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Hide seek behavior with only the vectors towards the enemy and the hiding spot


Calculating a 2D Vector's Cross Product“for” loop in python-pygame does not break under an “if” statementSTL Sort use of Static Functioncalculate vector after rotating it towards another by angle θ in 3D spaceRay plane intersection finding direction vectorMutable structs in a vectorWrong repositioning circle after collision with segment with a vector algorithmC# and XNA — How to make 3d model follow another 3d model using lerpHave trouble with obstacle avoidance in matplotlibSKlearn: KDTree how to return nearest neighbour based on threshold (Python)













2















For a pygame class, I am asked to implement various seek behaviors with limited information about the game world. Most behaviors have been easy to do, but I am blocked trying to implement the hide behavior with the information I have access to.



I am given two vectors and the position of an agent in the world. The first vector is the distance between the agent and the enemy it has to hide from. The second vector is the distance from the agent and the nearest column it can hide behind. Given this, I'd like to move the agent towards the column and make sure it stays hidden from the enemy.



In graphical term, I am trying to find the vector b in this image, I have access to the vector u and v and I am trying to calculate the vector w plus a scalar a for the intended distance of from the column + its radius.



Vector graphics



I currently have this code running, but it is obviously wrong as the vector I calculate is outside the bounds of the game world.



player_to_col_vector = (
col_distance[0] - enemy_distance[0],
col_distance[1] - enemy_distance[1],
)

normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
dx = normalized * acceptable_distance
dy = normalized * acceptable_distance


I think my issue is that I now have the vector wa, but I have no idea how to find the b vector from the information I have.










share|improve this question




























    2















    For a pygame class, I am asked to implement various seek behaviors with limited information about the game world. Most behaviors have been easy to do, but I am blocked trying to implement the hide behavior with the information I have access to.



    I am given two vectors and the position of an agent in the world. The first vector is the distance between the agent and the enemy it has to hide from. The second vector is the distance from the agent and the nearest column it can hide behind. Given this, I'd like to move the agent towards the column and make sure it stays hidden from the enemy.



    In graphical term, I am trying to find the vector b in this image, I have access to the vector u and v and I am trying to calculate the vector w plus a scalar a for the intended distance of from the column + its radius.



    Vector graphics



    I currently have this code running, but it is obviously wrong as the vector I calculate is outside the bounds of the game world.



    player_to_col_vector = (
    col_distance[0] - enemy_distance[0],
    col_distance[1] - enemy_distance[1],
    )

    normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
    dx = normalized * acceptable_distance
    dy = normalized * acceptable_distance


    I think my issue is that I now have the vector wa, but I have no idea how to find the b vector from the information I have.










    share|improve this question


























      2












      2








      2








      For a pygame class, I am asked to implement various seek behaviors with limited information about the game world. Most behaviors have been easy to do, but I am blocked trying to implement the hide behavior with the information I have access to.



      I am given two vectors and the position of an agent in the world. The first vector is the distance between the agent and the enemy it has to hide from. The second vector is the distance from the agent and the nearest column it can hide behind. Given this, I'd like to move the agent towards the column and make sure it stays hidden from the enemy.



      In graphical term, I am trying to find the vector b in this image, I have access to the vector u and v and I am trying to calculate the vector w plus a scalar a for the intended distance of from the column + its radius.



      Vector graphics



      I currently have this code running, but it is obviously wrong as the vector I calculate is outside the bounds of the game world.



      player_to_col_vector = (
      col_distance[0] - enemy_distance[0],
      col_distance[1] - enemy_distance[1],
      )

      normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
      dx = normalized * acceptable_distance
      dy = normalized * acceptable_distance


      I think my issue is that I now have the vector wa, but I have no idea how to find the b vector from the information I have.










      share|improve this question
















      For a pygame class, I am asked to implement various seek behaviors with limited information about the game world. Most behaviors have been easy to do, but I am blocked trying to implement the hide behavior with the information I have access to.



      I am given two vectors and the position of an agent in the world. The first vector is the distance between the agent and the enemy it has to hide from. The second vector is the distance from the agent and the nearest column it can hide behind. Given this, I'd like to move the agent towards the column and make sure it stays hidden from the enemy.



      In graphical term, I am trying to find the vector b in this image, I have access to the vector u and v and I am trying to calculate the vector w plus a scalar a for the intended distance of from the column + its radius.



      Vector graphics



      I currently have this code running, but it is obviously wrong as the vector I calculate is outside the bounds of the game world.



      player_to_col_vector = (
      col_distance[0] - enemy_distance[0],
      col_distance[1] - enemy_distance[1],
      )

      normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
      dx = normalized * acceptable_distance
      dy = normalized * acceptable_distance


      I think my issue is that I now have the vector wa, but I have no idea how to find the b vector from the information I have.







      python vector






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 8 at 21:22







      GPierre

















      asked Mar 8 at 20:37









      GPierreGPierre

      559




      559






















          1 Answer
          1






          active

          oldest

          votes


















          1














          I assume that acceptable_distance corresponds to the size of the vector a in the image. So acceptable_distance is the distance between C and D



          The calculation of the normalized vector is wrong. normalized is the reciprocal length of the vector from B to C:




          normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)



          In the following lenBC is the distance between B and C. dirBC is a Unit vector (this means its length is 1) and is the direction form B to C:



          lenBC = sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
          dirBC = (player_to_col_vector[0] / lenBC, player_to_col_vector[1] / lenBC)


          (dx, dy) is the vector from C to D.



          dx, dy = (dirBC[0] * acceptable_distance, dirBC[1] * acceptable_distance)


          The vector b, which is equal the point D, is the sum of the vector v and the vector a:



          bx, by = (col_distance[0] + dx, col_distance[1] + dy) 


          The vector from the point B to D is the sum of w and a:



          BDx, BDy = (player_to_col_vector[0] + dx, player_to_col_vector[1] + dy)



          Deleted, since the tag "pygame" was removed.



          The above code does all the calculations. But note, in PyGame there is an much easier way to do this, by using pygame.math.Vector2 for calculations:



          u = pygame.math.Vector2(enemy_distance)
          v = pygame.math.Vector2(col_distance)

          w = v - u
          a = w.normalize() * acceptable_distance
          b = v + a







          share|improve this answer

























          • Due to how the assignment has been made, we cannot import anything. The main code evaluates my code at run time and gives me some functions I can call by adding them to the top of my file. Vector math is not part of those functions sadly.

            – GPierre
            Mar 8 at 21:15











          • @GPierre pygame.math.Vector2 is part of PyGame. You tagged the question <pgame> all you've to is import pygame! Anyway the 1st part of the answer solves your issue with out any library functions.

            – Rabbid76
            Mar 8 at 21:16












          • I probably shouldn't have tagged pygame even though it's a pygame assignment. If we import anything in that assignment, it's an automatic 0 >.>

            – GPierre
            Mar 8 at 21:22











          • It works! Thanks a bunch

            – GPierre
            Mar 8 at 21:31











          • @GPierre You're welcome.

            – Rabbid76
            Mar 8 at 21:32











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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          1














          I assume that acceptable_distance corresponds to the size of the vector a in the image. So acceptable_distance is the distance between C and D



          The calculation of the normalized vector is wrong. normalized is the reciprocal length of the vector from B to C:




          normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)



          In the following lenBC is the distance between B and C. dirBC is a Unit vector (this means its length is 1) and is the direction form B to C:



          lenBC = sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
          dirBC = (player_to_col_vector[0] / lenBC, player_to_col_vector[1] / lenBC)


          (dx, dy) is the vector from C to D.



          dx, dy = (dirBC[0] * acceptable_distance, dirBC[1] * acceptable_distance)


          The vector b, which is equal the point D, is the sum of the vector v and the vector a:



          bx, by = (col_distance[0] + dx, col_distance[1] + dy) 


          The vector from the point B to D is the sum of w and a:



          BDx, BDy = (player_to_col_vector[0] + dx, player_to_col_vector[1] + dy)



          Deleted, since the tag "pygame" was removed.



          The above code does all the calculations. But note, in PyGame there is an much easier way to do this, by using pygame.math.Vector2 for calculations:



          u = pygame.math.Vector2(enemy_distance)
          v = pygame.math.Vector2(col_distance)

          w = v - u
          a = w.normalize() * acceptable_distance
          b = v + a







          share|improve this answer

























          • Due to how the assignment has been made, we cannot import anything. The main code evaluates my code at run time and gives me some functions I can call by adding them to the top of my file. Vector math is not part of those functions sadly.

            – GPierre
            Mar 8 at 21:15











          • @GPierre pygame.math.Vector2 is part of PyGame. You tagged the question <pgame> all you've to is import pygame! Anyway the 1st part of the answer solves your issue with out any library functions.

            – Rabbid76
            Mar 8 at 21:16












          • I probably shouldn't have tagged pygame even though it's a pygame assignment. If we import anything in that assignment, it's an automatic 0 >.>

            – GPierre
            Mar 8 at 21:22











          • It works! Thanks a bunch

            – GPierre
            Mar 8 at 21:31











          • @GPierre You're welcome.

            – Rabbid76
            Mar 8 at 21:32















          1














          I assume that acceptable_distance corresponds to the size of the vector a in the image. So acceptable_distance is the distance between C and D



          The calculation of the normalized vector is wrong. normalized is the reciprocal length of the vector from B to C:




          normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)



          In the following lenBC is the distance between B and C. dirBC is a Unit vector (this means its length is 1) and is the direction form B to C:



          lenBC = sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
          dirBC = (player_to_col_vector[0] / lenBC, player_to_col_vector[1] / lenBC)


          (dx, dy) is the vector from C to D.



          dx, dy = (dirBC[0] * acceptable_distance, dirBC[1] * acceptable_distance)


          The vector b, which is equal the point D, is the sum of the vector v and the vector a:



          bx, by = (col_distance[0] + dx, col_distance[1] + dy) 


          The vector from the point B to D is the sum of w and a:



          BDx, BDy = (player_to_col_vector[0] + dx, player_to_col_vector[1] + dy)



          Deleted, since the tag "pygame" was removed.



          The above code does all the calculations. But note, in PyGame there is an much easier way to do this, by using pygame.math.Vector2 for calculations:



          u = pygame.math.Vector2(enemy_distance)
          v = pygame.math.Vector2(col_distance)

          w = v - u
          a = w.normalize() * acceptable_distance
          b = v + a







          share|improve this answer

























          • Due to how the assignment has been made, we cannot import anything. The main code evaluates my code at run time and gives me some functions I can call by adding them to the top of my file. Vector math is not part of those functions sadly.

            – GPierre
            Mar 8 at 21:15











          • @GPierre pygame.math.Vector2 is part of PyGame. You tagged the question <pgame> all you've to is import pygame! Anyway the 1st part of the answer solves your issue with out any library functions.

            – Rabbid76
            Mar 8 at 21:16












          • I probably shouldn't have tagged pygame even though it's a pygame assignment. If we import anything in that assignment, it's an automatic 0 >.>

            – GPierre
            Mar 8 at 21:22











          • It works! Thanks a bunch

            – GPierre
            Mar 8 at 21:31











          • @GPierre You're welcome.

            – Rabbid76
            Mar 8 at 21:32













          1












          1








          1







          I assume that acceptable_distance corresponds to the size of the vector a in the image. So acceptable_distance is the distance between C and D



          The calculation of the normalized vector is wrong. normalized is the reciprocal length of the vector from B to C:




          normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)



          In the following lenBC is the distance between B and C. dirBC is a Unit vector (this means its length is 1) and is the direction form B to C:



          lenBC = sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
          dirBC = (player_to_col_vector[0] / lenBC, player_to_col_vector[1] / lenBC)


          (dx, dy) is the vector from C to D.



          dx, dy = (dirBC[0] * acceptable_distance, dirBC[1] * acceptable_distance)


          The vector b, which is equal the point D, is the sum of the vector v and the vector a:



          bx, by = (col_distance[0] + dx, col_distance[1] + dy) 


          The vector from the point B to D is the sum of w and a:



          BDx, BDy = (player_to_col_vector[0] + dx, player_to_col_vector[1] + dy)



          Deleted, since the tag "pygame" was removed.



          The above code does all the calculations. But note, in PyGame there is an much easier way to do this, by using pygame.math.Vector2 for calculations:



          u = pygame.math.Vector2(enemy_distance)
          v = pygame.math.Vector2(col_distance)

          w = v - u
          a = w.normalize() * acceptable_distance
          b = v + a







          share|improve this answer















          I assume that acceptable_distance corresponds to the size of the vector a in the image. So acceptable_distance is the distance between C and D



          The calculation of the normalized vector is wrong. normalized is the reciprocal length of the vector from B to C:




          normalized = 1 / sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)



          In the following lenBC is the distance between B and C. dirBC is a Unit vector (this means its length is 1) and is the direction form B to C:



          lenBC = sqrt(player_to_col_vector[0] ** 2 + player_to_col_vector[1] ** 2)
          dirBC = (player_to_col_vector[0] / lenBC, player_to_col_vector[1] / lenBC)


          (dx, dy) is the vector from C to D.



          dx, dy = (dirBC[0] * acceptable_distance, dirBC[1] * acceptable_distance)


          The vector b, which is equal the point D, is the sum of the vector v and the vector a:



          bx, by = (col_distance[0] + dx, col_distance[1] + dy) 


          The vector from the point B to D is the sum of w and a:



          BDx, BDy = (player_to_col_vector[0] + dx, player_to_col_vector[1] + dy)



          Deleted, since the tag "pygame" was removed.



          The above code does all the calculations. But note, in PyGame there is an much easier way to do this, by using pygame.math.Vector2 for calculations:



          u = pygame.math.Vector2(enemy_distance)
          v = pygame.math.Vector2(col_distance)

          w = v - u
          a = w.normalize() * acceptable_distance
          b = v + a








          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Mar 8 at 21:24

























          answered Mar 8 at 20:48









          Rabbid76Rabbid76

          42.9k123354




          42.9k123354












          • Due to how the assignment has been made, we cannot import anything. The main code evaluates my code at run time and gives me some functions I can call by adding them to the top of my file. Vector math is not part of those functions sadly.

            – GPierre
            Mar 8 at 21:15











          • @GPierre pygame.math.Vector2 is part of PyGame. You tagged the question <pgame> all you've to is import pygame! Anyway the 1st part of the answer solves your issue with out any library functions.

            – Rabbid76
            Mar 8 at 21:16












          • I probably shouldn't have tagged pygame even though it's a pygame assignment. If we import anything in that assignment, it's an automatic 0 >.>

            – GPierre
            Mar 8 at 21:22











          • It works! Thanks a bunch

            – GPierre
            Mar 8 at 21:31











          • @GPierre You're welcome.

            – Rabbid76
            Mar 8 at 21:32

















          • Due to how the assignment has been made, we cannot import anything. The main code evaluates my code at run time and gives me some functions I can call by adding them to the top of my file. Vector math is not part of those functions sadly.

            – GPierre
            Mar 8 at 21:15











          • @GPierre pygame.math.Vector2 is part of PyGame. You tagged the question <pgame> all you've to is import pygame! Anyway the 1st part of the answer solves your issue with out any library functions.

            – Rabbid76
            Mar 8 at 21:16












          • I probably shouldn't have tagged pygame even though it's a pygame assignment. If we import anything in that assignment, it's an automatic 0 >.>

            – GPierre
            Mar 8 at 21:22











          • It works! Thanks a bunch

            – GPierre
            Mar 8 at 21:31











          • @GPierre You're welcome.

            – Rabbid76
            Mar 8 at 21:32
















          Due to how the assignment has been made, we cannot import anything. The main code evaluates my code at run time and gives me some functions I can call by adding them to the top of my file. Vector math is not part of those functions sadly.

          – GPierre
          Mar 8 at 21:15





          Due to how the assignment has been made, we cannot import anything. The main code evaluates my code at run time and gives me some functions I can call by adding them to the top of my file. Vector math is not part of those functions sadly.

          – GPierre
          Mar 8 at 21:15













          @GPierre pygame.math.Vector2 is part of PyGame. You tagged the question <pgame> all you've to is import pygame! Anyway the 1st part of the answer solves your issue with out any library functions.

          – Rabbid76
          Mar 8 at 21:16






          @GPierre pygame.math.Vector2 is part of PyGame. You tagged the question <pgame> all you've to is import pygame! Anyway the 1st part of the answer solves your issue with out any library functions.

          – Rabbid76
          Mar 8 at 21:16














          I probably shouldn't have tagged pygame even though it's a pygame assignment. If we import anything in that assignment, it's an automatic 0 >.>

          – GPierre
          Mar 8 at 21:22





          I probably shouldn't have tagged pygame even though it's a pygame assignment. If we import anything in that assignment, it's an automatic 0 >.>

          – GPierre
          Mar 8 at 21:22













          It works! Thanks a bunch

          – GPierre
          Mar 8 at 21:31





          It works! Thanks a bunch

          – GPierre
          Mar 8 at 21:31













          @GPierre You're welcome.

          – Rabbid76
          Mar 8 at 21:32





          @GPierre You're welcome.

          – Rabbid76
          Mar 8 at 21:32



















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