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Exit statuses of comparisons in test constructs
2019 Community Moderator ElectionPOSIX test and -adifference between non-builtin 'test' and '['unix test when to use eq vs = vs == in test commands?What does `[ EXPRESSION ], [ ] and [OPTION` mean in `man test`?-n Vs !(exclamation mark) behaves differently with test commandDifference in conditions /test( test -n $st ) != ( test -z $st ) right?How to test list of proxy servers?Bash test: what does “=~” do?How to correctly test file's extension in if statement?
I was writing some "if then" statements and found what seemed to me an odd behavior. Upon investigation I realized that it boiled down to the exit code of the comparison I was making. I illustrate my findings in the following code snippet.
As you can see
rc=1
[ $rc -eq 0 ]
es_num=$?
[ $rc=0 ]
es_str=$?
echo "es_num is $es_num"
echo "es_str is $es_str"
Outputs
es_num is 1
es_str is 0
Is there any documentation, preferably from the POSIX standards, that talks about the difference in the exit statuses of -eq
and =
in a test construct?
What should I be aware of when writing conditional statements? What are some best practices regarding this?
Portable code is preferable to Bash code (which I'm using).
test control-flow
add a comment |
I was writing some "if then" statements and found what seemed to me an odd behavior. Upon investigation I realized that it boiled down to the exit code of the comparison I was making. I illustrate my findings in the following code snippet.
As you can see
rc=1
[ $rc -eq 0 ]
es_num=$?
[ $rc=0 ]
es_str=$?
echo "es_num is $es_num"
echo "es_str is $es_str"
Outputs
es_num is 1
es_str is 0
Is there any documentation, preferably from the POSIX standards, that talks about the difference in the exit statuses of -eq
and =
in a test construct?
What should I be aware of when writing conditional statements? What are some best practices regarding this?
Portable code is preferable to Bash code (which I'm using).
test control-flow
I didn't know about the space being necessary. What I meant with "odd" is "weird if you read as pseudo code, ignoring the quirks of the language". Thanks. @ilkkachu
– Elegance
Mar 7 at 19:16
1
The only way I can get[ $rc=0 ]
to fail withrc=1
is to setIFS
to 1 as well. That would cause both tests to error out and set$?
to 2 (inbash
).
– Kusalananda
Mar 7 at 19:25
@ilkkachu There was a typo. Of course I can't ignore them, but if I knew them, I wouldn't have to ask. That's exactly the point of the question.
– Elegance
Mar 7 at 21:29
@Elegance, ok, good, thanks. And yes, you're right, you wouldn't have to ask if you knew. It's just that even a typo like that can send the readers off in the wrong direction, looking for some really weird edge case that could explain the result. (The shell can be a bit quirky sometimes so there might have been a remote possibility of an edge case where both would return1
...)
– ilkkachu
Mar 7 at 21:52
@ilkkachu Thank you for the helpful feedback.
– Elegance
Mar 7 at 22:08
add a comment |
I was writing some "if then" statements and found what seemed to me an odd behavior. Upon investigation I realized that it boiled down to the exit code of the comparison I was making. I illustrate my findings in the following code snippet.
As you can see
rc=1
[ $rc -eq 0 ]
es_num=$?
[ $rc=0 ]
es_str=$?
echo "es_num is $es_num"
echo "es_str is $es_str"
Outputs
es_num is 1
es_str is 0
Is there any documentation, preferably from the POSIX standards, that talks about the difference in the exit statuses of -eq
and =
in a test construct?
What should I be aware of when writing conditional statements? What are some best practices regarding this?
Portable code is preferable to Bash code (which I'm using).
test control-flow
I was writing some "if then" statements and found what seemed to me an odd behavior. Upon investigation I realized that it boiled down to the exit code of the comparison I was making. I illustrate my findings in the following code snippet.
As you can see
rc=1
[ $rc -eq 0 ]
es_num=$?
[ $rc=0 ]
es_str=$?
echo "es_num is $es_num"
echo "es_str is $es_str"
Outputs
es_num is 1
es_str is 0
Is there any documentation, preferably from the POSIX standards, that talks about the difference in the exit statuses of -eq
and =
in a test construct?
What should I be aware of when writing conditional statements? What are some best practices regarding this?
Portable code is preferable to Bash code (which I'm using).
test control-flow
test control-flow
edited Mar 7 at 21:28
Elegance
asked Mar 7 at 18:35
EleganceElegance
183
183
I didn't know about the space being necessary. What I meant with "odd" is "weird if you read as pseudo code, ignoring the quirks of the language". Thanks. @ilkkachu
– Elegance
Mar 7 at 19:16
1
The only way I can get[ $rc=0 ]
to fail withrc=1
is to setIFS
to 1 as well. That would cause both tests to error out and set$?
to 2 (inbash
).
– Kusalananda
Mar 7 at 19:25
@ilkkachu There was a typo. Of course I can't ignore them, but if I knew them, I wouldn't have to ask. That's exactly the point of the question.
– Elegance
Mar 7 at 21:29
@Elegance, ok, good, thanks. And yes, you're right, you wouldn't have to ask if you knew. It's just that even a typo like that can send the readers off in the wrong direction, looking for some really weird edge case that could explain the result. (The shell can be a bit quirky sometimes so there might have been a remote possibility of an edge case where both would return1
...)
– ilkkachu
Mar 7 at 21:52
@ilkkachu Thank you for the helpful feedback.
– Elegance
Mar 7 at 22:08
add a comment |
I didn't know about the space being necessary. What I meant with "odd" is "weird if you read as pseudo code, ignoring the quirks of the language". Thanks. @ilkkachu
– Elegance
Mar 7 at 19:16
1
The only way I can get[ $rc=0 ]
to fail withrc=1
is to setIFS
to 1 as well. That would cause both tests to error out and set$?
to 2 (inbash
).
– Kusalananda
Mar 7 at 19:25
@ilkkachu There was a typo. Of course I can't ignore them, but if I knew them, I wouldn't have to ask. That's exactly the point of the question.
– Elegance
Mar 7 at 21:29
@Elegance, ok, good, thanks. And yes, you're right, you wouldn't have to ask if you knew. It's just that even a typo like that can send the readers off in the wrong direction, looking for some really weird edge case that could explain the result. (The shell can be a bit quirky sometimes so there might have been a remote possibility of an edge case where both would return1
...)
– ilkkachu
Mar 7 at 21:52
@ilkkachu Thank you for the helpful feedback.
– Elegance
Mar 7 at 22:08
I didn't know about the space being necessary. What I meant with "odd" is "weird if you read as pseudo code, ignoring the quirks of the language". Thanks. @ilkkachu
– Elegance
Mar 7 at 19:16
I didn't know about the space being necessary. What I meant with "odd" is "weird if you read as pseudo code, ignoring the quirks of the language". Thanks. @ilkkachu
– Elegance
Mar 7 at 19:16
1
1
The only way I can get
[ $rc=0 ]
to fail with rc=1
is to set IFS
to 1 as well. That would cause both tests to error out and set $?
to 2 (in bash
).– Kusalananda
Mar 7 at 19:25
The only way I can get
[ $rc=0 ]
to fail with rc=1
is to set IFS
to 1 as well. That would cause both tests to error out and set $?
to 2 (in bash
).– Kusalananda
Mar 7 at 19:25
@ilkkachu There was a typo. Of course I can't ignore them, but if I knew them, I wouldn't have to ask. That's exactly the point of the question.
– Elegance
Mar 7 at 21:29
@ilkkachu There was a typo. Of course I can't ignore them, but if I knew them, I wouldn't have to ask. That's exactly the point of the question.
– Elegance
Mar 7 at 21:29
@Elegance, ok, good, thanks. And yes, you're right, you wouldn't have to ask if you knew. It's just that even a typo like that can send the readers off in the wrong direction, looking for some really weird edge case that could explain the result. (The shell can be a bit quirky sometimes so there might have been a remote possibility of an edge case where both would return
1
...)– ilkkachu
Mar 7 at 21:52
@Elegance, ok, good, thanks. And yes, you're right, you wouldn't have to ask if you knew. It's just that even a typo like that can send the readers off in the wrong direction, looking for some really weird edge case that could explain the result. (The shell can be a bit quirky sometimes so there might have been a remote possibility of an edge case where both would return
1
...)– ilkkachu
Mar 7 at 21:52
@ilkkachu Thank you for the helpful feedback.
– Elegance
Mar 7 at 22:08
@ilkkachu Thank you for the helpful feedback.
– Elegance
Mar 7 at 22:08
add a comment |
2 Answers
2
active
oldest
votes
-eq
True if the integers n1 and n2 are algebraically equal; otherwise, false.
test
=
True if the strings s1 and s2 are identical; otherwise, false.
test
So -eq
compares integers and =
compares strings (which will also work with some limited integer cases).
You do have a syntax issue though, it should be:
[ "$rc" = 0 ]
And not
[ $rc=0 ]
[ "$rc" = 0 ]
should exit with 1 because rc
does not equal 0
[ $rc=0 ]
should actually exit with 0 because it's likely going to be treated as a string and the presence of a string within the [
test construct will evaluate to true
With the sh [
test there are a few differences:
# leading 0
$ [ 01 -eq 1 ]; echo $?
0
# adjacent whitespace
$ [ ' 1' -eq 1 ]; echo $?
0
# negative 0 vs positive 0
$ [ 0 -eq -0 ]; echo $?
0
However with the bash [[
test there are a large number of differences (Including the ones mentioned above):
# base 8
$ [[ 032 -eq 26 ]]; echo $?
0
# Arithmetic expressions
$ [[ 1*6+32/15*2-1 -eq 9 ]]; echo $?
0
# Base 64
$ [[ 64#Hello_world -eq -5506400892957379251 ]]; echo $?
0
I'm just a bit confused about what is meant by numeric and string comparisons. Let's say I use=
to compare numbers. When is it not going to not yield the same result as a numeric comparison?
– Elegance
Mar 7 at 19:17
Any examples with strings that have nothing but digits, and don't have leading zeros?
– Elegance
Mar 7 at 19:21
1
@Elegance The point is that with-eq
, the left and right hand side are compared as integers, not as strings. The test would evaluate the strings as integers (probably by passing them throughstrtol()
or some such C function) before carrying out the comparison.
– Kusalananda
Mar 7 at 19:43
1
@Elegance In abash
test with[[ ... -eq ... ]]
you could even have arithmetic calculations on either side, as in[[ 1+1 -eq 2 ]]
. Obviously,[[ 1+1 == 2 ]]
would not be true.
– Kusalananda
Mar 7 at 20:02
@Jesse_b You shared the same link twice. I take it the first one is incorrect.
– Elegance
Mar 7 at 22:09
|
show 1 more comment
For numeric comparisons you have to use -eq
whereas =
is for string comparisons (as from your variable naming you already seem to know).
One of the best introductions on the test
aka [
command I know is The Unix Shell's Humble If
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
-eq
True if the integers n1 and n2 are algebraically equal; otherwise, false.
test
=
True if the strings s1 and s2 are identical; otherwise, false.
test
So -eq
compares integers and =
compares strings (which will also work with some limited integer cases).
You do have a syntax issue though, it should be:
[ "$rc" = 0 ]
And not
[ $rc=0 ]
[ "$rc" = 0 ]
should exit with 1 because rc
does not equal 0
[ $rc=0 ]
should actually exit with 0 because it's likely going to be treated as a string and the presence of a string within the [
test construct will evaluate to true
With the sh [
test there are a few differences:
# leading 0
$ [ 01 -eq 1 ]; echo $?
0
# adjacent whitespace
$ [ ' 1' -eq 1 ]; echo $?
0
# negative 0 vs positive 0
$ [ 0 -eq -0 ]; echo $?
0
However with the bash [[
test there are a large number of differences (Including the ones mentioned above):
# base 8
$ [[ 032 -eq 26 ]]; echo $?
0
# Arithmetic expressions
$ [[ 1*6+32/15*2-1 -eq 9 ]]; echo $?
0
# Base 64
$ [[ 64#Hello_world -eq -5506400892957379251 ]]; echo $?
0
I'm just a bit confused about what is meant by numeric and string comparisons. Let's say I use=
to compare numbers. When is it not going to not yield the same result as a numeric comparison?
– Elegance
Mar 7 at 19:17
Any examples with strings that have nothing but digits, and don't have leading zeros?
– Elegance
Mar 7 at 19:21
1
@Elegance The point is that with-eq
, the left and right hand side are compared as integers, not as strings. The test would evaluate the strings as integers (probably by passing them throughstrtol()
or some such C function) before carrying out the comparison.
– Kusalananda
Mar 7 at 19:43
1
@Elegance In abash
test with[[ ... -eq ... ]]
you could even have arithmetic calculations on either side, as in[[ 1+1 -eq 2 ]]
. Obviously,[[ 1+1 == 2 ]]
would not be true.
– Kusalananda
Mar 7 at 20:02
@Jesse_b You shared the same link twice. I take it the first one is incorrect.
– Elegance
Mar 7 at 22:09
|
show 1 more comment
-eq
True if the integers n1 and n2 are algebraically equal; otherwise, false.
test
=
True if the strings s1 and s2 are identical; otherwise, false.
test
So -eq
compares integers and =
compares strings (which will also work with some limited integer cases).
You do have a syntax issue though, it should be:
[ "$rc" = 0 ]
And not
[ $rc=0 ]
[ "$rc" = 0 ]
should exit with 1 because rc
does not equal 0
[ $rc=0 ]
should actually exit with 0 because it's likely going to be treated as a string and the presence of a string within the [
test construct will evaluate to true
With the sh [
test there are a few differences:
# leading 0
$ [ 01 -eq 1 ]; echo $?
0
# adjacent whitespace
$ [ ' 1' -eq 1 ]; echo $?
0
# negative 0 vs positive 0
$ [ 0 -eq -0 ]; echo $?
0
However with the bash [[
test there are a large number of differences (Including the ones mentioned above):
# base 8
$ [[ 032 -eq 26 ]]; echo $?
0
# Arithmetic expressions
$ [[ 1*6+32/15*2-1 -eq 9 ]]; echo $?
0
# Base 64
$ [[ 64#Hello_world -eq -5506400892957379251 ]]; echo $?
0
I'm just a bit confused about what is meant by numeric and string comparisons. Let's say I use=
to compare numbers. When is it not going to not yield the same result as a numeric comparison?
– Elegance
Mar 7 at 19:17
Any examples with strings that have nothing but digits, and don't have leading zeros?
– Elegance
Mar 7 at 19:21
1
@Elegance The point is that with-eq
, the left and right hand side are compared as integers, not as strings. The test would evaluate the strings as integers (probably by passing them throughstrtol()
or some such C function) before carrying out the comparison.
– Kusalananda
Mar 7 at 19:43
1
@Elegance In abash
test with[[ ... -eq ... ]]
you could even have arithmetic calculations on either side, as in[[ 1+1 -eq 2 ]]
. Obviously,[[ 1+1 == 2 ]]
would not be true.
– Kusalananda
Mar 7 at 20:02
@Jesse_b You shared the same link twice. I take it the first one is incorrect.
– Elegance
Mar 7 at 22:09
|
show 1 more comment
-eq
True if the integers n1 and n2 are algebraically equal; otherwise, false.
test
=
True if the strings s1 and s2 are identical; otherwise, false.
test
So -eq
compares integers and =
compares strings (which will also work with some limited integer cases).
You do have a syntax issue though, it should be:
[ "$rc" = 0 ]
And not
[ $rc=0 ]
[ "$rc" = 0 ]
should exit with 1 because rc
does not equal 0
[ $rc=0 ]
should actually exit with 0 because it's likely going to be treated as a string and the presence of a string within the [
test construct will evaluate to true
With the sh [
test there are a few differences:
# leading 0
$ [ 01 -eq 1 ]; echo $?
0
# adjacent whitespace
$ [ ' 1' -eq 1 ]; echo $?
0
# negative 0 vs positive 0
$ [ 0 -eq -0 ]; echo $?
0
However with the bash [[
test there are a large number of differences (Including the ones mentioned above):
# base 8
$ [[ 032 -eq 26 ]]; echo $?
0
# Arithmetic expressions
$ [[ 1*6+32/15*2-1 -eq 9 ]]; echo $?
0
# Base 64
$ [[ 64#Hello_world -eq -5506400892957379251 ]]; echo $?
0
-eq
True if the integers n1 and n2 are algebraically equal; otherwise, false.
test
=
True if the strings s1 and s2 are identical; otherwise, false.
test
So -eq
compares integers and =
compares strings (which will also work with some limited integer cases).
You do have a syntax issue though, it should be:
[ "$rc" = 0 ]
And not
[ $rc=0 ]
[ "$rc" = 0 ]
should exit with 1 because rc
does not equal 0
[ $rc=0 ]
should actually exit with 0 because it's likely going to be treated as a string and the presence of a string within the [
test construct will evaluate to true
With the sh [
test there are a few differences:
# leading 0
$ [ 01 -eq 1 ]; echo $?
0
# adjacent whitespace
$ [ ' 1' -eq 1 ]; echo $?
0
# negative 0 vs positive 0
$ [ 0 -eq -0 ]; echo $?
0
However with the bash [[
test there are a large number of differences (Including the ones mentioned above):
# base 8
$ [[ 032 -eq 26 ]]; echo $?
0
# Arithmetic expressions
$ [[ 1*6+32/15*2-1 -eq 9 ]]; echo $?
0
# Base 64
$ [[ 64#Hello_world -eq -5506400892957379251 ]]; echo $?
0
edited Mar 7 at 20:32
answered Mar 7 at 18:50
Jesse_bJesse_b
13.8k23471
13.8k23471
I'm just a bit confused about what is meant by numeric and string comparisons. Let's say I use=
to compare numbers. When is it not going to not yield the same result as a numeric comparison?
– Elegance
Mar 7 at 19:17
Any examples with strings that have nothing but digits, and don't have leading zeros?
– Elegance
Mar 7 at 19:21
1
@Elegance The point is that with-eq
, the left and right hand side are compared as integers, not as strings. The test would evaluate the strings as integers (probably by passing them throughstrtol()
or some such C function) before carrying out the comparison.
– Kusalananda
Mar 7 at 19:43
1
@Elegance In abash
test with[[ ... -eq ... ]]
you could even have arithmetic calculations on either side, as in[[ 1+1 -eq 2 ]]
. Obviously,[[ 1+1 == 2 ]]
would not be true.
– Kusalananda
Mar 7 at 20:02
@Jesse_b You shared the same link twice. I take it the first one is incorrect.
– Elegance
Mar 7 at 22:09
|
show 1 more comment
I'm just a bit confused about what is meant by numeric and string comparisons. Let's say I use=
to compare numbers. When is it not going to not yield the same result as a numeric comparison?
– Elegance
Mar 7 at 19:17
Any examples with strings that have nothing but digits, and don't have leading zeros?
– Elegance
Mar 7 at 19:21
1
@Elegance The point is that with-eq
, the left and right hand side are compared as integers, not as strings. The test would evaluate the strings as integers (probably by passing them throughstrtol()
or some such C function) before carrying out the comparison.
– Kusalananda
Mar 7 at 19:43
1
@Elegance In abash
test with[[ ... -eq ... ]]
you could even have arithmetic calculations on either side, as in[[ 1+1 -eq 2 ]]
. Obviously,[[ 1+1 == 2 ]]
would not be true.
– Kusalananda
Mar 7 at 20:02
@Jesse_b You shared the same link twice. I take it the first one is incorrect.
– Elegance
Mar 7 at 22:09
I'm just a bit confused about what is meant by numeric and string comparisons. Let's say I use
=
to compare numbers. When is it not going to not yield the same result as a numeric comparison?– Elegance
Mar 7 at 19:17
I'm just a bit confused about what is meant by numeric and string comparisons. Let's say I use
=
to compare numbers. When is it not going to not yield the same result as a numeric comparison?– Elegance
Mar 7 at 19:17
Any examples with strings that have nothing but digits, and don't have leading zeros?
– Elegance
Mar 7 at 19:21
Any examples with strings that have nothing but digits, and don't have leading zeros?
– Elegance
Mar 7 at 19:21
1
1
@Elegance The point is that with
-eq
, the left and right hand side are compared as integers, not as strings. The test would evaluate the strings as integers (probably by passing them through strtol()
or some such C function) before carrying out the comparison.– Kusalananda
Mar 7 at 19:43
@Elegance The point is that with
-eq
, the left and right hand side are compared as integers, not as strings. The test would evaluate the strings as integers (probably by passing them through strtol()
or some such C function) before carrying out the comparison.– Kusalananda
Mar 7 at 19:43
1
1
@Elegance In a
bash
test with [[ ... -eq ... ]]
you could even have arithmetic calculations on either side, as in [[ 1+1 -eq 2 ]]
. Obviously, [[ 1+1 == 2 ]]
would not be true.– Kusalananda
Mar 7 at 20:02
@Elegance In a
bash
test with [[ ... -eq ... ]]
you could even have arithmetic calculations on either side, as in [[ 1+1 -eq 2 ]]
. Obviously, [[ 1+1 == 2 ]]
would not be true.– Kusalananda
Mar 7 at 20:02
@Jesse_b You shared the same link twice. I take it the first one is incorrect.
– Elegance
Mar 7 at 22:09
@Jesse_b You shared the same link twice. I take it the first one is incorrect.
– Elegance
Mar 7 at 22:09
|
show 1 more comment
For numeric comparisons you have to use -eq
whereas =
is for string comparisons (as from your variable naming you already seem to know).
One of the best introductions on the test
aka [
command I know is The Unix Shell's Humble If
add a comment |
For numeric comparisons you have to use -eq
whereas =
is for string comparisons (as from your variable naming you already seem to know).
One of the best introductions on the test
aka [
command I know is The Unix Shell's Humble If
add a comment |
For numeric comparisons you have to use -eq
whereas =
is for string comparisons (as from your variable naming you already seem to know).
One of the best introductions on the test
aka [
command I know is The Unix Shell's Humble If
For numeric comparisons you have to use -eq
whereas =
is for string comparisons (as from your variable naming you already seem to know).
One of the best introductions on the test
aka [
command I know is The Unix Shell's Humble If
answered Mar 7 at 18:55
freiheitsnetzfreiheitsnetz
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I didn't know about the space being necessary. What I meant with "odd" is "weird if you read as pseudo code, ignoring the quirks of the language". Thanks. @ilkkachu
– Elegance
Mar 7 at 19:16
1
The only way I can get
[ $rc=0 ]
to fail withrc=1
is to setIFS
to 1 as well. That would cause both tests to error out and set$?
to 2 (inbash
).– Kusalananda
Mar 7 at 19:25
@ilkkachu There was a typo. Of course I can't ignore them, but if I knew them, I wouldn't have to ask. That's exactly the point of the question.
– Elegance
Mar 7 at 21:29
@Elegance, ok, good, thanks. And yes, you're right, you wouldn't have to ask if you knew. It's just that even a typo like that can send the readers off in the wrong direction, looking for some really weird edge case that could explain the result. (The shell can be a bit quirky sometimes so there might have been a remote possibility of an edge case where both would return
1
...)– ilkkachu
Mar 7 at 21:52
@ilkkachu Thank you for the helpful feedback.
– Elegance
Mar 7 at 22:08