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Errorjava sql.SQLException: Parameter index out of range (1 >)
How do I generate random integers within a specific range in Java?The case against checked exceptionsHow do I break out of nested loops in Java?Does Java support default parameter values?mysql_fetch_array()/mysql_fetch_assoc()/mysql_fetch_row()/mysql_num_rows etc… expects parameter 1 to be resource or resultJava, 3 dots in parametersJava non-blocking IO selector causing channel register to blockMissing return statement in a non-void method compilesJava.sql.SQLException: Parameter index out of range 2> 1error: incompatible types: int cannot be converted to Client - Java
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i have an error with my Code, but i don't know what is...
(Java + MySQL)
public void deleteClientes(int nit)
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ";
delete(sql,nit);
Method that receives:
public void delete(String sql,int id)
final QueryRunner qr = new QueryRunner(true);
try
qr.update(conexion(),sql,"%"+id+"%");
catch (SQLException ex)
System.err.println("Error"+ex);
java mysql
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
add a comment |
i have an error with my Code, but i don't know what is...
(Java + MySQL)
public void deleteClientes(int nit)
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ";
delete(sql,nit);
Method that receives:
public void delete(String sql,int id)
final QueryRunner qr = new QueryRunner(true);
try
qr.update(conexion(),sql,"%"+id+"%");
catch (SQLException ex)
System.err.println("Error"+ex);
java mysql
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
add a comment |
i have an error with my Code, but i don't know what is...
(Java + MySQL)
public void deleteClientes(int nit)
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ";
delete(sql,nit);
Method that receives:
public void delete(String sql,int id)
final QueryRunner qr = new QueryRunner(true);
try
qr.update(conexion(),sql,"%"+id+"%");
catch (SQLException ex)
System.err.println("Error"+ex);
java mysql
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
i have an error with my Code, but i don't know what is...
(Java + MySQL)
public void deleteClientes(int nit)
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ";
delete(sql,nit);
Method that receives:
public void delete(String sql,int id)
final QueryRunner qr = new QueryRunner(true);
try
qr.update(conexion(),sql,"%"+id+"%");
catch (SQLException ex)
System.err.println("Error"+ex);
java mysql
java mysql
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
edited Mar 9 at 3:33
Book Of Zeus
45.9k12161162
45.9k12161162
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
asked Mar 9 at 3:26
Fernando Ca97Fernando Ca97
13
13
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Your query doesn't have a placeholder ?. It should be:
"DELETE FROM `clientes` WHERE `clientes`.`nit` = ?"
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Listo! Problem solved Thanks !
– Fernando Ca97
Mar 9 at 3:59
add a comment |
Need to add ? into sql statement where data will be placed based on parameter
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ?";
and
qr.update(conexion(),sql,id);
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
check data type and where condition, data will be deleted if condition matched
– Jahirul Islam Bhuiyan
Mar 9 at 3:53
"%"+id+"%", why did you add%?
– Jahirul Islam Bhuiyan
Mar 9 at 3:57
Listo! the error is fixed...i changed the fragment: qr.update(conexion(),sql,"%"+id+"%"); by: qr.update(conexion(),sql,id); and that's it!
– Fernando Ca97
Mar 9 at 3:58
accept my answer
– Jahirul Islam Bhuiyan
Mar 9 at 12:20
|
show 1 more comment
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your query doesn't have a placeholder ?. It should be:
"DELETE FROM `clientes` WHERE `clientes`.`nit` = ?"
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Listo! Problem solved Thanks !
– Fernando Ca97
Mar 9 at 3:59
add a comment |
Your query doesn't have a placeholder ?. It should be:
"DELETE FROM `clientes` WHERE `clientes`.`nit` = ?"
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Listo! Problem solved Thanks !
– Fernando Ca97
Mar 9 at 3:59
add a comment |
Your query doesn't have a placeholder ?. It should be:
"DELETE FROM `clientes` WHERE `clientes`.`nit` = ?"
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
Your query doesn't have a placeholder ?. It should be:
"DELETE FROM `clientes` WHERE `clientes`.`nit` = ?"
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
answered Mar 9 at 3:37
Sukhpal SinghSukhpal Singh
1,039212
1,039212
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Listo! Problem solved Thanks !
– Fernando Ca97
Mar 9 at 3:59
add a comment |
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Listo! Problem solved Thanks !
– Fernando Ca97
Mar 9 at 3:59
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Listo! Problem solved Thanks !
– Fernando Ca97
Mar 9 at 3:59
Listo! Problem solved Thanks !
– Fernando Ca97
Mar 9 at 3:59
add a comment |
Need to add ? into sql statement where data will be placed based on parameter
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ?";
and
qr.update(conexion(),sql,id);
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
check data type and where condition, data will be deleted if condition matched
– Jahirul Islam Bhuiyan
Mar 9 at 3:53
"%"+id+"%", why did you add%?
– Jahirul Islam Bhuiyan
Mar 9 at 3:57
Listo! the error is fixed...i changed the fragment: qr.update(conexion(),sql,"%"+id+"%"); by: qr.update(conexion(),sql,id); and that's it!
– Fernando Ca97
Mar 9 at 3:58
accept my answer
– Jahirul Islam Bhuiyan
Mar 9 at 12:20
|
show 1 more comment
Need to add ? into sql statement where data will be placed based on parameter
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ?";
and
qr.update(conexion(),sql,id);
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
check data type and where condition, data will be deleted if condition matched
– Jahirul Islam Bhuiyan
Mar 9 at 3:53
"%"+id+"%", why did you add%?
– Jahirul Islam Bhuiyan
Mar 9 at 3:57
Listo! the error is fixed...i changed the fragment: qr.update(conexion(),sql,"%"+id+"%"); by: qr.update(conexion(),sql,id); and that's it!
– Fernando Ca97
Mar 9 at 3:58
accept my answer
– Jahirul Islam Bhuiyan
Mar 9 at 12:20
|
show 1 more comment
Need to add ? into sql statement where data will be placed based on parameter
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ?";
and
qr.update(conexion(),sql,id);
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
Need to add ? into sql statement where data will be placed based on parameter
sql = "DELETE FROM `clientes` WHERE `clientes`.`nit` = ?";
and
qr.update(conexion(),sql,id);
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
edited Mar 9 at 3:59
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
answered Mar 9 at 3:40
Jahirul Islam BhuiyanJahirul Islam Bhuiyan
768413
768413
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
check data type and where condition, data will be deleted if condition matched
– Jahirul Islam Bhuiyan
Mar 9 at 3:53
"%"+id+"%", why did you add%?
– Jahirul Islam Bhuiyan
Mar 9 at 3:57
Listo! the error is fixed...i changed the fragment: qr.update(conexion(),sql,"%"+id+"%"); by: qr.update(conexion(),sql,id); and that's it!
– Fernando Ca97
Mar 9 at 3:58
accept my answer
– Jahirul Islam Bhuiyan
Mar 9 at 12:20
|
show 1 more comment
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
check data type and where condition, data will be deleted if condition matched
– Jahirul Islam Bhuiyan
Mar 9 at 3:53
"%"+id+"%", why did you add%?
– Jahirul Islam Bhuiyan
Mar 9 at 3:57
Listo! the error is fixed...i changed the fragment: qr.update(conexion(),sql,"%"+id+"%"); by: qr.update(conexion(),sql,id); and that's it!
– Fernando Ca97
Mar 9 at 3:58
accept my answer
– Jahirul Islam Bhuiyan
Mar 9 at 12:20
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
Nothing, the error don't come out now but not delete the row :(
– Fernando Ca97
Mar 9 at 3:50
check data type and where condition, data will be deleted if condition matched
– Jahirul Islam Bhuiyan
Mar 9 at 3:53
check data type and where condition, data will be deleted if condition matched
– Jahirul Islam Bhuiyan
Mar 9 at 3:53
"%"+id+"%", why did you add %?– Jahirul Islam Bhuiyan
Mar 9 at 3:57
"%"+id+"%", why did you add %?– Jahirul Islam Bhuiyan
Mar 9 at 3:57
Listo! the error is fixed...i changed the fragment: qr.update(conexion(),sql,"%"+id+"%"); by: qr.update(conexion(),sql,id); and that's it!
– Fernando Ca97
Mar 9 at 3:58
Listo! the error is fixed...i changed the fragment: qr.update(conexion(),sql,"%"+id+"%"); by: qr.update(conexion(),sql,id); and that's it!
– Fernando Ca97
Mar 9 at 3:58
accept my answer
– Jahirul Islam Bhuiyan
Mar 9 at 12:20
accept my answer
– Jahirul Islam Bhuiyan
Mar 9 at 12:20
|
show 1 more comment
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