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conditional check in Ansible iosxr_config module
Run command on the Ansible hostSpecify sudo password for AnsibleHow to create a directory using Ansibleansible: lineinfile for several lines?Ansible - variable changing it's value even though the condition is not metAnsible: filter a list by its attributesAnsible register variable in task and use it in templateAnsible: Conditional task parameterConditional variable check using Ansible with failed_when module?Ansible multiple when condition failing
I am trying to run a config from j2 onto IOSXR on checking a cond
ition
name: conf
iosxr_command:
commands: "show run interface Bundle-Ether 1234"
register: reg- name: put j2 on iosxr
iosxr_config:
src: templates/abc.j2
when : '" string" in reg.stdout'
- name: put j2 on iosxr
I don't get any errors but it always says the condition is false even though it is not supposed to .
Thanks !
ansible jinja2
asked Mar 7 at 21:56
SanjuSanju
12
add a comment |
I am trying to run a config from j2 onto IOSXR on checking a cond
ition
name: conf
iosxr_command:
commands: "show run interface Bundle-Ether 1234"
register: reg- name: put j2 on iosxr
iosxr_config:
src: templates/abc.j2
when : '" string" in reg.stdout'
- name: put j2 on iosxr
I don't get any errors but it always says the condition is false even though it is not supposed to .
Thanks !
ansible jinja2
asked Mar 7 at 21:56
SanjuSanju
12
add a comment |
I am trying to run a config from j2 onto IOSXR on checking a cond
ition
name: conf
iosxr_command:
commands: "show run interface Bundle-Ether 1234"
register: reg- name: put j2 on iosxr
iosxr_config:
src: templates/abc.j2
when : '" string" in reg.stdout'
- name: put j2 on iosxr
I don't get any errors but it always says the condition is false even though it is not supposed to .
Thanks !
ansible jinja2
asked Mar 7 at 21:56
SanjuSanju
12
I am trying to run a config from j2 onto IOSXR on checking a cond
ition
name: conf
iosxr_command:
commands: "show run interface Bundle-Ether 1234"
register: reg- name: put j2 on iosxr
iosxr_config:
src: templates/abc.j2
when : '" string" in reg.stdout'
- name: put j2 on iosxr
I don't get any errors but it always says the condition is false even though it is not supposed to .
Thanks !
ansible jinja2
ansible jinja2
asked Mar 7 at 21:56
SanjuSanju
12
asked Mar 7 at 21:56
SanjuSanju
12
asked Mar 7 at 21:56
SanjuSanju
12
asked Mar 7 at 21:56
SanjuSanju
12
asked Mar 7 at 21:56
SanjuSanju
12
12
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You used the quotes incorrectly in your conditional:
when: "string" in reg.stdout
The syntax of "when" can be a bit confusing as it is different from everywhere else, so here are some notable things you might find helpful:
- " " around the entire conditional are optional, but never use ' '
- any strings need to be in " " or ' '
- everything that is not surrounded by " " or ' ' is interpreted as either a keyword (i.e. in) or a variable (i.e. reg.stdout). You can use filters with those variables, but you should surround the variable and the filters with ( )
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
If I try that way I get the following error messageThis one looks easy to fix. It seems that there is a value started with a quote, and the YAML parser is expecting to see the line ended with the same kind of quote. For instance: when: "ok" in result.stdout Could be written as: when: '"ok" in result.stdout' Or equivalently: when: "'ok' in result.stdout"
– Sanju
Mar 8 at 14:54
add a comment |
Actually what I did was correct. I was checking wrong string in the condition .
answered Mar 8 at 16:55
SanjuSanju
12
add a comment |
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2 Answers
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2 Answers
2
active
oldest
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active
oldest
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active
oldest
votes
You used the quotes incorrectly in your conditional:
when: "string" in reg.stdout
The syntax of "when" can be a bit confusing as it is different from everywhere else, so here are some notable things you might find helpful:
- " " around the entire conditional are optional, but never use ' '
- any strings need to be in " " or ' '
- everything that is not surrounded by " " or ' ' is interpreted as either a keyword (i.e. in) or a variable (i.e. reg.stdout). You can use filters with those variables, but you should surround the variable and the filters with ( )
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
If I try that way I get the following error messageThis one looks easy to fix. It seems that there is a value started with a quote, and the YAML parser is expecting to see the line ended with the same kind of quote. For instance: when: "ok" in result.stdout Could be written as: when: '"ok" in result.stdout' Or equivalently: when: "'ok' in result.stdout"
– Sanju
Mar 8 at 14:54
add a comment |
You used the quotes incorrectly in your conditional:
when: "string" in reg.stdout
The syntax of "when" can be a bit confusing as it is different from everywhere else, so here are some notable things you might find helpful:
- " " around the entire conditional are optional, but never use ' '
- any strings need to be in " " or ' '
- everything that is not surrounded by " " or ' ' is interpreted as either a keyword (i.e. in) or a variable (i.e. reg.stdout). You can use filters with those variables, but you should surround the variable and the filters with ( )
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
If I try that way I get the following error messageThis one looks easy to fix. It seems that there is a value started with a quote, and the YAML parser is expecting to see the line ended with the same kind of quote. For instance: when: "ok" in result.stdout Could be written as: when: '"ok" in result.stdout' Or equivalently: when: "'ok' in result.stdout"
– Sanju
Mar 8 at 14:54
add a comment |
You used the quotes incorrectly in your conditional:
when: "string" in reg.stdout
The syntax of "when" can be a bit confusing as it is different from everywhere else, so here are some notable things you might find helpful:
- " " around the entire conditional are optional, but never use ' '
- any strings need to be in " " or ' '
- everything that is not surrounded by " " or ' ' is interpreted as either a keyword (i.e. in) or a variable (i.e. reg.stdout). You can use filters with those variables, but you should surround the variable and the filters with ( )
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
You used the quotes incorrectly in your conditional:
when: "string" in reg.stdout
The syntax of "when" can be a bit confusing as it is different from everywhere else, so here are some notable things you might find helpful:
- " " around the entire conditional are optional, but never use ' '
- any strings need to be in " " or ' '
- everything that is not surrounded by " " or ' ' is interpreted as either a keyword (i.e. in) or a variable (i.e. reg.stdout). You can use filters with those variables, but you should surround the variable and the filters with ( )
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
answered Mar 7 at 23:47
CERN_FanCERN_Fan
513
513
If I try that way I get the following error messageThis one looks easy to fix. It seems that there is a value started with a quote, and the YAML parser is expecting to see the line ended with the same kind of quote. For instance: when: "ok" in result.stdout Could be written as: when: '"ok" in result.stdout' Or equivalently: when: "'ok' in result.stdout"
– Sanju
Mar 8 at 14:54
add a comment |
If I try that way I get the following error messageThis one looks easy to fix. It seems that there is a value started with a quote, and the YAML parser is expecting to see the line ended with the same kind of quote. For instance: when: "ok" in result.stdout Could be written as: when: '"ok" in result.stdout' Or equivalently: when: "'ok' in result.stdout"
– Sanju
Mar 8 at 14:54
If I try that way I get the following error message
This one looks easy to fix. It seems that there is a value started with a quote, and the YAML parser is expecting to see the line ended with the same kind of quote. For instance: when: "ok" in result.stdout Could be written as: when: '"ok" in result.stdout' Or equivalently: when: "'ok' in result.stdout" – Sanju
Mar 8 at 14:54
If I try that way I get the following error message
This one looks easy to fix. It seems that there is a value started with a quote, and the YAML parser is expecting to see the line ended with the same kind of quote. For instance: when: "ok" in result.stdout Could be written as: when: '"ok" in result.stdout' Or equivalently: when: "'ok' in result.stdout" – Sanju
Mar 8 at 14:54
add a comment |
Actually what I did was correct. I was checking wrong string in the condition .
answered Mar 8 at 16:55
SanjuSanju
12
add a comment |
Actually what I did was correct. I was checking wrong string in the condition .
answered Mar 8 at 16:55
SanjuSanju
12
add a comment |
Actually what I did was correct. I was checking wrong string in the condition .
answered Mar 8 at 16:55
SanjuSanju
12
Actually what I did was correct. I was checking wrong string in the condition .
answered Mar 8 at 16:55
SanjuSanju
12
answered Mar 8 at 16:55
SanjuSanju
12
answered Mar 8 at 16:55
SanjuSanju
12
answered Mar 8 at 16:55
SanjuSanju
12
12
add a comment |
add a comment |
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