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BinaryWriter and BinaryReader not working in VB.NET


Is there a conditional ternary operator in VB.NET?IndexOutOfRangeException in VB.NETProblem in saving image to database from picturebox. VB.Net 2008. Framework 3.5Send Bulk Email in VB.NET Reciepients Emails will uploaded by excelVB .Net querying a SQL Server DB for average and getting “DS System.Data.DataSet”Fast throw unhandled exceptions in TPLVB.NET variable checkExecute Reader error on VB.net using MS ACCESS Database“Object reference not set to an instance of an object” when clearing a datatable with a checkboxhow can i Update access database from vb.net app






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-1















I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.



Here's the reader code:



Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


And here's the code for the writer:



Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.



Please help!
Thanks, w60










share|improve this question






















  • Can we assume that no exception is thrown in either case?

    – jmcilhinney
    Mar 9 at 2:49











  • @jmcilhinney That is correct.

    – w60
    Mar 9 at 2:51






  • 2





    By the way, if your are using a Windows Forms OpenFileDialog and SaveFileDialog then the ShowDialog method returns a DialogResult value, not a Boolean. You should be comparing to DialogResult.OK rather than to True. You should have Option Strict On, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.

    – jmcilhinney
    Mar 9 at 2:52











  • @jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers

    – w60
    Mar 9 at 2:54






  • 1





    You should turn Option Strict On in the project properties and you should also turn it On in the IDE options, so that it is On by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If block and at least indicate where you should be looking for the cause.

    – jmcilhinney
    Mar 9 at 3:01

















-1















I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.



Here's the reader code:



Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


And here's the code for the writer:



Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.



Please help!
Thanks, w60










share|improve this question






















  • Can we assume that no exception is thrown in either case?

    – jmcilhinney
    Mar 9 at 2:49











  • @jmcilhinney That is correct.

    – w60
    Mar 9 at 2:51






  • 2





    By the way, if your are using a Windows Forms OpenFileDialog and SaveFileDialog then the ShowDialog method returns a DialogResult value, not a Boolean. You should be comparing to DialogResult.OK rather than to True. You should have Option Strict On, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.

    – jmcilhinney
    Mar 9 at 2:52











  • @jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers

    – w60
    Mar 9 at 2:54






  • 1





    You should turn Option Strict On in the project properties and you should also turn it On in the IDE options, so that it is On by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If block and at least indicate where you should be looking for the cause.

    – jmcilhinney
    Mar 9 at 3:01













-1












-1








-1








I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.



Here's the reader code:



Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


And here's the code for the writer:



Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.



Please help!
Thanks, w60










share|improve this question














I'm making a program that reads and writes to .GRNT files, which is simply a custom file format I've made.



Here's the reader code:



Try
If ofd.ShowDialog() = True Then
Using br As New BinaryReader(File.Open(ofd.FileName, FileMode.Open))
txt.Text = br.ReadString
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


And here's the code for the writer:



Try
If sfd.ShowDialog() = True Then
Using bw As New BinaryWriter(File.Open(sfd.FileName, FileMode.Create))
bw.Write(txt.Text)
End Using
End If
Catch ex As Exception
MsgBox(ex.Message)
End Try


As you can see, very similar code, just changed a bit for the corresponding actions.
However, when I try to save or open a file, nothing shows up in the program's text field, and nothing is written to the directory.



Please help!
Thanks, w60







vb.net






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 9 at 2:43









w60w60

125




125












  • Can we assume that no exception is thrown in either case?

    – jmcilhinney
    Mar 9 at 2:49











  • @jmcilhinney That is correct.

    – w60
    Mar 9 at 2:51






  • 2





    By the way, if your are using a Windows Forms OpenFileDialog and SaveFileDialog then the ShowDialog method returns a DialogResult value, not a Boolean. You should be comparing to DialogResult.OK rather than to True. You should have Option Strict On, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.

    – jmcilhinney
    Mar 9 at 2:52











  • @jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers

    – w60
    Mar 9 at 2:54






  • 1





    You should turn Option Strict On in the project properties and you should also turn it On in the IDE options, so that it is On by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If block and at least indicate where you should be looking for the cause.

    – jmcilhinney
    Mar 9 at 3:01

















  • Can we assume that no exception is thrown in either case?

    – jmcilhinney
    Mar 9 at 2:49











  • @jmcilhinney That is correct.

    – w60
    Mar 9 at 2:51






  • 2





    By the way, if your are using a Windows Forms OpenFileDialog and SaveFileDialog then the ShowDialog method returns a DialogResult value, not a Boolean. You should be comparing to DialogResult.OK rather than to True. You should have Option Strict On, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.

    – jmcilhinney
    Mar 9 at 2:52











  • @jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers

    – w60
    Mar 9 at 2:54






  • 1





    You should turn Option Strict On in the project properties and you should also turn it On in the IDE options, so that it is On by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If block and at least indicate where you should be looking for the cause.

    – jmcilhinney
    Mar 9 at 3:01
















Can we assume that no exception is thrown in either case?

– jmcilhinney
Mar 9 at 2:49





Can we assume that no exception is thrown in either case?

– jmcilhinney
Mar 9 at 2:49













@jmcilhinney That is correct.

– w60
Mar 9 at 2:51





@jmcilhinney That is correct.

– w60
Mar 9 at 2:51




2




2





By the way, if your are using a Windows Forms OpenFileDialog and SaveFileDialog then the ShowDialog method returns a DialogResult value, not a Boolean. You should be comparing to DialogResult.OK rather than to True. You should have Option Strict On, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.

– jmcilhinney
Mar 9 at 2:52





By the way, if your are using a Windows Forms OpenFileDialog and SaveFileDialog then the ShowDialog method returns a DialogResult value, not a Boolean. You should be comparing to DialogResult.OK rather than to True. You should have Option Strict On, in which case that code wouldn't even compile. I'm not sure whether that is the source of your issue but it is certainly something to fix.

– jmcilhinney
Mar 9 at 2:52













@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers

– w60
Mar 9 at 2:54





@jmcilhinney That was the problem, which is weird because the method I was using had worked other times. Oh well, I guess I can remember this for next time. Thanks and cheers

– w60
Mar 9 at 2:54




1




1





You should turn Option Strict On in the project properties and you should also turn it On in the IDE options, so that it is On by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If block and at least indicate where you should be looking for the cause.

– jmcilhinney
Mar 9 at 3:01





You should turn Option Strict On in the project properties and you should also turn it On in the IDE options, so that it is On by default in future projects. The compiler will then flag issues like this. You should also learn how to debug your code, i.e. set breakpoints and step through the code while you examine state. Doing so in this case would have shown you that you weren't even getting into the If block and at least indicate where you should be looking for the cause.

– jmcilhinney
Mar 9 at 3:01












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