Ggtcf

Doesn't the system of the Supreme Court oppose justice?

Microchip documentation does not label CAN buss pins on micro controller pinout diagram

Quoting Keynes in a lecture

15% tax on $7.5k earnings. Is that right?

Showing a sum is positive

What is Cash Advance APR?

Why Shazam when there is already Superman?

What is going on with gets(stdin) on the site coderbyte?

How would you translate "more" for use as an interface button?

A Trivial Diagnosis

Why does Carol not get rid of the Kree symbol on her suit when she changes its colours?

The IT department bottlenecks progress, how should I handle this?

Plot of a tornado shape like surface

How does electrical safety system work on ISS?

awk assign to multiple variables at once

How to get directions in deep space?

How many arrows is an archer expected to fire by the end of the Tyranny of Dragons pair of adventures?

What to do when eye contact makes your coworker uncomfortable?

Review your own paper in Mathematics

What does Apple's new App Store requirement mean

What kind of floor tile is this?

Giving feedback to someone without sounding prejudiced

What are some good ways to treat frozen vegetables such that they behave like fresh vegetables when stir frying them?

It grows, but water kills it

Get Subscription Product author of a Woocommerce subscription

How do I get PHP errors to display?How do I get a YouTube video thumbnail from the YouTube API?Get WooCommerce Subscription Original (Initial) order numberWoocommerce get product ID's from CategoryIssues programmatically creating variable subscription product in WooCommerceWooCommerce Subscriptions missing “Completed” statusWoocommerce swap product in order (subscription)WooCommerce associate 'alternate widget' products to membership plan(s)WooCommerce: Get name and variation from a Subscription orderGet the author ID of each product in Woocommerce cart

2

How can I iterate through all current active woo subscriptions and print the user ID of the user who published the product related to each active subscription (PHP)? I think something like this will give just the subscriptions:

$args = array( 'subscriptions_per_page' => -1, 'post_type' => 'shop_subscription', // WC orders post type
 'post_status' => 'wc-active' );
 $subscriptions = wcs_get_subscriptions( $args );

php wordpress woocommerce author woocommerce-subscriptions

share|improve this question

edited Mar 10 at 20:21

LoicTheAztec

94k1367107

asked Mar 7 at 23:10

xendixendi

77711331

add a comment | 

2

How can I iterate through all current active woo subscriptions and print the user ID of the user who published the product related to each active subscription (PHP)? I think something like this will give just the subscriptions:

$args = array( 'subscriptions_per_page' => -1, 'post_type' => 'shop_subscription', // WC orders post type
 'post_status' => 'wc-active' );
 $subscriptions = wcs_get_subscriptions( $args );

php wordpress woocommerce author woocommerce-subscriptions

share|improve this question

edited Mar 10 at 20:21

LoicTheAztec

94k1367107

asked Mar 7 at 23:10

xendixendi

77711331

add a comment | 

How can I iterate through all current active woo subscriptions and print the user ID of the user who published the product related to each active subscription (PHP)? I think something like this will give just the subscriptions:

$args = array( 'subscriptions_per_page' => -1, 'post_type' => 'shop_subscription', // WC orders post type
 'post_status' => 'wc-active' );
 $subscriptions = wcs_get_subscriptions( $args );

php wordpress woocommerce author woocommerce-subscriptions

share|improve this question

edited Mar 10 at 20:21

LoicTheAztec

94k1367107

asked Mar 7 at 23:10

xendixendi

77711331

$args = array( 'subscriptions_per_page' => -1, 'post_type' => 'shop_subscription', // WC orders post type
 'post_status' => 'wc-active' );
 $subscriptions = wcs_get_subscriptions( $args );

share|improve this question

edited Mar 10 at 20:21

LoicTheAztec

94k1367107

asked Mar 7 at 23:10

xendixendi

77711331

share|improve this question

edited Mar 10 at 20:21

LoicTheAztec

94k1367107

asked Mar 7 at 23:10

xendixendi

77711331

edited Mar 10 at 20:21

LoicTheAztec

94k1367107

edited Mar 10 at 20:21

LoicTheAztec

94k1367107

asked Mar 7 at 23:10

xendixendi

77711331

asked Mar 7 at 23:10

xendixendi

77711331

1 Answer
1

active

oldest

votes

0

The following code will query all active subscriptions to get the author Id (that published the product of the active subscription):

// Get all active subscriptions
$subscriptions = wcs_get_subscriptions( array(
 'subscriptions_per_page' => -1,
 'subscription_status' => array('active') // Active subscriptions
) );

// 1) Loop through quieried active subscriptions
foreach($subscriptions as $subscription)

 // 2) Loop through subscription items
 foreach( $subscription->get_items() as $item_id => $item ) 
 
 // Get the subscription product author
 $author_id = get_post_field ('post_author', $item->get_product_id());
 // Display
 echo $author_id . '<br>';
 

Tested and works.

share|improve this answer

answered Mar 7 at 23:56

LoicTheAztecLoicTheAztec

94k1367107

add a comment | 

Your Answer

StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);

draft saved

draft discarded

Sign up or log in

StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);

Sign up using Google

Sign up using Facebook

Sign up using Email and Password

Post as a guest

Name

Email

Required, but never shown

StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55054276%2fget-subscription-product-author-of-a-woocommerce-subscription%23new-answer', 'question_page');

);

Post as a guest

Name

Email

Required, but never shown

0

The following code will query all active subscriptions to get the author Id (that published the product of the active subscription):

// Get all active subscriptions
$subscriptions = wcs_get_subscriptions( array(
 'subscriptions_per_page' => -1,
 'subscription_status' => array('active') // Active subscriptions
) );

// 1) Loop through quieried active subscriptions
foreach($subscriptions as $subscription)

 // 2) Loop through subscription items
 foreach( $subscription->get_items() as $item_id => $item ) 
 
 // Get the subscription product author
 $author_id = get_post_field ('post_author', $item->get_product_id());
 // Display
 echo $author_id . '<br>';
 

Tested and works.

share|improve this answer

answered Mar 7 at 23:56

LoicTheAztecLoicTheAztec

94k1367107

add a comment | 

0

The following code will query all active subscriptions to get the author Id (that published the product of the active subscription):

// Get all active subscriptions
$subscriptions = wcs_get_subscriptions( array(
 'subscriptions_per_page' => -1,
 'subscription_status' => array('active') // Active subscriptions
) );

// 1) Loop through quieried active subscriptions
foreach($subscriptions as $subscription)

 // 2) Loop through subscription items
 foreach( $subscription->get_items() as $item_id => $item ) 
 
 // Get the subscription product author
 $author_id = get_post_field ('post_author', $item->get_product_id());
 // Display
 echo $author_id . '<br>';
 

Tested and works.

share|improve this answer

answered Mar 7 at 23:56

LoicTheAztecLoicTheAztec

94k1367107

add a comment | 

The following code will query all active subscriptions to get the author Id (that published the product of the active subscription):

// Get all active subscriptions
$subscriptions = wcs_get_subscriptions( array(
 'subscriptions_per_page' => -1,
 'subscription_status' => array('active') // Active subscriptions
) );

// 1) Loop through quieried active subscriptions
foreach($subscriptions as $subscription)

 // 2) Loop through subscription items
 foreach( $subscription->get_items() as $item_id => $item ) 
 
 // Get the subscription product author
 $author_id = get_post_field ('post_author', $item->get_product_id());
 // Display
 echo $author_id . '<br>';
 

Tested and works.

share|improve this answer

answered Mar 7 at 23:56

LoicTheAztecLoicTheAztec

94k1367107

// Get all active subscriptions
$subscriptions = wcs_get_subscriptions( array(
 'subscriptions_per_page' => -1,
 'subscription_status' => array('active') // Active subscriptions
) );

// 1) Loop through quieried active subscriptions
foreach($subscriptions as $subscription)

 // 2) Loop through subscription items
 foreach( $subscription->get_items() as $item_id => $item ) 
 
 // Get the subscription product author
 $author_id = get_post_field ('post_author', $item->get_product_id());
 // Display
 echo $author_id . '<br>';
 

share|improve this answer

answered Mar 7 at 23:56

LoicTheAztecLoicTheAztec

94k1367107

answered Mar 7 at 23:56

LoicTheAztecLoicTheAztec

94k1367107

answered Mar 7 at 23:56

LoicTheAztecLoicTheAztec

94k1367107