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Get RSA Public or Private Key from KeyPair Generation Flutter



The Next CEO of Stack OverflowPublic & Private Keys in .NET besides RSAUse RSA private key to generate public key?How can I get the private key from an RSA public key?Can we have multiple public keys with a single private key for RSA?RSA Public Key formatJava - Public-private key encryption - how to calculate private key in RSAprivate/public key ssh-keygen -t rsaComputing private key of a user from his RSA public keyGenerate RSA Public Key from Modulus and ExponentFlutter - How can I generate a private/public key pair to encrypt messages










0















I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.



Here is the code I used



 var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));

secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));

var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");









share|improve this question






















  • Did you try keyPair.privateKey.toString() ?

    – Mazin Ibrahim
    Mar 8 at 16:17











  • @MazinIbrahim yes, that returns the same Instance of RSAPrivateKey

    – Epic Gamer_1
    Mar 8 at 16:33











  • This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert RSAPrivateKey to a readable form.

    – Mazin Ibrahim
    Mar 8 at 16:41











  • @MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output

    – Epic Gamer_1
    Mar 8 at 16:55















0















I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.



Here is the code I used



 var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));

secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));

var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");









share|improve this question






















  • Did you try keyPair.privateKey.toString() ?

    – Mazin Ibrahim
    Mar 8 at 16:17











  • @MazinIbrahim yes, that returns the same Instance of RSAPrivateKey

    – Epic Gamer_1
    Mar 8 at 16:33











  • This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert RSAPrivateKey to a readable form.

    – Mazin Ibrahim
    Mar 8 at 16:41











  • @MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output

    – Epic Gamer_1
    Mar 8 at 16:55













0












0








0








I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.



Here is the code I used



 var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));

secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));

var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");









share|improve this question














I have added pointycastle and generated a keypair, encrypting the trial "Hello World" string. From this, I want to get the values of the Private and Public Key. Is there anywhere they are stored, because whenever I try to print the values of keyPair.privateKey, it returns Instance of 'RSAPrivateKey.



Here is the code I used



 var keyParams = new RSAKeyGeneratorParameters(new BigInt.from(65537), 2048, 5);
var secureRandom = new FortunaRandom();
var random = new Random.secure();
List<int> seeds = [];
for (int i = 0; i < 32; i++)
seeds.add(random.nextInt(255));

secureRandom.seed(new KeyParameter(new Uint8List.fromList(seeds)));

var rngParams = new ParametersWithRandom(keyParams, secureRandom);
var k = new RSAKeyGenerator();
k.init(rngParams);
var keyPair = k.generateKeyPair();
var cipher = new RSAEngine()..init( true, new PublicKeyParameter<RSAPublicKey>(keyPair.publicKey));
print("pubkey: $keyPair.publicKey.toString()");
var cipherText = cipher.process(new Uint8List.fromList("Hello World".codeUnits));
print("Encrypted: $new String.fromCharCodes(cipherText)");
cipher.init( false, new PrivateKeyParameter<RSAPrivateKey>(keyPair.privateKey));
//cipher.init( false, new PrivateKeyParameter(keyPair.privateKey) )
var decrypted = cipher.process(cipherText);
print("Decrypted: $new String.fromCharCodes(decrypted)");






dart flutter public-key-encryption pointycastle






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 8 at 16:08









Epic Gamer_1Epic Gamer_1

2529




2529












  • Did you try keyPair.privateKey.toString() ?

    – Mazin Ibrahim
    Mar 8 at 16:17











  • @MazinIbrahim yes, that returns the same Instance of RSAPrivateKey

    – Epic Gamer_1
    Mar 8 at 16:33











  • This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert RSAPrivateKey to a readable form.

    – Mazin Ibrahim
    Mar 8 at 16:41











  • @MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output

    – Epic Gamer_1
    Mar 8 at 16:55

















  • Did you try keyPair.privateKey.toString() ?

    – Mazin Ibrahim
    Mar 8 at 16:17











  • @MazinIbrahim yes, that returns the same Instance of RSAPrivateKey

    – Epic Gamer_1
    Mar 8 at 16:33











  • This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert RSAPrivateKey to a readable form.

    – Mazin Ibrahim
    Mar 8 at 16:41











  • @MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output

    – Epic Gamer_1
    Mar 8 at 16:55
















Did you try keyPair.privateKey.toString() ?

– Mazin Ibrahim
Mar 8 at 16:17





Did you try keyPair.privateKey.toString() ?

– Mazin Ibrahim
Mar 8 at 16:17













@MazinIbrahim yes, that returns the same Instance of RSAPrivateKey

– Epic Gamer_1
Mar 8 at 16:33





@MazinIbrahim yes, that returns the same Instance of RSAPrivateKey

– Epic Gamer_1
Mar 8 at 16:33













This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert RSAPrivateKey to a readable form.

– Mazin Ibrahim
Mar 8 at 16:41





This package is poorly documented.I suggest you take a look inside their github code to figure out how to convert RSAPrivateKey to a readable form.

– Mazin Ibrahim
Mar 8 at 16:41













@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output

– Epic Gamer_1
Mar 8 at 16:55





@MazinIbrahim I have tried, but I can't see anything converting it into a readable form. I've tried looking in their Object, as well its generation function, but in there it still shows the same instance output

– Epic Gamer_1
Mar 8 at 16:55












1 Answer
1






active

oldest

votes


















0














Make sure to import package:pointycastle/asymmetric/api.dart, then use:



 var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus


Recreate from the individual parts:



 RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);





share|improve this answer

























  • From this, can i recreate a key from just the modulus of public key and exponent of private key?

    – Epic Gamer_1
    Mar 19 at 16:38











  • Both need the modulus and exponent. The private key also needs p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.

    – Richard Heap
    Mar 19 at 16:59











  • I know you can do that, but from the value of the key, can you make it? (From a single key value?)

    – Epic Gamer_1
    Mar 19 at 19:27











  • It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes p and q so if you're storing your key using that format you'll have those numbers available.)

    – Richard Heap
    Mar 19 at 21:31











  • also, can I generate a .pem file for this?

    – Epic Gamer_1
    Mar 20 at 11:12











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1 Answer
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active

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Make sure to import package:pointycastle/asymmetric/api.dart, then use:



 var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus


Recreate from the individual parts:



 RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);





share|improve this answer

























  • From this, can i recreate a key from just the modulus of public key and exponent of private key?

    – Epic Gamer_1
    Mar 19 at 16:38











  • Both need the modulus and exponent. The private key also needs p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.

    – Richard Heap
    Mar 19 at 16:59











  • I know you can do that, but from the value of the key, can you make it? (From a single key value?)

    – Epic Gamer_1
    Mar 19 at 19:27











  • It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes p and q so if you're storing your key using that format you'll have those numbers available.)

    – Richard Heap
    Mar 19 at 21:31











  • also, can I generate a .pem file for this?

    – Epic Gamer_1
    Mar 20 at 11:12















0














Make sure to import package:pointycastle/asymmetric/api.dart, then use:



 var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus


Recreate from the individual parts:



 RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);





share|improve this answer

























  • From this, can i recreate a key from just the modulus of public key and exponent of private key?

    – Epic Gamer_1
    Mar 19 at 16:38











  • Both need the modulus and exponent. The private key also needs p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.

    – Richard Heap
    Mar 19 at 16:59











  • I know you can do that, but from the value of the key, can you make it? (From a single key value?)

    – Epic Gamer_1
    Mar 19 at 19:27











  • It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes p and q so if you're storing your key using that format you'll have those numbers available.)

    – Richard Heap
    Mar 19 at 21:31











  • also, can I generate a .pem file for this?

    – Epic Gamer_1
    Mar 20 at 11:12













0












0








0







Make sure to import package:pointycastle/asymmetric/api.dart, then use:



 var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus


Recreate from the individual parts:



 RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);





share|improve this answer















Make sure to import package:pointycastle/asymmetric/api.dart, then use:



 var k = RSAKeyGenerator()..init(rngParams);
AsymmetricKeyPair<PublicKey, PrivateKey> keyPair = k.generateKeyPair();
RSAPrivateKey privateKey = keyPair.privateKey;
RSAPublicKey publicKey = keyPair.publicKey;
print(privateKey.d); // prints private exponent
print(publicKey.n); // prints modulus


Recreate from the individual parts:



 RSAPrivateKey foo = RSAPrivateKey(
privateKey.n,
privateKey.d,
privateKey.p,
privateKey.q,
);
RSAPublicKey bar = RSAPublicKey(publicKey.n, publicKey.e);






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 19 at 17:35

























answered Mar 8 at 17:31









Richard HeapRichard Heap

7,72121019




7,72121019












  • From this, can i recreate a key from just the modulus of public key and exponent of private key?

    – Epic Gamer_1
    Mar 19 at 16:38











  • Both need the modulus and exponent. The private key also needs p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.

    – Richard Heap
    Mar 19 at 16:59











  • I know you can do that, but from the value of the key, can you make it? (From a single key value?)

    – Epic Gamer_1
    Mar 19 at 19:27











  • It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes p and q so if you're storing your key using that format you'll have those numbers available.)

    – Richard Heap
    Mar 19 at 21:31











  • also, can I generate a .pem file for this?

    – Epic Gamer_1
    Mar 20 at 11:12

















  • From this, can i recreate a key from just the modulus of public key and exponent of private key?

    – Epic Gamer_1
    Mar 19 at 16:38











  • Both need the modulus and exponent. The private key also needs p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.

    – Richard Heap
    Mar 19 at 16:59











  • I know you can do that, but from the value of the key, can you make it? (From a single key value?)

    – Epic Gamer_1
    Mar 19 at 19:27











  • It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes p and q so if you're storing your key using that format you'll have those numbers available.)

    – Richard Heap
    Mar 19 at 21:31











  • also, can I generate a .pem file for this?

    – Epic Gamer_1
    Mar 20 at 11:12
















From this, can i recreate a key from just the modulus of public key and exponent of private key?

– Epic Gamer_1
Mar 19 at 16:38





From this, can i recreate a key from just the modulus of public key and exponent of private key?

– Epic Gamer_1
Mar 19 at 16:38













Both need the modulus and exponent. The private key also needs p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.

– Richard Heap
Mar 19 at 16:59





Both need the modulus and exponent. The private key also needs p and q. Check the constructors of RSAPrivateKey and RSAPublicKey.

– Richard Heap
Mar 19 at 16:59













I know you can do that, but from the value of the key, can you make it? (From a single key value?)

– Epic Gamer_1
Mar 19 at 19:27





I know you can do that, but from the value of the key, can you make it? (From a single key value?)

– Epic Gamer_1
Mar 19 at 19:27













It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes p and q so if you're storing your key using that format you'll have those numbers available.)

– Richard Heap
Mar 19 at 21:31





It doesn't look like it, but try it by supplying dummy values instead. (Incidentally, PKCS#1 format includes p and q so if you're storing your key using that format you'll have those numbers available.)

– Richard Heap
Mar 19 at 21:31













also, can I generate a .pem file for this?

– Epic Gamer_1
Mar 20 at 11:12





also, can I generate a .pem file for this?

– Epic Gamer_1
Mar 20 at 11:12



















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