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Connecting numpy array of points to form a contour?


How do I connect to a MySQL Database in Python?Is there a NumPy function to return the first index of something in an array?Limiting floats to two decimal pointsHow to print the full NumPy array, without truncation?Sorting arrays in NumPy by columnNumpy array dimensionsPeak detection in a 2D arrayHow to access the ith column of a NumPy multidimensional array?Dump a NumPy array into a csv fileFind Area of a OpenCV Contour






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0















def cnts_convex_hull(cnts,image):
results=[]
points=[]
for cnt in cnts:
for point in cnt:
reg_point=point[0]
print(reg_point)
points.append(reg_point)
results=np.array(points)
# i want to add a fn to form a contour , then use convexhull() on it.

img=cv2.imread("3.jpg")
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
min = np.array([0, 100 , 100])
max = np.array([179, 255, 255])
mask = cv2.inRange(hsv, min, max)
res = cv2.bitwise_and(img, img, mask=mask)
##################################################
gray_res = cv2.cvtColor(res, cv2.COLOR_BGR2GRAY)
kernal = np.ones((5, 5), np.uint8)
gray_res = cv2.morphologyEx(gray_res, cv2.MORPH_CLOSE, kernal)
##################################################
edges = cv2.Canny(gray_res, 100, 100)
cnts,h = cv2.findContours(edges.copy(), cv2.RETR_TREE,
cv2.CHAIN_APPROX_SIMPLE)
cnts = sorted(cnts, key = cv2.contourArea, reverse = True)[:10]
cnts_convex_hull(cnts,img)
cv2.imshow('frame',img)
cv2.waitKey(0)


the problem on my hand is simple, i have (after filtering and edge detecting and the usual stuff) something that looks like this:
https://i.stack.imgur.com/GUrYZ.png , which i want to eventually close to shape rather than 2 lines, so i want to form a convex hull on them and by them i mean the whole list of points for the 2 contours.
so in the above code i was able to get the points in a np.array()
but i cannot transform them in the shape of contour so i can preform convexhull on them










share|improve this question
























  • The easiest might be to find the ends of both lines/contours and draw lines between them on a copy of the image. Now you use findcontours to find the shape as a single contour.

    – J.D.
    Mar 9 at 9:40












  • that's actually a pretty neat idea!

    – Abdelrahman Helaly
    Mar 9 at 11:21

















0















def cnts_convex_hull(cnts,image):
results=[]
points=[]
for cnt in cnts:
for point in cnt:
reg_point=point[0]
print(reg_point)
points.append(reg_point)
results=np.array(points)
# i want to add a fn to form a contour , then use convexhull() on it.

img=cv2.imread("3.jpg")
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
min = np.array([0, 100 , 100])
max = np.array([179, 255, 255])
mask = cv2.inRange(hsv, min, max)
res = cv2.bitwise_and(img, img, mask=mask)
##################################################
gray_res = cv2.cvtColor(res, cv2.COLOR_BGR2GRAY)
kernal = np.ones((5, 5), np.uint8)
gray_res = cv2.morphologyEx(gray_res, cv2.MORPH_CLOSE, kernal)
##################################################
edges = cv2.Canny(gray_res, 100, 100)
cnts,h = cv2.findContours(edges.copy(), cv2.RETR_TREE,
cv2.CHAIN_APPROX_SIMPLE)
cnts = sorted(cnts, key = cv2.contourArea, reverse = True)[:10]
cnts_convex_hull(cnts,img)
cv2.imshow('frame',img)
cv2.waitKey(0)


the problem on my hand is simple, i have (after filtering and edge detecting and the usual stuff) something that looks like this:
https://i.stack.imgur.com/GUrYZ.png , which i want to eventually close to shape rather than 2 lines, so i want to form a convex hull on them and by them i mean the whole list of points for the 2 contours.
so in the above code i was able to get the points in a np.array()
but i cannot transform them in the shape of contour so i can preform convexhull on them










share|improve this question
























  • The easiest might be to find the ends of both lines/contours and draw lines between them on a copy of the image. Now you use findcontours to find the shape as a single contour.

    – J.D.
    Mar 9 at 9:40












  • that's actually a pretty neat idea!

    – Abdelrahman Helaly
    Mar 9 at 11:21













0












0








0








def cnts_convex_hull(cnts,image):
results=[]
points=[]
for cnt in cnts:
for point in cnt:
reg_point=point[0]
print(reg_point)
points.append(reg_point)
results=np.array(points)
# i want to add a fn to form a contour , then use convexhull() on it.

img=cv2.imread("3.jpg")
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
min = np.array([0, 100 , 100])
max = np.array([179, 255, 255])
mask = cv2.inRange(hsv, min, max)
res = cv2.bitwise_and(img, img, mask=mask)
##################################################
gray_res = cv2.cvtColor(res, cv2.COLOR_BGR2GRAY)
kernal = np.ones((5, 5), np.uint8)
gray_res = cv2.morphologyEx(gray_res, cv2.MORPH_CLOSE, kernal)
##################################################
edges = cv2.Canny(gray_res, 100, 100)
cnts,h = cv2.findContours(edges.copy(), cv2.RETR_TREE,
cv2.CHAIN_APPROX_SIMPLE)
cnts = sorted(cnts, key = cv2.contourArea, reverse = True)[:10]
cnts_convex_hull(cnts,img)
cv2.imshow('frame',img)
cv2.waitKey(0)


the problem on my hand is simple, i have (after filtering and edge detecting and the usual stuff) something that looks like this:
https://i.stack.imgur.com/GUrYZ.png , which i want to eventually close to shape rather than 2 lines, so i want to form a convex hull on them and by them i mean the whole list of points for the 2 contours.
so in the above code i was able to get the points in a np.array()
but i cannot transform them in the shape of contour so i can preform convexhull on them










share|improve this question
















def cnts_convex_hull(cnts,image):
results=[]
points=[]
for cnt in cnts:
for point in cnt:
reg_point=point[0]
print(reg_point)
points.append(reg_point)
results=np.array(points)
# i want to add a fn to form a contour , then use convexhull() on it.

img=cv2.imread("3.jpg")
hsv = cv2.cvtColor(img, cv2.COLOR_BGR2HSV)
min = np.array([0, 100 , 100])
max = np.array([179, 255, 255])
mask = cv2.inRange(hsv, min, max)
res = cv2.bitwise_and(img, img, mask=mask)
##################################################
gray_res = cv2.cvtColor(res, cv2.COLOR_BGR2GRAY)
kernal = np.ones((5, 5), np.uint8)
gray_res = cv2.morphologyEx(gray_res, cv2.MORPH_CLOSE, kernal)
##################################################
edges = cv2.Canny(gray_res, 100, 100)
cnts,h = cv2.findContours(edges.copy(), cv2.RETR_TREE,
cv2.CHAIN_APPROX_SIMPLE)
cnts = sorted(cnts, key = cv2.contourArea, reverse = True)[:10]
cnts_convex_hull(cnts,img)
cv2.imshow('frame',img)
cv2.waitKey(0)


the problem on my hand is simple, i have (after filtering and edge detecting and the usual stuff) something that looks like this:
https://i.stack.imgur.com/GUrYZ.png , which i want to eventually close to shape rather than 2 lines, so i want to form a convex hull on them and by them i mean the whole list of points for the 2 contours.
so in the above code i was able to get the points in a np.array()
but i cannot transform them in the shape of contour so i can preform convexhull on them







python opencv






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 9 at 3:27







Abdelrahman Helaly

















asked Mar 9 at 3:20









Abdelrahman HelalyAbdelrahman Helaly

11




11












  • The easiest might be to find the ends of both lines/contours and draw lines between them on a copy of the image. Now you use findcontours to find the shape as a single contour.

    – J.D.
    Mar 9 at 9:40












  • that's actually a pretty neat idea!

    – Abdelrahman Helaly
    Mar 9 at 11:21

















  • The easiest might be to find the ends of both lines/contours and draw lines between them on a copy of the image. Now you use findcontours to find the shape as a single contour.

    – J.D.
    Mar 9 at 9:40












  • that's actually a pretty neat idea!

    – Abdelrahman Helaly
    Mar 9 at 11:21
















The easiest might be to find the ends of both lines/contours and draw lines between them on a copy of the image. Now you use findcontours to find the shape as a single contour.

– J.D.
Mar 9 at 9:40






The easiest might be to find the ends of both lines/contours and draw lines between them on a copy of the image. Now you use findcontours to find the shape as a single contour.

– J.D.
Mar 9 at 9:40














that's actually a pretty neat idea!

– Abdelrahman Helaly
Mar 9 at 11:21





that's actually a pretty neat idea!

– Abdelrahman Helaly
Mar 9 at 11:21












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