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BinaryWriter and BinaryReader not working in VB.NET
Is there a conditional ternary operator in VB.NET?IndexOutOfRangeException in VB.NETProblem in saving image to database from picturebox. VB.Net 2008. Framework 3.5Send Bulk Email in VB.NET Reciepients Emails will uploaded by excelVB .Net querying a SQL Server DB for average and getting “DS System.Data.DataSet”Fast throw unhandled exceptions in TPLVB.NET variable checkExecute Reader error on VB.net using MS ACCESS Database“Object reference not set to an instance of an object” when clearing a datatable with a checkboxhow can i Update access database from vb.net app
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I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.
Here's the reader code:
Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
And here's the code for the writer:
Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.
Please help!
Thanks, w60
vb.net
add a comment |
I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.
Here's the reader code:
Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
And here's the code for the writer:
Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.
Please help!
Thanks, w60
vb.net
Can we assume that no exception is thrown in either case?
– jmcilhinney
Mar 9 at 2:49
@jmcilhinney That is correct.
– w60
Mar 9 at 2:51
2
By the way, if your are using a Windows FormsOpenFileDialog
andSaveFileDialog
then theShowDialog
method returns aDialogResult
value, not aBoolean
. You should be comparing toDialogResult.OK
rather than toTrue
. You should haveOption Strict On
, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.
– jmcilhinney
Mar 9 at 2:52
@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers
– w60
Mar 9 at 2:54
1
You should turnOption Strict On
in the project properties and you should also turn itOn
in the IDE options, so that it isOn
by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into theIf
block and at least indicate where you should be looking for the cause.
– jmcilhinney
Mar 9 at 3:01
add a comment |
I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.
Here's the reader code:
Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
And here's the code for the writer:
Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.
Please help!
Thanks, w60
vb.net
I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.
Here's the reader code:
Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
And here's the code for the writer:
Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try
As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.
Please help!
Thanks, w60
vb.net
vb.net
asked Mar 9 at 2:43
w60w60
125
125
Can we assume that no exception is thrown in either case?
– jmcilhinney
Mar 9 at 2:49
@jmcilhinney That is correct.
– w60
Mar 9 at 2:51
2
By the way, if your are using a Windows FormsOpenFileDialog
andSaveFileDialog
then theShowDialog
method returns aDialogResult
value, not aBoolean
. You should be comparing toDialogResult.OK
rather than toTrue
. You should haveOption Strict On
, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.
– jmcilhinney
Mar 9 at 2:52
@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers
– w60
Mar 9 at 2:54
1
You should turnOption Strict On
in the project properties and you should also turn itOn
in the IDE options, so that it isOn
by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into theIf
block and at least indicate where you should be looking for the cause.
– jmcilhinney
Mar 9 at 3:01
add a comment |
Can we assume that no exception is thrown in either case?
– jmcilhinney
Mar 9 at 2:49
@jmcilhinney That is correct.
– w60
Mar 9 at 2:51
2
By the way, if your are using a Windows FormsOpenFileDialog
andSaveFileDialog
then theShowDialog
method returns aDialogResult
value, not aBoolean
. You should be comparing toDialogResult.OK
rather than toTrue
. You should haveOption Strict On
, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.
– jmcilhinney
Mar 9 at 2:52
@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers
– w60
Mar 9 at 2:54
1
You should turnOption Strict On
in the project properties and you should also turn itOn
in the IDE options, so that it isOn
by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into theIf
block and at least indicate where you should be looking for the cause.
– jmcilhinney
Mar 9 at 3:01
Can we assume that no exception is thrown in either case?
– jmcilhinney
Mar 9 at 2:49
Can we assume that no exception is thrown in either case?
– jmcilhinney
Mar 9 at 2:49
@jmcilhinney That is correct.
– w60
Mar 9 at 2:51
@jmcilhinney That is correct.
– w60
Mar 9 at 2:51
2
2
By the way, if your are using a Windows Forms
OpenFileDialog
and SaveFileDialog
then the ShowDialog
method returns a DialogResult
value, not a Boolean
. You should be comparing to DialogResult.OK
rather than to True
. You should have Option Strict On
, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.– jmcilhinney
Mar 9 at 2:52
By the way, if your are using a Windows Forms
OpenFileDialog
and SaveFileDialog
then the ShowDialog
method returns a DialogResult
value, not a Boolean
. You should be comparing to DialogResult.OK
rather than to True
. You should have Option Strict On
, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.– jmcilhinney
Mar 9 at 2:52
@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers
– w60
Mar 9 at 2:54
@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers
– w60
Mar 9 at 2:54
1
1
You should turn
Option Strict On
in the project properties and you should also turn it On
in the IDE options, so that it is On
by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If
block and at least indicate where you should be looking for the cause.– jmcilhinney
Mar 9 at 3:01
You should turn
Option Strict On
in the project properties and you should also turn it On
in the IDE options, so that it is On
by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If
block and at least indicate where you should be looking for the cause.– jmcilhinney
Mar 9 at 3:01
add a comment |
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Can we assume that no exception is thrown in either case?
– jmcilhinney
Mar 9 at 2:49
@jmcilhinney That is correct.
– w60
Mar 9 at 2:51
2
By the way, if your are using a Windows Forms
OpenFileDialog
andSaveFileDialog
then theShowDialog
method returns aDialogResult
value, not aBoolean
. You should be comparing toDialogResult.OK
rather than toTrue
. You should haveOption Strict On
, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.– jmcilhinney
Mar 9 at 2:52
@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers
– w60
Mar 9 at 2:54
1
You should turn
Option Strict On
in the project properties and you should also turn itOn
in the IDE options, so that it isOn
by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into theIf
block and at least indicate where you should be looking for the cause.– jmcilhinney
Mar 9 at 3:01