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Filtering Exactly Same String Returns 0
2019 Community Moderator ElectionWhat is the difference between String and string in C#?How do I iterate over the words of a string?How do I read / convert an InputStream into a String in Java?Case insensitive 'Contains(string)'How do I make the first letter of a string uppercase in JavaScript?How to replace all occurrences of a string in JavaScriptHow to check whether a string contains a substring in JavaScript?Does Python have a string 'contains' substring method?How do I convert a String to an int in Java?Why is char[] preferred over String for passwords?
I have customer rentals data based on region. I want to filter a specific, I copy region name from data and still returns 0 rows.
Rentals[Rentals$Region == "Paris",]
I can't understand what is the problem and how to solve it.
Thank you.
r string filter character
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
add a comment |
I have customer rentals data based on region. I want to filter a specific, I copy region name from data and still returns 0 rows.
Rentals[Rentals$Region == "Paris",]
I can't understand what is the problem and how to solve it.
Thank you.
r string filter character
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
Check if there is leading/lagging spacesRentals[trimws(Rentals$Region) == "Paris",](A reproducible example withdputwould be better)
– akrun
Mar 7 at 12:18
Please add a reproducible example. Do adput(data)on your data. If your data is too big, do adput(head(data)).
– boski
Mar 7 at 12:19
1
@akrun It worked. I use this code:Rentals$Region <- trimws(Rentals$Region)and now it works. Thank you.
– Ece Özçınar
Mar 7 at 12:28
add a comment |
I have customer rentals data based on region. I want to filter a specific, I copy region name from data and still returns 0 rows.
Rentals[Rentals$Region == "Paris",]
I can't understand what is the problem and how to solve it.
Thank you.
r string filter character
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
I have customer rentals data based on region. I want to filter a specific, I copy region name from data and still returns 0 rows.
Rentals[Rentals$Region == "Paris",]
I can't understand what is the problem and how to solve it.
Thank you.
r string filter character
r string filter character
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
edited Mar 7 at 12:52
Saurabh Chauhan
2,2521825
2,2521825
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
asked Mar 7 at 12:16
Ece ÖzçınarEce Özçınar
1
1
Check if there is leading/lagging spacesRentals[trimws(Rentals$Region) == "Paris",](A reproducible example withdputwould be better)
– akrun
Mar 7 at 12:18
Please add a reproducible example. Do adput(data)on your data. If your data is too big, do adput(head(data)).
– boski
Mar 7 at 12:19
1
@akrun It worked. I use this code:Rentals$Region <- trimws(Rentals$Region)and now it works. Thank you.
– Ece Özçınar
Mar 7 at 12:28
add a comment |
Check if there is leading/lagging spacesRentals[trimws(Rentals$Region) == "Paris",](A reproducible example withdputwould be better)
– akrun
Mar 7 at 12:18
Please add a reproducible example. Do adput(data)on your data. If your data is too big, do adput(head(data)).
– boski
Mar 7 at 12:19
1
@akrun It worked. I use this code:Rentals$Region <- trimws(Rentals$Region)and now it works. Thank you.
– Ece Özçınar
Mar 7 at 12:28
Check if there is leading/lagging spaces
Rentals[trimws(Rentals$Region) == "Paris",] (A reproducible example with dput would be better)– akrun
Mar 7 at 12:18
Check if there is leading/lagging spaces
Rentals[trimws(Rentals$Region) == "Paris",] (A reproducible example with dput would be better)– akrun
Mar 7 at 12:18
Please add a reproducible example. Do a
dput(data) on your data. If your data is too big, do a dput(head(data)).– boski
Mar 7 at 12:19
Please add a reproducible example. Do a
dput(data) on your data. If your data is too big, do a dput(head(data)).– boski
Mar 7 at 12:19
1
1
@akrun It worked. I use this code:
Rentals$Region <- trimws(Rentals$Region) and now it works. Thank you.– Ece Özçınar
Mar 7 at 12:28
@akrun It worked. I use this code:
Rentals$Region <- trimws(Rentals$Region) and now it works. Thank you.– Ece Özçınar
Mar 7 at 12:28
add a comment |
2 Answers
2
active
oldest
votes
The issue would be in having leading/lagging spaces in strings. It can be resolved with trimws that removes the white space from both ends (if any).
Rentals[trimws(Rentals$Region) == "Paris",]
answered Mar 7 at 14:20
akrunakrun
414k13201275
add a comment |
Try installing and loading dplyr and perform filtering action...
install.package("dplyr")
library(dplyr)
filter(Rentals, Region == "Paris")
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
There's no reason this would be different. (Also, you need the lastsininstall.packages. And quotes around"dplyr"in that line.)
– Gregor
Mar 7 at 12:55
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
The issue would be in having leading/lagging spaces in strings. It can be resolved with trimws that removes the white space from both ends (if any).
Rentals[trimws(Rentals$Region) == "Paris",]
answered Mar 7 at 14:20
akrunakrun
414k13201275
add a comment |
The issue would be in having leading/lagging spaces in strings. It can be resolved with trimws that removes the white space from both ends (if any).
Rentals[trimws(Rentals$Region) == "Paris",]
answered Mar 7 at 14:20
akrunakrun
414k13201275
add a comment |
The issue would be in having leading/lagging spaces in strings. It can be resolved with trimws that removes the white space from both ends (if any).
Rentals[trimws(Rentals$Region) == "Paris",]
answered Mar 7 at 14:20
akrunakrun
414k13201275
The issue would be in having leading/lagging spaces in strings. It can be resolved with trimws that removes the white space from both ends (if any).
Rentals[trimws(Rentals$Region) == "Paris",]
answered Mar 7 at 14:20
akrunakrun
414k13201275
answered Mar 7 at 14:20
akrunakrun
414k13201275
answered Mar 7 at 14:20
akrunakrun
414k13201275
answered Mar 7 at 14:20
akrunakrun
414k13201275
414k13201275
add a comment |
add a comment |
Try installing and loading dplyr and perform filtering action...
install.package("dplyr")
library(dplyr)
filter(Rentals, Region == "Paris")
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
There's no reason this would be different. (Also, you need the lastsininstall.packages. And quotes around"dplyr"in that line.)
– Gregor
Mar 7 at 12:55
add a comment |
Try installing and loading dplyr and perform filtering action...
install.package("dplyr")
library(dplyr)
filter(Rentals, Region == "Paris")
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
There's no reason this would be different. (Also, you need the lastsininstall.packages. And quotes around"dplyr"in that line.)
– Gregor
Mar 7 at 12:55
add a comment |
Try installing and loading dplyr and perform filtering action...
install.package("dplyr")
library(dplyr)
filter(Rentals, Region == "Paris")
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
Try installing and loading dplyr and perform filtering action...
install.package("dplyr")
library(dplyr)
filter(Rentals, Region == "Paris")
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
edited Mar 7 at 12:58
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
answered Mar 7 at 12:25
Shahruq SarfarazShahruq Sarfaraz
113
113
There's no reason this would be different. (Also, you need the lastsininstall.packages. And quotes around"dplyr"in that line.)
– Gregor
Mar 7 at 12:55
add a comment |
There's no reason this would be different. (Also, you need the lastsininstall.packages. And quotes around"dplyr"in that line.)
– Gregor
Mar 7 at 12:55
There's no reason this would be different. (Also, you need the last
s in install.packages. And quotes around "dplyr" in that line.)– Gregor
Mar 7 at 12:55
There's no reason this would be different. (Also, you need the last
s in install.packages. And quotes around "dplyr" in that line.)– Gregor
Mar 7 at 12:55
add a comment |
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Check if there is leading/lagging spaces
Rentals[trimws(Rentals$Region) == "Paris",](A reproducible example withdputwould be better)– akrun
Mar 7 at 12:18
Please add a reproducible example. Do a
dput(data)on your data. If your data is too big, do adput(head(data)).– boski
Mar 7 at 12:19
1
@akrun It worked. I use this code:
Rentals$Region <- trimws(Rentals$Region)and now it works. Thank you.– Ece Özçınar
Mar 7 at 12:28