Merge (join) data frames - too many rows in resultLeft joining two tables with identical keysHow to join (merge) data frames (inner, outer, left, right)?Left join only selected columns in R with the merge() functionSubset of a data frame including elements of another data frame at the specified columnsR - Merge 2 data frames with one column being differentMerge returns duplicate rowsMerge two python pandas data frames of different length but keep all rows in output data frameMerging multiple data frames in a loopMerge two data.frames where one of the data frame contain an extra rowPython:merge data frame with different rowsMerging rows from two data frames in pairs

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Merge (join) data frames - too many rows in result


Left joining two tables with identical keysHow to join (merge) data frames (inner, outer, left, right)?Left join only selected columns in R with the merge() functionSubset of a data frame including elements of another data frame at the specified columnsR - Merge 2 data frames with one column being differentMerge returns duplicate rowsMerge two python pandas data frames of different length but keep all rows in output data frameMerging multiple data frames in a loopMerge two data.frames where one of the data frame contain an extra rowPython:merge data frame with different rowsMerging rows from two data frames in pairs













-1















I have two data frames(df1 and df2). I want to join them using merge function.



df1 has 3903 rows and df2 has 351 rows.



I want to left join df2 to df1 by a common column(column1). I am using merge function.



My code is like below:



dfjoin<-merge(df1,df2, by="column1",all.x=TRUE)


So I expect dfjoin has 3903 rows equal to rows of df1. However it returns 4010 rows.



Why does it return more rows than expected. I will be very glad for any help. Thanks a lot.










share|improve this question



















  • 1





    This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.

    – RDizzl3
    Mar 12 '16 at 10:12












  • Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!

    – RDizzl3
    Mar 12 '16 at 10:16











  • not reproducible

    – jangorecki
    Mar 12 '16 at 12:05















-1















I have two data frames(df1 and df2). I want to join them using merge function.



df1 has 3903 rows and df2 has 351 rows.



I want to left join df2 to df1 by a common column(column1). I am using merge function.



My code is like below:



dfjoin<-merge(df1,df2, by="column1",all.x=TRUE)


So I expect dfjoin has 3903 rows equal to rows of df1. However it returns 4010 rows.



Why does it return more rows than expected. I will be very glad for any help. Thanks a lot.










share|improve this question



















  • 1





    This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.

    – RDizzl3
    Mar 12 '16 at 10:12












  • Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!

    – RDizzl3
    Mar 12 '16 at 10:16











  • not reproducible

    – jangorecki
    Mar 12 '16 at 12:05













-1












-1








-1


1






I have two data frames(df1 and df2). I want to join them using merge function.



df1 has 3903 rows and df2 has 351 rows.



I want to left join df2 to df1 by a common column(column1). I am using merge function.



My code is like below:



dfjoin<-merge(df1,df2, by="column1",all.x=TRUE)


So I expect dfjoin has 3903 rows equal to rows of df1. However it returns 4010 rows.



Why does it return more rows than expected. I will be very glad for any help. Thanks a lot.










share|improve this question
















I have two data frames(df1 and df2). I want to join them using merge function.



df1 has 3903 rows and df2 has 351 rows.



I want to left join df2 to df1 by a common column(column1). I am using merge function.



My code is like below:



dfjoin<-merge(df1,df2, by="column1",all.x=TRUE)


So I expect dfjoin has 3903 rows equal to rows of df1. However it returns 4010 rows.



Why does it return more rows than expected. I will be very glad for any help. Thanks a lot.







r merge






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jul 31 '18 at 0:33









Gregor

67.1k1095179




67.1k1095179










asked Mar 12 '16 at 9:51









oercimoercim

7002620




7002620







  • 1





    This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.

    – RDizzl3
    Mar 12 '16 at 10:12












  • Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!

    – RDizzl3
    Mar 12 '16 at 10:16











  • not reproducible

    – jangorecki
    Mar 12 '16 at 12:05












  • 1





    This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.

    – RDizzl3
    Mar 12 '16 at 10:12












  • Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!

    – RDizzl3
    Mar 12 '16 at 10:16











  • not reproducible

    – jangorecki
    Mar 12 '16 at 12:05







1




1





This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.

– RDizzl3
Mar 12 '16 at 10:12






This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.

– RDizzl3
Mar 12 '16 at 10:12














Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!

– RDizzl3
Mar 12 '16 at 10:16





Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!

– RDizzl3
Mar 12 '16 at 10:16













not reproducible

– jangorecki
Mar 12 '16 at 12:05





not reproducible

– jangorecki
Mar 12 '16 at 12:05












3 Answers
3






active

oldest

votes


















1














This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.



Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!






share|improve this answer























  • Thanks a lt RDizzl3. As you said the tables were not one to one mapping.

    – oercim
    Mar 12 '16 at 23:46


















1














I can't be sure without seeing an example of your problem, but usually the syntax is:



df <- merge(df1, df2, by.all="name_of_column_in_common", all.x=T)


However, if the columns you are matching on have duplicated values, r will match all possible combinations. So,



df1 <- data.frame(id=c("a","a","b","c"), x1=rnorm(4))
df2 <- data.frame(id=c("a","a","b"), x2=rnorm(3))
df <- merge(df1, df2, by.all="id", all.x=T)


Will give you a df of dimensions 6 by 3, as each "a" in df2 has been matched to each "a" in df1, 2 by 2 for 4 permutations.






share|improve this answer






























    0














    To make sure that your second data frame is unique on the join column(s), you can use my package safejoin (a wrapper around dplyr's join functions) which will give you an explicit error if it's not the case.



    Current situation :



    df1 <- data.frame(column1 = c("a","b","b"), X = 1:3)
    df2 <- data.frame(column1 = c("a","b"), Y = 4:5)
    df3 <- data.frame(column1 = c("a","a","b"), Y = 4:6)

    merge(df1,df2, by="column1",all.x=TRUE)
    # column1 X Y
    # 1 a 1 4
    # 2 b 2 5
    # 3 b 3 5

    merge(df1,df3, by="column1",all.x=TRUE)
    # column1 X Y
    # 1 a 1 4
    # 2 a 1 5
    # 3 b 2 6
    # 4 b 3 6


    Some values were duplicated by mistake.



    Using safejoin :



    # devtools::install_github("moodymudskipper/safejoin")
    library(safejoin)
    safe_left_join(df1, df2, check= "V")
    # column1 X Y
    # 1 a 1 4
    # 2 b 2 5
    # 3 b 3 5

    safe_left_join(df1, df3, check= "V")
    # Error: y is not unique on column1
    # Call `rlang::last_error()` to see a backtrace


    check = "V" controls that the join columns are unique on the right hand side (check = "U" like Unique checks that they are unique on the left hand side, "V" is the next letter in the alphabet).






    share|improve this answer






















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      3 Answers
      3






      active

      oldest

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      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.



      Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!






      share|improve this answer























      • Thanks a lt RDizzl3. As you said the tables were not one to one mapping.

        – oercim
        Mar 12 '16 at 23:46















      1














      This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.



      Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!






      share|improve this answer























      • Thanks a lt RDizzl3. As you said the tables were not one to one mapping.

        – oercim
        Mar 12 '16 at 23:46













      1












      1








      1







      This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.



      Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!






      share|improve this answer













      This may be because the values in column1 from df2 are not a 1-1 mapping. Meaning a single value in column1 may be related to more than one value in column2. You can check this by using table(df2$column1). If you find a value from column1 with a count > 1 then this is the reason.



      Also I would like to recommend an alternative if you are more comfortable with sql there is a very nice library called sqldf which allows you to use sql like queries on your data frames!







      share|improve this answer












      share|improve this answer



      share|improve this answer










      answered Mar 12 '16 at 10:22









      RDizzl3RDizzl3

      198111




      198111












      • Thanks a lt RDizzl3. As you said the tables were not one to one mapping.

        – oercim
        Mar 12 '16 at 23:46

















      • Thanks a lt RDizzl3. As you said the tables were not one to one mapping.

        – oercim
        Mar 12 '16 at 23:46
















      Thanks a lt RDizzl3. As you said the tables were not one to one mapping.

      – oercim
      Mar 12 '16 at 23:46





      Thanks a lt RDizzl3. As you said the tables were not one to one mapping.

      – oercim
      Mar 12 '16 at 23:46













      1














      I can't be sure without seeing an example of your problem, but usually the syntax is:



      df <- merge(df1, df2, by.all="name_of_column_in_common", all.x=T)


      However, if the columns you are matching on have duplicated values, r will match all possible combinations. So,



      df1 <- data.frame(id=c("a","a","b","c"), x1=rnorm(4))
      df2 <- data.frame(id=c("a","a","b"), x2=rnorm(3))
      df <- merge(df1, df2, by.all="id", all.x=T)


      Will give you a df of dimensions 6 by 3, as each "a" in df2 has been matched to each "a" in df1, 2 by 2 for 4 permutations.






      share|improve this answer



























        1














        I can't be sure without seeing an example of your problem, but usually the syntax is:



        df <- merge(df1, df2, by.all="name_of_column_in_common", all.x=T)


        However, if the columns you are matching on have duplicated values, r will match all possible combinations. So,



        df1 <- data.frame(id=c("a","a","b","c"), x1=rnorm(4))
        df2 <- data.frame(id=c("a","a","b"), x2=rnorm(3))
        df <- merge(df1, df2, by.all="id", all.x=T)


        Will give you a df of dimensions 6 by 3, as each "a" in df2 has been matched to each "a" in df1, 2 by 2 for 4 permutations.






        share|improve this answer

























          1












          1








          1







          I can't be sure without seeing an example of your problem, but usually the syntax is:



          df <- merge(df1, df2, by.all="name_of_column_in_common", all.x=T)


          However, if the columns you are matching on have duplicated values, r will match all possible combinations. So,



          df1 <- data.frame(id=c("a","a","b","c"), x1=rnorm(4))
          df2 <- data.frame(id=c("a","a","b"), x2=rnorm(3))
          df <- merge(df1, df2, by.all="id", all.x=T)


          Will give you a df of dimensions 6 by 3, as each "a" in df2 has been matched to each "a" in df1, 2 by 2 for 4 permutations.






          share|improve this answer













          I can't be sure without seeing an example of your problem, but usually the syntax is:



          df <- merge(df1, df2, by.all="name_of_column_in_common", all.x=T)


          However, if the columns you are matching on have duplicated values, r will match all possible combinations. So,



          df1 <- data.frame(id=c("a","a","b","c"), x1=rnorm(4))
          df2 <- data.frame(id=c("a","a","b"), x2=rnorm(3))
          df <- merge(df1, df2, by.all="id", all.x=T)


          Will give you a df of dimensions 6 by 3, as each "a" in df2 has been matched to each "a" in df1, 2 by 2 for 4 permutations.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 12 '16 at 10:20









          gfgmgfgm

          2,703727




          2,703727





















              0














              To make sure that your second data frame is unique on the join column(s), you can use my package safejoin (a wrapper around dplyr's join functions) which will give you an explicit error if it's not the case.



              Current situation :



              df1 <- data.frame(column1 = c("a","b","b"), X = 1:3)
              df2 <- data.frame(column1 = c("a","b"), Y = 4:5)
              df3 <- data.frame(column1 = c("a","a","b"), Y = 4:6)

              merge(df1,df2, by="column1",all.x=TRUE)
              # column1 X Y
              # 1 a 1 4
              # 2 b 2 5
              # 3 b 3 5

              merge(df1,df3, by="column1",all.x=TRUE)
              # column1 X Y
              # 1 a 1 4
              # 2 a 1 5
              # 3 b 2 6
              # 4 b 3 6


              Some values were duplicated by mistake.



              Using safejoin :



              # devtools::install_github("moodymudskipper/safejoin")
              library(safejoin)
              safe_left_join(df1, df2, check= "V")
              # column1 X Y
              # 1 a 1 4
              # 2 b 2 5
              # 3 b 3 5

              safe_left_join(df1, df3, check= "V")
              # Error: y is not unique on column1
              # Call `rlang::last_error()` to see a backtrace


              check = "V" controls that the join columns are unique on the right hand side (check = "U" like Unique checks that they are unique on the left hand side, "V" is the next letter in the alphabet).






              share|improve this answer



























                0














                To make sure that your second data frame is unique on the join column(s), you can use my package safejoin (a wrapper around dplyr's join functions) which will give you an explicit error if it's not the case.



                Current situation :



                df1 <- data.frame(column1 = c("a","b","b"), X = 1:3)
                df2 <- data.frame(column1 = c("a","b"), Y = 4:5)
                df3 <- data.frame(column1 = c("a","a","b"), Y = 4:6)

                merge(df1,df2, by="column1",all.x=TRUE)
                # column1 X Y
                # 1 a 1 4
                # 2 b 2 5
                # 3 b 3 5

                merge(df1,df3, by="column1",all.x=TRUE)
                # column1 X Y
                # 1 a 1 4
                # 2 a 1 5
                # 3 b 2 6
                # 4 b 3 6


                Some values were duplicated by mistake.



                Using safejoin :



                # devtools::install_github("moodymudskipper/safejoin")
                library(safejoin)
                safe_left_join(df1, df2, check= "V")
                # column1 X Y
                # 1 a 1 4
                # 2 b 2 5
                # 3 b 3 5

                safe_left_join(df1, df3, check= "V")
                # Error: y is not unique on column1
                # Call `rlang::last_error()` to see a backtrace


                check = "V" controls that the join columns are unique on the right hand side (check = "U" like Unique checks that they are unique on the left hand side, "V" is the next letter in the alphabet).






                share|improve this answer

























                  0












                  0








                  0







                  To make sure that your second data frame is unique on the join column(s), you can use my package safejoin (a wrapper around dplyr's join functions) which will give you an explicit error if it's not the case.



                  Current situation :



                  df1 <- data.frame(column1 = c("a","b","b"), X = 1:3)
                  df2 <- data.frame(column1 = c("a","b"), Y = 4:5)
                  df3 <- data.frame(column1 = c("a","a","b"), Y = 4:6)

                  merge(df1,df2, by="column1",all.x=TRUE)
                  # column1 X Y
                  # 1 a 1 4
                  # 2 b 2 5
                  # 3 b 3 5

                  merge(df1,df3, by="column1",all.x=TRUE)
                  # column1 X Y
                  # 1 a 1 4
                  # 2 a 1 5
                  # 3 b 2 6
                  # 4 b 3 6


                  Some values were duplicated by mistake.



                  Using safejoin :



                  # devtools::install_github("moodymudskipper/safejoin")
                  library(safejoin)
                  safe_left_join(df1, df2, check= "V")
                  # column1 X Y
                  # 1 a 1 4
                  # 2 b 2 5
                  # 3 b 3 5

                  safe_left_join(df1, df3, check= "V")
                  # Error: y is not unique on column1
                  # Call `rlang::last_error()` to see a backtrace


                  check = "V" controls that the join columns are unique on the right hand side (check = "U" like Unique checks that they are unique on the left hand side, "V" is the next letter in the alphabet).






                  share|improve this answer













                  To make sure that your second data frame is unique on the join column(s), you can use my package safejoin (a wrapper around dplyr's join functions) which will give you an explicit error if it's not the case.



                  Current situation :



                  df1 <- data.frame(column1 = c("a","b","b"), X = 1:3)
                  df2 <- data.frame(column1 = c("a","b"), Y = 4:5)
                  df3 <- data.frame(column1 = c("a","a","b"), Y = 4:6)

                  merge(df1,df2, by="column1",all.x=TRUE)
                  # column1 X Y
                  # 1 a 1 4
                  # 2 b 2 5
                  # 3 b 3 5

                  merge(df1,df3, by="column1",all.x=TRUE)
                  # column1 X Y
                  # 1 a 1 4
                  # 2 a 1 5
                  # 3 b 2 6
                  # 4 b 3 6


                  Some values were duplicated by mistake.



                  Using safejoin :



                  # devtools::install_github("moodymudskipper/safejoin")
                  library(safejoin)
                  safe_left_join(df1, df2, check= "V")
                  # column1 X Y
                  # 1 a 1 4
                  # 2 b 2 5
                  # 3 b 3 5

                  safe_left_join(df1, df3, check= "V")
                  # Error: y is not unique on column1
                  # Call `rlang::last_error()` to see a backtrace


                  check = "V" controls that the join columns are unique on the right hand side (check = "U" like Unique checks that they are unique on the left hand side, "V" is the next letter in the alphabet).







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 8 at 21:31









                  Moody_MudskipperMoody_Mudskipper

                  24.2k33466




                  24.2k33466



























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