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Adjacency list to matrix pandas
2019 Community Moderator ElectionHow do I check if a list is empty?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonHow to make a flat list out of list of lists?How do I list all files of a directory?Renaming columns in pandasDelete column from pandas DataFrame by column nameHow to iterate over rows in a DataFrame in Pandas?Select rows from a DataFrame based on values in a column in pandasGet list from pandas DataFrame column headers
I'm trying to get through a toy example of building an adjacency matrix from a list, but already I can't quite figure it out. I am thinking in terms of .loc() but I'm not sure how to index correctly.
'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
I've started to build the matrix with:
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns = graph['nodes'], index = graph['edges'])
but now I'm not sure how to fill it in. I think there's an easy one liner, maybe with a list comprehension?
Expected output:
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
python pandas dataframe adjacency-matrix adjacency-list
add a comment |
I'm trying to get through a toy example of building an adjacency matrix from a list, but already I can't quite figure it out. I am thinking in terms of .loc() but I'm not sure how to index correctly.
'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
I've started to build the matrix with:
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns = graph['nodes'], index = graph['edges'])
but now I'm not sure how to fill it in. I think there's an easy one liner, maybe with a list comprehension?
Expected output:
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
python pandas dataframe adjacency-matrix adjacency-list
1
What's the expected output?
– pistol2myhead
Mar 7 at 12:12
thank you, I added it now. Currently the dataframe/matrix is filled in with all 0s
– Frederic Bastiat
Mar 7 at 12:16
Updated the answer @FredericBastiat , as it seems from your adjacency matrix that the graph is directed
– yatu
Mar 7 at 15:51
add a comment |
I'm trying to get through a toy example of building an adjacency matrix from a list, but already I can't quite figure it out. I am thinking in terms of .loc() but I'm not sure how to index correctly.
'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
I've started to build the matrix with:
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns = graph['nodes'], index = graph['edges'])
but now I'm not sure how to fill it in. I think there's an easy one liner, maybe with a list comprehension?
Expected output:
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
python pandas dataframe adjacency-matrix adjacency-list
I'm trying to get through a toy example of building an adjacency matrix from a list, but already I can't quite figure it out. I am thinking in terms of .loc() but I'm not sure how to index correctly.
'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
I've started to build the matrix with:
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns = graph['nodes'], index = graph['edges'])
but now I'm not sure how to fill it in. I think there's an easy one liner, maybe with a list comprehension?
Expected output:
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
python pandas dataframe adjacency-matrix adjacency-list
python pandas dataframe adjacency-matrix adjacency-list
edited Mar 7 at 12:17
Frederic Bastiat
asked Mar 7 at 12:11
Frederic BastiatFrederic Bastiat
375317
375317
1
What's the expected output?
– pistol2myhead
Mar 7 at 12:12
thank you, I added it now. Currently the dataframe/matrix is filled in with all 0s
– Frederic Bastiat
Mar 7 at 12:16
Updated the answer @FredericBastiat , as it seems from your adjacency matrix that the graph is directed
– yatu
Mar 7 at 15:51
add a comment |
1
What's the expected output?
– pistol2myhead
Mar 7 at 12:12
thank you, I added it now. Currently the dataframe/matrix is filled in with all 0s
– Frederic Bastiat
Mar 7 at 12:16
Updated the answer @FredericBastiat , as it seems from your adjacency matrix that the graph is directed
– yatu
Mar 7 at 15:51
1
1
What's the expected output?
– pistol2myhead
Mar 7 at 12:12
What's the expected output?
– pistol2myhead
Mar 7 at 12:12
thank you, I added it now. Currently the dataframe/matrix is filled in with all 0s
– Frederic Bastiat
Mar 7 at 12:16
thank you, I added it now. Currently the dataframe/matrix is filled in with all 0s
– Frederic Bastiat
Mar 7 at 12:16
Updated the answer @FredericBastiat , as it seems from your adjacency matrix that the graph is directed
– yatu
Mar 7 at 15:51
Updated the answer @FredericBastiat , as it seems from your adjacency matrix that the graph is directed
– yatu
Mar 7 at 15:51
add a comment |
3 Answers
3
active
oldest
votes
A simple way to obtain the adjacency matrix is by using NetworkX
d = 'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
It appears that from your adjacency matrix the graph is directed. You can create a directed graph as shown bellow and define its nodes and edges from the dictionary with:
import networkx as nx
g = nx.DiGraph()
g.add_nodes_from(d['nodes'])
g.add_edges_from(d['edges'])
And then you can obtain the adjacency matrix from the network with nx.adjacency_matrix:
m = nx.adjacency_matrix(g)
m.todense()
matrix([[0, 1, 0, 1, 0],
[0, 0, 1, 0, 1],
[0, 0, 0, 1, 0],
[0, 0, 0, 0, 1],
[1, 1, 1, 0, 0]], dtype=int64)
And for a dataframe with the corresponding nodes as columns you can do:
pd.DataFrame(m.todense(), columns=nx.nodes(g))
A B C D E
0 0 1 0 1 0
1 0 0 1 0 1
2 0 0 0 1 0
3 0 0 0 0 1
4 1 1 1 0 0
add a comment |
for undirected graph
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 1
B 1 0 1 0 1
C 0 1 0 1 1
D 1 0 1 0 1
E 1 1 1 1 0
for directed graph:
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
print(adj_matr)
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
# adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
add a comment |
For a directed graph you can use:
df = pd.DataFrame(graph['edges'], columns=['From', 'To'])
df['Edge'] = 1
adj = df.pivot(index='From', columns='To', values='Edge').fillna(0)
add a comment |
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3 Answers
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active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
A simple way to obtain the adjacency matrix is by using NetworkX
d = 'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
It appears that from your adjacency matrix the graph is directed. You can create a directed graph as shown bellow and define its nodes and edges from the dictionary with:
import networkx as nx
g = nx.DiGraph()
g.add_nodes_from(d['nodes'])
g.add_edges_from(d['edges'])
And then you can obtain the adjacency matrix from the network with nx.adjacency_matrix:
m = nx.adjacency_matrix(g)
m.todense()
matrix([[0, 1, 0, 1, 0],
[0, 0, 1, 0, 1],
[0, 0, 0, 1, 0],
[0, 0, 0, 0, 1],
[1, 1, 1, 0, 0]], dtype=int64)
And for a dataframe with the corresponding nodes as columns you can do:
pd.DataFrame(m.todense(), columns=nx.nodes(g))
A B C D E
0 0 1 0 1 0
1 0 0 1 0 1
2 0 0 0 1 0
3 0 0 0 0 1
4 1 1 1 0 0
add a comment |
A simple way to obtain the adjacency matrix is by using NetworkX
d = 'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
It appears that from your adjacency matrix the graph is directed. You can create a directed graph as shown bellow and define its nodes and edges from the dictionary with:
import networkx as nx
g = nx.DiGraph()
g.add_nodes_from(d['nodes'])
g.add_edges_from(d['edges'])
And then you can obtain the adjacency matrix from the network with nx.adjacency_matrix:
m = nx.adjacency_matrix(g)
m.todense()
matrix([[0, 1, 0, 1, 0],
[0, 0, 1, 0, 1],
[0, 0, 0, 1, 0],
[0, 0, 0, 0, 1],
[1, 1, 1, 0, 0]], dtype=int64)
And for a dataframe with the corresponding nodes as columns you can do:
pd.DataFrame(m.todense(), columns=nx.nodes(g))
A B C D E
0 0 1 0 1 0
1 0 0 1 0 1
2 0 0 0 1 0
3 0 0 0 0 1
4 1 1 1 0 0
add a comment |
A simple way to obtain the adjacency matrix is by using NetworkX
d = 'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
It appears that from your adjacency matrix the graph is directed. You can create a directed graph as shown bellow and define its nodes and edges from the dictionary with:
import networkx as nx
g = nx.DiGraph()
g.add_nodes_from(d['nodes'])
g.add_edges_from(d['edges'])
And then you can obtain the adjacency matrix from the network with nx.adjacency_matrix:
m = nx.adjacency_matrix(g)
m.todense()
matrix([[0, 1, 0, 1, 0],
[0, 0, 1, 0, 1],
[0, 0, 0, 1, 0],
[0, 0, 0, 0, 1],
[1, 1, 1, 0, 0]], dtype=int64)
And for a dataframe with the corresponding nodes as columns you can do:
pd.DataFrame(m.todense(), columns=nx.nodes(g))
A B C D E
0 0 1 0 1 0
1 0 0 1 0 1
2 0 0 0 1 0
3 0 0 0 0 1
4 1 1 1 0 0
A simple way to obtain the adjacency matrix is by using NetworkX
d = 'nodes':['A', 'B', 'C', 'D', 'E'],
'edges':[('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'),('E', 'B'), ('E', 'C')]
It appears that from your adjacency matrix the graph is directed. You can create a directed graph as shown bellow and define its nodes and edges from the dictionary with:
import networkx as nx
g = nx.DiGraph()
g.add_nodes_from(d['nodes'])
g.add_edges_from(d['edges'])
And then you can obtain the adjacency matrix from the network with nx.adjacency_matrix:
m = nx.adjacency_matrix(g)
m.todense()
matrix([[0, 1, 0, 1, 0],
[0, 0, 1, 0, 1],
[0, 0, 0, 1, 0],
[0, 0, 0, 0, 1],
[1, 1, 1, 0, 0]], dtype=int64)
And for a dataframe with the corresponding nodes as columns you can do:
pd.DataFrame(m.todense(), columns=nx.nodes(g))
A B C D E
0 0 1 0 1 0
1 0 0 1 0 1
2 0 0 0 1 0
3 0 0 0 0 1
4 1 1 1 0 0
edited Mar 7 at 15:49
answered Mar 7 at 12:17
yatuyatu
13.4k31341
13.4k31341
add a comment |
add a comment |
for undirected graph
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 1
B 1 0 1 0 1
C 0 1 0 1 1
D 1 0 1 0 1
E 1 1 1 1 0
for directed graph:
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
print(adj_matr)
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
# adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
add a comment |
for undirected graph
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 1
B 1 0 1 0 1
C 0 1 0 1 1
D 1 0 1 0 1
E 1 1 1 1 0
for directed graph:
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
print(adj_matr)
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
# adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
add a comment |
for undirected graph
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 1
B 1 0 1 0 1
C 0 1 0 1 1
D 1 0 1 0 1
E 1 1 1 1 0
for directed graph:
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
print(adj_matr)
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
# adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
for undirected graph
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 1
B 1 0 1 0 1
C 0 1 0 1 1
D 1 0 1 0 1
E 1 1 1 1 0
for directed graph:
graph = 'nodes': ['A', 'B', 'C', 'D', 'E'],
'edges': [('A', 'B'), ('A', 'D'), ('B', 'C'), ('B', 'E'), ('C', 'D'),
('D', 'E'), ('E', 'A'), ('E', 'B'), ('E', 'C')]
n = len(graph['nodes'])
adj_matr = pd.DataFrame(0, columns=graph['nodes'], index=graph['nodes'])
print(adj_matr)
for i in graph['edges']:
adj_matr.at[i[0], i[1]] = 1
# adj_matr.at[i[1], i[0]] = 1
print(adj_matr)
A B C D E
A 0 1 0 1 0
B 0 0 1 0 1
C 0 0 0 1 0
D 0 0 0 0 1
E 1 1 1 0 0
edited Mar 7 at 12:24
answered Mar 7 at 12:16
NihalNihal
3,22261532
3,22261532
add a comment |
add a comment |
For a directed graph you can use:
df = pd.DataFrame(graph['edges'], columns=['From', 'To'])
df['Edge'] = 1
adj = df.pivot(index='From', columns='To', values='Edge').fillna(0)
add a comment |
For a directed graph you can use:
df = pd.DataFrame(graph['edges'], columns=['From', 'To'])
df['Edge'] = 1
adj = df.pivot(index='From', columns='To', values='Edge').fillna(0)
add a comment |
For a directed graph you can use:
df = pd.DataFrame(graph['edges'], columns=['From', 'To'])
df['Edge'] = 1
adj = df.pivot(index='From', columns='To', values='Edge').fillna(0)
For a directed graph you can use:
df = pd.DataFrame(graph['edges'], columns=['From', 'To'])
df['Edge'] = 1
adj = df.pivot(index='From', columns='To', values='Edge').fillna(0)
edited Mar 7 at 13:37
answered Mar 7 at 13:32
JoergVanAkenJoergVanAken
84167
84167
add a comment |
add a comment |
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1
What's the expected output?
– pistol2myhead
Mar 7 at 12:12
thank you, I added it now. Currently the dataframe/matrix is filled in with all 0s
– Frederic Bastiat
Mar 7 at 12:16
Updated the answer @FredericBastiat , as it seems from your adjacency matrix that the graph is directed
– yatu
Mar 7 at 15:51