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Generics bounded parameter not applied for interface



The Next CEO of Stack OverflowWhy can this generic method with a bound return any type?How to generate a random alpha-numeric string?Create Generic method constraining T to an EnumCollections.emptyList() returns a List<Object>?How do I generate random integers within a specific range in Java?How do I make the method return type generic?How to create a generic array in Java?Does Java support default parameter values?Java bounded parameters in generic methodsBounded Generic Types in Method Parameters C#Multiple generic bounds including type parameter










2















Below is the code where I declared two methods whose return type are bounded parameters but one is based on interface whereas other is based on a class. In the test() method, assigning return type to String fails for method where bounded parameter extends from Class which is expected, but compiler doesn't throw error when the bounded parameter is based on interface. Can you explain why does this happen?



import java.io.FileInputStream;
import java.util.function.Predicate;

public class Dummy

<T extends Predicate<String>> T getBoundedByInterface()

return null;


<T extends FileInputStream> T getBoundedByClass()
return null;

public void test()

String compilationError = getBoundedByClass(); //Expected
String works = getBoundedByInterface(); //No compilation error. Why?












share|improve this question






















  • Possible duplicate stackoverflow.com/questions/29670018/…

    – Radiodef
    Mar 8 at 19:43















2















Below is the code where I declared two methods whose return type are bounded parameters but one is based on interface whereas other is based on a class. In the test() method, assigning return type to String fails for method where bounded parameter extends from Class which is expected, but compiler doesn't throw error when the bounded parameter is based on interface. Can you explain why does this happen?



import java.io.FileInputStream;
import java.util.function.Predicate;

public class Dummy

<T extends Predicate<String>> T getBoundedByInterface()

return null;


<T extends FileInputStream> T getBoundedByClass()
return null;

public void test()

String compilationError = getBoundedByClass(); //Expected
String works = getBoundedByInterface(); //No compilation error. Why?












share|improve this question






















  • Possible duplicate stackoverflow.com/questions/29670018/…

    – Radiodef
    Mar 8 at 19:43













2












2








2








Below is the code where I declared two methods whose return type are bounded parameters but one is based on interface whereas other is based on a class. In the test() method, assigning return type to String fails for method where bounded parameter extends from Class which is expected, but compiler doesn't throw error when the bounded parameter is based on interface. Can you explain why does this happen?



import java.io.FileInputStream;
import java.util.function.Predicate;

public class Dummy

<T extends Predicate<String>> T getBoundedByInterface()

return null;


<T extends FileInputStream> T getBoundedByClass()
return null;

public void test()

String compilationError = getBoundedByClass(); //Expected
String works = getBoundedByInterface(); //No compilation error. Why?












share|improve this question














Below is the code where I declared two methods whose return type are bounded parameters but one is based on interface whereas other is based on a class. In the test() method, assigning return type to String fails for method where bounded parameter extends from Class which is expected, but compiler doesn't throw error when the bounded parameter is based on interface. Can you explain why does this happen?



import java.io.FileInputStream;
import java.util.function.Predicate;

public class Dummy

<T extends Predicate<String>> T getBoundedByInterface()

return null;


<T extends FileInputStream> T getBoundedByClass()
return null;

public void test()

String compilationError = getBoundedByClass(); //Expected
String works = getBoundedByInterface(); //No compilation error. Why?









java generics bounded-types






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 8 at 19:21









PrafullPrafull

284




284












  • Possible duplicate stackoverflow.com/questions/29670018/…

    – Radiodef
    Mar 8 at 19:43

















  • Possible duplicate stackoverflow.com/questions/29670018/…

    – Radiodef
    Mar 8 at 19:43
















Possible duplicate stackoverflow.com/questions/29670018/…

– Radiodef
Mar 8 at 19:43





Possible duplicate stackoverflow.com/questions/29670018/…

– Radiodef
Mar 8 at 19:43












1 Answer
1






active

oldest

votes


















2














The Java compiler will determine if the variable type can satisfy the generic return type of the method called. With a class such as FileInputStream, it knows that no class can be both a FileInputStream and a String because a class can't inherit from more than one class, so this is disallowed. Additionally we know that String is also final, but that doesn't figure into the compiler's logic.



However, with an interface, it's possible for a subclass to extend the bound and be a subclass of another class.



class Thing extends FileInputStream implements Predicate<String> 
// Implementation



This compiles for that reason.



Thing works = getBoundedByInterface();


Notice that it also works with String because the compiler doesn't take into account that String is final.






share|improve this answer























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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    The Java compiler will determine if the variable type can satisfy the generic return type of the method called. With a class such as FileInputStream, it knows that no class can be both a FileInputStream and a String because a class can't inherit from more than one class, so this is disallowed. Additionally we know that String is also final, but that doesn't figure into the compiler's logic.



    However, with an interface, it's possible for a subclass to extend the bound and be a subclass of another class.



    class Thing extends FileInputStream implements Predicate<String> 
    // Implementation



    This compiles for that reason.



    Thing works = getBoundedByInterface();


    Notice that it also works with String because the compiler doesn't take into account that String is final.






    share|improve this answer



























      2














      The Java compiler will determine if the variable type can satisfy the generic return type of the method called. With a class such as FileInputStream, it knows that no class can be both a FileInputStream and a String because a class can't inherit from more than one class, so this is disallowed. Additionally we know that String is also final, but that doesn't figure into the compiler's logic.



      However, with an interface, it's possible for a subclass to extend the bound and be a subclass of another class.



      class Thing extends FileInputStream implements Predicate<String> 
      // Implementation



      This compiles for that reason.



      Thing works = getBoundedByInterface();


      Notice that it also works with String because the compiler doesn't take into account that String is final.






      share|improve this answer

























        2












        2








        2







        The Java compiler will determine if the variable type can satisfy the generic return type of the method called. With a class such as FileInputStream, it knows that no class can be both a FileInputStream and a String because a class can't inherit from more than one class, so this is disallowed. Additionally we know that String is also final, but that doesn't figure into the compiler's logic.



        However, with an interface, it's possible for a subclass to extend the bound and be a subclass of another class.



        class Thing extends FileInputStream implements Predicate<String> 
        // Implementation



        This compiles for that reason.



        Thing works = getBoundedByInterface();


        Notice that it also works with String because the compiler doesn't take into account that String is final.






        share|improve this answer













        The Java compiler will determine if the variable type can satisfy the generic return type of the method called. With a class such as FileInputStream, it knows that no class can be both a FileInputStream and a String because a class can't inherit from more than one class, so this is disallowed. Additionally we know that String is also final, but that doesn't figure into the compiler's logic.



        However, with an interface, it's possible for a subclass to extend the bound and be a subclass of another class.



        class Thing extends FileInputStream implements Predicate<String> 
        // Implementation



        This compiles for that reason.



        Thing works = getBoundedByInterface();


        Notice that it also works with String because the compiler doesn't take into account that String is final.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Mar 8 at 19:29









        rgettmanrgettman

        152k21209293




        152k21209293





























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