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Finding related entities from three list



2019 Community Moderator ElectionHow do I check if a list is empty?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonHow to randomly select an item from a list?How do you split a list into evenly sized chunks?How to make a flat list out of list of lists?How to get the number of elements in a list in Python?How to concatenate two lists in Python?How to clone or copy a list?How do I list all files of a directory?










2















I have three lists that contain the following data:



Entities: ['Ashraf', 'Afghanistan', 'Afghanistan', 'Kabul']
Relations: ['Born', 'President', 'employee', 'Capital', 'Located', 'Lecturer', 'University']
sentence_list: ['Ashraf','Born', 'in', 'Kabul', '.' 'Ashraf', 'is', 'the', 'president', 'of', 'Afghanistan', '.', ...]


As the sentence_list is a list of sentences. In each sentence, I want to check if any word of Entities and Relations, the combination of specific words should be added in another list. such as, (Ashraf, born, Kabul) in the first sentence.



What I did:



First incomplete Solution:



# read file
with open('../data/parse.txt', 'r') as myfile:
json_data = json.load(myfile)

for i in range(len(json_data)): # the dataset was in json format
if json_data[i]['word'] in relation(json_data)[0]: # I extract the relations
print(json_data[i]['word'])
if json_data[i]['word'] in entities(json_data)[0]:
print(json[i]['word'])


The output: (Ashraf, Born, Ashraf), where I want (Ashraf, Born, Kabul)



The next incomplete solution: I stored json_data to a list and then I did this:



json_data2 = []
for i in range(len(json_data)):
json2_data.append(json_data[i]['word'])
print(json_data2)


'''
Now I tried if I can find any element of `Entities` list and `Relations` list
in each sentence of `sentence_list`. And then it should store matched
entities and relations based on sentence to a list. '''

for line in json_data2:
for rel in relation(obj):
for ent in entities(obj):
match = re.findall(rel, line['word'])
if match:
print('word matched relations: %s ==> word: %s' % (rel, line['address']))
match2 = re.findall(ent, line['word'])
if match2:
print('word matched entities: %s ==> word: %s' % (ent, line['address']))


Unfortunately, does not work?










share|improve this question




























    2















    I have three lists that contain the following data:



    Entities: ['Ashraf', 'Afghanistan', 'Afghanistan', 'Kabul']
    Relations: ['Born', 'President', 'employee', 'Capital', 'Located', 'Lecturer', 'University']
    sentence_list: ['Ashraf','Born', 'in', 'Kabul', '.' 'Ashraf', 'is', 'the', 'president', 'of', 'Afghanistan', '.', ...]


    As the sentence_list is a list of sentences. In each sentence, I want to check if any word of Entities and Relations, the combination of specific words should be added in another list. such as, (Ashraf, born, Kabul) in the first sentence.



    What I did:



    First incomplete Solution:



    # read file
    with open('../data/parse.txt', 'r') as myfile:
    json_data = json.load(myfile)

    for i in range(len(json_data)): # the dataset was in json format
    if json_data[i]['word'] in relation(json_data)[0]: # I extract the relations
    print(json_data[i]['word'])
    if json_data[i]['word'] in entities(json_data)[0]:
    print(json[i]['word'])


    The output: (Ashraf, Born, Ashraf), where I want (Ashraf, Born, Kabul)



    The next incomplete solution: I stored json_data to a list and then I did this:



    json_data2 = []
    for i in range(len(json_data)):
    json2_data.append(json_data[i]['word'])
    print(json_data2)


    '''
    Now I tried if I can find any element of `Entities` list and `Relations` list
    in each sentence of `sentence_list`. And then it should store matched
    entities and relations based on sentence to a list. '''

    for line in json_data2:
    for rel in relation(obj):
    for ent in entities(obj):
    match = re.findall(rel, line['word'])
    if match:
    print('word matched relations: %s ==> word: %s' % (rel, line['address']))
    match2 = re.findall(ent, line['word'])
    if match2:
    print('word matched entities: %s ==> word: %s' % (ent, line['address']))


    Unfortunately, does not work?










    share|improve this question


























      2












      2








      2








      I have three lists that contain the following data:



      Entities: ['Ashraf', 'Afghanistan', 'Afghanistan', 'Kabul']
      Relations: ['Born', 'President', 'employee', 'Capital', 'Located', 'Lecturer', 'University']
      sentence_list: ['Ashraf','Born', 'in', 'Kabul', '.' 'Ashraf', 'is', 'the', 'president', 'of', 'Afghanistan', '.', ...]


      As the sentence_list is a list of sentences. In each sentence, I want to check if any word of Entities and Relations, the combination of specific words should be added in another list. such as, (Ashraf, born, Kabul) in the first sentence.



      What I did:



      First incomplete Solution:



      # read file
      with open('../data/parse.txt', 'r') as myfile:
      json_data = json.load(myfile)

      for i in range(len(json_data)): # the dataset was in json format
      if json_data[i]['word'] in relation(json_data)[0]: # I extract the relations
      print(json_data[i]['word'])
      if json_data[i]['word'] in entities(json_data)[0]:
      print(json[i]['word'])


      The output: (Ashraf, Born, Ashraf), where I want (Ashraf, Born, Kabul)



      The next incomplete solution: I stored json_data to a list and then I did this:



      json_data2 = []
      for i in range(len(json_data)):
      json2_data.append(json_data[i]['word'])
      print(json_data2)


      '''
      Now I tried if I can find any element of `Entities` list and `Relations` list
      in each sentence of `sentence_list`. And then it should store matched
      entities and relations based on sentence to a list. '''

      for line in json_data2:
      for rel in relation(obj):
      for ent in entities(obj):
      match = re.findall(rel, line['word'])
      if match:
      print('word matched relations: %s ==> word: %s' % (rel, line['address']))
      match2 = re.findall(ent, line['word'])
      if match2:
      print('word matched entities: %s ==> word: %s' % (ent, line['address']))


      Unfortunately, does not work?










      share|improve this question
















      I have three lists that contain the following data:



      Entities: ['Ashraf', 'Afghanistan', 'Afghanistan', 'Kabul']
      Relations: ['Born', 'President', 'employee', 'Capital', 'Located', 'Lecturer', 'University']
      sentence_list: ['Ashraf','Born', 'in', 'Kabul', '.' 'Ashraf', 'is', 'the', 'president', 'of', 'Afghanistan', '.', ...]


      As the sentence_list is a list of sentences. In each sentence, I want to check if any word of Entities and Relations, the combination of specific words should be added in another list. such as, (Ashraf, born, Kabul) in the first sentence.



      What I did:



      First incomplete Solution:



      # read file
      with open('../data/parse.txt', 'r') as myfile:
      json_data = json.load(myfile)

      for i in range(len(json_data)): # the dataset was in json format
      if json_data[i]['word'] in relation(json_data)[0]: # I extract the relations
      print(json_data[i]['word'])
      if json_data[i]['word'] in entities(json_data)[0]:
      print(json[i]['word'])


      The output: (Ashraf, Born, Ashraf), where I want (Ashraf, Born, Kabul)



      The next incomplete solution: I stored json_data to a list and then I did this:



      json_data2 = []
      for i in range(len(json_data)):
      json2_data.append(json_data[i]['word'])
      print(json_data2)


      '''
      Now I tried if I can find any element of `Entities` list and `Relations` list
      in each sentence of `sentence_list`. And then it should store matched
      entities and relations based on sentence to a list. '''

      for line in json_data2:
      for rel in relation(obj):
      for ent in entities(obj):
      match = re.findall(rel, line['word'])
      if match:
      print('word matched relations: %s ==> word: %s' % (rel, line['address']))
      match2 = re.findall(ent, line['word'])
      if match2:
      print('word matched entities: %s ==> word: %s' % (ent, line['address']))


      Unfortunately, does not work?







      python list






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 11 hours ago









      yatu

      12.4k31341




      12.4k31341










      asked 18 hours ago









      user2988094user2988094

      199




      199






















          1 Answer
          1






          active

          oldest

          votes


















          1














          You could use the following list comprehension:



          to_match = set(Entities+Relations)
          l = [j for j in to_match if j in i
          for i in ' '.join(sentence_list).split('.')[:-1]]


          Output



          ['Ashraf', 'Born', 'Kabul', 'Afghanistan', 'Ashraf']



          Note that I'm, returning a list of sets to avoid duplicate values, given that for instance in Entities Afghanistan appears twice.



          Useful reads:



          • List comprehensions


          • sets — Unordered collections of unique elements


          • string methods






          share|improve this answer

























          • Thank you, but in the second or more index of the list, it takes repeated elements from Entities list. As you defined each sentence by .split('.') but it should select from both 'Entities and Relations' based on its existence in the sentence-list. How to fix that?

            – user2988094
            18 hours ago












          • IIUC the update should fix that

            – yatu
            18 hours ago











          • Thank you very much. It's solved by using set.

            – user2988094
            18 hours ago






          • 1





            I upvoted, thank you again

            – user2988094
            17 hours ago










          Your Answer






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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          You could use the following list comprehension:



          to_match = set(Entities+Relations)
          l = [j for j in to_match if j in i
          for i in ' '.join(sentence_list).split('.')[:-1]]


          Output



          ['Ashraf', 'Born', 'Kabul', 'Afghanistan', 'Ashraf']



          Note that I'm, returning a list of sets to avoid duplicate values, given that for instance in Entities Afghanistan appears twice.



          Useful reads:



          • List comprehensions


          • sets — Unordered collections of unique elements


          • string methods






          share|improve this answer

























          • Thank you, but in the second or more index of the list, it takes repeated elements from Entities list. As you defined each sentence by .split('.') but it should select from both 'Entities and Relations' based on its existence in the sentence-list. How to fix that?

            – user2988094
            18 hours ago












          • IIUC the update should fix that

            – yatu
            18 hours ago











          • Thank you very much. It's solved by using set.

            – user2988094
            18 hours ago






          • 1





            I upvoted, thank you again

            – user2988094
            17 hours ago















          1














          You could use the following list comprehension:



          to_match = set(Entities+Relations)
          l = [j for j in to_match if j in i
          for i in ' '.join(sentence_list).split('.')[:-1]]


          Output



          ['Ashraf', 'Born', 'Kabul', 'Afghanistan', 'Ashraf']



          Note that I'm, returning a list of sets to avoid duplicate values, given that for instance in Entities Afghanistan appears twice.



          Useful reads:



          • List comprehensions


          • sets — Unordered collections of unique elements


          • string methods






          share|improve this answer

























          • Thank you, but in the second or more index of the list, it takes repeated elements from Entities list. As you defined each sentence by .split('.') but it should select from both 'Entities and Relations' based on its existence in the sentence-list. How to fix that?

            – user2988094
            18 hours ago












          • IIUC the update should fix that

            – yatu
            18 hours ago











          • Thank you very much. It's solved by using set.

            – user2988094
            18 hours ago






          • 1





            I upvoted, thank you again

            – user2988094
            17 hours ago













          1












          1








          1







          You could use the following list comprehension:



          to_match = set(Entities+Relations)
          l = [j for j in to_match if j in i
          for i in ' '.join(sentence_list).split('.')[:-1]]


          Output



          ['Ashraf', 'Born', 'Kabul', 'Afghanistan', 'Ashraf']



          Note that I'm, returning a list of sets to avoid duplicate values, given that for instance in Entities Afghanistan appears twice.



          Useful reads:



          • List comprehensions


          • sets — Unordered collections of unique elements


          • string methods






          share|improve this answer















          You could use the following list comprehension:



          to_match = set(Entities+Relations)
          l = [j for j in to_match if j in i
          for i in ' '.join(sentence_list).split('.')[:-1]]


          Output



          ['Ashraf', 'Born', 'Kabul', 'Afghanistan', 'Ashraf']



          Note that I'm, returning a list of sets to avoid duplicate values, given that for instance in Entities Afghanistan appears twice.



          Useful reads:



          • List comprehensions


          • sets — Unordered collections of unique elements


          • string methods







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 18 hours ago

























          answered 18 hours ago









          yatuyatu

          12.4k31341




          12.4k31341












          • Thank you, but in the second or more index of the list, it takes repeated elements from Entities list. As you defined each sentence by .split('.') but it should select from both 'Entities and Relations' based on its existence in the sentence-list. How to fix that?

            – user2988094
            18 hours ago












          • IIUC the update should fix that

            – yatu
            18 hours ago











          • Thank you very much. It's solved by using set.

            – user2988094
            18 hours ago






          • 1





            I upvoted, thank you again

            – user2988094
            17 hours ago

















          • Thank you, but in the second or more index of the list, it takes repeated elements from Entities list. As you defined each sentence by .split('.') but it should select from both 'Entities and Relations' based on its existence in the sentence-list. How to fix that?

            – user2988094
            18 hours ago












          • IIUC the update should fix that

            – yatu
            18 hours ago











          • Thank you very much. It's solved by using set.

            – user2988094
            18 hours ago






          • 1





            I upvoted, thank you again

            – user2988094
            17 hours ago
















          Thank you, but in the second or more index of the list, it takes repeated elements from Entities list. As you defined each sentence by .split('.') but it should select from both 'Entities and Relations' based on its existence in the sentence-list. How to fix that?

          – user2988094
          18 hours ago






          Thank you, but in the second or more index of the list, it takes repeated elements from Entities list. As you defined each sentence by .split('.') but it should select from both 'Entities and Relations' based on its existence in the sentence-list. How to fix that?

          – user2988094
          18 hours ago














          IIUC the update should fix that

          – yatu
          18 hours ago





          IIUC the update should fix that

          – yatu
          18 hours ago













          Thank you very much. It's solved by using set.

          – user2988094
          18 hours ago





          Thank you very much. It's solved by using set.

          – user2988094
          18 hours ago




          1




          1





          I upvoted, thank you again

          – user2988094
          17 hours ago





          I upvoted, thank you again

          – user2988094
          17 hours ago



















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