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How to use a variable from a different class

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1

I have a rather simple question. How can I use variables from different classes in dart?

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var useVariable = variable + 1; // This gives me an error saying:
 // Undefined name 'variable' 

dart

share|improve this question

asked Mar 9 at 2:20

ExtraExtra

8811

add a comment | 

1

I have a rather simple question. How can I use variables from different classes in dart?

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var useVariable = variable + 1; // This gives me an error saying:
 // Undefined name 'variable' 

dart

share|improve this question

asked Mar 9 at 2:20

ExtraExtra

8811

add a comment | 

I have a rather simple question. How can I use variables from different classes in dart?

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var useVariable = variable + 1; // This gives me an error saying:
 // Undefined name 'variable' 

dart

share|improve this question

asked Mar 9 at 2:20

ExtraExtra

8811

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var useVariable = variable + 1; // This gives me an error saying:
 // Undefined name 'variable' 

share|improve this question

asked Mar 9 at 2:20

ExtraExtra

8811

share|improve this question

asked Mar 9 at 2:20

ExtraExtra

8811

asked Mar 9 at 2:20

ExtraExtra

8811

asked Mar 9 at 2:20

ExtraExtra

8811

1 Answer
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votes

1

Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.

Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.

That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:

Option 1 - static member variable

You can make a static (class level) member, which will be the same for all objects.

class ContainsVariable 

 static var variable = 1;



class DoesNotContainVariable 

 var useVariable = ContainsVariable.variable + 1; // here, you are using a
 // static (class) variable, 
 // not an instance variable. 
 // That is why you are using 
 // the class name. 

Option 2 - instantiation

You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var instanceOfContainsVariable;
 var useVariable; 

 DoesNotContainVariable() // this is a constructor function
 var instanceOfContainsVariable = new ContainsVariable();
 useVariable = instanceOfContainsVariable.variable + 1;
 

share|improve this answer

answered Mar 9 at 5:35

Balázs PukliBalázs Pukli

1113

add a comment | 

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1

Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.

Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.

That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:

Option 1 - static member variable

You can make a static (class level) member, which will be the same for all objects.

class ContainsVariable 

 static var variable = 1;



class DoesNotContainVariable 

 var useVariable = ContainsVariable.variable + 1; // here, you are using a
 // static (class) variable, 
 // not an instance variable. 
 // That is why you are using 
 // the class name. 

Option 2 - instantiation

You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var instanceOfContainsVariable;
 var useVariable; 

 DoesNotContainVariable() // this is a constructor function
 var instanceOfContainsVariable = new ContainsVariable();
 useVariable = instanceOfContainsVariable.variable + 1;
 

share|improve this answer

answered Mar 9 at 5:35

Balázs PukliBalázs Pukli

1113

add a comment | 

1

Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.

Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.

That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:

Option 1 - static member variable

You can make a static (class level) member, which will be the same for all objects.

class ContainsVariable 

 static var variable = 1;



class DoesNotContainVariable 

 var useVariable = ContainsVariable.variable + 1; // here, you are using a
 // static (class) variable, 
 // not an instance variable. 
 // That is why you are using 
 // the class name. 

Option 2 - instantiation

You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var instanceOfContainsVariable;
 var useVariable; 

 DoesNotContainVariable() // this is a constructor function
 var instanceOfContainsVariable = new ContainsVariable();
 useVariable = instanceOfContainsVariable.variable + 1;
 

share|improve this answer

answered Mar 9 at 5:35

Balázs PukliBalázs Pukli

1113

add a comment | 

Having their own scope is a very fundamental feature of classes in Object Oriented Programming, corresponding to OOP principles.

Also note that from your code, it seems that you have not properly understood the idea of instantiation in Object Oriented Programming, since you are trying to set an instance variable without instantiating the class. I highly suggest to look into this topic to gain more understanding.

That being said, there are most definitely many ways to achieve what you want. Since your code sample is very general, I'm not exactly sure what you are trying to do, so I'll provide 2 examples, which might be useful:

Option 1 - static member variable

You can make a static (class level) member, which will be the same for all objects.

class ContainsVariable 

 static var variable = 1;



class DoesNotContainVariable 

 var useVariable = ContainsVariable.variable + 1; // here, you are using a
 // static (class) variable, 
 // not an instance variable. 
 // That is why you are using 
 // the class name. 

Option 2 - instantiation

You can instantiate the class - by creating an object of that class - and access the member of that object. Notice that there is no static statement here.

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var instanceOfContainsVariable;
 var useVariable; 

 DoesNotContainVariable() // this is a constructor function
 var instanceOfContainsVariable = new ContainsVariable();
 useVariable = instanceOfContainsVariable.variable + 1;
 

share|improve this answer

answered Mar 9 at 5:35

Balázs PukliBalázs Pukli

1113

class ContainsVariable 

 static var variable = 1;



class DoesNotContainVariable 

 var useVariable = ContainsVariable.variable + 1; // here, you are using a
 // static (class) variable, 
 // not an instance variable. 
 // That is why you are using 
 // the class name. 

class ContainsVariable 

 var variable = 1;



class DoesNotContainVariable 

 var instanceOfContainsVariable;
 var useVariable; 

 DoesNotContainVariable() // this is a constructor function
 var instanceOfContainsVariable = new ContainsVariable();
 useVariable = instanceOfContainsVariable.variable + 1;
 

share|improve this answer

answered Mar 9 at 5:35

Balázs PukliBalázs Pukli

1113

answered Mar 9 at 5:35

Balázs PukliBalázs Pukli

1113

answered Mar 9 at 5:35

Balázs PukliBalázs Pukli

1113