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SQL - group by another SQL statement with multiple rows



2019 Community Moderator ElectionHow can I prevent SQL injection in PHP?Add a column with a default value to an existing table in SQL ServerHow to concatenate text from multiple rows into a single text string in SQL server?Can I concatenate multiple MySQL rows into one field?Inserting multiple rows in a single SQL query?How do I UPDATE from a SELECT in SQL Server?Select first row in each GROUP BY group?SQL select only rows with max value on a columnHow to import an SQL file using the command line in MySQL?How to convert a row value to column header in mysql for Wordpress database










1















I am trying to get an SQL statement for wordpress to work by grouping different meta columns.



I have one table with votes, one table with locations and one table with reference links to some cities (Each city can contain multiple locations).



I am trying to group all votes based on each big city, but I am having some trouble putting the two SQL statements into one.



Here is the query to get the top 50 locations in terms of number of votes:



SELECT Count(*) as Amount, meta.meta_value as Location FROM wp_votes as votes
LEFT JOIN wp_postmeta as meta ON votes.`post_id` = meta.`post_id`
WHERE meta.meta_key = 'location'
AND votes.`post_id` IS NOT NULL AND votes.`post_id` <> 0
GROUP BY meta.meta_value
ORDER BY Amount DESC
LIMIT 50;


This returns a response like this:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1250 | Brooklyn |
|---------------------|------------------|
| 400 | Manhattan |
|---------------------|------------------|
| 300 | Chicago |


And here is the query to get the Cities based on the location. It returns a list of cities (in the example above it would just return New York) and the two locations "Brooklyn", "Manhattan" would be "included" in New York.



SELECT meta_value FROM wp_posts as location
LEFT JOIN wp_postmeta as city ON city.`post_id` = location.`ID`
WHERE city.`meta_key` = 'reference'
GROUP BY city.`meta_value`;


The idea here is to map these two queries together, so that if there is a match in location from the first query and the location in the second query, it would group the rows by the city name instead.



So the output for the combined queries would be:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1650 | New York |
|---------------------|------------------|
| 300 | Chicago |
|---------------------|------------------|


Is this possible?










share|improve this question






















  • That LEFT JOIN returns regular INNER JOIN result since you have the outer table conditions in the WHERE clause. Move city conditions to the ON clause to get true LEFT JOIN result.

    – jarlh
    Mar 7 at 12:25
















1















I am trying to get an SQL statement for wordpress to work by grouping different meta columns.



I have one table with votes, one table with locations and one table with reference links to some cities (Each city can contain multiple locations).



I am trying to group all votes based on each big city, but I am having some trouble putting the two SQL statements into one.



Here is the query to get the top 50 locations in terms of number of votes:



SELECT Count(*) as Amount, meta.meta_value as Location FROM wp_votes as votes
LEFT JOIN wp_postmeta as meta ON votes.`post_id` = meta.`post_id`
WHERE meta.meta_key = 'location'
AND votes.`post_id` IS NOT NULL AND votes.`post_id` <> 0
GROUP BY meta.meta_value
ORDER BY Amount DESC
LIMIT 50;


This returns a response like this:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1250 | Brooklyn |
|---------------------|------------------|
| 400 | Manhattan |
|---------------------|------------------|
| 300 | Chicago |


And here is the query to get the Cities based on the location. It returns a list of cities (in the example above it would just return New York) and the two locations "Brooklyn", "Manhattan" would be "included" in New York.



SELECT meta_value FROM wp_posts as location
LEFT JOIN wp_postmeta as city ON city.`post_id` = location.`ID`
WHERE city.`meta_key` = 'reference'
GROUP BY city.`meta_value`;


The idea here is to map these two queries together, so that if there is a match in location from the first query and the location in the second query, it would group the rows by the city name instead.



So the output for the combined queries would be:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1650 | New York |
|---------------------|------------------|
| 300 | Chicago |
|---------------------|------------------|


Is this possible?










share|improve this question






















  • That LEFT JOIN returns regular INNER JOIN result since you have the outer table conditions in the WHERE clause. Move city conditions to the ON clause to get true LEFT JOIN result.

    – jarlh
    Mar 7 at 12:25














1












1








1








I am trying to get an SQL statement for wordpress to work by grouping different meta columns.



I have one table with votes, one table with locations and one table with reference links to some cities (Each city can contain multiple locations).



I am trying to group all votes based on each big city, but I am having some trouble putting the two SQL statements into one.



Here is the query to get the top 50 locations in terms of number of votes:



SELECT Count(*) as Amount, meta.meta_value as Location FROM wp_votes as votes
LEFT JOIN wp_postmeta as meta ON votes.`post_id` = meta.`post_id`
WHERE meta.meta_key = 'location'
AND votes.`post_id` IS NOT NULL AND votes.`post_id` <> 0
GROUP BY meta.meta_value
ORDER BY Amount DESC
LIMIT 50;


This returns a response like this:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1250 | Brooklyn |
|---------------------|------------------|
| 400 | Manhattan |
|---------------------|------------------|
| 300 | Chicago |


And here is the query to get the Cities based on the location. It returns a list of cities (in the example above it would just return New York) and the two locations "Brooklyn", "Manhattan" would be "included" in New York.



SELECT meta_value FROM wp_posts as location
LEFT JOIN wp_postmeta as city ON city.`post_id` = location.`ID`
WHERE city.`meta_key` = 'reference'
GROUP BY city.`meta_value`;


The idea here is to map these two queries together, so that if there is a match in location from the first query and the location in the second query, it would group the rows by the city name instead.



So the output for the combined queries would be:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1650 | New York |
|---------------------|------------------|
| 300 | Chicago |
|---------------------|------------------|


Is this possible?










share|improve this question














I am trying to get an SQL statement for wordpress to work by grouping different meta columns.



I have one table with votes, one table with locations and one table with reference links to some cities (Each city can contain multiple locations).



I am trying to group all votes based on each big city, but I am having some trouble putting the two SQL statements into one.



Here is the query to get the top 50 locations in terms of number of votes:



SELECT Count(*) as Amount, meta.meta_value as Location FROM wp_votes as votes
LEFT JOIN wp_postmeta as meta ON votes.`post_id` = meta.`post_id`
WHERE meta.meta_key = 'location'
AND votes.`post_id` IS NOT NULL AND votes.`post_id` <> 0
GROUP BY meta.meta_value
ORDER BY Amount DESC
LIMIT 50;


This returns a response like this:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1250 | Brooklyn |
|---------------------|------------------|
| 400 | Manhattan |
|---------------------|------------------|
| 300 | Chicago |


And here is the query to get the Cities based on the location. It returns a list of cities (in the example above it would just return New York) and the two locations "Brooklyn", "Manhattan" would be "included" in New York.



SELECT meta_value FROM wp_posts as location
LEFT JOIN wp_postmeta as city ON city.`post_id` = location.`ID`
WHERE city.`meta_key` = 'reference'
GROUP BY city.`meta_value`;


The idea here is to map these two queries together, so that if there is a match in location from the first query and the location in the second query, it would group the rows by the city name instead.



So the output for the combined queries would be:



|---------------------|------------------|
| Amount | meta_value |
|---------------------|------------------|
| 1650 | New York |
|---------------------|------------------|
| 300 | Chicago |
|---------------------|------------------|


Is this possible?







mysql sql database wordpress






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 7 at 12:24









user2868900user2868900

8413




8413












  • That LEFT JOIN returns regular INNER JOIN result since you have the outer table conditions in the WHERE clause. Move city conditions to the ON clause to get true LEFT JOIN result.

    – jarlh
    Mar 7 at 12:25


















  • That LEFT JOIN returns regular INNER JOIN result since you have the outer table conditions in the WHERE clause. Move city conditions to the ON clause to get true LEFT JOIN result.

    – jarlh
    Mar 7 at 12:25

















That LEFT JOIN returns regular INNER JOIN result since you have the outer table conditions in the WHERE clause. Move city conditions to the ON clause to get true LEFT JOIN result.

– jarlh
Mar 7 at 12:25






That LEFT JOIN returns regular INNER JOIN result since you have the outer table conditions in the WHERE clause. Move city conditions to the ON clause to get true LEFT JOIN result.

– jarlh
Mar 7 at 12:25













1 Answer
1






active

oldest

votes


















0














Just include a second JOIN to get the reference:



SELECT c.meta_value as city, Count(*) as Amount 
FROM wp_votes v LEFT JOIN
wp_postmeta l
ON v.`post_id` = l.`post_id` AND
l.meta_key = 'location' LEFT JOIN
wp_postmeta c
ON l.id = c.`post_id` AND
c.meta_key = 'city'
WHERE v.`post_id` IS NOT NULL AND v.`post_id` <> 0
GROUP BY c.meta_value
ORDER BY Amount DESC
LIMIT 50;





share|improve this answer

























  • Thank you for the answer! Although, when running this query I just get one single row with all votes as result. The problem might be that the locations and cities in the second query are separate entries (i.e. not linked to the posts in the first query). So I need to check if the location-values in the first query matches any of the location-values in the second query and then do the sorting

    – user2868900
    Mar 7 at 12:48











  • @user2868900 . . . Something seems wrong with the data model, because you are using post_id for a different purpose. In any case, this is fixed by adjusting the JOIN condition.

    – Gordon Linoff
    Mar 7 at 13:34











  • The data model becomes really messed up due to this being a wordpress site, and the functionality added is based on Advanced Custom Fields and frontend functionality rather than an actual data model. Thank you, I will try to make it work.

    – user2868900
    Mar 7 at 14:03










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Just include a second JOIN to get the reference:



SELECT c.meta_value as city, Count(*) as Amount 
FROM wp_votes v LEFT JOIN
wp_postmeta l
ON v.`post_id` = l.`post_id` AND
l.meta_key = 'location' LEFT JOIN
wp_postmeta c
ON l.id = c.`post_id` AND
c.meta_key = 'city'
WHERE v.`post_id` IS NOT NULL AND v.`post_id` <> 0
GROUP BY c.meta_value
ORDER BY Amount DESC
LIMIT 50;





share|improve this answer

























  • Thank you for the answer! Although, when running this query I just get one single row with all votes as result. The problem might be that the locations and cities in the second query are separate entries (i.e. not linked to the posts in the first query). So I need to check if the location-values in the first query matches any of the location-values in the second query and then do the sorting

    – user2868900
    Mar 7 at 12:48











  • @user2868900 . . . Something seems wrong with the data model, because you are using post_id for a different purpose. In any case, this is fixed by adjusting the JOIN condition.

    – Gordon Linoff
    Mar 7 at 13:34











  • The data model becomes really messed up due to this being a wordpress site, and the functionality added is based on Advanced Custom Fields and frontend functionality rather than an actual data model. Thank you, I will try to make it work.

    – user2868900
    Mar 7 at 14:03















0














Just include a second JOIN to get the reference:



SELECT c.meta_value as city, Count(*) as Amount 
FROM wp_votes v LEFT JOIN
wp_postmeta l
ON v.`post_id` = l.`post_id` AND
l.meta_key = 'location' LEFT JOIN
wp_postmeta c
ON l.id = c.`post_id` AND
c.meta_key = 'city'
WHERE v.`post_id` IS NOT NULL AND v.`post_id` <> 0
GROUP BY c.meta_value
ORDER BY Amount DESC
LIMIT 50;





share|improve this answer

























  • Thank you for the answer! Although, when running this query I just get one single row with all votes as result. The problem might be that the locations and cities in the second query are separate entries (i.e. not linked to the posts in the first query). So I need to check if the location-values in the first query matches any of the location-values in the second query and then do the sorting

    – user2868900
    Mar 7 at 12:48











  • @user2868900 . . . Something seems wrong with the data model, because you are using post_id for a different purpose. In any case, this is fixed by adjusting the JOIN condition.

    – Gordon Linoff
    Mar 7 at 13:34











  • The data model becomes really messed up due to this being a wordpress site, and the functionality added is based on Advanced Custom Fields and frontend functionality rather than an actual data model. Thank you, I will try to make it work.

    – user2868900
    Mar 7 at 14:03













0












0








0







Just include a second JOIN to get the reference:



SELECT c.meta_value as city, Count(*) as Amount 
FROM wp_votes v LEFT JOIN
wp_postmeta l
ON v.`post_id` = l.`post_id` AND
l.meta_key = 'location' LEFT JOIN
wp_postmeta c
ON l.id = c.`post_id` AND
c.meta_key = 'city'
WHERE v.`post_id` IS NOT NULL AND v.`post_id` <> 0
GROUP BY c.meta_value
ORDER BY Amount DESC
LIMIT 50;





share|improve this answer















Just include a second JOIN to get the reference:



SELECT c.meta_value as city, Count(*) as Amount 
FROM wp_votes v LEFT JOIN
wp_postmeta l
ON v.`post_id` = l.`post_id` AND
l.meta_key = 'location' LEFT JOIN
wp_postmeta c
ON l.id = c.`post_id` AND
c.meta_key = 'city'
WHERE v.`post_id` IS NOT NULL AND v.`post_id` <> 0
GROUP BY c.meta_value
ORDER BY Amount DESC
LIMIT 50;






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 7 at 13:34

























answered Mar 7 at 12:28









Gordon LinoffGordon Linoff

786k35310416




786k35310416












  • Thank you for the answer! Although, when running this query I just get one single row with all votes as result. The problem might be that the locations and cities in the second query are separate entries (i.e. not linked to the posts in the first query). So I need to check if the location-values in the first query matches any of the location-values in the second query and then do the sorting

    – user2868900
    Mar 7 at 12:48











  • @user2868900 . . . Something seems wrong with the data model, because you are using post_id for a different purpose. In any case, this is fixed by adjusting the JOIN condition.

    – Gordon Linoff
    Mar 7 at 13:34











  • The data model becomes really messed up due to this being a wordpress site, and the functionality added is based on Advanced Custom Fields and frontend functionality rather than an actual data model. Thank you, I will try to make it work.

    – user2868900
    Mar 7 at 14:03

















  • Thank you for the answer! Although, when running this query I just get one single row with all votes as result. The problem might be that the locations and cities in the second query are separate entries (i.e. not linked to the posts in the first query). So I need to check if the location-values in the first query matches any of the location-values in the second query and then do the sorting

    – user2868900
    Mar 7 at 12:48











  • @user2868900 . . . Something seems wrong with the data model, because you are using post_id for a different purpose. In any case, this is fixed by adjusting the JOIN condition.

    – Gordon Linoff
    Mar 7 at 13:34











  • The data model becomes really messed up due to this being a wordpress site, and the functionality added is based on Advanced Custom Fields and frontend functionality rather than an actual data model. Thank you, I will try to make it work.

    – user2868900
    Mar 7 at 14:03
















Thank you for the answer! Although, when running this query I just get one single row with all votes as result. The problem might be that the locations and cities in the second query are separate entries (i.e. not linked to the posts in the first query). So I need to check if the location-values in the first query matches any of the location-values in the second query and then do the sorting

– user2868900
Mar 7 at 12:48





Thank you for the answer! Although, when running this query I just get one single row with all votes as result. The problem might be that the locations and cities in the second query are separate entries (i.e. not linked to the posts in the first query). So I need to check if the location-values in the first query matches any of the location-values in the second query and then do the sorting

– user2868900
Mar 7 at 12:48













@user2868900 . . . Something seems wrong with the data model, because you are using post_id for a different purpose. In any case, this is fixed by adjusting the JOIN condition.

– Gordon Linoff
Mar 7 at 13:34





@user2868900 . . . Something seems wrong with the data model, because you are using post_id for a different purpose. In any case, this is fixed by adjusting the JOIN condition.

– Gordon Linoff
Mar 7 at 13:34













The data model becomes really messed up due to this being a wordpress site, and the functionality added is based on Advanced Custom Fields and frontend functionality rather than an actual data model. Thank you, I will try to make it work.

– user2868900
Mar 7 at 14:03





The data model becomes really messed up due to this being a wordpress site, and the functionality added is based on Advanced Custom Fields and frontend functionality rather than an actual data model. Thank you, I will try to make it work.

– user2868900
Mar 7 at 14:03



















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