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find: list date and size without using -printf


How do I get current datetime on the Windows command line, in a suitable format for using in a filename?Use grep --exclude/--include syntax to not grep through certain filesUsing ls to list directories and their total sizesHow to exclude a directory in find . commandGiven two directory trees, how can I find out which files differ?How to recursively find and list the latest modified files in a directory with subdirectories and times?How can I recursively find all files in current and subfolders based on wildcard matching?How do I find all files containing specific text on Linux?How to get the current date and time in the terminal and set a custom command in terminal for it?How to display modified date time with 'find' command?













0















Is there a way to do the following without using the -printf option, which I don't have?



find . -printf "%p (%s, %Tb %Td %TY %TH:%TM)n"


Basically I want the size and date/time to be listed alongside the names.



A sample output of the following structure:



 .
 |-one
 |-two
 | |-two_2
 | |-two_1
 |-test_file


would be:



. (4096, Mar 06 2019 16:38)
./one (4096, Mar 06 2019 16:37)
./two (4096, Mar 06 2019 16:38)
./two/two_2 (4096, Mar 06 2019 16:38)
./two/two_1 (4096, Mar 06 2019 16:38)
./test_file (0, Mar 06 2019 16:38)





linux command-line grep find







share|improve this question


























    0















    Is there a way to do the following without using the -printf option, which I don't have?



    find . -printf "%p (%s, %Tb %Td %TY %TH:%TM)n"


    Basically I want the size and date/time to be listed alongside the names.



    A sample output of the following structure:



     .
     |-one
     |-two
     | |-two_2
     | |-two_1
     |-test_file


    would be:



    . (4096, Mar 06 2019 16:38)
    ./one (4096, Mar 06 2019 16:37)
    ./two (4096, Mar 06 2019 16:38)
    ./two/two_2 (4096, Mar 06 2019 16:38)
    ./two/two_1 (4096, Mar 06 2019 16:38)
    ./test_file (0, Mar 06 2019 16:38)





    linux command-line grep find







    share|improve this question
























      0












      0








      0








      Is there a way to do the following without using the -printf option, which I don't have?



      find . -printf "%p (%s, %Tb %Td %TY %TH:%TM)n"


      Basically I want the size and date/time to be listed alongside the names.



      A sample output of the following structure:



       .
       |-one
       |-two
       | |-two_2
       | |-two_1
       |-test_file


      would be:



      . (4096, Mar 06 2019 16:38)
      ./one (4096, Mar 06 2019 16:37)
      ./two (4096, Mar 06 2019 16:38)
      ./two/two_2 (4096, Mar 06 2019 16:38)
      ./two/two_1 (4096, Mar 06 2019 16:38)
      ./test_file (0, Mar 06 2019 16:38)





      linux command-line grep find







      share|improve this question














      Is there a way to do the following without using the -printf option, which I don't have?



      find . -printf "%p (%s, %Tb %Td %TY %TH:%TM)n"


      Basically I want the size and date/time to be listed alongside the names.



      A sample output of the following structure:



       .
       |-one
       |-two
       | |-two_2
       | |-two_1
       |-test_file


      would be:



      . (4096, Mar 06 2019 16:38)
      ./one (4096, Mar 06 2019 16:37)
      ./two (4096, Mar 06 2019 16:38)
      ./two/two_2 (4096, Mar 06 2019 16:38)
      ./two/two_1 (4096, Mar 06 2019 16:38)
      ./test_file (0, Mar 06 2019 16:38)





      linux command-line grep find




      linux command-line grep find






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 8 at 2:15









      JobsJobs

      1,75721235




      1,75721235






















          1 Answer
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          0














          I've figured it out.



          -exec stat


          could be used instead to get size and date info.



          find . -type f -exec stat -c '%n (%z , %A , %s)' + | sed -
          e s'/.000000000//'g


          This is useful when the -printf option is not available.






          share|improve this answer






















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            1 Answer
            1






            active

            oldest

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            active

            oldest

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            active

            oldest

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            0














            I've figured it out.



            -exec stat


            could be used instead to get size and date info.



            find . -type f -exec stat -c '%n (%z , %A , %s)' + | sed -
            e s'/.000000000//'g


            This is useful when the -printf option is not available.






            share|improve this answer



























              0














              I've figured it out.



              -exec stat


              could be used instead to get size and date info.



              find . -type f -exec stat -c '%n (%z , %A , %s)' + | sed -
              e s'/.000000000//'g


              This is useful when the -printf option is not available.






              share|improve this answer

























                0












                0








                0







                I've figured it out.



                -exec stat


                could be used instead to get size and date info.



                find . -type f -exec stat -c '%n (%z , %A , %s)' + | sed -
                e s'/.000000000//'g


                This is useful when the -printf option is not available.






                share|improve this answer













                I've figured it out.



                -exec stat


                could be used instead to get size and date info.



                find . -type f -exec stat -c '%n (%z , %A , %s)' + | sed -
                e s'/.000000000//'g


                This is useful when the -printf option is not available.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 9 at 21:13









                JobsJobs

                1,75721235




                1,75721235





























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