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How to search a specific part of a JSON object and add to an already existing object
Safely turning a JSON string into an objectHow do I format a Microsoft JSON date?How can I pretty-print JSON in a shell script?How do I generate random integers within a specific range in Java?How do I test for an empty JavaScript object?Fling gesture detection on grid layoutHow to parse JSON in JavaConvert JS object to JSON stringHow can I pretty-print JSON using JavaScript?How to POST JSON data with Curl from Terminal/Commandline to Test Spring REST?
I'm new to using JSONs and I'm having a bit of difficulty. I am using the Kitsu API and parsing the JSON I get when I login. When I parse my json the image below pops up, but inside the 1 object array I want to get the large url in the avatar object inside of the attributes object and I don't know how.The beginning of the JSON, The middle of the JSON, The end. Lastly, I want to know how to edit the slug part of the JSON, if you don't know that's cool the main thing is getting the avatar url.
Picture of my error
java
android json asked Mar 7 at 22:10
jmorg85jmorg85
15
add a comment |
I'm new to using JSONs and I'm having a bit of difficulty. I am using the Kitsu API and parsing the JSON I get when I login. When I parse my json the image below pops up, but inside the 1 object array I want to get the large url in the avatar object inside of the attributes object and I don't know how.The beginning of the JSON, The middle of the JSON, The end. Lastly, I want to know how to edit the slug part of the JSON, if you don't know that's cool the main thing is getting the avatar url.
Picture of my error
java
android json asked Mar 7 at 22:10
jmorg85jmorg85
15
stackoverflow.com/help/mcve
– Marcin Orlowski
Mar 7 at 22:12
add a comment |
I'm new to using JSONs and I'm having a bit of difficulty. I am using the Kitsu API and parsing the JSON I get when I login. When I parse my json the image below pops up, but inside the 1 object array I want to get the large url in the avatar object inside of the attributes object and I don't know how.The beginning of the JSON, The middle of the JSON, The end. Lastly, I want to know how to edit the slug part of the JSON, if you don't know that's cool the main thing is getting the avatar url.
Picture of my error
java
android json asked Mar 7 at 22:10
jmorg85jmorg85
15
I'm new to using JSONs and I'm having a bit of difficulty. I am using the Kitsu API and parsing the JSON I get when I login. When I parse my json the image below pops up, but inside the 1 object array I want to get the large url in the avatar object inside of the attributes object and I don't know how.The beginning of the JSON, The middle of the JSON, The end. Lastly, I want to know how to edit the slug part of the JSON, if you don't know that's cool the main thing is getting the avatar url.
Picture of my error
java
android json java
android json asked Mar 7 at 22:10
jmorg85jmorg85
15
asked Mar 7 at 22:10
jmorg85jmorg85
15
edited Mar 7 at 22:28
jmorg85
asked Mar 7 at 22:10
jmorg85jmorg85
15
asked Mar 7 at 22:10
jmorg85jmorg85
15
asked Mar 7 at 22:10
jmorg85jmorg85
15
15
stackoverflow.com/help/mcve
– Marcin Orlowski
Mar 7 at 22:12
add a comment |
stackoverflow.com/help/mcve
– Marcin Orlowski
Mar 7 at 22:12
stackoverflow.com/help/mcve
– Marcin Orlowski
Mar 7 at 22:12
stackoverflow.com/help/mcve
– Marcin Orlowski
Mar 7 at 22:12
add a comment |
1 Answer
1
active
oldest
votes
Please, try this...
JSONObject myObject = new JSONObject(jsonStr);
JSONArray myArray = myObject.getJSONArray("data");
JSONObject obj = myArray.getJSONObject(0);
String id = obj.getString("id");
String type = obj.getString("type");
//change the lines bellow
JSONObject attributes = obj.getJSONObject("attributes");
JSONObject avatar = attributes.getJSONObject("avatar");
String large = avatar.getString("large");
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
Okay, I tried that and it's just not taking data, I'm also semi new to stack overflow so it'll be a bit before I add a picture of what I'm getting.
– jmorg85
Mar 7 at 22:27
Please, share your code where you are trying to read.
– Bruno Carneiro
Mar 7 at 22:39
JSONObject myObject = new JSONObject(jsonStr); JSONArray myArray = myObject.getJSONArray("data"); JSONObject obj = myArray.getJSONObject(0); String id = obj.getString("id"); String type = obj.getString("type"); JSONObject attributes = new JSONObject("attributes"); String avatar = jsonStr.data[0].attributes.avatar.large;
– jmorg85
Mar 7 at 22:44
I'm sorry, but due to stack overflow's character limit I can't put in the whole method.
– jmorg85
Mar 7 at 22:46
But yeah only data is red, while everything else if fine.
– jmorg85
Mar 7 at 22:47
|
show 6 more comments
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Please, try this...
JSONObject myObject = new JSONObject(jsonStr);
JSONArray myArray = myObject.getJSONArray("data");
JSONObject obj = myArray.getJSONObject(0);
String id = obj.getString("id");
String type = obj.getString("type");
//change the lines bellow
JSONObject attributes = obj.getJSONObject("attributes");
JSONObject avatar = attributes.getJSONObject("avatar");
String large = avatar.getString("large");
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
Okay, I tried that and it's just not taking data, I'm also semi new to stack overflow so it'll be a bit before I add a picture of what I'm getting.
– jmorg85
Mar 7 at 22:27
Please, share your code where you are trying to read.
– Bruno Carneiro
Mar 7 at 22:39
JSONObject myObject = new JSONObject(jsonStr); JSONArray myArray = myObject.getJSONArray("data"); JSONObject obj = myArray.getJSONObject(0); String id = obj.getString("id"); String type = obj.getString("type"); JSONObject attributes = new JSONObject("attributes"); String avatar = jsonStr.data[0].attributes.avatar.large;
– jmorg85
Mar 7 at 22:44
I'm sorry, but due to stack overflow's character limit I can't put in the whole method.
– jmorg85
Mar 7 at 22:46
But yeah only data is red, while everything else if fine.
– jmorg85
Mar 7 at 22:47
|
show 6 more comments
Please, try this...
JSONObject myObject = new JSONObject(jsonStr);
JSONArray myArray = myObject.getJSONArray("data");
JSONObject obj = myArray.getJSONObject(0);
String id = obj.getString("id");
String type = obj.getString("type");
//change the lines bellow
JSONObject attributes = obj.getJSONObject("attributes");
JSONObject avatar = attributes.getJSONObject("avatar");
String large = avatar.getString("large");
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
Okay, I tried that and it's just not taking data, I'm also semi new to stack overflow so it'll be a bit before I add a picture of what I'm getting.
– jmorg85
Mar 7 at 22:27
Please, share your code where you are trying to read.
– Bruno Carneiro
Mar 7 at 22:39
JSONObject myObject = new JSONObject(jsonStr); JSONArray myArray = myObject.getJSONArray("data"); JSONObject obj = myArray.getJSONObject(0); String id = obj.getString("id"); String type = obj.getString("type"); JSONObject attributes = new JSONObject("attributes"); String avatar = jsonStr.data[0].attributes.avatar.large;
– jmorg85
Mar 7 at 22:44
I'm sorry, but due to stack overflow's character limit I can't put in the whole method.
– jmorg85
Mar 7 at 22:46
But yeah only data is red, while everything else if fine.
– jmorg85
Mar 7 at 22:47
|
show 6 more comments
Please, try this...
JSONObject myObject = new JSONObject(jsonStr);
JSONArray myArray = myObject.getJSONArray("data");
JSONObject obj = myArray.getJSONObject(0);
String id = obj.getString("id");
String type = obj.getString("type");
//change the lines bellow
JSONObject attributes = obj.getJSONObject("attributes");
JSONObject avatar = attributes.getJSONObject("avatar");
String large = avatar.getString("large");
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
Please, try this...
JSONObject myObject = new JSONObject(jsonStr);
JSONArray myArray = myObject.getJSONArray("data");
JSONObject obj = myArray.getJSONObject(0);
String id = obj.getString("id");
String type = obj.getString("type");
//change the lines bellow
JSONObject attributes = obj.getJSONObject("attributes");
JSONObject avatar = attributes.getJSONObject("avatar");
String large = avatar.getString("large");
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
edited Mar 7 at 23:16
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
answered Mar 7 at 22:21
Bruno CarneiroBruno Carneiro
1449
1449
Okay, I tried that and it's just not taking data, I'm also semi new to stack overflow so it'll be a bit before I add a picture of what I'm getting.
– jmorg85
Mar 7 at 22:27
Please, share your code where you are trying to read.
– Bruno Carneiro
Mar 7 at 22:39
JSONObject myObject = new JSONObject(jsonStr); JSONArray myArray = myObject.getJSONArray("data"); JSONObject obj = myArray.getJSONObject(0); String id = obj.getString("id"); String type = obj.getString("type"); JSONObject attributes = new JSONObject("attributes"); String avatar = jsonStr.data[0].attributes.avatar.large;
– jmorg85
Mar 7 at 22:44
I'm sorry, but due to stack overflow's character limit I can't put in the whole method.
– jmorg85
Mar 7 at 22:46
But yeah only data is red, while everything else if fine.
– jmorg85
Mar 7 at 22:47
|
show 6 more comments
Okay, I tried that and it's just not taking data, I'm also semi new to stack overflow so it'll be a bit before I add a picture of what I'm getting.
– jmorg85
Mar 7 at 22:27
Please, share your code where you are trying to read.
– Bruno Carneiro
Mar 7 at 22:39
JSONObject myObject = new JSONObject(jsonStr); JSONArray myArray = myObject.getJSONArray("data"); JSONObject obj = myArray.getJSONObject(0); String id = obj.getString("id"); String type = obj.getString("type"); JSONObject attributes = new JSONObject("attributes"); String avatar = jsonStr.data[0].attributes.avatar.large;
– jmorg85
Mar 7 at 22:44
I'm sorry, but due to stack overflow's character limit I can't put in the whole method.
– jmorg85
Mar 7 at 22:46
But yeah only data is red, while everything else if fine.
– jmorg85
Mar 7 at 22:47
Okay, I tried that and it's just not taking data, I'm also semi new to stack overflow so it'll be a bit before I add a picture of what I'm getting.
– jmorg85
Mar 7 at 22:27
Okay, I tried that and it's just not taking data, I'm also semi new to stack overflow so it'll be a bit before I add a picture of what I'm getting.
– jmorg85
Mar 7 at 22:27
Please, share your code where you are trying to read.
– Bruno Carneiro
Mar 7 at 22:39
Please, share your code where you are trying to read.
– Bruno Carneiro
Mar 7 at 22:39
JSONObject myObject = new JSONObject(jsonStr); JSONArray myArray = myObject.getJSONArray("data"); JSONObject obj = myArray.getJSONObject(0); String id = obj.getString("id"); String type = obj.getString("type"); JSONObject attributes = new JSONObject("attributes"); String avatar = jsonStr.data[0].attributes.avatar.large;
– jmorg85
Mar 7 at 22:44
JSONObject myObject = new JSONObject(jsonStr); JSONArray myArray = myObject.getJSONArray("data"); JSONObject obj = myArray.getJSONObject(0); String id = obj.getString("id"); String type = obj.getString("type"); JSONObject attributes = new JSONObject("attributes"); String avatar = jsonStr.data[0].attributes.avatar.large;
– jmorg85
Mar 7 at 22:44
I'm sorry, but due to stack overflow's character limit I can't put in the whole method.
– jmorg85
Mar 7 at 22:46
I'm sorry, but due to stack overflow's character limit I can't put in the whole method.
– jmorg85
Mar 7 at 22:46
But yeah only data is red, while everything else if fine.
– jmorg85
Mar 7 at 22:47
But yeah only data is red, while everything else if fine.
– jmorg85
Mar 7 at 22:47
|
show 6 more comments
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stackoverflow.com/help/mcve
– Marcin Orlowski
Mar 7 at 22:12