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SnakeYaml not serializing private or protected fields
What is the difference between public, protected, package-private and private in Java?Why does Java have transient fields?Java Inventory Program problemsHow to tell Jackson to ignore a field during serialization if its value is null?Clone a Singleton objectMethod override returns nullParsing yaml file using snakeyaml with integer as keyJava - Method executed prior to Default Constructorjava exception - why does it catch?How to throw a custom exception from inside JAVA Transformer in Mule ESB 3.8?
I am trying to dump/serialize a Java POJO with SnakeYaml and the private and protected fields are not being serialized.
public class Dice
private Integer a;
protected Integer b;
public Integer c;
public Dice(Integer a, Integer b, Integer c)
this.a = a;
this.b = b;
this.c = c;
public Integer getA()
return a;
public Integer getB()
return b;
public Integer getC()
return c;
public static void main(String[] args)
Dice dice = new Dice(1,2,3);
Yaml yaml = new Yaml();
String output = yaml.dump(dice);
System.out.println(output);
which produces the following:
!!com.ibm.watson.pml.gpm.plan.Dice c: 3
I've seen lots of examples that show the private and protected fields being serialized properly. I've tried 1.17 and 1.23 with the same results.
java snakeyaml
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
add a comment |
I am trying to dump/serialize a Java POJO with SnakeYaml and the private and protected fields are not being serialized.
public class Dice
private Integer a;
protected Integer b;
public Integer c;
public Dice(Integer a, Integer b, Integer c)
this.a = a;
this.b = b;
this.c = c;
public Integer getA()
return a;
public Integer getB()
return b;
public Integer getC()
return c;
public static void main(String[] args)
Dice dice = new Dice(1,2,3);
Yaml yaml = new Yaml();
String output = yaml.dump(dice);
System.out.println(output);
which produces the following:
!!com.ibm.watson.pml.gpm.plan.Dice c: 3
I've seen lots of examples that show the private and protected fields being serialized properly. I've tried 1.17 and 1.23 with the same results.
java snakeyaml
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
add a comment |
I am trying to dump/serialize a Java POJO with SnakeYaml and the private and protected fields are not being serialized.
public class Dice
private Integer a;
protected Integer b;
public Integer c;
public Dice(Integer a, Integer b, Integer c)
this.a = a;
this.b = b;
this.c = c;
public Integer getA()
return a;
public Integer getB()
return b;
public Integer getC()
return c;
public static void main(String[] args)
Dice dice = new Dice(1,2,3);
Yaml yaml = new Yaml();
String output = yaml.dump(dice);
System.out.println(output);
which produces the following:
!!com.ibm.watson.pml.gpm.plan.Dice c: 3
I've seen lots of examples that show the private and protected fields being serialized properly. I've tried 1.17 and 1.23 with the same results.
java snakeyaml
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
I am trying to dump/serialize a Java POJO with SnakeYaml and the private and protected fields are not being serialized.
public class Dice
private Integer a;
protected Integer b;
public Integer c;
public Dice(Integer a, Integer b, Integer c)
this.a = a;
this.b = b;
this.c = c;
public Integer getA()
return a;
public Integer getB()
return b;
public Integer getC()
return c;
public static void main(String[] args)
Dice dice = new Dice(1,2,3);
Yaml yaml = new Yaml();
String output = yaml.dump(dice);
System.out.println(output);
which produces the following:
!!com.ibm.watson.pml.gpm.plan.Dice c: 3
I've seen lots of examples that show the private and protected fields being serialized properly. I've tried 1.17 and 1.23 with the same results.
java snakeyaml
java snakeyaml
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
asked Mar 8 at 21:04
David WoodDavid Wood
1081111
1081111
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Yaml.setBeanAccess(BeanAccess.FIELD);
answered Mar 11 at 15:49
AndreyAndrey
653
add a comment |
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1 Answer
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active
oldest
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Yaml.setBeanAccess(BeanAccess.FIELD);
answered Mar 11 at 15:49
AndreyAndrey
653
add a comment |
Yaml.setBeanAccess(BeanAccess.FIELD);
answered Mar 11 at 15:49
AndreyAndrey
653
add a comment |
Yaml.setBeanAccess(BeanAccess.FIELD);
answered Mar 11 at 15:49
AndreyAndrey
653
Yaml.setBeanAccess(BeanAccess.FIELD);
answered Mar 11 at 15:49
AndreyAndrey
653
answered Mar 11 at 15:49
AndreyAndrey
653
answered Mar 11 at 15:49
AndreyAndrey
653
answered Mar 11 at 15:49
AndreyAndrey
653
653
add a comment |
add a comment |
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