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return bool value with two reduce inside each other js

1

const find = haystack => search.toLowerCase().split(/s/)
 .reduce((f, c) => , false)

here I need to get a bool from this function, when the haystack value only consist of one word like "matchedValue" it was quite ok to do with one reduce(), but when I have the haystack value like "match value" and I wanna filter the results even when the search value match the second part of the field I needed two reduce() but it seems I am missing something

javascript arrays

share|improve this question

edited Mar 7 at 16:20

Tiw

4,00261530

asked Mar 7 at 10:46

NassifNassif

114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What are the conditions for the boolean exactly?
  
  – AndrewL64
  Mar 7 at 10:50
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  so the case is I have a search term let's say "test", and I have haystack, when the haystack starts with "test" the filter is working like search = 'test' haystack= 'test me' this fine when I have this function ``` const find = haystack => search.toLowerCase().split(/s/) .reduce((f, c) => f || haystack.toLowerCase().startsWith(c), false) ``` but if the haystack = 'me test' search = 'test' that function is not working anymore because it takes the haystack as one string
  
  – Nassif
  Mar 7 at 10:53
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  So you want to check if your haystack string has a word e.g. "test" in it or not?
  
  – AndrewL64
  Mar 7 at 11:37
  

  
  
  
  

add a comment | 

1

const find = haystack => search.toLowerCase().split(/s/)
 .reduce((f, c) => , false)

here I need to get a bool from this function, when the haystack value only consist of one word like "matchedValue" it was quite ok to do with one reduce(), but when I have the haystack value like "match value" and I wanna filter the results even when the search value match the second part of the field I needed two reduce() but it seems I am missing something

javascript arrays

share|improve this question

edited Mar 7 at 16:20

Tiw

4,00261530

asked Mar 7 at 10:46

NassifNassif

114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What are the conditions for the boolean exactly?
  
  – AndrewL64
  Mar 7 at 10:50
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  so the case is I have a search term let's say "test", and I have haystack, when the haystack starts with "test" the filter is working like search = 'test' haystack= 'test me' this fine when I have this function ``` const find = haystack => search.toLowerCase().split(/s/) .reduce((f, c) => f || haystack.toLowerCase().startsWith(c), false) ``` but if the haystack = 'me test' search = 'test' that function is not working anymore because it takes the haystack as one string
  
  – Nassif
  Mar 7 at 10:53
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  So you want to check if your haystack string has a word e.g. "test" in it or not?
  
  – AndrewL64
  Mar 7 at 11:37
  

  
  
  
  

add a comment | 

const find = haystack => search.toLowerCase().split(/s/)
 .reduce((f, c) => , false)

here I need to get a bool from this function, when the haystack value only consist of one word like "matchedValue" it was quite ok to do with one reduce(), but when I have the haystack value like "match value" and I wanna filter the results even when the search value match the second part of the field I needed two reduce() but it seems I am missing something

javascript arrays

share|improve this question

edited Mar 7 at 16:20

Tiw

4,00261530

asked Mar 7 at 10:46

NassifNassif

114

const find = haystack => search.toLowerCase().split(/s/)
 .reduce((f, c) => , false)

share|improve this question

edited Mar 7 at 16:20

Tiw

4,00261530

asked Mar 7 at 10:46

NassifNassif

114

share|improve this question

edited Mar 7 at 16:20

Tiw

4,00261530

asked Mar 7 at 10:46

NassifNassif

114

edited Mar 7 at 16:20

Tiw

4,00261530

edited Mar 7 at 16:20

Tiw

4,00261530

asked Mar 7 at 10:46

NassifNassif

114

asked Mar 7 at 10:46

NassifNassif

114

2 Answers
2

active

oldest

votes

0

try this:

const find = (queryString,token) => queryString.toLowerCase().split(/s+/).includes(token);

console.log(find("test me","test"));
console.log(find("me test","test"));

share|improve this answer

answered Mar 7 at 11:16

RK_15RK_15

2948

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you, the point includes is very strict it is like === I want something to filter when the string starts with some characters it doesn't have to match entirely
  
  – Nassif
  Mar 7 at 11:34
  

  
  
  
  

add a comment | 

0

const find = (haystack, search) => 
 search = search.toLowerCase().split(/s/)
 haystack = haystack.toLowerCase().split(/s/)

 return search.some(searchTerm => 
 return haystack.some(haystackTerm => 
 return haystackTerm.startsWith(searchTerm)
 )
 )
 

Thanks everyone tried to help, I found this way and it worked for me

share|improve this answer

answered Mar 7 at 12:36

NassifNassif

114

add a comment | 

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0

try this:

const find = (queryString,token) => queryString.toLowerCase().split(/s+/).includes(token);

console.log(find("test me","test"));
console.log(find("me test","test"));

share|improve this answer

answered Mar 7 at 11:16

RK_15RK_15

2948

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you, the point includes is very strict it is like === I want something to filter when the string starts with some characters it doesn't have to match entirely
  
  – Nassif
  Mar 7 at 11:34
  

  
  
  
  

add a comment | 

0

try this:

const find = (queryString,token) => queryString.toLowerCase().split(/s+/).includes(token);

console.log(find("test me","test"));
console.log(find("me test","test"));

share|improve this answer

answered Mar 7 at 11:16

RK_15RK_15

2948

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you, the point includes is very strict it is like === I want something to filter when the string starts with some characters it doesn't have to match entirely
  
  – Nassif
  Mar 7 at 11:34
  

  
  
  
  

add a comment | 

try this:

const find = (queryString,token) => queryString.toLowerCase().split(/s+/).includes(token);

console.log(find("test me","test"));
console.log(find("me test","test"));

share|improve this answer

answered Mar 7 at 11:16

RK_15RK_15

2948

const find = (queryString,token) => queryString.toLowerCase().split(/s+/).includes(token);

console.log(find("test me","test"));
console.log(find("me test","test"));

share|improve this answer

answered Mar 7 at 11:16

RK_15RK_15

2948

answered Mar 7 at 11:16

RK_15RK_15

2948

answered Mar 7 at 11:16

RK_15RK_15

2948

0

const find = (haystack, search) => 
 search = search.toLowerCase().split(/s/)
 haystack = haystack.toLowerCase().split(/s/)

 return search.some(searchTerm => 
 return haystack.some(haystackTerm => 
 return haystackTerm.startsWith(searchTerm)
 )
 )
 

Thanks everyone tried to help, I found this way and it worked for me

share|improve this answer

answered Mar 7 at 12:36

NassifNassif

114

add a comment | 

0

const find = (haystack, search) => 
 search = search.toLowerCase().split(/s/)
 haystack = haystack.toLowerCase().split(/s/)

 return search.some(searchTerm => 
 return haystack.some(haystackTerm => 
 return haystackTerm.startsWith(searchTerm)
 )
 )
 

Thanks everyone tried to help, I found this way and it worked for me

share|improve this answer

answered Mar 7 at 12:36

NassifNassif

114

add a comment | 

const find = (haystack, search) => 
 search = search.toLowerCase().split(/s/)
 haystack = haystack.toLowerCase().split(/s/)

 return search.some(searchTerm => 
 return haystack.some(haystackTerm => 
 return haystackTerm.startsWith(searchTerm)
 )
 )
 

Thanks everyone tried to help, I found this way and it worked for me

share|improve this answer

answered Mar 7 at 12:36

NassifNassif

114

const find = (haystack, search) => 
 search = search.toLowerCase().split(/s/)
 haystack = haystack.toLowerCase().split(/s/)

 return search.some(searchTerm => 
 return haystack.some(haystackTerm => 
 return haystackTerm.startsWith(searchTerm)
 )
 )
 

share|improve this answer

answered Mar 7 at 12:36

NassifNassif

114

answered Mar 7 at 12:36

NassifNassif

114

answered Mar 7 at 12:36

NassifNassif

114