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0

I want to change the value of _"ans"_ in every condition of this script:

main()
 char in;
 int ans=0;
 printf ("Enter character");
 scanf ("%c",&in);
 if (in == '+' && in == '/' && in == '*' && in == '-')
 ans=10;
 

How do I do that?

c

share|improve this question

edited Mar 8 at 5:17

Emma

1,0271819

asked Mar 8 at 1:55

SaurabhSaurabh

6012

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  You want to replace && with ||.
  
  – William Pursell
  Mar 8 at 1:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The next class will teach you with the || (or) operator.
  
  – Geno Chen
  Mar 8 at 1:59
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  if is not a function. It is a conditional statement. en.wikipedia.org/wiki/…
  
  – Pablo
  Mar 8 at 2:03
  
  

  
  
  
  

add a comment | 

0

I want to change the value of _"ans"_ in every condition of this script:

main()
 char in;
 int ans=0;
 printf ("Enter character");
 scanf ("%c",&in);
 if (in == '+' && in == '/' && in == '*' && in == '-')
 ans=10;
 

How do I do that?

c

share|improve this question

edited Mar 8 at 5:17

Emma

1,0271819

asked Mar 8 at 1:55

SaurabhSaurabh

6012

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  You want to replace && with ||.
  
  – William Pursell
  Mar 8 at 1:58
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The next class will teach you with the || (or) operator.
  
  – Geno Chen
  Mar 8 at 1:59
  

  
  
  
  


• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  if is not a function. It is a conditional statement. en.wikipedia.org/wiki/…
  
  – Pablo
  Mar 8 at 2:03
  
  

  
  
  
  

add a comment | 

I want to change the value of _"ans"_ in every condition of this script:

main()
 char in;
 int ans=0;
 printf ("Enter character");
 scanf ("%c",&in);
 if (in == '+' && in == '/' && in == '*' && in == '-')
 ans=10;
 

How do I do that?

c

share|improve this question

edited Mar 8 at 5:17

Emma

1,0271819

asked Mar 8 at 1:55

SaurabhSaurabh

6012

main()
 char in;
 int ans=0;
 printf ("Enter character");
 scanf ("%c",&in);
 if (in == '+' && in == '/' && in == '*' && in == '-')
 ans=10;
 

share|improve this question

edited Mar 8 at 5:17

Emma

1,0271819

asked Mar 8 at 1:55

SaurabhSaurabh

6012

share|improve this question

edited Mar 8 at 5:17

Emma

1,0271819

asked Mar 8 at 1:55

SaurabhSaurabh

6012

edited Mar 8 at 5:17

Emma

1,0271819

edited Mar 8 at 5:17

Emma

1,0271819

asked Mar 8 at 1:55

SaurabhSaurabh

6012

asked Mar 8 at 1:55

SaurabhSaurabh

6012

2 Answers
2

active

oldest

votes

5

if (A && B)… does not mean:

• do this if A is true, and


• do this if B is true.

It means:

• do this if A is true and B is true.

To make a condition so the if is triggered if A is true and is triggered if B is true, you use A || B. This means:

• do this if A is true or B is true.

share|improve this answer

answered Mar 8 at 2:00

Eric PostpischilEric Postpischil

78.9k886166

add a comment | 

2

In the end, you'll probably want a switch case.

main()

 char in;
 int ans=10;
 printf ("Enter character");
 scanf ("%c",&in);
 switch(in)
 case '+':
 ans=ans+10;
 break;
 case '-':
 ans=ans-10;
 break;
 case '/':
 ans=ans/10;
 break;
 case '*':
 ans=ans*10;
 break;

 

Further steps in the exercise are probably going to be to parse the input factors to the calculations as well, rather than just multiplying static ans with 10.

share|improve this answer

edited Mar 20 at 0:33

answered Mar 8 at 2:03

visiblemanvisibleman

1,694820

add a comment | 

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5

if (A && B)… does not mean:

• do this if A is true, and


• do this if B is true.

It means:

• do this if A is true and B is true.

To make a condition so the if is triggered if A is true and is triggered if B is true, you use A || B. This means:

• do this if A is true or B is true.

share|improve this answer

answered Mar 8 at 2:00

Eric PostpischilEric Postpischil

78.9k886166

add a comment | 

5

if (A && B)… does not mean:

• do this if A is true, and


• do this if B is true.

It means:

• do this if A is true and B is true.

To make a condition so the if is triggered if A is true and is triggered if B is true, you use A || B. This means:

• do this if A is true or B is true.

share|improve this answer

answered Mar 8 at 2:00

Eric PostpischilEric Postpischil

78.9k886166

add a comment | 

if (A && B)… does not mean:

• do this if A is true, and


• do this if B is true.

It means:

• do this if A is true and B is true.

To make a condition so the if is triggered if A is true and is triggered if B is true, you use A || B. This means:

• do this if A is true or B is true.

share|improve this answer

answered Mar 8 at 2:00

Eric PostpischilEric Postpischil

78.9k886166

share|improve this answer

answered Mar 8 at 2:00

Eric PostpischilEric Postpischil

78.9k886166

answered Mar 8 at 2:00

Eric PostpischilEric Postpischil

78.9k886166

answered Mar 8 at 2:00

Eric PostpischilEric Postpischil

78.9k886166

2

In the end, you'll probably want a switch case.

main()

 char in;
 int ans=10;
 printf ("Enter character");
 scanf ("%c",&in);
 switch(in)
 case '+':
 ans=ans+10;
 break;
 case '-':
 ans=ans-10;
 break;
 case '/':
 ans=ans/10;
 break;
 case '*':
 ans=ans*10;
 break;

 

Further steps in the exercise are probably going to be to parse the input factors to the calculations as well, rather than just multiplying static ans with 10.

share|improve this answer

edited Mar 20 at 0:33

answered Mar 8 at 2:03

visiblemanvisibleman

1,694820

add a comment | 

2

In the end, you'll probably want a switch case.

main()

 char in;
 int ans=10;
 printf ("Enter character");
 scanf ("%c",&in);
 switch(in)
 case '+':
 ans=ans+10;
 break;
 case '-':
 ans=ans-10;
 break;
 case '/':
 ans=ans/10;
 break;
 case '*':
 ans=ans*10;
 break;

 

Further steps in the exercise are probably going to be to parse the input factors to the calculations as well, rather than just multiplying static ans with 10.

share|improve this answer

edited Mar 20 at 0:33

answered Mar 8 at 2:03

visiblemanvisibleman

1,694820

add a comment | 

In the end, you'll probably want a switch case.

main()

 char in;
 int ans=10;
 printf ("Enter character");
 scanf ("%c",&in);
 switch(in)
 case '+':
 ans=ans+10;
 break;
 case '-':
 ans=ans-10;
 break;
 case '/':
 ans=ans/10;
 break;
 case '*':
 ans=ans*10;
 break;

 

Further steps in the exercise are probably going to be to parse the input factors to the calculations as well, rather than just multiplying static ans with 10.

share|improve this answer

edited Mar 20 at 0:33

answered Mar 8 at 2:03

visiblemanvisibleman

1,694820

main()

 char in;
 int ans=10;
 printf ("Enter character");
 scanf ("%c",&in);
 switch(in)
 case '+':
 ans=ans+10;
 break;
 case '-':
 ans=ans-10;
 break;
 case '/':
 ans=ans/10;
 break;
 case '*':
 ans=ans*10;
 break;

 

share|improve this answer

edited Mar 20 at 0:33

answered Mar 8 at 2:03

visiblemanvisibleman

1,694820

answered Mar 8 at 2:03

visiblemanvisibleman

1,694820

answered Mar 8 at 2:03

visiblemanvisibleman

1,694820