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Java:Replace specific word with other content unchanged



2019 Community Moderator ElectionHow do I create a Java string from the contents of a file?How do I generate random integers within a specific range in Java?Regular expression to match a line that doesn't contain a word?How to negate specific word in regex?Is there a way to capture each group if multiple occurrences are matched?Greedy vs. Reluctant vs. Possessive QuantifiersThe usage of Pattern, Matcher, replaceTrouble trying to negate a word in Java regexNeed a way to print out lookahead portion of a regex pattern in java?Replace instead of append in java pattern matching?










-1















I am new here and would you like to help me?



There may be lines like




389 392 "magnifyingglas" 1 0 4 392 6616 0 8529270
0 |



390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |



391 391 "weaponrack" 1 0 6 390 6631 0 6800 0 |




I want to subtract 20 from the second number.



Like




390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |




To




390 371 "armourstand" 1 0 6 391 6630 0 6800 0 |




But I don't know how to do it.



I may get the second number,then I don't know how to do with it.
There may be same numbers in this line,but I just want to replace the second number.



Thanks a lot.



============================================================================
update



 Pattern p = Pattern.compile("^(\d+)\s+3(9)[0-2]\sS+\s+(1)\s+\d\s+6") ;
Matcher m = p.matcher("6621 391 "weaponrack" 1 0 6 371 6631 0 6800 0 |") ;


I want something like this



m.group(2).replace(7);


But I could find the similar method.



I see some documents say that we can use "$" to get the group reference, and it doesn't explain more.



Well, I read lines from text, and use "^(d+)s+3(7)0-21(s+ds+)6"
to find the matched line.
And then I need to replace the 39[0-2] to be 37[0-2].
It can be done by minus 20 or other ways which I don't care.










share|improve this question
























  • You can add some code and contextualize your doubt for a better understanding from the community

    – tomrlh
    Mar 7 at 12:39











  • You just provide a better context of you are trying to do. I don't know what you are talking about. Do you always have 6 digits in your first number?

    – Ctorres
    Mar 7 at 13:16















-1















I am new here and would you like to help me?



There may be lines like




389 392 "magnifyingglas" 1 0 4 392 6616 0 8529270
0 |



390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |



391 391 "weaponrack" 1 0 6 390 6631 0 6800 0 |




I want to subtract 20 from the second number.



Like




390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |




To




390 371 "armourstand" 1 0 6 391 6630 0 6800 0 |




But I don't know how to do it.



I may get the second number,then I don't know how to do with it.
There may be same numbers in this line,but I just want to replace the second number.



Thanks a lot.



============================================================================
update



 Pattern p = Pattern.compile("^(\d+)\s+3(9)[0-2]\sS+\s+(1)\s+\d\s+6") ;
Matcher m = p.matcher("6621 391 "weaponrack" 1 0 6 371 6631 0 6800 0 |") ;


I want something like this



m.group(2).replace(7);


But I could find the similar method.



I see some documents say that we can use "$" to get the group reference, and it doesn't explain more.



Well, I read lines from text, and use "^(d+)s+3(7)0-21(s+ds+)6"
to find the matched line.
And then I need to replace the 39[0-2] to be 37[0-2].
It can be done by minus 20 or other ways which I don't care.










share|improve this question
























  • You can add some code and contextualize your doubt for a better understanding from the community

    – tomrlh
    Mar 7 at 12:39











  • You just provide a better context of you are trying to do. I don't know what you are talking about. Do you always have 6 digits in your first number?

    – Ctorres
    Mar 7 at 13:16













-1












-1








-1








I am new here and would you like to help me?



There may be lines like




389 392 "magnifyingglas" 1 0 4 392 6616 0 8529270
0 |



390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |



391 391 "weaponrack" 1 0 6 390 6631 0 6800 0 |




I want to subtract 20 from the second number.



Like




390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |




To




390 371 "armourstand" 1 0 6 391 6630 0 6800 0 |




But I don't know how to do it.



I may get the second number,then I don't know how to do with it.
There may be same numbers in this line,but I just want to replace the second number.



Thanks a lot.



============================================================================
update



 Pattern p = Pattern.compile("^(\d+)\s+3(9)[0-2]\sS+\s+(1)\s+\d\s+6") ;
Matcher m = p.matcher("6621 391 "weaponrack" 1 0 6 371 6631 0 6800 0 |") ;


I want something like this



m.group(2).replace(7);


But I could find the similar method.



I see some documents say that we can use "$" to get the group reference, and it doesn't explain more.



Well, I read lines from text, and use "^(d+)s+3(7)0-21(s+ds+)6"
to find the matched line.
And then I need to replace the 39[0-2] to be 37[0-2].
It can be done by minus 20 or other ways which I don't care.










share|improve this question
















I am new here and would you like to help me?



There may be lines like




389 392 "magnifyingglas" 1 0 4 392 6616 0 8529270
0 |



390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |



391 391 "weaponrack" 1 0 6 390 6631 0 6800 0 |




I want to subtract 20 from the second number.



Like




390 391 "armourstand" 1 0 6 391 6630 0 6800 0 |




To




390 371 "armourstand" 1 0 6 391 6630 0 6800 0 |




But I don't know how to do it.



I may get the second number,then I don't know how to do with it.
There may be same numbers in this line,but I just want to replace the second number.



Thanks a lot.



============================================================================
update



 Pattern p = Pattern.compile("^(\d+)\s+3(9)[0-2]\sS+\s+(1)\s+\d\s+6") ;
Matcher m = p.matcher("6621 391 "weaponrack" 1 0 6 371 6631 0 6800 0 |") ;


I want something like this



m.group(2).replace(7);


But I could find the similar method.



I see some documents say that we can use "$" to get the group reference, and it doesn't explain more.



Well, I read lines from text, and use "^(d+)s+3(7)0-21(s+ds+)6"
to find the matched line.
And then I need to replace the 39[0-2] to be 37[0-2].
It can be done by minus 20 or other ways which I don't care.







java regex regex-group






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 9 at 5:20







Sharon_Xu

















asked Mar 7 at 12:30









Sharon_XuSharon_Xu

12




12












  • You can add some code and contextualize your doubt for a better understanding from the community

    – tomrlh
    Mar 7 at 12:39











  • You just provide a better context of you are trying to do. I don't know what you are talking about. Do you always have 6 digits in your first number?

    – Ctorres
    Mar 7 at 13:16

















  • You can add some code and contextualize your doubt for a better understanding from the community

    – tomrlh
    Mar 7 at 12:39











  • You just provide a better context of you are trying to do. I don't know what you are talking about. Do you always have 6 digits in your first number?

    – Ctorres
    Mar 7 at 13:16
















You can add some code and contextualize your doubt for a better understanding from the community

– tomrlh
Mar 7 at 12:39





You can add some code and contextualize your doubt for a better understanding from the community

– tomrlh
Mar 7 at 12:39













You just provide a better context of you are trying to do. I don't know what you are talking about. Do you always have 6 digits in your first number?

– Ctorres
Mar 7 at 13:16





You just provide a better context of you are trying to do. I don't know what you are talking about. Do you always have 6 digits in your first number?

– Ctorres
Mar 7 at 13:16












1 Answer
1






active

oldest

votes


















0














Well,@Ctorres gives me an idea now.



When I get the matched line,put it in a char array.



First we skip the array first number,and blank spaces.



Then change the char'9' to be '7'.



But I think it's really complex.






share|improve this answer






















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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Well,@Ctorres gives me an idea now.



    When I get the matched line,put it in a char array.



    First we skip the array first number,and blank spaces.



    Then change the char'9' to be '7'.



    But I think it's really complex.






    share|improve this answer



























      0














      Well,@Ctorres gives me an idea now.



      When I get the matched line,put it in a char array.



      First we skip the array first number,and blank spaces.



      Then change the char'9' to be '7'.



      But I think it's really complex.






      share|improve this answer

























        0












        0








        0







        Well,@Ctorres gives me an idea now.



        When I get the matched line,put it in a char array.



        First we skip the array first number,and blank spaces.



        Then change the char'9' to be '7'.



        But I think it's really complex.






        share|improve this answer













        Well,@Ctorres gives me an idea now.



        When I get the matched line,put it in a char array.



        First we skip the array first number,and blank spaces.



        Then change the char'9' to be '7'.



        But I think it's really complex.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 7 at 13:39









        Sharon_XuSharon_Xu

        12




        12





























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