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Dart: spread operator for constructor
2019 Community Moderator ElectionCalling the base constructor in C#Virtual member call in a constructorWhat are the rules for calling the superclass constructor?How do I call one constructor from another in Java?Can I call a constructor from another constructor (do constructor chaining) in C++?Call one constructor from anotherDifference between Constructor and ngOnInitHow can I prevent a multi-line Text widget from getting clipped when placed within a Row?How to get constraints like Height and Width of container in flutterHow to set OutlineButton width > child width and the border expand to all available space?
In my flutter app, I have widgets like below:
Container(
decoration: BoxDecoration(
border: Border.all(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
),
child: Text('Container 2'),
)
Both use the same properties for their borders. So I was wondering if there's a spread-operator-like way of inserting the same properties for both widgets? Maybe like:
const borderBase = (
color: Colors.red,
width: 2,
style: BorderStyle.solid,
)
Container(
decoration: BoxDecoration(
border: Border.all(
...borderBase,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
...borderBase,
),
),
),
child: Text('Container 2'),
)
constructor properties dart
flutter spread-syntax asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
add a comment |
In my flutter app, I have widgets like below:
Container(
decoration: BoxDecoration(
border: Border.all(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
),
child: Text('Container 2'),
)
Both use the same properties for their borders. So I was wondering if there's a spread-operator-like way of inserting the same properties for both widgets? Maybe like:
const borderBase = (
color: Colors.red,
width: 2,
style: BorderStyle.solid,
)
Container(
decoration: BoxDecoration(
border: Border.all(
...borderBase,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
...borderBase,
),
),
),
child: Text('Container 2'),
)
constructor properties dart
flutter spread-syntax asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
add a comment |
In my flutter app, I have widgets like below:
Container(
decoration: BoxDecoration(
border: Border.all(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
),
child: Text('Container 2'),
)
Both use the same properties for their borders. So I was wondering if there's a spread-operator-like way of inserting the same properties for both widgets? Maybe like:
const borderBase = (
color: Colors.red,
width: 2,
style: BorderStyle.solid,
)
Container(
decoration: BoxDecoration(
border: Border.all(
...borderBase,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
...borderBase,
),
),
),
child: Text('Container 2'),
)
constructor properties dart
flutter spread-syntax asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
In my flutter app, I have widgets like below:
Container(
decoration: BoxDecoration(
border: Border.all(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
),
),
),
child: Text('Container 2'),
)
Both use the same properties for their borders. So I was wondering if there's a spread-operator-like way of inserting the same properties for both widgets? Maybe like:
const borderBase = (
color: Colors.red,
width: 2,
style: BorderStyle.solid,
)
Container(
decoration: BoxDecoration(
border: Border.all(
...borderBase,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: BorderSide(
...borderBase,
),
),
),
child: Text('Container 2'),
)
constructor properties dart
flutter spread-syntax constructor properties dart
flutter spread-syntax asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
edited Mar 7 at 10:37
Giraldi
asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
asked Mar 7 at 10:34
GiraldiGiraldi
12k41937
12k41937
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You can do something like this:
const BorderSide borderBase = BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
);
Container(
decoration: BoxDecoration(
border: Border.all(
color: borderBase.color,
width: borderBase.width,
style: borderBase.style,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: borderBase,
),
),
child: Text('Container 2'),
)
Not the best but still some reuse.
edited Mar 7 at 12:27
Giraldi
12k41937
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
But this way I get errors in theborderBasevariable sayingUndefined name 'color', and other linter errors.
– Giraldi
Mar 7 at 12:15
Oh, I think you meant theborderBasevar should use theBorderSide()class, right? Cause that seems to work.
– Giraldi
Mar 7 at 12:26
1
I updated it for you. Tx for the tips!
– Giraldi
Mar 7 at 12:28
add a comment |
There is no such thing.
A spread operator is in development, but it is only for lists, not classes (https://github.com/dart-lang/language/issues/47)
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
I see. So ther's no way to re-use the same properties dynamically? Meaning I have to repeat them everytime?
– Giraldi
Mar 7 at 10:38
Yes, you're forced to. But you can discuss about it on the issue. I think this is an interesting feature too.
– Rémi Rousselet
Mar 7 at 10:47
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can do something like this:
const BorderSide borderBase = BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
);
Container(
decoration: BoxDecoration(
border: Border.all(
color: borderBase.color,
width: borderBase.width,
style: borderBase.style,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: borderBase,
),
),
child: Text('Container 2'),
)
Not the best but still some reuse.
edited Mar 7 at 12:27
Giraldi
12k41937
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
But this way I get errors in theborderBasevariable sayingUndefined name 'color', and other linter errors.
– Giraldi
Mar 7 at 12:15
Oh, I think you meant theborderBasevar should use theBorderSide()class, right? Cause that seems to work.
– Giraldi
Mar 7 at 12:26
1
I updated it for you. Tx for the tips!
– Giraldi
Mar 7 at 12:28
add a comment |
You can do something like this:
const BorderSide borderBase = BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
);
Container(
decoration: BoxDecoration(
border: Border.all(
color: borderBase.color,
width: borderBase.width,
style: borderBase.style,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: borderBase,
),
),
child: Text('Container 2'),
)
Not the best but still some reuse.
edited Mar 7 at 12:27
Giraldi
12k41937
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
But this way I get errors in theborderBasevariable sayingUndefined name 'color', and other linter errors.
– Giraldi
Mar 7 at 12:15
Oh, I think you meant theborderBasevar should use theBorderSide()class, right? Cause that seems to work.
– Giraldi
Mar 7 at 12:26
1
I updated it for you. Tx for the tips!
– Giraldi
Mar 7 at 12:28
add a comment |
You can do something like this:
const BorderSide borderBase = BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
);
Container(
decoration: BoxDecoration(
border: Border.all(
color: borderBase.color,
width: borderBase.width,
style: borderBase.style,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: borderBase,
),
),
child: Text('Container 2'),
)
Not the best but still some reuse.
edited Mar 7 at 12:27
Giraldi
12k41937
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
You can do something like this:
const BorderSide borderBase = BorderSide(
color: Colors.red,
width: 2,
style: BorderStyle.solid,
);
Container(
decoration: BoxDecoration(
border: Border.all(
color: borderBase.color,
width: borderBase.width,
style: borderBase.style,
),
),
child: Text('Container 1'),
)
Container(
decoration: BoxDecoration(
border: Border(
top: borderBase,
),
),
child: Text('Container 2'),
)
Not the best but still some reuse.
edited Mar 7 at 12:27
Giraldi
12k41937
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
edited Mar 7 at 12:27
Giraldi
12k41937
edited Mar 7 at 12:27
Giraldi
12k41937
edited Mar 7 at 12:27
Giraldi
12k41937
12k41937
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
answered Mar 7 at 10:49
Daniel PDaniel P
2,42112834
2,42112834
But this way I get errors in theborderBasevariable sayingUndefined name 'color', and other linter errors.
– Giraldi
Mar 7 at 12:15
Oh, I think you meant theborderBasevar should use theBorderSide()class, right? Cause that seems to work.
– Giraldi
Mar 7 at 12:26
1
I updated it for you. Tx for the tips!
– Giraldi
Mar 7 at 12:28
add a comment |
But this way I get errors in theborderBasevariable sayingUndefined name 'color', and other linter errors.
– Giraldi
Mar 7 at 12:15
Oh, I think you meant theborderBasevar should use theBorderSide()class, right? Cause that seems to work.
– Giraldi
Mar 7 at 12:26
1
I updated it for you. Tx for the tips!
– Giraldi
Mar 7 at 12:28
But this way I get errors in the
borderBase variable saying Undefined name 'color', and other linter errors.– Giraldi
Mar 7 at 12:15
But this way I get errors in the
borderBase variable saying Undefined name 'color', and other linter errors.– Giraldi
Mar 7 at 12:15
Oh, I think you meant the
borderBase var should use the BorderSide() class, right? Cause that seems to work.– Giraldi
Mar 7 at 12:26
Oh, I think you meant the
borderBase var should use the BorderSide() class, right? Cause that seems to work.– Giraldi
Mar 7 at 12:26
1
1
I updated it for you. Tx for the tips!
– Giraldi
Mar 7 at 12:28
I updated it for you. Tx for the tips!
– Giraldi
Mar 7 at 12:28
add a comment |
There is no such thing.
A spread operator is in development, but it is only for lists, not classes (https://github.com/dart-lang/language/issues/47)
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
I see. So ther's no way to re-use the same properties dynamically? Meaning I have to repeat them everytime?
– Giraldi
Mar 7 at 10:38
Yes, you're forced to. But you can discuss about it on the issue. I think this is an interesting feature too.
– Rémi Rousselet
Mar 7 at 10:47
add a comment |
There is no such thing.
A spread operator is in development, but it is only for lists, not classes (https://github.com/dart-lang/language/issues/47)
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
I see. So ther's no way to re-use the same properties dynamically? Meaning I have to repeat them everytime?
– Giraldi
Mar 7 at 10:38
Yes, you're forced to. But you can discuss about it on the issue. I think this is an interesting feature too.
– Rémi Rousselet
Mar 7 at 10:47
add a comment |
There is no such thing.
A spread operator is in development, but it is only for lists, not classes (https://github.com/dart-lang/language/issues/47)
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
There is no such thing.
A spread operator is in development, but it is only for lists, not classes (https://github.com/dart-lang/language/issues/47)
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
answered Mar 7 at 10:36
Rémi RousseletRémi Rousselet
33.7k380105
33.7k380105
I see. So ther's no way to re-use the same properties dynamically? Meaning I have to repeat them everytime?
– Giraldi
Mar 7 at 10:38
Yes, you're forced to. But you can discuss about it on the issue. I think this is an interesting feature too.
– Rémi Rousselet
Mar 7 at 10:47
add a comment |
I see. So ther's no way to re-use the same properties dynamically? Meaning I have to repeat them everytime?
– Giraldi
Mar 7 at 10:38
Yes, you're forced to. But you can discuss about it on the issue. I think this is an interesting feature too.
– Rémi Rousselet
Mar 7 at 10:47
I see. So ther's no way to re-use the same properties dynamically? Meaning I have to repeat them everytime?
– Giraldi
Mar 7 at 10:38
I see. So ther's no way to re-use the same properties dynamically? Meaning I have to repeat them everytime?
– Giraldi
Mar 7 at 10:38
Yes, you're forced to. But you can discuss about it on the issue. I think this is an interesting feature too.
– Rémi Rousselet
Mar 7 at 10:47
Yes, you're forced to. But you can discuss about it on the issue. I think this is an interesting feature too.
– Rémi Rousselet
Mar 7 at 10:47
add a comment |
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