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I need to replace one cell with another in pandas dataframe


Converting a Pandas GroupBy object to DataFrameRenaming columns in pandasAdding new column to existing DataFrame in Python pandasDelete column from pandas DataFrame by column nameCreating an empty Pandas DataFrame, then filling it?Set value for particular cell in pandas DataFrame using index“Large data” work flows using pandasHow do I get the row count of a Pandas dataframe?How to iterate over rows in a DataFrame in Pandas?Select rows from a DataFrame based on values in a column in pandas













-1















I want to replace one cell of a row with another cell of same row in pandas data frameenter image description here










share|improve this question
























  • Historie will be replace by ''1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.''

    – zatskumar
    Feb 21 at 9:42











  • and '' 1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.'' will be replace by Stuttgart

    – zatskumar
    Feb 21 at 9:42















-1















I want to replace one cell of a row with another cell of same row in pandas data frameenter image description here










share|improve this question
























  • Historie will be replace by ''1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.''

    – zatskumar
    Feb 21 at 9:42











  • and '' 1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.'' will be replace by Stuttgart

    – zatskumar
    Feb 21 at 9:42













-1












-1








-1








I want to replace one cell of a row with another cell of same row in pandas data frameenter image description here










share|improve this question
















I want to replace one cell of a row with another cell of same row in pandas data frameenter image description here







python-3.x pandas






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 8 at 2:17









Scott Boston

56.9k73158




56.9k73158










asked Feb 21 at 9:39









zatskumarzatskumar

144




144












  • Historie will be replace by ''1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.''

    – zatskumar
    Feb 21 at 9:42











  • and '' 1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.'' will be replace by Stuttgart

    – zatskumar
    Feb 21 at 9:42

















  • Historie will be replace by ''1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.''

    – zatskumar
    Feb 21 at 9:42











  • and '' 1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.'' will be replace by Stuttgart

    – zatskumar
    Feb 21 at 9:42
















Historie will be replace by ''1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.''

– zatskumar
Feb 21 at 9:42





Historie will be replace by ''1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.''

– zatskumar
Feb 21 at 9:42













and '' 1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.'' will be replace by Stuttgart

– zatskumar
Feb 21 at 9:42





and '' 1.) "Verein Technologietransfer Handwerk" (Stiftung Adalbert- Seifriz-Preis) e.V.'' will be replace by Stuttgart

– zatskumar
Feb 21 at 9:42












1 Answer
1






active

oldest

votes


















0














This can solve your specific problem:



df.iloc[4,3] = df.iloc[4,2]
df.iloc[4,2] = df.iloc[4,1]


Cannot say more without knowing what you're actually trying to do






share|improve this answer























  • thank you so much. I finally figure it out. But having another problem . In my data frame I have different city name, Like: 'Stittgart', Munich...etc. Some of the city are like '1) Stuttgart' that. I have use this code for x in prep_table1['Sitz']: list_x = x.split(')') if len(list_x) == 1: prep_table1['New_sitz'] = list_x[0] elif len(list_x) == 2: prep_table1['New_sitz'] = list_x[1] else: prep_table1['New_sitz'] = list_x[2] but it only filled with 'March'. By the way last row has 1.) March. How can I solve this prob.

    – zatskumar
    Feb 21 at 12:00











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














This can solve your specific problem:



df.iloc[4,3] = df.iloc[4,2]
df.iloc[4,2] = df.iloc[4,1]


Cannot say more without knowing what you're actually trying to do






share|improve this answer























  • thank you so much. I finally figure it out. But having another problem . In my data frame I have different city name, Like: 'Stittgart', Munich...etc. Some of the city are like '1) Stuttgart' that. I have use this code for x in prep_table1['Sitz']: list_x = x.split(')') if len(list_x) == 1: prep_table1['New_sitz'] = list_x[0] elif len(list_x) == 2: prep_table1['New_sitz'] = list_x[1] else: prep_table1['New_sitz'] = list_x[2] but it only filled with 'March'. By the way last row has 1.) March. How can I solve this prob.

    – zatskumar
    Feb 21 at 12:00
















0














This can solve your specific problem:



df.iloc[4,3] = df.iloc[4,2]
df.iloc[4,2] = df.iloc[4,1]


Cannot say more without knowing what you're actually trying to do






share|improve this answer























  • thank you so much. I finally figure it out. But having another problem . In my data frame I have different city name, Like: 'Stittgart', Munich...etc. Some of the city are like '1) Stuttgart' that. I have use this code for x in prep_table1['Sitz']: list_x = x.split(')') if len(list_x) == 1: prep_table1['New_sitz'] = list_x[0] elif len(list_x) == 2: prep_table1['New_sitz'] = list_x[1] else: prep_table1['New_sitz'] = list_x[2] but it only filled with 'March'. By the way last row has 1.) March. How can I solve this prob.

    – zatskumar
    Feb 21 at 12:00














0












0








0







This can solve your specific problem:



df.iloc[4,3] = df.iloc[4,2]
df.iloc[4,2] = df.iloc[4,1]


Cannot say more without knowing what you're actually trying to do






share|improve this answer













This can solve your specific problem:



df.iloc[4,3] = df.iloc[4,2]
df.iloc[4,2] = df.iloc[4,1]


Cannot say more without knowing what you're actually trying to do







share|improve this answer












share|improve this answer



share|improve this answer










answered Feb 21 at 10:42









ArpanArpan

615




615












  • thank you so much. I finally figure it out. But having another problem . In my data frame I have different city name, Like: 'Stittgart', Munich...etc. Some of the city are like '1) Stuttgart' that. I have use this code for x in prep_table1['Sitz']: list_x = x.split(')') if len(list_x) == 1: prep_table1['New_sitz'] = list_x[0] elif len(list_x) == 2: prep_table1['New_sitz'] = list_x[1] else: prep_table1['New_sitz'] = list_x[2] but it only filled with 'March'. By the way last row has 1.) March. How can I solve this prob.

    – zatskumar
    Feb 21 at 12:00


















  • thank you so much. I finally figure it out. But having another problem . In my data frame I have different city name, Like: 'Stittgart', Munich...etc. Some of the city are like '1) Stuttgart' that. I have use this code for x in prep_table1['Sitz']: list_x = x.split(')') if len(list_x) == 1: prep_table1['New_sitz'] = list_x[0] elif len(list_x) == 2: prep_table1['New_sitz'] = list_x[1] else: prep_table1['New_sitz'] = list_x[2] but it only filled with 'March'. By the way last row has 1.) March. How can I solve this prob.

    – zatskumar
    Feb 21 at 12:00

















thank you so much. I finally figure it out. But having another problem . In my data frame I have different city name, Like: 'Stittgart', Munich...etc. Some of the city are like '1) Stuttgart' that. I have use this code for x in prep_table1['Sitz']: list_x = x.split(')') if len(list_x) == 1: prep_table1['New_sitz'] = list_x[0] elif len(list_x) == 2: prep_table1['New_sitz'] = list_x[1] else: prep_table1['New_sitz'] = list_x[2] but it only filled with 'March'. By the way last row has 1.) March. How can I solve this prob.

– zatskumar
Feb 21 at 12:00






thank you so much. I finally figure it out. But having another problem . In my data frame I have different city name, Like: 'Stittgart', Munich...etc. Some of the city are like '1) Stuttgart' that. I have use this code for x in prep_table1['Sitz']: list_x = x.split(')') if len(list_x) == 1: prep_table1['New_sitz'] = list_x[0] elif len(list_x) == 2: prep_table1['New_sitz'] = list_x[1] else: prep_table1['New_sitz'] = list_x[2] but it only filled with 'March'. By the way last row has 1.) March. How can I solve this prob.

– zatskumar
Feb 21 at 12:00




















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