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Type narrowing doens't work as expected for object


How to tell TypeScript that optional property in object exists and is set?Type definition in object literal in TypeScriptAre strongly-typed functions as parameters possible in TypeScript?Typescript: Interfaces vs TypesTypeScript. How to use not exported type definitions?Typescript check if property in object in typesafe wayWhy doesn't typescript undefined type behave same as optional?TypeScript Inline static type guardType for non-falsy, aka truthykeyof interface without generic index signaturesHow can I check that a string is a property a particular interface in TypeScript













0















interface Obj 
foo?: string;
bar?: string;


const fn = (obj: Obj, key: keyof Obj) =>
if (obj.foo)
const val1 = obj.foo; // string


if (obj['foo'])
const val2 = obj['foo'] // string


const picked = obj[key];

if (picked)
const val3 = picked; // string


if (obj[key])
const val4 = obj[key]; // string
;


I wonder why type narrowing doesn't work in case of val4.



I know I can use ! or custom defined type guards answered here. But what I want to know is the reason.










share|improve this question


























    0















    interface Obj 
    foo?: string;
    bar?: string;


    const fn = (obj: Obj, key: keyof Obj) =>
    if (obj.foo)
    const val1 = obj.foo; // string


    if (obj['foo'])
    const val2 = obj['foo'] // string


    const picked = obj[key];

    if (picked)
    const val3 = picked; // string


    if (obj[key])
    const val4 = obj[key]; // string
    ;


    I wonder why type narrowing doesn't work in case of val4.



    I know I can use ! or custom defined type guards answered here. But what I want to know is the reason.










    share|improve this question
























      0












      0








      0








      interface Obj 
      foo?: string;
      bar?: string;


      const fn = (obj: Obj, key: keyof Obj) =>
      if (obj.foo)
      const val1 = obj.foo; // string


      if (obj['foo'])
      const val2 = obj['foo'] // string


      const picked = obj[key];

      if (picked)
      const val3 = picked; // string


      if (obj[key])
      const val4 = obj[key]; // string
      ;


      I wonder why type narrowing doesn't work in case of val4.



      I know I can use ! or custom defined type guards answered here. But what I want to know is the reason.










      share|improve this question














      interface Obj 
      foo?: string;
      bar?: string;


      const fn = (obj: Obj, key: keyof Obj) =>
      if (obj.foo)
      const val1 = obj.foo; // string


      if (obj['foo'])
      const val2 = obj['foo'] // string


      const picked = obj[key];

      if (picked)
      const val3 = picked; // string


      if (obj[key])
      const val4 = obj[key]; // string
      ;


      I wonder why type narrowing doesn't work in case of val4.



      I know I can use ! or custom defined type guards answered here. But what I want to know is the reason.







      typescript






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 8 at 9:38









      chatoo2412chatoo2412

      9815




      9815






















          1 Answer
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          0














          Narowing does not work on dynamic access to the object (access with [] and a variable as the index). This limitation is due to performance reasons. You can search GitHub for issues around this, here is one.






          share|improve this answer






















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            1 Answer
            1






            active

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            active

            oldest

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            active

            oldest

            votes









            0














            Narowing does not work on dynamic access to the object (access with [] and a variable as the index). This limitation is due to performance reasons. You can search GitHub for issues around this, here is one.






            share|improve this answer



























              0














              Narowing does not work on dynamic access to the object (access with [] and a variable as the index). This limitation is due to performance reasons. You can search GitHub for issues around this, here is one.






              share|improve this answer

























                0












                0








                0







                Narowing does not work on dynamic access to the object (access with [] and a variable as the index). This limitation is due to performance reasons. You can search GitHub for issues around this, here is one.






                share|improve this answer













                Narowing does not work on dynamic access to the object (access with [] and a variable as the index). This limitation is due to performance reasons. You can search GitHub for issues around this, here is one.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Mar 8 at 9:48









                Titian Cernicova-DragomirTitian Cernicova-Dragomir

                71.6k35068




                71.6k35068





























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