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Numpy Array Manipulation Based off of Internal Values
Is there a NumPy function to return the first index of something in an array?How to print the full NumPy array, without truncation?Find nearest value in numpy arrayNumpy array dimensionsHow to access the ith column of a NumPy multidimensional array?Dump a NumPy array into a csv fileHow do I get indices of N maximum values in a NumPy array?How to convert 2D float numpy array to 2D int numpy array?How should I divide a large (~50Gb) dataset into training, test, and validation sets?Select rows from a DataFrame based on values in a column in pandas
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty height:90px;width:728px;box-sizing:border-box;
I am trying to accomplish a weird task.
I need to complete the following without the use of sklearn, and preferably with numpy:
- Given a dataset, split the data into 5 equal "folds", or partitions
- Within each partition, split the data into a "training" and "testing" set, with an 80/20 split
- Here is the catch: Your dataset is labeled for classes. So take for example a dataset with 100 instances, and class A with 33 samples and class B with 67 samples. I should create 5 folds of 20 data instances, where in each fold, class A has something like 6 or 7 (1/3) values and class B has the rest
My issue that:
I do not know how to properly return a test and training set for each fold, despite being able to split it appropriately, and, more important, I do not know how to incorporate the proper division of # of elements per class.
My current code is here. It is commented where I am stuck:
import numpy
def csv_to_array(file):
# Open the file, and load it in delimiting on the ',' for a comma separated value file
data = open(file, 'r')
data = numpy.loadtxt(data, delimiter=',')
# Loop through the data in the array
for index in range(len(data)):
# Utilize a try catch to try and convert to float, if it can't convert to float, converts to 0
try:
data[index] = [float(x) for x in data[index]]
except Exception:
data[index] = 0
except ValueError:
data[index] = 0
# Return the now type-formatted data
return data
def five_cross_fold_validation(dataset):
# print("DATASET", dataset)
numpy.random.shuffle(dataset)
num_rows = dataset.shape[0]
split_mark = int(num_rows / 5)
folds = []
temp1 = dataset[:split_mark]
# print("TEMP1", temp1)
temp2 = dataset[split_mark:split_mark*2]
# print("TEMP2", temp2)
temp3 = dataset[split_mark*2:split_mark*3]
# print("TEMP3", temp3)
temp4 = dataset[split_mark*3:split_mark*4]
# print("TEMP4", temp4)
temp5 = dataset[split_mark*4:]
# print("TEMP5", temp5)
folds.append(temp1)
folds.append(temp2)
folds.append(temp3)
folds.append(temp4)
folds.append(temp5)
# folds = numpy.asarray(folds)
for fold in folds:
# fold = numpy.asarray(fold)
num_rows = fold.shape[0]
split_mark = int(num_rows * .8)
fold_training = fold[split_mark:]
fold_testing = fold[:split_mark]
print(type(fold))
# fold.tolist()
list(fold)
print(type(fold))
del fold[0:len(fold)]
fold.append(fold_training)
fold.append(fold_testing)
fold = numpy.asarray(fold)
# Somehow, return a testing and training set within each fold
# print(folds)
return folds
def confirm_size(folds):
total = 0
for fold in folds:
curr = len(fold)
total = total + curr
return total
def main():
print("BEGINNING CFV")
ecoli = csv_to_array('Classification/ecoli.csv')
print(len(ecoli))
folds = five_cross_fold_validation(ecoli)
size = confirm_size(folds)
print(size)
main()
Additionally, for reference, I have attached my csv I am working with (it is a modification of the UCI Ecoli Dataset.) The classes here are the values in the last column. So 0, 1, 2, 3, 4. It is important to note that there are not equal amounts of each class.
0.61,0.45,0.48,0.5,0.48,0.35,0.41,0
0.17,0.38,0.48,0.5,0.45,0.42,0.5,0
0.44,0.35,0.48,0.5,0.55,0.55,0.61,0
0.43,0.4,0.48,0.5,0.39,0.28,0.39,0
0.42,0.35,0.48,0.5,0.58,0.15,0.27,0
0.23,0.33,0.48,0.5,0.43,0.33,0.43,0
0.37,0.52,0.48,0.5,0.42,0.42,0.36,0
0.29,0.3,0.48,0.5,0.45,0.03,0.17,0
0.22,0.36,0.48,0.5,0.35,0.39,0.47,0
0.23,0.58,0.48,0.5,0.37,0.53,0.59,0
0.47,0.47,0.48,0.5,0.22,0.16,0.26,0
0.54,0.47,0.48,0.5,0.28,0.33,0.42,0
0.51,0.37,0.48,0.5,0.35,0.36,0.45,0
0.4,0.35,0.48,0.5,0.45,0.33,0.42,0
0.44,0.34,0.48,0.5,0.3,0.33,0.43,0
0.44,0.49,0.48,0.5,0.39,0.38,0.4,0
0.43,0.32,0.48,0.5,0.33,0.45,0.52,0
0.49,0.43,0.48,0.5,0.49,0.3,0.4,0
0.47,0.28,0.48,0.5,0.56,0.2,0.25,0
0.32,0.33,0.48,0.5,0.6,0.06,0.2,0
0.34,0.35,0.48,0.5,0.51,0.49,0.56,0
0.35,0.34,0.48,0.5,0.46,0.3,0.27,0
0.38,0.3,0.48,0.5,0.43,0.29,0.39,0
0.38,0.44,0.48,0.5,0.43,0.2,0.31,0
0.41,0.51,0.48,0.5,0.58,0.2,0.31,0
0.34,0.42,0.48,0.5,0.41,0.34,0.43,0
0.51,0.49,0.48,0.5,0.53,0.14,0.26,0
0.25,0.51,0.48,0.5,0.37,0.42,0.5,0
0.29,0.28,0.48,0.5,0.5,0.42,0.5,0
0.25,0.26,0.48,0.5,0.39,0.32,0.42,0
0.24,0.41,0.48,0.5,0.49,0.23,0.34,0
0.17,0.39,0.48,0.5,0.53,0.3,0.39,0
0.04,0.31,0.48,0.5,0.41,0.29,0.39,0
0.61,0.36,0.48,0.5,0.49,0.35,0.44,0
0.34,0.51,0.48,0.5,0.44,0.37,0.46,0
0.28,0.33,0.48,0.5,0.45,0.22,0.33,0
0.4,0.46,0.48,0.5,0.42,0.35,0.44,0
0.23,0.34,0.48,0.5,0.43,0.26,0.37,0
0.37,0.44,0.48,0.5,0.42,0.39,0.47,0
0,0.38,0.48,0.5,0.42,0.48,0.55,0
0.39,0.31,0.48,0.5,0.38,0.34,0.43,0
0.3,0.44,0.48,0.5,0.49,0.22,0.33,0
0.27,0.3,0.48,0.5,0.71,0.28,0.39,0
0.17,0.52,0.48,0.5,0.49,0.37,0.46,0
0.36,0.42,0.48,0.5,0.53,0.32,0.41,0
0.3,0.37,0.48,0.5,0.43,0.18,0.3,0
0.26,0.4,0.48,0.5,0.36,0.26,0.37,0
0.4,0.41,0.48,0.5,0.55,0.22,0.33,0
0.22,0.34,0.48,0.5,0.42,0.29,0.39,0
0.44,0.35,0.48,0.5,0.44,0.52,0.59,0
0.27,0.42,0.48,0.5,0.37,0.38,0.43,0
0.16,0.43,0.48,0.5,0.54,0.27,0.37,0
0.06,0.61,0.48,0.5,0.49,0.92,0.37,1
0.44,0.52,0.48,0.5,0.43,0.47,0.54,1
0.63,0.47,0.48,0.5,0.51,0.82,0.84,1
0.23,0.48,0.48,0.5,0.59,0.88,0.89,1
0.34,0.49,0.48,0.5,0.58,0.85,0.8,1
0.43,0.4,0.48,0.5,0.58,0.75,0.78,1
0.46,0.61,0.48,0.5,0.48,0.86,0.87,1
0.27,0.35,0.48,0.5,0.51,0.77,0.79,1
python python-3.x numpy machine-learning numpy-ndarray
|
show 2 more comments
I am trying to accomplish a weird task.
I need to complete the following without the use of sklearn, and preferably with numpy:
- Given a dataset, split the data into 5 equal "folds", or partitions
- Within each partition, split the data into a "training" and "testing" set, with an 80/20 split
- Here is the catch: Your dataset is labeled for classes. So take for example a dataset with 100 instances, and class A with 33 samples and class B with 67 samples. I should create 5 folds of 20 data instances, where in each fold, class A has something like 6 or 7 (1/3) values and class B has the rest
My issue that:
I do not know how to properly return a test and training set for each fold, despite being able to split it appropriately, and, more important, I do not know how to incorporate the proper division of # of elements per class.
My current code is here. It is commented where I am stuck:
import numpy
def csv_to_array(file):
# Open the file, and load it in delimiting on the ',' for a comma separated value file
data = open(file, 'r')
data = numpy.loadtxt(data, delimiter=',')
# Loop through the data in the array
for index in range(len(data)):
# Utilize a try catch to try and convert to float, if it can't convert to float, converts to 0
try:
data[index] = [float(x) for x in data[index]]
except Exception:
data[index] = 0
except ValueError:
data[index] = 0
# Return the now type-formatted data
return data
def five_cross_fold_validation(dataset):
# print("DATASET", dataset)
numpy.random.shuffle(dataset)
num_rows = dataset.shape[0]
split_mark = int(num_rows / 5)
folds = []
temp1 = dataset[:split_mark]
# print("TEMP1", temp1)
temp2 = dataset[split_mark:split_mark*2]
# print("TEMP2", temp2)
temp3 = dataset[split_mark*2:split_mark*3]
# print("TEMP3", temp3)
temp4 = dataset[split_mark*3:split_mark*4]
# print("TEMP4", temp4)
temp5 = dataset[split_mark*4:]
# print("TEMP5", temp5)
folds.append(temp1)
folds.append(temp2)
folds.append(temp3)
folds.append(temp4)
folds.append(temp5)
# folds = numpy.asarray(folds)
for fold in folds:
# fold = numpy.asarray(fold)
num_rows = fold.shape[0]
split_mark = int(num_rows * .8)
fold_training = fold[split_mark:]
fold_testing = fold[:split_mark]
print(type(fold))
# fold.tolist()
list(fold)
print(type(fold))
del fold[0:len(fold)]
fold.append(fold_training)
fold.append(fold_testing)
fold = numpy.asarray(fold)
# Somehow, return a testing and training set within each fold
# print(folds)
return folds
def confirm_size(folds):
total = 0
for fold in folds:
curr = len(fold)
total = total + curr
return total
def main():
print("BEGINNING CFV")
ecoli = csv_to_array('Classification/ecoli.csv')
print(len(ecoli))
folds = five_cross_fold_validation(ecoli)
size = confirm_size(folds)
print(size)
main()
Additionally, for reference, I have attached my csv I am working with (it is a modification of the UCI Ecoli Dataset.) The classes here are the values in the last column. So 0, 1, 2, 3, 4. It is important to note that there are not equal amounts of each class.
0.61,0.45,0.48,0.5,0.48,0.35,0.41,0
0.17,0.38,0.48,0.5,0.45,0.42,0.5,0
0.44,0.35,0.48,0.5,0.55,0.55,0.61,0
0.43,0.4,0.48,0.5,0.39,0.28,0.39,0
0.42,0.35,0.48,0.5,0.58,0.15,0.27,0
0.23,0.33,0.48,0.5,0.43,0.33,0.43,0
0.37,0.52,0.48,0.5,0.42,0.42,0.36,0
0.29,0.3,0.48,0.5,0.45,0.03,0.17,0
0.22,0.36,0.48,0.5,0.35,0.39,0.47,0
0.23,0.58,0.48,0.5,0.37,0.53,0.59,0
0.47,0.47,0.48,0.5,0.22,0.16,0.26,0
0.54,0.47,0.48,0.5,0.28,0.33,0.42,0
0.51,0.37,0.48,0.5,0.35,0.36,0.45,0
0.4,0.35,0.48,0.5,0.45,0.33,0.42,0
0.44,0.34,0.48,0.5,0.3,0.33,0.43,0
0.44,0.49,0.48,0.5,0.39,0.38,0.4,0
0.43,0.32,0.48,0.5,0.33,0.45,0.52,0
0.49,0.43,0.48,0.5,0.49,0.3,0.4,0
0.47,0.28,0.48,0.5,0.56,0.2,0.25,0
0.32,0.33,0.48,0.5,0.6,0.06,0.2,0
0.34,0.35,0.48,0.5,0.51,0.49,0.56,0
0.35,0.34,0.48,0.5,0.46,0.3,0.27,0
0.38,0.3,0.48,0.5,0.43,0.29,0.39,0
0.38,0.44,0.48,0.5,0.43,0.2,0.31,0
0.41,0.51,0.48,0.5,0.58,0.2,0.31,0
0.34,0.42,0.48,0.5,0.41,0.34,0.43,0
0.51,0.49,0.48,0.5,0.53,0.14,0.26,0
0.25,0.51,0.48,0.5,0.37,0.42,0.5,0
0.29,0.28,0.48,0.5,0.5,0.42,0.5,0
0.25,0.26,0.48,0.5,0.39,0.32,0.42,0
0.24,0.41,0.48,0.5,0.49,0.23,0.34,0
0.17,0.39,0.48,0.5,0.53,0.3,0.39,0
0.04,0.31,0.48,0.5,0.41,0.29,0.39,0
0.61,0.36,0.48,0.5,0.49,0.35,0.44,0
0.34,0.51,0.48,0.5,0.44,0.37,0.46,0
0.28,0.33,0.48,0.5,0.45,0.22,0.33,0
0.4,0.46,0.48,0.5,0.42,0.35,0.44,0
0.23,0.34,0.48,0.5,0.43,0.26,0.37,0
0.37,0.44,0.48,0.5,0.42,0.39,0.47,0
0,0.38,0.48,0.5,0.42,0.48,0.55,0
0.39,0.31,0.48,0.5,0.38,0.34,0.43,0
0.3,0.44,0.48,0.5,0.49,0.22,0.33,0
0.27,0.3,0.48,0.5,0.71,0.28,0.39,0
0.17,0.52,0.48,0.5,0.49,0.37,0.46,0
0.36,0.42,0.48,0.5,0.53,0.32,0.41,0
0.3,0.37,0.48,0.5,0.43,0.18,0.3,0
0.26,0.4,0.48,0.5,0.36,0.26,0.37,0
0.4,0.41,0.48,0.5,0.55,0.22,0.33,0
0.22,0.34,0.48,0.5,0.42,0.29,0.39,0
0.44,0.35,0.48,0.5,0.44,0.52,0.59,0
0.27,0.42,0.48,0.5,0.37,0.38,0.43,0
0.16,0.43,0.48,0.5,0.54,0.27,0.37,0
0.06,0.61,0.48,0.5,0.49,0.92,0.37,1
0.44,0.52,0.48,0.5,0.43,0.47,0.54,1
0.63,0.47,0.48,0.5,0.51,0.82,0.84,1
0.23,0.48,0.48,0.5,0.59,0.88,0.89,1
0.34,0.49,0.48,0.5,0.58,0.85,0.8,1
0.43,0.4,0.48,0.5,0.58,0.75,0.78,1
0.46,0.61,0.48,0.5,0.48,0.86,0.87,1
0.27,0.35,0.48,0.5,0.51,0.77,0.79,1
python python-3.x numpy machine-learning numpy-ndarray
Do you need the ratio to be exact (± 1) or do you need an expected ratio of |A|/|B|?
– cglacet
Mar 9 at 1:03
1
Also how do you distinguish A from B in the CSV?
– cglacet
Mar 9 at 1:13
Sorry for delay. Didnt hear the notification. The last column of the csv I pasted in contains the "classes", i.e., 0 1 2 3 4. I will make that edit.
– Jerry M.
Mar 9 at 1:22
And I'm sorry that I dont follow the first part.
– Jerry M.
Mar 9 at 1:23
The first part is actually important, because if you just need to have samples that are statistically representative of your input distribution of classes, then you can just pick 20% of the rows at random. The expected proportion of classes in the samples will be the same as in the input. On the other hand, if you need to have exactly the same proportions in the output, then you'll have to pick a random sample of size 0.2*(class size/total sample size) from each class.
– cglacet
Mar 9 at 1:33
|
show 2 more comments
I am trying to accomplish a weird task.
I need to complete the following without the use of sklearn, and preferably with numpy:
- Given a dataset, split the data into 5 equal "folds", or partitions
- Within each partition, split the data into a "training" and "testing" set, with an 80/20 split
- Here is the catch: Your dataset is labeled for classes. So take for example a dataset with 100 instances, and class A with 33 samples and class B with 67 samples. I should create 5 folds of 20 data instances, where in each fold, class A has something like 6 or 7 (1/3) values and class B has the rest
My issue that:
I do not know how to properly return a test and training set for each fold, despite being able to split it appropriately, and, more important, I do not know how to incorporate the proper division of # of elements per class.
My current code is here. It is commented where I am stuck:
import numpy
def csv_to_array(file):
# Open the file, and load it in delimiting on the ',' for a comma separated value file
data = open(file, 'r')
data = numpy.loadtxt(data, delimiter=',')
# Loop through the data in the array
for index in range(len(data)):
# Utilize a try catch to try and convert to float, if it can't convert to float, converts to 0
try:
data[index] = [float(x) for x in data[index]]
except Exception:
data[index] = 0
except ValueError:
data[index] = 0
# Return the now type-formatted data
return data
def five_cross_fold_validation(dataset):
# print("DATASET", dataset)
numpy.random.shuffle(dataset)
num_rows = dataset.shape[0]
split_mark = int(num_rows / 5)
folds = []
temp1 = dataset[:split_mark]
# print("TEMP1", temp1)
temp2 = dataset[split_mark:split_mark*2]
# print("TEMP2", temp2)
temp3 = dataset[split_mark*2:split_mark*3]
# print("TEMP3", temp3)
temp4 = dataset[split_mark*3:split_mark*4]
# print("TEMP4", temp4)
temp5 = dataset[split_mark*4:]
# print("TEMP5", temp5)
folds.append(temp1)
folds.append(temp2)
folds.append(temp3)
folds.append(temp4)
folds.append(temp5)
# folds = numpy.asarray(folds)
for fold in folds:
# fold = numpy.asarray(fold)
num_rows = fold.shape[0]
split_mark = int(num_rows * .8)
fold_training = fold[split_mark:]
fold_testing = fold[:split_mark]
print(type(fold))
# fold.tolist()
list(fold)
print(type(fold))
del fold[0:len(fold)]
fold.append(fold_training)
fold.append(fold_testing)
fold = numpy.asarray(fold)
# Somehow, return a testing and training set within each fold
# print(folds)
return folds
def confirm_size(folds):
total = 0
for fold in folds:
curr = len(fold)
total = total + curr
return total
def main():
print("BEGINNING CFV")
ecoli = csv_to_array('Classification/ecoli.csv')
print(len(ecoli))
folds = five_cross_fold_validation(ecoli)
size = confirm_size(folds)
print(size)
main()
Additionally, for reference, I have attached my csv I am working with (it is a modification of the UCI Ecoli Dataset.) The classes here are the values in the last column. So 0, 1, 2, 3, 4. It is important to note that there are not equal amounts of each class.
0.61,0.45,0.48,0.5,0.48,0.35,0.41,0
0.17,0.38,0.48,0.5,0.45,0.42,0.5,0
0.44,0.35,0.48,0.5,0.55,0.55,0.61,0
0.43,0.4,0.48,0.5,0.39,0.28,0.39,0
0.42,0.35,0.48,0.5,0.58,0.15,0.27,0
0.23,0.33,0.48,0.5,0.43,0.33,0.43,0
0.37,0.52,0.48,0.5,0.42,0.42,0.36,0
0.29,0.3,0.48,0.5,0.45,0.03,0.17,0
0.22,0.36,0.48,0.5,0.35,0.39,0.47,0
0.23,0.58,0.48,0.5,0.37,0.53,0.59,0
0.47,0.47,0.48,0.5,0.22,0.16,0.26,0
0.54,0.47,0.48,0.5,0.28,0.33,0.42,0
0.51,0.37,0.48,0.5,0.35,0.36,0.45,0
0.4,0.35,0.48,0.5,0.45,0.33,0.42,0
0.44,0.34,0.48,0.5,0.3,0.33,0.43,0
0.44,0.49,0.48,0.5,0.39,0.38,0.4,0
0.43,0.32,0.48,0.5,0.33,0.45,0.52,0
0.49,0.43,0.48,0.5,0.49,0.3,0.4,0
0.47,0.28,0.48,0.5,0.56,0.2,0.25,0
0.32,0.33,0.48,0.5,0.6,0.06,0.2,0
0.34,0.35,0.48,0.5,0.51,0.49,0.56,0
0.35,0.34,0.48,0.5,0.46,0.3,0.27,0
0.38,0.3,0.48,0.5,0.43,0.29,0.39,0
0.38,0.44,0.48,0.5,0.43,0.2,0.31,0
0.41,0.51,0.48,0.5,0.58,0.2,0.31,0
0.34,0.42,0.48,0.5,0.41,0.34,0.43,0
0.51,0.49,0.48,0.5,0.53,0.14,0.26,0
0.25,0.51,0.48,0.5,0.37,0.42,0.5,0
0.29,0.28,0.48,0.5,0.5,0.42,0.5,0
0.25,0.26,0.48,0.5,0.39,0.32,0.42,0
0.24,0.41,0.48,0.5,0.49,0.23,0.34,0
0.17,0.39,0.48,0.5,0.53,0.3,0.39,0
0.04,0.31,0.48,0.5,0.41,0.29,0.39,0
0.61,0.36,0.48,0.5,0.49,0.35,0.44,0
0.34,0.51,0.48,0.5,0.44,0.37,0.46,0
0.28,0.33,0.48,0.5,0.45,0.22,0.33,0
0.4,0.46,0.48,0.5,0.42,0.35,0.44,0
0.23,0.34,0.48,0.5,0.43,0.26,0.37,0
0.37,0.44,0.48,0.5,0.42,0.39,0.47,0
0,0.38,0.48,0.5,0.42,0.48,0.55,0
0.39,0.31,0.48,0.5,0.38,0.34,0.43,0
0.3,0.44,0.48,0.5,0.49,0.22,0.33,0
0.27,0.3,0.48,0.5,0.71,0.28,0.39,0
0.17,0.52,0.48,0.5,0.49,0.37,0.46,0
0.36,0.42,0.48,0.5,0.53,0.32,0.41,0
0.3,0.37,0.48,0.5,0.43,0.18,0.3,0
0.26,0.4,0.48,0.5,0.36,0.26,0.37,0
0.4,0.41,0.48,0.5,0.55,0.22,0.33,0
0.22,0.34,0.48,0.5,0.42,0.29,0.39,0
0.44,0.35,0.48,0.5,0.44,0.52,0.59,0
0.27,0.42,0.48,0.5,0.37,0.38,0.43,0
0.16,0.43,0.48,0.5,0.54,0.27,0.37,0
0.06,0.61,0.48,0.5,0.49,0.92,0.37,1
0.44,0.52,0.48,0.5,0.43,0.47,0.54,1
0.63,0.47,0.48,0.5,0.51,0.82,0.84,1
0.23,0.48,0.48,0.5,0.59,0.88,0.89,1
0.34,0.49,0.48,0.5,0.58,0.85,0.8,1
0.43,0.4,0.48,0.5,0.58,0.75,0.78,1
0.46,0.61,0.48,0.5,0.48,0.86,0.87,1
0.27,0.35,0.48,0.5,0.51,0.77,0.79,1
python python-3.x numpy machine-learning numpy-ndarray
I am trying to accomplish a weird task.
I need to complete the following without the use of sklearn, and preferably with numpy:
- Given a dataset, split the data into 5 equal "folds", or partitions
- Within each partition, split the data into a "training" and "testing" set, with an 80/20 split
- Here is the catch: Your dataset is labeled for classes. So take for example a dataset with 100 instances, and class A with 33 samples and class B with 67 samples. I should create 5 folds of 20 data instances, where in each fold, class A has something like 6 or 7 (1/3) values and class B has the rest
My issue that:
I do not know how to properly return a test and training set for each fold, despite being able to split it appropriately, and, more important, I do not know how to incorporate the proper division of # of elements per class.
My current code is here. It is commented where I am stuck:
import numpy
def csv_to_array(file):
# Open the file, and load it in delimiting on the ',' for a comma separated value file
data = open(file, 'r')
data = numpy.loadtxt(data, delimiter=',')
# Loop through the data in the array
for index in range(len(data)):
# Utilize a try catch to try and convert to float, if it can't convert to float, converts to 0
try:
data[index] = [float(x) for x in data[index]]
except Exception:
data[index] = 0
except ValueError:
data[index] = 0
# Return the now type-formatted data
return data
def five_cross_fold_validation(dataset):
# print("DATASET", dataset)
numpy.random.shuffle(dataset)
num_rows = dataset.shape[0]
split_mark = int(num_rows / 5)
folds = []
temp1 = dataset[:split_mark]
# print("TEMP1", temp1)
temp2 = dataset[split_mark:split_mark*2]
# print("TEMP2", temp2)
temp3 = dataset[split_mark*2:split_mark*3]
# print("TEMP3", temp3)
temp4 = dataset[split_mark*3:split_mark*4]
# print("TEMP4", temp4)
temp5 = dataset[split_mark*4:]
# print("TEMP5", temp5)
folds.append(temp1)
folds.append(temp2)
folds.append(temp3)
folds.append(temp4)
folds.append(temp5)
# folds = numpy.asarray(folds)
for fold in folds:
# fold = numpy.asarray(fold)
num_rows = fold.shape[0]
split_mark = int(num_rows * .8)
fold_training = fold[split_mark:]
fold_testing = fold[:split_mark]
print(type(fold))
# fold.tolist()
list(fold)
print(type(fold))
del fold[0:len(fold)]
fold.append(fold_training)
fold.append(fold_testing)
fold = numpy.asarray(fold)
# Somehow, return a testing and training set within each fold
# print(folds)
return folds
def confirm_size(folds):
total = 0
for fold in folds:
curr = len(fold)
total = total + curr
return total
def main():
print("BEGINNING CFV")
ecoli = csv_to_array('Classification/ecoli.csv')
print(len(ecoli))
folds = five_cross_fold_validation(ecoli)
size = confirm_size(folds)
print(size)
main()
Additionally, for reference, I have attached my csv I am working with (it is a modification of the UCI Ecoli Dataset.) The classes here are the values in the last column. So 0, 1, 2, 3, 4. It is important to note that there are not equal amounts of each class.
0.61,0.45,0.48,0.5,0.48,0.35,0.41,0
0.17,0.38,0.48,0.5,0.45,0.42,0.5,0
0.44,0.35,0.48,0.5,0.55,0.55,0.61,0
0.43,0.4,0.48,0.5,0.39,0.28,0.39,0
0.42,0.35,0.48,0.5,0.58,0.15,0.27,0
0.23,0.33,0.48,0.5,0.43,0.33,0.43,0
0.37,0.52,0.48,0.5,0.42,0.42,0.36,0
0.29,0.3,0.48,0.5,0.45,0.03,0.17,0
0.22,0.36,0.48,0.5,0.35,0.39,0.47,0
0.23,0.58,0.48,0.5,0.37,0.53,0.59,0
0.47,0.47,0.48,0.5,0.22,0.16,0.26,0
0.54,0.47,0.48,0.5,0.28,0.33,0.42,0
0.51,0.37,0.48,0.5,0.35,0.36,0.45,0
0.4,0.35,0.48,0.5,0.45,0.33,0.42,0
0.44,0.34,0.48,0.5,0.3,0.33,0.43,0
0.44,0.49,0.48,0.5,0.39,0.38,0.4,0
0.43,0.32,0.48,0.5,0.33,0.45,0.52,0
0.49,0.43,0.48,0.5,0.49,0.3,0.4,0
0.47,0.28,0.48,0.5,0.56,0.2,0.25,0
0.32,0.33,0.48,0.5,0.6,0.06,0.2,0
0.34,0.35,0.48,0.5,0.51,0.49,0.56,0
0.35,0.34,0.48,0.5,0.46,0.3,0.27,0
0.38,0.3,0.48,0.5,0.43,0.29,0.39,0
0.38,0.44,0.48,0.5,0.43,0.2,0.31,0
0.41,0.51,0.48,0.5,0.58,0.2,0.31,0
0.34,0.42,0.48,0.5,0.41,0.34,0.43,0
0.51,0.49,0.48,0.5,0.53,0.14,0.26,0
0.25,0.51,0.48,0.5,0.37,0.42,0.5,0
0.29,0.28,0.48,0.5,0.5,0.42,0.5,0
0.25,0.26,0.48,0.5,0.39,0.32,0.42,0
0.24,0.41,0.48,0.5,0.49,0.23,0.34,0
0.17,0.39,0.48,0.5,0.53,0.3,0.39,0
0.04,0.31,0.48,0.5,0.41,0.29,0.39,0
0.61,0.36,0.48,0.5,0.49,0.35,0.44,0
0.34,0.51,0.48,0.5,0.44,0.37,0.46,0
0.28,0.33,0.48,0.5,0.45,0.22,0.33,0
0.4,0.46,0.48,0.5,0.42,0.35,0.44,0
0.23,0.34,0.48,0.5,0.43,0.26,0.37,0
0.37,0.44,0.48,0.5,0.42,0.39,0.47,0
0,0.38,0.48,0.5,0.42,0.48,0.55,0
0.39,0.31,0.48,0.5,0.38,0.34,0.43,0
0.3,0.44,0.48,0.5,0.49,0.22,0.33,0
0.27,0.3,0.48,0.5,0.71,0.28,0.39,0
0.17,0.52,0.48,0.5,0.49,0.37,0.46,0
0.36,0.42,0.48,0.5,0.53,0.32,0.41,0
0.3,0.37,0.48,0.5,0.43,0.18,0.3,0
0.26,0.4,0.48,0.5,0.36,0.26,0.37,0
0.4,0.41,0.48,0.5,0.55,0.22,0.33,0
0.22,0.34,0.48,0.5,0.42,0.29,0.39,0
0.44,0.35,0.48,0.5,0.44,0.52,0.59,0
0.27,0.42,0.48,0.5,0.37,0.38,0.43,0
0.16,0.43,0.48,0.5,0.54,0.27,0.37,0
0.06,0.61,0.48,0.5,0.49,0.92,0.37,1
0.44,0.52,0.48,0.5,0.43,0.47,0.54,1
0.63,0.47,0.48,0.5,0.51,0.82,0.84,1
0.23,0.48,0.48,0.5,0.59,0.88,0.89,1
0.34,0.49,0.48,0.5,0.58,0.85,0.8,1
0.43,0.4,0.48,0.5,0.58,0.75,0.78,1
0.46,0.61,0.48,0.5,0.48,0.86,0.87,1
0.27,0.35,0.48,0.5,0.51,0.77,0.79,1
python python-3.x numpy machine-learning numpy-ndarray
python python-3.x numpy machine-learning numpy-ndarray
edited Mar 9 at 2:01
Jerry M.
asked Mar 9 at 0:10
Jerry M.Jerry M.
7881728
7881728
Do you need the ratio to be exact (± 1) or do you need an expected ratio of |A|/|B|?
– cglacet
Mar 9 at 1:03
1
Also how do you distinguish A from B in the CSV?
– cglacet
Mar 9 at 1:13
Sorry for delay. Didnt hear the notification. The last column of the csv I pasted in contains the "classes", i.e., 0 1 2 3 4. I will make that edit.
– Jerry M.
Mar 9 at 1:22
And I'm sorry that I dont follow the first part.
– Jerry M.
Mar 9 at 1:23
The first part is actually important, because if you just need to have samples that are statistically representative of your input distribution of classes, then you can just pick 20% of the rows at random. The expected proportion of classes in the samples will be the same as in the input. On the other hand, if you need to have exactly the same proportions in the output, then you'll have to pick a random sample of size 0.2*(class size/total sample size) from each class.
– cglacet
Mar 9 at 1:33
|
show 2 more comments
Do you need the ratio to be exact (± 1) or do you need an expected ratio of |A|/|B|?
– cglacet
Mar 9 at 1:03
1
Also how do you distinguish A from B in the CSV?
– cglacet
Mar 9 at 1:13
Sorry for delay. Didnt hear the notification. The last column of the csv I pasted in contains the "classes", i.e., 0 1 2 3 4. I will make that edit.
– Jerry M.
Mar 9 at 1:22
And I'm sorry that I dont follow the first part.
– Jerry M.
Mar 9 at 1:23
The first part is actually important, because if you just need to have samples that are statistically representative of your input distribution of classes, then you can just pick 20% of the rows at random. The expected proportion of classes in the samples will be the same as in the input. On the other hand, if you need to have exactly the same proportions in the output, then you'll have to pick a random sample of size 0.2*(class size/total sample size) from each class.
– cglacet
Mar 9 at 1:33
Do you need the ratio to be exact (± 1) or do you need an expected ratio of |A|/|B|?
– cglacet
Mar 9 at 1:03
Do you need the ratio to be exact (± 1) or do you need an expected ratio of |A|/|B|?
– cglacet
Mar 9 at 1:03
1
1
Also how do you distinguish A from B in the CSV?
– cglacet
Mar 9 at 1:13
Also how do you distinguish A from B in the CSV?
– cglacet
Mar 9 at 1:13
Sorry for delay. Didnt hear the notification. The last column of the csv I pasted in contains the "classes", i.e., 0 1 2 3 4. I will make that edit.
– Jerry M.
Mar 9 at 1:22
Sorry for delay. Didnt hear the notification. The last column of the csv I pasted in contains the "classes", i.e., 0 1 2 3 4. I will make that edit.
– Jerry M.
Mar 9 at 1:22
And I'm sorry that I dont follow the first part.
– Jerry M.
Mar 9 at 1:23
And I'm sorry that I dont follow the first part.
– Jerry M.
Mar 9 at 1:23
The first part is actually important, because if you just need to have samples that are statistically representative of your input distribution of classes, then you can just pick 20% of the rows at random. The expected proportion of classes in the samples will be the same as in the input. On the other hand, if you need to have exactly the same proportions in the output, then you'll have to pick a random sample of size 0.2*(class size/total sample size) from each class.
– cglacet
Mar 9 at 1:33
The first part is actually important, because if you just need to have samples that are statistically representative of your input distribution of classes, then you can just pick 20% of the rows at random. The expected proportion of classes in the samples will be the same as in the input. On the other hand, if you need to have exactly the same proportions in the output, then you'll have to pick a random sample of size 0.2*(class size/total sample size) from each class.
– cglacet
Mar 9 at 1:33
|
show 2 more comments
1 Answer
1
active
oldest
votes
Edit I replaced np.random.shuffle(A)
by A = np.random.permutation(A)
, the only difference is that it doesn't mutate the input array. This doesn't make any difference in this code, but it is safer in general.
The idea is to randomly sample the input by using numpy.random.permutation
. Once the rows are shuffled we just need to iterate over all the possible tests sets (sliding window of the desired size, here 20% of the input size). The corresponding training sets are just composed of all remaining elements.
This will preserve the original classes distribution on all subsets even though we pick them in order because we shuffled the input.
The following code iterate over the test/train sets combinations:
import numpy as np
def csv_to_array(file):
with open(file, 'r') as f:
data = np.loadtxt(f, delimiter=',')
return data
def classes_distribution(A):
"""Print the class distributions of array A."""
nb_classes = np.unique(A[:,-1]).shape[0]
total_size = A.shape[0]
for i in range(nb_classes):
class_size = sum(row[-1] == i for row in A)
class_p = class_size/total_size
print(f"t P(class_i) = class_p:.3f")
def random_samples(A, test_set_p=0.2):
"""Split the input array A in two uniformly chosen
random sets: test/training.
Repeat this until all rows have been yielded once at least
once as a test set."""
A = np.random.permutation(A)
sample_size = int(test_set_p*A.shape[0])
for start in range(0, A.shape[0], sample_size):
end = start + sample_size
yield
"test": A[start:end,],
"train": np.append(A[:start,], A[end:,], 0)
def main():
ecoli = csv_to_array('ecoli.csv')
print("Input set shape: ", ecoli.shape)
print("Input set class distribution:")
classes_distribution(ecoli)
print("Training sets class distributions:")
for iteration in random_samples(ecoli):
test_set = iteration["test"]
training_set = iteration["train"]
classes_distribution(training_set)
print("---")
# ... Do what ever with these two sets
main()
It produces an output of the form:
Input set shape: (169, 8)
Input set class distribution:
P(class_0) = 0.308
P(class_1) = 0.213
P(class_2) = 0.207
P(class_3) = 0.118
P(class_4) = 0.154
Training sets class distributions:
P(class_0) = 0.316
P(class_1) = 0.206
P(class_2) = 0.199
P(class_3) = 0.118
P(class_4) = 0.162
...
add a comment |
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1 Answer
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active
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active
oldest
votes
Edit I replaced np.random.shuffle(A)
by A = np.random.permutation(A)
, the only difference is that it doesn't mutate the input array. This doesn't make any difference in this code, but it is safer in general.
The idea is to randomly sample the input by using numpy.random.permutation
. Once the rows are shuffled we just need to iterate over all the possible tests sets (sliding window of the desired size, here 20% of the input size). The corresponding training sets are just composed of all remaining elements.
This will preserve the original classes distribution on all subsets even though we pick them in order because we shuffled the input.
The following code iterate over the test/train sets combinations:
import numpy as np
def csv_to_array(file):
with open(file, 'r') as f:
data = np.loadtxt(f, delimiter=',')
return data
def classes_distribution(A):
"""Print the class distributions of array A."""
nb_classes = np.unique(A[:,-1]).shape[0]
total_size = A.shape[0]
for i in range(nb_classes):
class_size = sum(row[-1] == i for row in A)
class_p = class_size/total_size
print(f"t P(class_i) = class_p:.3f")
def random_samples(A, test_set_p=0.2):
"""Split the input array A in two uniformly chosen
random sets: test/training.
Repeat this until all rows have been yielded once at least
once as a test set."""
A = np.random.permutation(A)
sample_size = int(test_set_p*A.shape[0])
for start in range(0, A.shape[0], sample_size):
end = start + sample_size
yield
"test": A[start:end,],
"train": np.append(A[:start,], A[end:,], 0)
def main():
ecoli = csv_to_array('ecoli.csv')
print("Input set shape: ", ecoli.shape)
print("Input set class distribution:")
classes_distribution(ecoli)
print("Training sets class distributions:")
for iteration in random_samples(ecoli):
test_set = iteration["test"]
training_set = iteration["train"]
classes_distribution(training_set)
print("---")
# ... Do what ever with these two sets
main()
It produces an output of the form:
Input set shape: (169, 8)
Input set class distribution:
P(class_0) = 0.308
P(class_1) = 0.213
P(class_2) = 0.207
P(class_3) = 0.118
P(class_4) = 0.154
Training sets class distributions:
P(class_0) = 0.316
P(class_1) = 0.206
P(class_2) = 0.199
P(class_3) = 0.118
P(class_4) = 0.162
...
add a comment |
Edit I replaced np.random.shuffle(A)
by A = np.random.permutation(A)
, the only difference is that it doesn't mutate the input array. This doesn't make any difference in this code, but it is safer in general.
The idea is to randomly sample the input by using numpy.random.permutation
. Once the rows are shuffled we just need to iterate over all the possible tests sets (sliding window of the desired size, here 20% of the input size). The corresponding training sets are just composed of all remaining elements.
This will preserve the original classes distribution on all subsets even though we pick them in order because we shuffled the input.
The following code iterate over the test/train sets combinations:
import numpy as np
def csv_to_array(file):
with open(file, 'r') as f:
data = np.loadtxt(f, delimiter=',')
return data
def classes_distribution(A):
"""Print the class distributions of array A."""
nb_classes = np.unique(A[:,-1]).shape[0]
total_size = A.shape[0]
for i in range(nb_classes):
class_size = sum(row[-1] == i for row in A)
class_p = class_size/total_size
print(f"t P(class_i) = class_p:.3f")
def random_samples(A, test_set_p=0.2):
"""Split the input array A in two uniformly chosen
random sets: test/training.
Repeat this until all rows have been yielded once at least
once as a test set."""
A = np.random.permutation(A)
sample_size = int(test_set_p*A.shape[0])
for start in range(0, A.shape[0], sample_size):
end = start + sample_size
yield
"test": A[start:end,],
"train": np.append(A[:start,], A[end:,], 0)
def main():
ecoli = csv_to_array('ecoli.csv')
print("Input set shape: ", ecoli.shape)
print("Input set class distribution:")
classes_distribution(ecoli)
print("Training sets class distributions:")
for iteration in random_samples(ecoli):
test_set = iteration["test"]
training_set = iteration["train"]
classes_distribution(training_set)
print("---")
# ... Do what ever with these two sets
main()
It produces an output of the form:
Input set shape: (169, 8)
Input set class distribution:
P(class_0) = 0.308
P(class_1) = 0.213
P(class_2) = 0.207
P(class_3) = 0.118
P(class_4) = 0.154
Training sets class distributions:
P(class_0) = 0.316
P(class_1) = 0.206
P(class_2) = 0.199
P(class_3) = 0.118
P(class_4) = 0.162
...
add a comment |
Edit I replaced np.random.shuffle(A)
by A = np.random.permutation(A)
, the only difference is that it doesn't mutate the input array. This doesn't make any difference in this code, but it is safer in general.
The idea is to randomly sample the input by using numpy.random.permutation
. Once the rows are shuffled we just need to iterate over all the possible tests sets (sliding window of the desired size, here 20% of the input size). The corresponding training sets are just composed of all remaining elements.
This will preserve the original classes distribution on all subsets even though we pick them in order because we shuffled the input.
The following code iterate over the test/train sets combinations:
import numpy as np
def csv_to_array(file):
with open(file, 'r') as f:
data = np.loadtxt(f, delimiter=',')
return data
def classes_distribution(A):
"""Print the class distributions of array A."""
nb_classes = np.unique(A[:,-1]).shape[0]
total_size = A.shape[0]
for i in range(nb_classes):
class_size = sum(row[-1] == i for row in A)
class_p = class_size/total_size
print(f"t P(class_i) = class_p:.3f")
def random_samples(A, test_set_p=0.2):
"""Split the input array A in two uniformly chosen
random sets: test/training.
Repeat this until all rows have been yielded once at least
once as a test set."""
A = np.random.permutation(A)
sample_size = int(test_set_p*A.shape[0])
for start in range(0, A.shape[0], sample_size):
end = start + sample_size
yield
"test": A[start:end,],
"train": np.append(A[:start,], A[end:,], 0)
def main():
ecoli = csv_to_array('ecoli.csv')
print("Input set shape: ", ecoli.shape)
print("Input set class distribution:")
classes_distribution(ecoli)
print("Training sets class distributions:")
for iteration in random_samples(ecoli):
test_set = iteration["test"]
training_set = iteration["train"]
classes_distribution(training_set)
print("---")
# ... Do what ever with these two sets
main()
It produces an output of the form:
Input set shape: (169, 8)
Input set class distribution:
P(class_0) = 0.308
P(class_1) = 0.213
P(class_2) = 0.207
P(class_3) = 0.118
P(class_4) = 0.154
Training sets class distributions:
P(class_0) = 0.316
P(class_1) = 0.206
P(class_2) = 0.199
P(class_3) = 0.118
P(class_4) = 0.162
...
Edit I replaced np.random.shuffle(A)
by A = np.random.permutation(A)
, the only difference is that it doesn't mutate the input array. This doesn't make any difference in this code, but it is safer in general.
The idea is to randomly sample the input by using numpy.random.permutation
. Once the rows are shuffled we just need to iterate over all the possible tests sets (sliding window of the desired size, here 20% of the input size). The corresponding training sets are just composed of all remaining elements.
This will preserve the original classes distribution on all subsets even though we pick them in order because we shuffled the input.
The following code iterate over the test/train sets combinations:
import numpy as np
def csv_to_array(file):
with open(file, 'r') as f:
data = np.loadtxt(f, delimiter=',')
return data
def classes_distribution(A):
"""Print the class distributions of array A."""
nb_classes = np.unique(A[:,-1]).shape[0]
total_size = A.shape[0]
for i in range(nb_classes):
class_size = sum(row[-1] == i for row in A)
class_p = class_size/total_size
print(f"t P(class_i) = class_p:.3f")
def random_samples(A, test_set_p=0.2):
"""Split the input array A in two uniformly chosen
random sets: test/training.
Repeat this until all rows have been yielded once at least
once as a test set."""
A = np.random.permutation(A)
sample_size = int(test_set_p*A.shape[0])
for start in range(0, A.shape[0], sample_size):
end = start + sample_size
yield
"test": A[start:end,],
"train": np.append(A[:start,], A[end:,], 0)
def main():
ecoli = csv_to_array('ecoli.csv')
print("Input set shape: ", ecoli.shape)
print("Input set class distribution:")
classes_distribution(ecoli)
print("Training sets class distributions:")
for iteration in random_samples(ecoli):
test_set = iteration["test"]
training_set = iteration["train"]
classes_distribution(training_set)
print("---")
# ... Do what ever with these two sets
main()
It produces an output of the form:
Input set shape: (169, 8)
Input set class distribution:
P(class_0) = 0.308
P(class_1) = 0.213
P(class_2) = 0.207
P(class_3) = 0.118
P(class_4) = 0.154
Training sets class distributions:
P(class_0) = 0.316
P(class_1) = 0.206
P(class_2) = 0.199
P(class_3) = 0.118
P(class_4) = 0.162
...
edited Mar 9 at 10:55
answered Mar 9 at 3:20
cglacetcglacet
1,414819
1,414819
add a comment |
add a comment |
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Do you need the ratio to be exact (± 1) or do you need an expected ratio of |A|/|B|?
– cglacet
Mar 9 at 1:03
1
Also how do you distinguish A from B in the CSV?
– cglacet
Mar 9 at 1:13
Sorry for delay. Didnt hear the notification. The last column of the csv I pasted in contains the "classes", i.e., 0 1 2 3 4. I will make that edit.
– Jerry M.
Mar 9 at 1:22
And I'm sorry that I dont follow the first part.
– Jerry M.
Mar 9 at 1:23
The first part is actually important, because if you just need to have samples that are statistically representative of your input distribution of classes, then you can just pick 20% of the rows at random. The expected proportion of classes in the samples will be the same as in the input. On the other hand, if you need to have exactly the same proportions in the output, then you'll have to pick a random sample of size 0.2*(class size/total sample size) from each class.
– cglacet
Mar 9 at 1:33