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0

I'm working on a program that should convert a user inputted floating point number to an integer, I got it to work but only for floating point numbers that don't have a fractional part that exceeds 2^-1, which is obviously 1/2. It'll work for numbers like 75.5 or 2.5, but not a number like 75.625. I need to keep the code in this format, but I am not sure what I should make the program shift left and right (around the hashtags) by to cancel out the fractional part regardless of what the fractional part is.

.data
 Prompt: .asciiz "n Please Input a value for the float N = "
 result1: .asciiz " The converted N is "
.text
 li $v0, 4 # system call code for Print String
 la $a0, Prompt # loads address of prompt into $a0
 syscall # print the message in Prompt
 li $v0, 6 # System call code for Read Float
 syscall # read whatever you input float as 
 mfc1 $t1, $f0 # Stores the float value into the $t1
 srl $t2, $t1, 23 # srl by 23 to leave out the biased exponent and store it 
 in $t2
 add $s3, $t2, -127 # Subtract 127 to get the exponent
 sll $t4, $t1, 9 # Shift left and right by 9 to remove the exponent
 srl $t5, $t4, 9 
 addi $t6, $t5, 8388608 # Add the implied bit (2^24)
 add $t7, $s3, 9 # Add 9 to the exponent value
 sllv $s4, $t6, $t7 # Shifts the implied bit to 2^32 (32nd bit)
 ###########################
 rol $s5, $t6, $t7 #rotate to the left by whatever the exponent + 9 is to 
 get 
 the integer part of the number to the first few bits
 sll $s5, $s5, 1
 srl $s5, $s5, 1 # sll and srl cancels out the fractional part #should be 
 1001011 #s5 is the newly converted integer
 ######################
 li $v0, 4 # Tells computer to get ready to print a .asciiz number
 la $a0, result1
 syscall
 li $v0, 1 # Tells computer to get ready to print the converted integer 
 number
 move $a0, $s5 # Moves the contents of $s5 to %a0 so it can be called
 syscall # Returns the integer

mips

share|improve this question

edited Mar 9 at 5:43

Lost Soul

asked Mar 9 at 2:37

Lost SoulLost Soul

357

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Usually you would just use a cvt.w.s or cvt.w.d instruction to convert a float (or double) to integer...
  
  – Chris Dodd
  Mar 9 at 4:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I can't use conversion instructions. I wish it were that easy haha
  
  – Lost Soul
  Mar 9 at 5:00
  
  

  
  
  
  

add a comment | 

0

I'm working on a program that should convert a user inputted floating point number to an integer, I got it to work but only for floating point numbers that don't have a fractional part that exceeds 2^-1, which is obviously 1/2. It'll work for numbers like 75.5 or 2.5, but not a number like 75.625. I need to keep the code in this format, but I am not sure what I should make the program shift left and right (around the hashtags) by to cancel out the fractional part regardless of what the fractional part is.

.data
 Prompt: .asciiz "n Please Input a value for the float N = "
 result1: .asciiz " The converted N is "
.text
 li $v0, 4 # system call code for Print String
 la $a0, Prompt # loads address of prompt into $a0
 syscall # print the message in Prompt
 li $v0, 6 # System call code for Read Float
 syscall # read whatever you input float as 
 mfc1 $t1, $f0 # Stores the float value into the $t1
 srl $t2, $t1, 23 # srl by 23 to leave out the biased exponent and store it 
 in $t2
 add $s3, $t2, -127 # Subtract 127 to get the exponent
 sll $t4, $t1, 9 # Shift left and right by 9 to remove the exponent
 srl $t5, $t4, 9 
 addi $t6, $t5, 8388608 # Add the implied bit (2^24)
 add $t7, $s3, 9 # Add 9 to the exponent value
 sllv $s4, $t6, $t7 # Shifts the implied bit to 2^32 (32nd bit)
 ###########################
 rol $s5, $t6, $t7 #rotate to the left by whatever the exponent + 9 is to 
 get 
 the integer part of the number to the first few bits
 sll $s5, $s5, 1
 srl $s5, $s5, 1 # sll and srl cancels out the fractional part #should be 
 1001011 #s5 is the newly converted integer
 ######################
 li $v0, 4 # Tells computer to get ready to print a .asciiz number
 la $a0, result1
 syscall
 li $v0, 1 # Tells computer to get ready to print the converted integer 
 number
 move $a0, $s5 # Moves the contents of $s5 to %a0 so it can be called
 syscall # Returns the integer

mips

share|improve this question

edited Mar 9 at 5:43

Lost Soul

asked Mar 9 at 2:37

Lost SoulLost Soul

357

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Usually you would just use a cvt.w.s or cvt.w.d instruction to convert a float (or double) to integer...
  
  – Chris Dodd
  Mar 9 at 4:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I can't use conversion instructions. I wish it were that easy haha
  
  – Lost Soul
  Mar 9 at 5:00
  
  

  
  
  
  

add a comment | 

I'm working on a program that should convert a user inputted floating point number to an integer, I got it to work but only for floating point numbers that don't have a fractional part that exceeds 2^-1, which is obviously 1/2. It'll work for numbers like 75.5 or 2.5, but not a number like 75.625. I need to keep the code in this format, but I am not sure what I should make the program shift left and right (around the hashtags) by to cancel out the fractional part regardless of what the fractional part is.

.data
 Prompt: .asciiz "n Please Input a value for the float N = "
 result1: .asciiz " The converted N is "
.text
 li $v0, 4 # system call code for Print String
 la $a0, Prompt # loads address of prompt into $a0
 syscall # print the message in Prompt
 li $v0, 6 # System call code for Read Float
 syscall # read whatever you input float as 
 mfc1 $t1, $f0 # Stores the float value into the $t1
 srl $t2, $t1, 23 # srl by 23 to leave out the biased exponent and store it 
 in $t2
 add $s3, $t2, -127 # Subtract 127 to get the exponent
 sll $t4, $t1, 9 # Shift left and right by 9 to remove the exponent
 srl $t5, $t4, 9 
 addi $t6, $t5, 8388608 # Add the implied bit (2^24)
 add $t7, $s3, 9 # Add 9 to the exponent value
 sllv $s4, $t6, $t7 # Shifts the implied bit to 2^32 (32nd bit)
 ###########################
 rol $s5, $t6, $t7 #rotate to the left by whatever the exponent + 9 is to 
 get 
 the integer part of the number to the first few bits
 sll $s5, $s5, 1
 srl $s5, $s5, 1 # sll and srl cancels out the fractional part #should be 
 1001011 #s5 is the newly converted integer
 ######################
 li $v0, 4 # Tells computer to get ready to print a .asciiz number
 la $a0, result1
 syscall
 li $v0, 1 # Tells computer to get ready to print the converted integer 
 number
 move $a0, $s5 # Moves the contents of $s5 to %a0 so it can be called
 syscall # Returns the integer

mips

share|improve this question

edited Mar 9 at 5:43

Lost Soul

asked Mar 9 at 2:37

Lost SoulLost Soul

357

.data
 Prompt: .asciiz "n Please Input a value for the float N = "
 result1: .asciiz " The converted N is "
.text
 li $v0, 4 # system call code for Print String
 la $a0, Prompt # loads address of prompt into $a0
 syscall # print the message in Prompt
 li $v0, 6 # System call code for Read Float
 syscall # read whatever you input float as 
 mfc1 $t1, $f0 # Stores the float value into the $t1
 srl $t2, $t1, 23 # srl by 23 to leave out the biased exponent and store it 
 in $t2
 add $s3, $t2, -127 # Subtract 127 to get the exponent
 sll $t4, $t1, 9 # Shift left and right by 9 to remove the exponent
 srl $t5, $t4, 9 
 addi $t6, $t5, 8388608 # Add the implied bit (2^24)
 add $t7, $s3, 9 # Add 9 to the exponent value
 sllv $s4, $t6, $t7 # Shifts the implied bit to 2^32 (32nd bit)
 ###########################
 rol $s5, $t6, $t7 #rotate to the left by whatever the exponent + 9 is to 
 get 
 the integer part of the number to the first few bits
 sll $s5, $s5, 1
 srl $s5, $s5, 1 # sll and srl cancels out the fractional part #should be 
 1001011 #s5 is the newly converted integer
 ######################
 li $v0, 4 # Tells computer to get ready to print a .asciiz number
 la $a0, result1
 syscall
 li $v0, 1 # Tells computer to get ready to print the converted integer 
 number
 move $a0, $s5 # Moves the contents of $s5 to %a0 so it can be called
 syscall # Returns the integer

share|improve this question

edited Mar 9 at 5:43

Lost Soul

asked Mar 9 at 2:37

Lost SoulLost Soul

357

share|improve this question

edited Mar 9 at 5:43

Lost Soul

asked Mar 9 at 2:37

Lost SoulLost Soul

357

asked Mar 9 at 2:37

Lost SoulLost Soul

357

asked Mar 9 at 2:37

Lost SoulLost Soul

357