaScript?For-each over an array in JavaScript?
0
I'm trying to update an array with some mongoose values. But it only works if the array.push is inside the callback function. I've tried to code in several ways but outside the callback I always get an empty array. Here are some code:
let y = [];
Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr )
.then(function(os)
y.push(os);
)
.catch(err => throw err; );
console.log(y);
Using async/await:
let y = [];
async function docs()
const numDocs = await Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec();
return numDocs;
docs().then(function (err,n) y.push(n); );
console.log(y);
Help, please. I don't know what to do...
arrays node.js count array-push
edited Mar 8 at 20:17
Luc
288
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
add a comment |
0
I'm trying to update an array with some mongoose values. But it only works if the array.push is inside the callback function. I've tried to code in several ways but outside the callback I always get an empty array. Here are some code:
let y = [];
Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr )
.then(function(os)
y.push(os);
)
.catch(err => throw err; );
console.log(y);
Using async/await:
let y = [];
async function docs()
const numDocs = await Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec();
return numDocs;
docs().then(function (err,n) y.push(n); );
console.log(y);
Help, please. I don't know what to do...
arrays node.js count array-push
edited Mar 8 at 20:17
Luc
288
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
Why in the first function you do not use theexec()method and the second one you used it?
– SergioEscudero
Mar 8 at 17:31
Put the console.log() inside the callback function, on the line after you modify the array. Because it's async, the array has not yet been modified at the time you log it.
– Martin Joiner
Mar 8 at 17:33
1
Thanks Sergio, I just forgot the exec(), but it doesn't alter the results.
– Fábio Medeiros
Mar 8 at 17:36
@Martin, thanks for your reply. Your suggestion works but I need the updated array outside the callback, how could I retrieve it?
– Fábio Medeiros
Mar 8 at 17:39
@FábioMedeiros I would recommend you read up on the basic concepts of Asynchronous code. Basically you cannot assume the code executes in the order it is written so even though your console.log(y) is on the last line, it does not mean the push() has happened yet. I can recommend MDN as a source of learning developer.mozilla.org/en-US/docs/Learn/JavaScript/Asynchronous
– Martin Joiner
Mar 11 at 20:43
add a comment |
0
0
0
I'm trying to update an array with some mongoose values. But it only works if the array.push is inside the callback function. I've tried to code in several ways but outside the callback I always get an empty array. Here are some code:
let y = [];
Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr )
.then(function(os)
y.push(os);
)
.catch(err => throw err; );
console.log(y);
Using async/await:
let y = [];
async function docs()
const numDocs = await Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec();
return numDocs;
docs().then(function (err,n) y.push(n); );
console.log(y);
Help, please. I don't know what to do...
arrays node.js count array-push
edited Mar 8 at 20:17
Luc
288
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
I'm trying to update an array with some mongoose values. But it only works if the array.push is inside the callback function. I've tried to code in several ways but outside the callback I always get an empty array. Here are some code:
let y = [];
Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr )
.then(function(os)
y.push(os);
)
.catch(err => throw err; );
console.log(y);
Using async/await:
let y = [];
async function docs()
const numDocs = await Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec();
return numDocs;
docs().then(function (err,n) y.push(n); );
console.log(y);
Help, please. I don't know what to do...
arrays node.js count array-push
arrays node.js count array-push
edited Mar 8 at 20:17
Luc
288
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
edited Mar 8 at 20:17
Luc
288
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
edited Mar 8 at 20:17
Luc
288
edited Mar 8 at 20:17
Luc
288
edited Mar 8 at 20:17
Luc
288
288
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
asked Mar 8 at 17:28
Fábio MedeirosFábio Medeiros
11
11
Why in the first function you do not use theexec()method and the second one you used it?
– SergioEscudero
Mar 8 at 17:31
Put the console.log() inside the callback function, on the line after you modify the array. Because it's async, the array has not yet been modified at the time you log it.
– Martin Joiner
Mar 8 at 17:33
1
Thanks Sergio, I just forgot the exec(), but it doesn't alter the results.
– Fábio Medeiros
Mar 8 at 17:36
@Martin, thanks for your reply. Your suggestion works but I need the updated array outside the callback, how could I retrieve it?
– Fábio Medeiros
Mar 8 at 17:39
@FábioMedeiros I would recommend you read up on the basic concepts of Asynchronous code. Basically you cannot assume the code executes in the order it is written so even though your console.log(y) is on the last line, it does not mean the push() has happened yet. I can recommend MDN as a source of learning developer.mozilla.org/en-US/docs/Learn/JavaScript/Asynchronous
– Martin Joiner
Mar 11 at 20:43
add a comment |
Why in the first function you do not use theexec()method and the second one you used it?
– SergioEscudero
Mar 8 at 17:31
Put the console.log() inside the callback function, on the line after you modify the array. Because it's async, the array has not yet been modified at the time you log it.
– Martin Joiner
Mar 8 at 17:33
1
Thanks Sergio, I just forgot the exec(), but it doesn't alter the results.
– Fábio Medeiros
Mar 8 at 17:36
@Martin, thanks for your reply. Your suggestion works but I need the updated array outside the callback, how could I retrieve it?
– Fábio Medeiros
Mar 8 at 17:39
@FábioMedeiros I would recommend you read up on the basic concepts of Asynchronous code. Basically you cannot assume the code executes in the order it is written so even though your console.log(y) is on the last line, it does not mean the push() has happened yet. I can recommend MDN as a source of learning developer.mozilla.org/en-US/docs/Learn/JavaScript/Asynchronous
– Martin Joiner
Mar 11 at 20:43
Why in the first function you do not use the
exec() method and the second one you used it?– SergioEscudero
Mar 8 at 17:31
Why in the first function you do not use the
exec() method and the second one you used it?– SergioEscudero
Mar 8 at 17:31
Put the console.log() inside the callback function, on the line after you modify the array. Because it's async, the array has not yet been modified at the time you log it.
– Martin Joiner
Mar 8 at 17:33
Put the console.log() inside the callback function, on the line after you modify the array. Because it's async, the array has not yet been modified at the time you log it.
– Martin Joiner
Mar 8 at 17:33
1
1
Thanks Sergio, I just forgot the exec(), but it doesn't alter the results.
– Fábio Medeiros
Mar 8 at 17:36
Thanks Sergio, I just forgot the exec(), but it doesn't alter the results.
– Fábio Medeiros
Mar 8 at 17:36
@Martin, thanks for your reply. Your suggestion works but I need the updated array outside the callback, how could I retrieve it?
– Fábio Medeiros
Mar 8 at 17:39
@Martin, thanks for your reply. Your suggestion works but I need the updated array outside the callback, how could I retrieve it?
– Fábio Medeiros
Mar 8 at 17:39
@FábioMedeiros I would recommend you read up on the basic concepts of Asynchronous code. Basically you cannot assume the code executes in the order it is written so even though your console.log(y) is on the last line, it does not mean the push() has happened yet. I can recommend MDN as a source of learning developer.mozilla.org/en-US/docs/Learn/JavaScript/Asynchronous
– Martin Joiner
Mar 11 at 20:43
@FábioMedeiros I would recommend you read up on the basic concepts of Asynchronous code. Basically you cannot assume the code executes in the order it is written so even though your console.log(y) is on the last line, it does not mean the push() has happened yet. I can recommend MDN as a source of learning developer.mozilla.org/en-US/docs/Learn/JavaScript/Asynchronous
– Martin Joiner
Mar 11 at 20:43
add a comment |
1 Answer
1
active
oldest
votes
0
My understanding is that you are missing a promise.
let y = [];
const docs = async () =>
return await Promise.all(Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec());
const docsToPush = docs()
y.push(docsToPush)
console.log(y);
answered Mar 8 at 18:27
LucLuc
288
@FábioMedeiros Just an extra note, I'm making the assumption you are using this to build a web app or api of some sort, you could change the const to var but I would recommend against this, using var opens you up to possible security threats.
– Luc
Mar 8 at 20:25
add a comment |
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0
My understanding is that you are missing a promise.
let y = [];
const docs = async () =>
return await Promise.all(Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec());
const docsToPush = docs()
y.push(docsToPush)
console.log(y);
answered Mar 8 at 18:27
LucLuc
288
@FábioMedeiros Just an extra note, I'm making the assumption you are using this to build a web app or api of some sort, you could change the const to var but I would recommend against this, using var opens you up to possible security threats.
– Luc
Mar 8 at 20:25
add a comment |
0
My understanding is that you are missing a promise.
let y = [];
const docs = async () =>
return await Promise.all(Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec());
const docsToPush = docs()
y.push(docsToPush)
console.log(y);
answered Mar 8 at 18:27
LucLuc
288
@FábioMedeiros Just an extra note, I'm making the assumption you are using this to build a web app or api of some sort, you could change the const to var but I would recommend against this, using var opens you up to possible security threats.
– Luc
Mar 8 at 20:25
add a comment |
0
0
0
My understanding is that you are missing a promise.
let y = [];
const docs = async () =>
return await Promise.all(Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec());
const docsToPush = docs()
y.push(docsToPush)
console.log(y);
answered Mar 8 at 18:27
LucLuc
288
My understanding is that you are missing a promise.
let y = [];
const docs = async () =>
return await Promise.all(Shops.countDocuments( dt_encerramento: $gte: jan, $lte: abr ).exec());
const docsToPush = docs()
y.push(docsToPush)
console.log(y);
answered Mar 8 at 18:27
LucLuc
288
answered Mar 8 at 18:27
LucLuc
288
answered Mar 8 at 18:27
LucLuc
288
answered Mar 8 at 18:27
LucLuc
288
288
@FábioMedeiros Just an extra note, I'm making the assumption you are using this to build a web app or api of some sort, you could change the const to var but I would recommend against this, using var opens you up to possible security threats.
– Luc
Mar 8 at 20:25
add a comment |
@FábioMedeiros Just an extra note, I'm making the assumption you are using this to build a web app or api of some sort, you could change the const to var but I would recommend against this, using var opens you up to possible security threats.
– Luc
Mar 8 at 20:25
@FábioMedeiros Just an extra note, I'm making the assumption you are using this to build a web app or api of some sort, you could change the const to var but I would recommend against this, using var opens you up to possible security threats.
– Luc
Mar 8 at 20:25
@FábioMedeiros Just an extra note, I'm making the assumption you are using this to build a web app or api of some sort, you could change the const to var but I would recommend against this, using var opens you up to possible security threats.
– Luc
Mar 8 at 20:25
add a comment |
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Why in the first function you do not use the
exec()method and the second one you used it?– SergioEscudero
Mar 8 at 17:31
Put the console.log() inside the callback function, on the line after you modify the array. Because it's async, the array has not yet been modified at the time you log it.
– Martin Joiner
Mar 8 at 17:33
1
Thanks Sergio, I just forgot the exec(), but it doesn't alter the results.
– Fábio Medeiros
Mar 8 at 17:36
@Martin, thanks for your reply. Your suggestion works but I need the updated array outside the callback, how could I retrieve it?
– Fábio Medeiros
Mar 8 at 17:39
@FábioMedeiros I would recommend you read up on the basic concepts of Asynchronous code. Basically you cannot assume the code executes in the order it is written so even though your console.log(y) is on the last line, it does not mean the push() has happened yet. I can recommend MDN as a source of learning developer.mozilla.org/en-US/docs/Learn/JavaScript/Asynchronous
– Martin Joiner
Mar 11 at 20:43