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Custom WP Plugin and form handling


shell_exec escaping quotes in php for Twitter API --> Getting CURL to work with obscure twitter api methodextract url from xml response and redirectSolution for invalid REQUEST_URI sent using CURLHow much bandwidth do I generate to destination web site with my curl code?ABBYY OCR SDK: I am trying a sample script for recognizing business cards but not getting any outputphp Curl posting to PHPBBHow to implement cache system in php for json apiHow to load details automaticallycURL not working sometimes and gives empty resulthow can i check if RESTAPI is down using curl php













0















Hi thats is my first post and please don't kill me :D
So, I work on my custom WP plugin. The plugin simple fetch data from one XML file and display it in widget area. Now I want to let the Administrator to choose a data source (simple form like this:



admin-page.php



<h3> Please select a data source </h3>
<form method ="post" action="#">
<select name="Data source">
<option value="news1">Data source 1</option>
<option value="news2">Data source 2</option>
<option value="news3">Data source 3</option>
</select>
<input type="hidden" name="action" value="Specifed url goes here ?" />
<input type="submit">
</form>


All functionality of the widget is stored in my-widget-functions.php



$url='http://mydatasource/xyz?';
$ch = curl_init();
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL,$url);
$result=curl_exec($ch);
curl_close($ch);
.........
convert->xml;/


Here is my question. I want to change the data source based on user(admin) input, in my case that means the variable $url stored in my-widget-functions.php.
Some suggestions, how to do that? Change a variable in another file, based on user input?



I tried to pass the user input between this 2 files with sessions, but it doesn't work. Actually, in that way, the user input was not stored in the WP-DB.










share|improve this question




























    0















    Hi thats is my first post and please don't kill me :D
    So, I work on my custom WP plugin. The plugin simple fetch data from one XML file and display it in widget area. Now I want to let the Administrator to choose a data source (simple form like this:



    admin-page.php



    <h3> Please select a data source </h3>
    <form method ="post" action="#">
    <select name="Data source">
    <option value="news1">Data source 1</option>
    <option value="news2">Data source 2</option>
    <option value="news3">Data source 3</option>
    </select>
    <input type="hidden" name="action" value="Specifed url goes here ?" />
    <input type="submit">
    </form>


    All functionality of the widget is stored in my-widget-functions.php



    $url='http://mydatasource/xyz?';
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_URL,$url);
    $result=curl_exec($ch);
    curl_close($ch);
    .........
    convert->xml;/


    Here is my question. I want to change the data source based on user(admin) input, in my case that means the variable $url stored in my-widget-functions.php.
    Some suggestions, how to do that? Change a variable in another file, based on user input?



    I tried to pass the user input between this 2 files with sessions, but it doesn't work. Actually, in that way, the user input was not stored in the WP-DB.










    share|improve this question


























      0












      0








      0








      Hi thats is my first post and please don't kill me :D
      So, I work on my custom WP plugin. The plugin simple fetch data from one XML file and display it in widget area. Now I want to let the Administrator to choose a data source (simple form like this:



      admin-page.php



      <h3> Please select a data source </h3>
      <form method ="post" action="#">
      <select name="Data source">
      <option value="news1">Data source 1</option>
      <option value="news2">Data source 2</option>
      <option value="news3">Data source 3</option>
      </select>
      <input type="hidden" name="action" value="Specifed url goes here ?" />
      <input type="submit">
      </form>


      All functionality of the widget is stored in my-widget-functions.php



      $url='http://mydatasource/xyz?';
      $ch = curl_init();
      curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
      curl_setopt($ch, CURLOPT_URL,$url);
      $result=curl_exec($ch);
      curl_close($ch);
      .........
      convert->xml;/


      Here is my question. I want to change the data source based on user(admin) input, in my case that means the variable $url stored in my-widget-functions.php.
      Some suggestions, how to do that? Change a variable in another file, based on user input?



      I tried to pass the user input between this 2 files with sessions, but it doesn't work. Actually, in that way, the user input was not stored in the WP-DB.










      share|improve this question
















      Hi thats is my first post and please don't kill me :D
      So, I work on my custom WP plugin. The plugin simple fetch data from one XML file and display it in widget area. Now I want to let the Administrator to choose a data source (simple form like this:



      admin-page.php



      <h3> Please select a data source </h3>
      <form method ="post" action="#">
      <select name="Data source">
      <option value="news1">Data source 1</option>
      <option value="news2">Data source 2</option>
      <option value="news3">Data source 3</option>
      </select>
      <input type="hidden" name="action" value="Specifed url goes here ?" />
      <input type="submit">
      </form>


      All functionality of the widget is stored in my-widget-functions.php



      $url='http://mydatasource/xyz?';
      $ch = curl_init();
      curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
      curl_setopt($ch, CURLOPT_URL,$url);
      $result=curl_exec($ch);
      curl_close($ch);
      .........
      convert->xml;/


      Here is my question. I want to change the data source based on user(admin) input, in my case that means the variable $url stored in my-widget-functions.php.
      Some suggestions, how to do that? Change a variable in another file, based on user input?



      I tried to pass the user input between this 2 files with sessions, but it doesn't work. Actually, in that way, the user input was not stored in the WP-DB.







      php wordpress






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Mar 8 at 9:47









      astro_asz

      1,081823




      1,081823










      asked Mar 8 at 9:34









      Qonquistador123Qonquistador123

      12




      12






















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