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How to use regex to match some words if they exist (if not match others left as well)
Match all occurrences of a regexHow to “inverse match” with regex?Regular expression to match a line that doesn't contain a word?How do you access the matched groups in a JavaScript regular expression?How to negate specific word in regex?RegEx match open tags except XHTML self-contained tagsHow to check whether a String fully matches a Regex in Scala?How to match, but not capture, part of a regex?Replace only some groups with RegexSwift extract regex matches
For example,
the string is:
"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"
How do I match the following:
['0x0:', '0x1:', '0x2-0x3:']
in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!
regex
add a comment |
For example,
the string is:
"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"
How do I match the following:
['0x0:', '0x1:', '0x2-0x3:']
in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!
regex
So basically you need to match0x#:
and0x#-0x#:
? Can there be two digits after thex
?
– Andrew
Mar 8 at 0:02
Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!
– Fatih Aktaş
Mar 8 at 8:29
add a comment |
For example,
the string is:
"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"
How do I match the following:
['0x0:', '0x1:', '0x2-0x3:']
in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!
regex
For example,
the string is:
"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"
How do I match the following:
['0x0:', '0x1:', '0x2-0x3:']
in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!
regex
regex
edited Mar 7 at 23:59
Vaishali
21.9k41336
21.9k41336
asked Mar 7 at 23:57
nuofan xunuofan xu
111
111
So basically you need to match0x#:
and0x#-0x#:
? Can there be two digits after thex
?
– Andrew
Mar 8 at 0:02
Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!
– Fatih Aktaş
Mar 8 at 8:29
add a comment |
So basically you need to match0x#:
and0x#-0x#:
? Can there be two digits after thex
?
– Andrew
Mar 8 at 0:02
Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!
– Fatih Aktaş
Mar 8 at 8:29
So basically you need to match
0x#:
and 0x#-0x#:
? Can there be two digits after the x
?– Andrew
Mar 8 at 0:02
So basically you need to match
0x#:
and 0x#-0x#:
? Can there be two digits after the x
?– Andrew
Mar 8 at 0:02
Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!
– Fatih Aktaş
Mar 8 at 8:29
Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!
– Fatih Aktaş
Mar 8 at 8:29
add a comment |
2 Answers
2
active
oldest
votes
You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.
((dxd)-?)+:
And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.
add a comment |
0xd(-0xd)?:
This regex will match 0x#:
and 0x#-0x#:
, where #
is a digit. As you can see, the part between parenthesis is optional by using that ?
.
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.
((dxd)-?)+:
And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.
add a comment |
You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.
((dxd)-?)+:
And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.
add a comment |
You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.
((dxd)-?)+:
And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.
You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.
((dxd)-?)+:
And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.
answered Mar 8 at 1:51
Fatih AktaşFatih Aktaş
391213
391213
add a comment |
add a comment |
0xd(-0xd)?:
This regex will match 0x#:
and 0x#-0x#:
, where #
is a digit. As you can see, the part between parenthesis is optional by using that ?
.
add a comment |
0xd(-0xd)?:
This regex will match 0x#:
and 0x#-0x#:
, where #
is a digit. As you can see, the part between parenthesis is optional by using that ?
.
add a comment |
0xd(-0xd)?:
This regex will match 0x#:
and 0x#-0x#:
, where #
is a digit. As you can see, the part between parenthesis is optional by using that ?
.
0xd(-0xd)?:
This regex will match 0x#:
and 0x#-0x#:
, where #
is a digit. As you can see, the part between parenthesis is optional by using that ?
.
answered Mar 8 at 0:04
AndrewAndrew
5,05311731
5,05311731
add a comment |
add a comment |
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So basically you need to match
0x#:
and0x#-0x#:
? Can there be two digits after thex
?– Andrew
Mar 8 at 0:02
Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!
– Fatih Aktaş
Mar 8 at 8:29