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Sorting Alphanumeric Lists by Character Detection (python)
How do I check if a list is empty?How do I sort a list of dictionaries by a value of the dictionary?Calling an external command in PythonWhat are metaclasses in Python?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonDoes Python have a ternary conditional operator?How do I sort a dictionary by value?Sort array of objects by string property valueHow do I list all files of a directory?
I'm making a program that is able to open a zip file and list off the file names in alphanumeric order. Here's my code:
import zipfile
import re
zip_file = zipfile.ZipFile('/home/aaaa/exploit/example.zip','r')
for name in zip_file.namelist():
sorted(str(name in zip_file.namelist()))
print(name)
zip_file.close()
And here's the output:
example/
example/txt2.txt
example/txt3.txt
example/txt1.txt
I would like name in zip_file.namelist() to be organized as such:
example/
example/txt1.txt
example/txt2.txt
example/txt3.txt
but I'm not very sure how to sort alphanumeric strings like this by the number only.
python sorting
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
asked Mar 8 at 20:40
AstradesAstrades
33
add a comment |
I'm making a program that is able to open a zip file and list off the file names in alphanumeric order. Here's my code:
import zipfile
import re
zip_file = zipfile.ZipFile('/home/aaaa/exploit/example.zip','r')
for name in zip_file.namelist():
sorted(str(name in zip_file.namelist()))
print(name)
zip_file.close()
And here's the output:
example/
example/txt2.txt
example/txt3.txt
example/txt1.txt
I would like name in zip_file.namelist() to be organized as such:
example/
example/txt1.txt
example/txt2.txt
example/txt3.txt
but I'm not very sure how to sort alphanumeric strings like this by the number only.
python sorting
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
asked Mar 8 at 20:40
AstradesAstrades
33
add a comment |
I'm making a program that is able to open a zip file and list off the file names in alphanumeric order. Here's my code:
import zipfile
import re
zip_file = zipfile.ZipFile('/home/aaaa/exploit/example.zip','r')
for name in zip_file.namelist():
sorted(str(name in zip_file.namelist()))
print(name)
zip_file.close()
And here's the output:
example/
example/txt2.txt
example/txt3.txt
example/txt1.txt
I would like name in zip_file.namelist() to be organized as such:
example/
example/txt1.txt
example/txt2.txt
example/txt3.txt
but I'm not very sure how to sort alphanumeric strings like this by the number only.
python sorting
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
asked Mar 8 at 20:40
AstradesAstrades
33
I'm making a program that is able to open a zip file and list off the file names in alphanumeric order. Here's my code:
import zipfile
import re
zip_file = zipfile.ZipFile('/home/aaaa/exploit/example.zip','r')
for name in zip_file.namelist():
sorted(str(name in zip_file.namelist()))
print(name)
zip_file.close()
And here's the output:
example/
example/txt2.txt
example/txt3.txt
example/txt1.txt
I would like name in zip_file.namelist() to be organized as such:
example/
example/txt1.txt
example/txt2.txt
example/txt3.txt
but I'm not very sure how to sort alphanumeric strings like this by the number only.
python sorting
python sorting
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
asked Mar 8 at 20:40
AstradesAstrades
33
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
asked Mar 8 at 20:40
AstradesAstrades
33
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
edited Mar 8 at 20:47
jonrsharpe
78.8k11110221
78.8k11110221
asked Mar 8 at 20:40
AstradesAstrades
33
asked Mar 8 at 20:40
AstradesAstrades
33
asked Mar 8 at 20:40
AstradesAstrades
33
33
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You aren't sorting the list before you loop through them. Try this:
for name in sorted(zip_file.namelist()):
print(name)
answered Mar 8 at 20:48
JabJab
8,228185497
p e r f e c t t y
– Astrades
Mar 8 at 20:56
add a comment |
namelist points to an internal object filelist. You can try to sort the output data: sorted(zip_file.namelist()), or either you can touch the internal object zip_file.filelist.sort() instead.
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You aren't sorting the list before you loop through them. Try this:
for name in sorted(zip_file.namelist()):
print(name)
answered Mar 8 at 20:48
JabJab
8,228185497
p e r f e c t t y
– Astrades
Mar 8 at 20:56
add a comment |
You aren't sorting the list before you loop through them. Try this:
for name in sorted(zip_file.namelist()):
print(name)
answered Mar 8 at 20:48
JabJab
8,228185497
p e r f e c t t y
– Astrades
Mar 8 at 20:56
add a comment |
You aren't sorting the list before you loop through them. Try this:
for name in sorted(zip_file.namelist()):
print(name)
answered Mar 8 at 20:48
JabJab
8,228185497
You aren't sorting the list before you loop through them. Try this:
for name in sorted(zip_file.namelist()):
print(name)
answered Mar 8 at 20:48
JabJab
8,228185497
answered Mar 8 at 20:48
JabJab
8,228185497
answered Mar 8 at 20:48
JabJab
8,228185497
answered Mar 8 at 20:48
JabJab
8,228185497
8,228185497
p e r f e c t t y
– Astrades
Mar 8 at 20:56
add a comment |
p e r f e c t t y
– Astrades
Mar 8 at 20:56
p e r f e c t t y
– Astrades
Mar 8 at 20:56
p e r f e c t t y
– Astrades
Mar 8 at 20:56
add a comment |
namelist points to an internal object filelist. You can try to sort the output data: sorted(zip_file.namelist()), or either you can touch the internal object zip_file.filelist.sort() instead.
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
add a comment |
namelist points to an internal object filelist. You can try to sort the output data: sorted(zip_file.namelist()), or either you can touch the internal object zip_file.filelist.sort() instead.
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
add a comment |
namelist points to an internal object filelist. You can try to sort the output data: sorted(zip_file.namelist()), or either you can touch the internal object zip_file.filelist.sort() instead.
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
namelist points to an internal object filelist. You can try to sort the output data: sorted(zip_file.namelist()), or either you can touch the internal object zip_file.filelist.sort() instead.
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
answered Mar 8 at 20:48
Pablo MartinezPablo Martinez
3215
3215
add a comment |
add a comment |
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