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pycharm can't reference global variable inside a function
What is the Python equivalent of static variables inside a function?How to import a module given its name?Using global variables in a functionHow do I pass a variable by reference?Using global variables between files?how to define a global variable to be used in a function of an imported file?Unresolved reference issue in PyCharmpython mock global function that is used in classUsing variables inside a function in another python fileHow to reset global variable in a subsequent import
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I defines a global variable in function.But PyCharm can't reference this global variable.
code like this:
a.py:
g_Handle = None
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.g_handle
# PyCharm will reference 'g_handle' as None,
# but I want reference 'g_handle' as mods.handle_class
I try to add type for g_handle, but I don't want import mods directly in a.py
a.py:
g_handle =None # type: mods.handle_class
but this is not work.can't find mods
so I want to know how to let PyCharm can reference g_handle as mods.handle_class.
Thank you.
python pycharm
|
show 1 more comment
I defines a global variable in function.But PyCharm can't reference this global variable.
code like this:
a.py:
g_Handle = None
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.g_handle
# PyCharm will reference 'g_handle' as None,
# but I want reference 'g_handle' as mods.handle_class
I try to add type for g_handle, but I don't want import mods directly in a.py
a.py:
g_handle =None # type: mods.handle_class
but this is not work.can't find mods
so I want to know how to let PyCharm can reference g_handle as mods.handle_class.
Thank you.
python pycharm
it is like you are not definingg_handle
in your filea.py
. You should define it at the zero-indentation level.
– lmiguelvargasf
Mar 9 at 3:53
yes . but I don't want assignt it at the zero-indentation level.Only want assign it in function. And I want PyCharm want reference g_handle as mods.handle_class.
– sair
Mar 9 at 4:01
a global variable by definition should be declared at the zero-indentation level. Otherwise, we are talking about local variables inside a function which are not accessible in other functions due scoping rules.
– lmiguelvargasf
Mar 9 at 4:02
em.I'm sorry for didn't explain this question clearly.I have edited the question already.
– sair
Mar 9 at 5:02
it looks like you will haveg_handle
set as None until you callInit
– lmiguelvargasf
Mar 9 at 5:07
|
show 1 more comment
I defines a global variable in function.But PyCharm can't reference this global variable.
code like this:
a.py:
g_Handle = None
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.g_handle
# PyCharm will reference 'g_handle' as None,
# but I want reference 'g_handle' as mods.handle_class
I try to add type for g_handle, but I don't want import mods directly in a.py
a.py:
g_handle =None # type: mods.handle_class
but this is not work.can't find mods
so I want to know how to let PyCharm can reference g_handle as mods.handle_class.
Thank you.
python pycharm
I defines a global variable in function.But PyCharm can't reference this global variable.
code like this:
a.py:
g_Handle = None
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.g_handle
# PyCharm will reference 'g_handle' as None,
# but I want reference 'g_handle' as mods.handle_class
I try to add type for g_handle, but I don't want import mods directly in a.py
a.py:
g_handle =None # type: mods.handle_class
but this is not work.can't find mods
so I want to know how to let PyCharm can reference g_handle as mods.handle_class.
Thank you.
python pycharm
python pycharm
edited Mar 9 at 4:59
sair
asked Mar 9 at 3:46
sairsair
12
12
it is like you are not definingg_handle
in your filea.py
. You should define it at the zero-indentation level.
– lmiguelvargasf
Mar 9 at 3:53
yes . but I don't want assignt it at the zero-indentation level.Only want assign it in function. And I want PyCharm want reference g_handle as mods.handle_class.
– sair
Mar 9 at 4:01
a global variable by definition should be declared at the zero-indentation level. Otherwise, we are talking about local variables inside a function which are not accessible in other functions due scoping rules.
– lmiguelvargasf
Mar 9 at 4:02
em.I'm sorry for didn't explain this question clearly.I have edited the question already.
– sair
Mar 9 at 5:02
it looks like you will haveg_handle
set as None until you callInit
– lmiguelvargasf
Mar 9 at 5:07
|
show 1 more comment
it is like you are not definingg_handle
in your filea.py
. You should define it at the zero-indentation level.
– lmiguelvargasf
Mar 9 at 3:53
yes . but I don't want assignt it at the zero-indentation level.Only want assign it in function. And I want PyCharm want reference g_handle as mods.handle_class.
– sair
Mar 9 at 4:01
a global variable by definition should be declared at the zero-indentation level. Otherwise, we are talking about local variables inside a function which are not accessible in other functions due scoping rules.
– lmiguelvargasf
Mar 9 at 4:02
em.I'm sorry for didn't explain this question clearly.I have edited the question already.
– sair
Mar 9 at 5:02
it looks like you will haveg_handle
set as None until you callInit
– lmiguelvargasf
Mar 9 at 5:07
it is like you are not defining
g_handle
in your file a.py
. You should define it at the zero-indentation level.– lmiguelvargasf
Mar 9 at 3:53
it is like you are not defining
g_handle
in your file a.py
. You should define it at the zero-indentation level.– lmiguelvargasf
Mar 9 at 3:53
yes . but I don't want assignt it at the zero-indentation level.Only want assign it in function. And I want PyCharm want reference g_handle as mods.handle_class.
– sair
Mar 9 at 4:01
yes . but I don't want assignt it at the zero-indentation level.Only want assign it in function. And I want PyCharm want reference g_handle as mods.handle_class.
– sair
Mar 9 at 4:01
a global variable by definition should be declared at the zero-indentation level. Otherwise, we are talking about local variables inside a function which are not accessible in other functions due scoping rules.
– lmiguelvargasf
Mar 9 at 4:02
a global variable by definition should be declared at the zero-indentation level. Otherwise, we are talking about local variables inside a function which are not accessible in other functions due scoping rules.
– lmiguelvargasf
Mar 9 at 4:02
em.I'm sorry for didn't explain this question clearly.I have edited the question already.
– sair
Mar 9 at 5:02
em.I'm sorry for didn't explain this question clearly.I have edited the question already.
– sair
Mar 9 at 5:02
it looks like you will have
g_handle
set as None until you call Init
– lmiguelvargasf
Mar 9 at 5:07
it looks like you will have
g_handle
set as None until you call Init
– lmiguelvargasf
Mar 9 at 5:07
|
show 1 more comment
1 Answer
1
active
oldest
votes
I'm not sure if it's an element of the way you're asking your question, but it looks like you've got multiple problems here. The first is an import reference problem (or possibly using an import where a class would be more effective).
See, if you run the code only as you have described and provided, you would never get the correct answer that you seek because the Init function in a.py would never get called.
You need to have the intended global variable defined in some way in the global scope prior to being used like in your code.
The global statement merely tells the interpreter to link the values of the provided variable across all states. It does not define the variable in the outermost scope on its own.
Therefore, something like this (EDIT: FIXED):
a.py:
g_handle = False
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.Init()
a.g_handle
...should work to return what you're looking for.
If you could use a class instead of importing from another module, you could save yourself from trouble too:
import mods
class a():
g_handle = False
global g_handle
def __init__(self, handle_class):
g_handle = handle_class()
if __name__ == "__main__":
a(mods.handle_class).g_handle
but PyCharm can't reference a.g_handle as mods.handle_class alse, and no have smart code completion.I'm sorry for didn't explain this question clearly.
– sair
Mar 9 at 4:55
sorry I made a mistake in my code. it should work now. I changed g = False to g_handle = False
– etherwar
Mar 10 at 12:46
add a comment |
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I'm not sure if it's an element of the way you're asking your question, but it looks like you've got multiple problems here. The first is an import reference problem (or possibly using an import where a class would be more effective).
See, if you run the code only as you have described and provided, you would never get the correct answer that you seek because the Init function in a.py would never get called.
You need to have the intended global variable defined in some way in the global scope prior to being used like in your code.
The global statement merely tells the interpreter to link the values of the provided variable across all states. It does not define the variable in the outermost scope on its own.
Therefore, something like this (EDIT: FIXED):
a.py:
g_handle = False
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.Init()
a.g_handle
...should work to return what you're looking for.
If you could use a class instead of importing from another module, you could save yourself from trouble too:
import mods
class a():
g_handle = False
global g_handle
def __init__(self, handle_class):
g_handle = handle_class()
if __name__ == "__main__":
a(mods.handle_class).g_handle
but PyCharm can't reference a.g_handle as mods.handle_class alse, and no have smart code completion.I'm sorry for didn't explain this question clearly.
– sair
Mar 9 at 4:55
sorry I made a mistake in my code. it should work now. I changed g = False to g_handle = False
– etherwar
Mar 10 at 12:46
add a comment |
I'm not sure if it's an element of the way you're asking your question, but it looks like you've got multiple problems here. The first is an import reference problem (or possibly using an import where a class would be more effective).
See, if you run the code only as you have described and provided, you would never get the correct answer that you seek because the Init function in a.py would never get called.
You need to have the intended global variable defined in some way in the global scope prior to being used like in your code.
The global statement merely tells the interpreter to link the values of the provided variable across all states. It does not define the variable in the outermost scope on its own.
Therefore, something like this (EDIT: FIXED):
a.py:
g_handle = False
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.Init()
a.g_handle
...should work to return what you're looking for.
If you could use a class instead of importing from another module, you could save yourself from trouble too:
import mods
class a():
g_handle = False
global g_handle
def __init__(self, handle_class):
g_handle = handle_class()
if __name__ == "__main__":
a(mods.handle_class).g_handle
but PyCharm can't reference a.g_handle as mods.handle_class alse, and no have smart code completion.I'm sorry for didn't explain this question clearly.
– sair
Mar 9 at 4:55
sorry I made a mistake in my code. it should work now. I changed g = False to g_handle = False
– etherwar
Mar 10 at 12:46
add a comment |
I'm not sure if it's an element of the way you're asking your question, but it looks like you've got multiple problems here. The first is an import reference problem (or possibly using an import where a class would be more effective).
See, if you run the code only as you have described and provided, you would never get the correct answer that you seek because the Init function in a.py would never get called.
You need to have the intended global variable defined in some way in the global scope prior to being used like in your code.
The global statement merely tells the interpreter to link the values of the provided variable across all states. It does not define the variable in the outermost scope on its own.
Therefore, something like this (EDIT: FIXED):
a.py:
g_handle = False
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.Init()
a.g_handle
...should work to return what you're looking for.
If you could use a class instead of importing from another module, you could save yourself from trouble too:
import mods
class a():
g_handle = False
global g_handle
def __init__(self, handle_class):
g_handle = handle_class()
if __name__ == "__main__":
a(mods.handle_class).g_handle
I'm not sure if it's an element of the way you're asking your question, but it looks like you've got multiple problems here. The first is an import reference problem (or possibly using an import where a class would be more effective).
See, if you run the code only as you have described and provided, you would never get the correct answer that you seek because the Init function in a.py would never get called.
You need to have the intended global variable defined in some way in the global scope prior to being used like in your code.
The global statement merely tells the interpreter to link the values of the provided variable across all states. It does not define the variable in the outermost scope on its own.
Therefore, something like this (EDIT: FIXED):
a.py:
g_handle = False
def Init():
import mods
global g_handle
g_handle = mods.handle_class()
b.py:
import a
a.Init()
a.g_handle
...should work to return what you're looking for.
If you could use a class instead of importing from another module, you could save yourself from trouble too:
import mods
class a():
g_handle = False
global g_handle
def __init__(self, handle_class):
g_handle = handle_class()
if __name__ == "__main__":
a(mods.handle_class).g_handle
edited Mar 10 at 12:54
answered Mar 9 at 4:38
etherwaretherwar
8319
8319
but PyCharm can't reference a.g_handle as mods.handle_class alse, and no have smart code completion.I'm sorry for didn't explain this question clearly.
– sair
Mar 9 at 4:55
sorry I made a mistake in my code. it should work now. I changed g = False to g_handle = False
– etherwar
Mar 10 at 12:46
add a comment |
but PyCharm can't reference a.g_handle as mods.handle_class alse, and no have smart code completion.I'm sorry for didn't explain this question clearly.
– sair
Mar 9 at 4:55
sorry I made a mistake in my code. it should work now. I changed g = False to g_handle = False
– etherwar
Mar 10 at 12:46
but PyCharm can't reference a.g_handle as mods.handle_class alse, and no have smart code completion.I'm sorry for didn't explain this question clearly.
– sair
Mar 9 at 4:55
but PyCharm can't reference a.g_handle as mods.handle_class alse, and no have smart code completion.I'm sorry for didn't explain this question clearly.
– sair
Mar 9 at 4:55
sorry I made a mistake in my code. it should work now. I changed g = False to g_handle = False
– etherwar
Mar 10 at 12:46
sorry I made a mistake in my code. it should work now. I changed g = False to g_handle = False
– etherwar
Mar 10 at 12:46
add a comment |
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it is like you are not defining
g_handle
in your filea.py
. You should define it at the zero-indentation level.– lmiguelvargasf
Mar 9 at 3:53
yes . but I don't want assignt it at the zero-indentation level.Only want assign it in function. And I want PyCharm want reference g_handle as mods.handle_class.
– sair
Mar 9 at 4:01
a global variable by definition should be declared at the zero-indentation level. Otherwise, we are talking about local variables inside a function which are not accessible in other functions due scoping rules.
– lmiguelvargasf
Mar 9 at 4:02
em.I'm sorry for didn't explain this question clearly.I have edited the question already.
– sair
Mar 9 at 5:02
it looks like you will have
g_handle
set as None until you callInit
– lmiguelvargasf
Mar 9 at 5:07