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How to use regex to match some words if they exist (if not match others left as well)


Match all occurrences of a regexHow to “inverse match” with regex?Regular expression to match a line that doesn't contain a word?How do you access the matched groups in a JavaScript regular expression?How to negate specific word in regex?RegEx match open tags except XHTML self-contained tagsHow to check whether a String fully matches a Regex in Scala?How to match, but not capture, part of a regex?Replace only some groups with RegexSwift extract regex matches













2















For example,
the string is:



"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"


How do I match the following:



['0x0:', '0x1:', '0x2-0x3:'] 


in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!










share|improve this question
























  • So basically you need to match 0x#: and 0x#-0x#:? Can there be two digits after the x?

    – Andrew
    Mar 8 at 0:02











  • Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!

    – Fatih Aktaş
    Mar 8 at 8:29















2















For example,
the string is:



"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"


How do I match the following:



['0x0:', '0x1:', '0x2-0x3:'] 


in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!










share|improve this question
























  • So basically you need to match 0x#: and 0x#-0x#:? Can there be two digits after the x?

    – Andrew
    Mar 8 at 0:02











  • Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!

    – Fatih Aktaş
    Mar 8 at 8:29













2












2








2








For example,
the string is:



"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"


How do I match the following:



['0x0:', '0x1:', '0x2-0x3:'] 


in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!










share|improve this question
















For example,
the string is:



"0x0:dqwdq0x1:dqwd0x2-0x3:sdqwd"


How do I match the following:



['0x0:', '0x1:', '0x2-0x3:'] 


in regex, or better, use re module in python? In most cases the patterns will be in 0x[0-9] but the thing is sometimes there would have an extra piece: -0x[0-9] in the string. Thanks for help!







regex






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 7 at 23:59









Vaishali

21.9k41336




21.9k41336










asked Mar 7 at 23:57









nuofan xunuofan xu

111




111












  • So basically you need to match 0x#: and 0x#-0x#:? Can there be two digits after the x?

    – Andrew
    Mar 8 at 0:02











  • Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!

    – Fatih Aktaş
    Mar 8 at 8:29

















  • So basically you need to match 0x#: and 0x#-0x#:? Can there be two digits after the x?

    – Andrew
    Mar 8 at 0:02











  • Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!

    – Fatih Aktaş
    Mar 8 at 8:29
















So basically you need to match 0x#: and 0x#-0x#:? Can there be two digits after the x?

– Andrew
Mar 8 at 0:02





So basically you need to match 0x#: and 0x#-0x#:? Can there be two digits after the x?

– Andrew
Mar 8 at 0:02













Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!

– Fatih Aktaş
Mar 8 at 8:29





Please don't forget to select my post as the answer, if it helps. Let me know if anything goes wrong. Thank you!

– Fatih Aktaş
Mar 8 at 8:29












2 Answers
2






active

oldest

votes


















1














You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.



((dxd)-?)+:


And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.






share|improve this answer






























    0














    0xd(-0xd)?:


    This regex will match 0x#: and 0x#-0x#:, where # is a digit. As you can see, the part between parenthesis is optional by using that ?.






    share|improve this answer






















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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.



      ((dxd)-?)+:


      And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.






      share|improve this answer



























        1














        You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.



        ((dxd)-?)+:


        And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.






        share|improve this answer

























          1












          1








          1







          You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.



          ((dxd)-?)+:


          And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.






          share|improve this answer













          You can use the code below to get the 0x0:, 0x0-0x0: or even more 0x0-0x0-0x0: numbers.



          ((dxd)-?)+:


          And yes, python should be able to do the job. As long as the regular expression is correct to match what you want, the language you use shouldn't make a difference.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Mar 8 at 1:51









          Fatih AktaşFatih Aktaş

          391213




          391213























              0














              0xd(-0xd)?:


              This regex will match 0x#: and 0x#-0x#:, where # is a digit. As you can see, the part between parenthesis is optional by using that ?.






              share|improve this answer



























                0














                0xd(-0xd)?:


                This regex will match 0x#: and 0x#-0x#:, where # is a digit. As you can see, the part between parenthesis is optional by using that ?.






                share|improve this answer

























                  0












                  0








                  0







                  0xd(-0xd)?:


                  This regex will match 0x#: and 0x#-0x#:, where # is a digit. As you can see, the part between parenthesis is optional by using that ?.






                  share|improve this answer













                  0xd(-0xd)?:


                  This regex will match 0x#: and 0x#-0x#:, where # is a digit. As you can see, the part between parenthesis is optional by using that ?.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Mar 8 at 0:04









                  AndrewAndrew

                  5,05311731




                  5,05311731



























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