Ggtcf

const items = [
 id: 'item1',
 children: [ 
 id: 'item1-1',
 children: [
 id: 'item1-1-1' ,
 id: 'item1-1-2' ,
 id: 'item1-1-3'
 children: [
 id: 'item1-1-3-1'
 ]
 ,
 ]
 ,
 id: 'item1-2',
 children: [
 id: 'item1-2-1' 
 ]
 
 ]
 ,
 id: 'item2' 
]

What I want to is like below,

function getFullDepthOfObject()
 ...


getFullIndexOfObject('item1') =====> return '1'
getFullIndexOfObject('item1-2') =====> return '1-2'
getFullIndexOfObject('item1-1-1') =====> return '1-1-1'
getFullIndexOfObject('item1-1-2') =====> return '1-1-2'
getFullIndexOfObject('item2') ===> return '2'

I have struggled with this too much time, But I couldn't make it. I think I should stack each of parent index, But I don't know how to get its parent. Is there a way to do this?

Not parse of id string. Each id has randomic string. The id like item1-2 is for easier demonstration.

I think my way is too verbose...
I tried like ...

// Get Full Index of item1-1


// First, get the target's depth.
var depth = 0;

function getDepthOfId(object, id) 
 var level;
 if (object.id === id) return 1;
 object.children && object.children.some(o => level = getDepthOfId(o, id));
 return level && level + 1;


depth = getDepthOfId(items[0], 'item1-1');
console.log('depth === ', depth)


// Then, iterate recursively with length of depth.

var indexStacks = [];


function getNestedIndexOfId(obj, id, index) 
 if (obj.id === id) 
 indexStacks = [index, ...indexStacks]
 return index;
 

 if (obj.children) 
 depth++;
 obj.children.map((child, i) => 
 getNestedIndexOfId(child, id, i)
 )
 


// I can get the inner index, but I can't get its parent id.
// I don't know how to this..

function getParentId(obj, id)
 // ...?
 var parentId;
 return parentId;


for(var i=0; i<depth; i++)
 getNestedIndexOfId('...')



// full path will be 
indexStacks.join('-')

const items = [
 id: 'item1',
 children: [
 id: 'item1-1',
 children: [
 id: 'item1-1-1' ,
 id: 'item1-1-2' ,
 id: 'item1-1-3',
 children: [
 id: 'item1-1-3-1'
 ]
 
 ]
 ,
 id: 'item1-2',
 children: [
 id: 'item1-2-1' 
 ]
 
 ]
 ,
 id: 'item2' 
];

const searchIt = (node, search, path = '', position = 0) => 
 if (node.id && node.id === search) return path !== '' ? `$path-$position` : position;
 if (!node.children) return false
 const index = node.children.findIndex((x) => x.id && x.id === search);
 if (index >= 0) 
 return path !== '' ? `$path-$index + 1` : index + 1;
 
 for (let i = 0; i < node.children.length; i++) 
 const result = searchIt(node.children[i], search, path !== '' ? `$path-$i+1` : i + 1, i);
 if (result)
 return result;
 
 
 return false;
;

console.log(searchIt(children: items, 'item1-1'));
console.log(searchIt(children: items, 'item1-1-1'));
console.log(searchIt(children: items, 'item1-1-2'));
console.log(searchIt(children: items, 'item1-1-3'));
console.log(searchIt(children: items, 'item1-1-3-1'));
console.log(searchIt(children: items, 'item1-2-1'));
console.log(searchIt(children: items, 'item1-1-3-2'));
console.log(searchIt(children: items, 'item1-2-2'));
console.log(searchIt(children: items, 'item3'));

You could take an recursive and iterative approach. On found, the path is returned from the most inner object to the outer call of the function.

function getPath(array, id) 
 var result;
 array.some((o, i) => );
 return result;


const items = [ id: 'item1', children: [ id: 'item1-1', children: [ id: 'item1-1-1' , id: 'item1-1-2' , id: 'item1-1-3', children: [ id: 'item1-1-3-1'] ] , id: 'item1-2', children: [ id: 'item1-2-1' ] ] , id: 'item2' ];


console.log(getPath(items, 'item1')); // '1'
console.log(getPath(items, 'item1-2')); // '1-2'
console.log(getPath(items, 'item1-1-1')); // '1-1-1'
console.log(getPath(items, 'item1-1-2')); // '1-1-2'
console.log(getPath(items, 'item2')); // '2'

You can solve this problem using recursion. I have edited my code block and made it into a testable snippet. I had to fix an error in your data (missing comma or something don't remember).

const items = [
 id: 'itemA',
 children: [ 
 id: 'item1-1',
 children: [
 id: 'item1-1-1' ,
 id: 'item1-1-2' ,
 id: 'item1-1-3', children: [ id: 'item1-1-3-1' ] ,
 ]
 ,
 id: 'item1-2', children: [ id: 'item1-2-1' ] ,
 ],
 ,
 id: 'item2' 
];


const getItemLevel = (targetKey, item, depth = 0) => 
 if (item.id === targetKey) return depth;
 let foundLevel = null;
 if (item.children) 
 item.children.forEach((child) => 
 if (foundLevel) return;
 foundLevel = getItemLevel(targetKey, child, depth +1);
 )
 
 return foundLevel;


console.log(getItemLevel('item1-1-1', id:'root', children: items ));
console.log(getItemLevel('item2', id:'root', children: items ));
console.log(getItemLevel('item1-1-3-1', id:'root', children: items ));
console.log(getItemLevel('keydoesnotexist', id:'root', children: items ));

a simple way:

const recursiveFind = (arr, id, res = indexes: [], found: false) => 
 if (!Array.isArray(arr)) return res

 const index = arr.findIndex(e => e.id === id)

 if (index < 0) 
 for (let i = 0; i < arr.length; i++) 
 res.indexes.push(i+1)
 const childIndexes = recursiveFind(arr[i].children, id, res)
 if (childIndexes.found)
 return childIndexes
 
 
 
 else 
 res.found = true
 res.indexes.push(index+1)
 

 return res


recursiveFind(items, 'item1-1-2').indexes.join('-')

If it's ok to use Lodash+Deepdash, then:

let path;

_.eachDeep(items,(val,key,parent,context)=>
 if(path) return false;
 if(val.id=='item1-1-2')
 path=context.path;
 return false;
 
,tree:true,pathFormat:'array');

console.log(_(path).without('children').map(v=>parseInt(v)+1).join('-'));

Here is a codepen for this