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What does the “::” mean in C++?
2019 Community Moderator ElectionThe Definitive C++ Book Guide and ListWhy are begin(container) and end(container) accessible everywhere but aren't in global namespace?What are the differences between a pointer variable and a reference variable in C++?What does the explicit keyword mean?What are POD types in C++?The Definitive C++ Book Guide and ListWhat is the effect of extern “C” in C++?What is the “-->” operator in C++?What is the copy-and-swap idiom?What is The Rule of Three?C++11 introduced a standardized memory model. What does it mean? And how is it going to affect C++ programming?Why is it faster to process a sorted array than an unsorted array?
What does this symbol mean?
AirlineTicket::AirlineTicket()
c++
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
add a comment |
What does this symbol mean?
AirlineTicket::AirlineTicket()
c++
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
6
The fact that you're asking the question suggests that you have not yet read a basic introductory book on C++ - you should probably make it a priority to do so before you get much further with learning the language.
– Paul R
Mar 17 '11 at 21:38
2
@Paul R: Exactly. Here's the book list: stackoverflow.com/questions/388242/…
– Fred Larson
Mar 17 '11 at 21:42
thanks @Fred Larson
– Milad Sobhkhiz
Mar 17 '11 at 21:47
2
@PaulR Not everyone who arrives upon this question is looking to learn C++. I, for example, just happened to be skimming some C++ code and wanted to get the general idea of what the program is doing and needed a quick reference :)
– Ebony Maw
Dec 16 '18 at 18:34
add a comment |
What does this symbol mean?
AirlineTicket::AirlineTicket()
c++
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
What does this symbol mean?
AirlineTicket::AirlineTicket()
c++
c++
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
edited May 8 '17 at 12:11
Mateusz Piotrowski
3,95063152
3,95063152
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
asked Mar 17 '11 at 21:33
Milad SobhkhizMilad Sobhkhiz
3994723
3994723
6
The fact that you're asking the question suggests that you have not yet read a basic introductory book on C++ - you should probably make it a priority to do so before you get much further with learning the language.
– Paul R
Mar 17 '11 at 21:38
2
@Paul R: Exactly. Here's the book list: stackoverflow.com/questions/388242/…
– Fred Larson
Mar 17 '11 at 21:42
thanks @Fred Larson
– Milad Sobhkhiz
Mar 17 '11 at 21:47
2
@PaulR Not everyone who arrives upon this question is looking to learn C++. I, for example, just happened to be skimming some C++ code and wanted to get the general idea of what the program is doing and needed a quick reference :)
– Ebony Maw
Dec 16 '18 at 18:34
add a comment |
6
The fact that you're asking the question suggests that you have not yet read a basic introductory book on C++ - you should probably make it a priority to do so before you get much further with learning the language.
– Paul R
Mar 17 '11 at 21:38
2
@Paul R: Exactly. Here's the book list: stackoverflow.com/questions/388242/…
– Fred Larson
Mar 17 '11 at 21:42
thanks @Fred Larson
– Milad Sobhkhiz
Mar 17 '11 at 21:47
2
@PaulR Not everyone who arrives upon this question is looking to learn C++. I, for example, just happened to be skimming some C++ code and wanted to get the general idea of what the program is doing and needed a quick reference :)
– Ebony Maw
Dec 16 '18 at 18:34
6
6
The fact that you're asking the question suggests that you have not yet read a basic introductory book on C++ - you should probably make it a priority to do so before you get much further with learning the language.
– Paul R
Mar 17 '11 at 21:38
The fact that you're asking the question suggests that you have not yet read a basic introductory book on C++ - you should probably make it a priority to do so before you get much further with learning the language.
– Paul R
Mar 17 '11 at 21:38
2
2
@Paul R: Exactly. Here's the book list: stackoverflow.com/questions/388242/…
– Fred Larson
Mar 17 '11 at 21:42
@Paul R: Exactly. Here's the book list: stackoverflow.com/questions/388242/…
– Fred Larson
Mar 17 '11 at 21:42
thanks @Fred Larson
– Milad Sobhkhiz
Mar 17 '11 at 21:47
thanks @Fred Larson
– Milad Sobhkhiz
Mar 17 '11 at 21:47
2
2
@PaulR Not everyone who arrives upon this question is looking to learn C++. I, for example, just happened to be skimming some C++ code and wanted to get the general idea of what the program is doing and needed a quick reference :)
– Ebony Maw
Dec 16 '18 at 18:34
@PaulR Not everyone who arrives upon this question is looking to learn C++. I, for example, just happened to be skimming some C++ code and wanted to get the general idea of what the program is doing and needed a quick reference :)
– Ebony Maw
Dec 16 '18 at 18:34
add a comment |
4 Answers
4
active
oldest
votes
:: is the scope resolution operator - used to qualify names. In this case it is used to separate the class AirlineTicket from the constructor AirlineTicket(), forming the qualified name AirlineTicket::AirlineTicket()
You use this whenever you need to be explicit with regards to what you're referring to. Some samples:
namespace foo
class bar;
class bar;
using namespace foo;
Now you have to use the scope resolution operator to refer to a specific bar.
::foo::bar is a fully qualified name.
::bar is another fully qualified name. (:: first means "global namespace")
struct Base
void foo();
;
struct Derived : Base
void foo();
void bar()
Derived::foo();
Base::foo();
;
This uses scope resolution to select specific versions of foo.
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
add a comment |
In C++ the :: is called the Scope Resolution Operator. It makes it clear to which namespace or class a symbol belongs.
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
add a comment |
It declares a namespace. So in AirlineTicket:: you can call all public functions of the AirlineTicket class and AirlineTicket() is the function in that namespace (in this case the constructor).
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
add a comment |
AirlineTicket is like a namespace for your class. You have to use it in the implementation of the constructor.
answered Mar 17 '11 at 21:35
ChrisChris
3542416
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
:: is the scope resolution operator - used to qualify names. In this case it is used to separate the class AirlineTicket from the constructor AirlineTicket(), forming the qualified name AirlineTicket::AirlineTicket()
You use this whenever you need to be explicit with regards to what you're referring to. Some samples:
namespace foo
class bar;
class bar;
using namespace foo;
Now you have to use the scope resolution operator to refer to a specific bar.
::foo::bar is a fully qualified name.
::bar is another fully qualified name. (:: first means "global namespace")
struct Base
void foo();
;
struct Derived : Base
void foo();
void bar()
Derived::foo();
Base::foo();
;
This uses scope resolution to select specific versions of foo.
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
add a comment |
:: is the scope resolution operator - used to qualify names. In this case it is used to separate the class AirlineTicket from the constructor AirlineTicket(), forming the qualified name AirlineTicket::AirlineTicket()
You use this whenever you need to be explicit with regards to what you're referring to. Some samples:
namespace foo
class bar;
class bar;
using namespace foo;
Now you have to use the scope resolution operator to refer to a specific bar.
::foo::bar is a fully qualified name.
::bar is another fully qualified name. (:: first means "global namespace")
struct Base
void foo();
;
struct Derived : Base
void foo();
void bar()
Derived::foo();
Base::foo();
;
This uses scope resolution to select specific versions of foo.
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
add a comment |
:: is the scope resolution operator - used to qualify names. In this case it is used to separate the class AirlineTicket from the constructor AirlineTicket(), forming the qualified name AirlineTicket::AirlineTicket()
You use this whenever you need to be explicit with regards to what you're referring to. Some samples:
namespace foo
class bar;
class bar;
using namespace foo;
Now you have to use the scope resolution operator to refer to a specific bar.
::foo::bar is a fully qualified name.
::bar is another fully qualified name. (:: first means "global namespace")
struct Base
void foo();
;
struct Derived : Base
void foo();
void bar()
Derived::foo();
Base::foo();
;
This uses scope resolution to select specific versions of foo.
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
:: is the scope resolution operator - used to qualify names. In this case it is used to separate the class AirlineTicket from the constructor AirlineTicket(), forming the qualified name AirlineTicket::AirlineTicket()
You use this whenever you need to be explicit with regards to what you're referring to. Some samples:
namespace foo
class bar;
class bar;
using namespace foo;
Now you have to use the scope resolution operator to refer to a specific bar.
::foo::bar is a fully qualified name.
::bar is another fully qualified name. (:: first means "global namespace")
struct Base
void foo();
;
struct Derived : Base
void foo();
void bar()
Derived::foo();
Base::foo();
;
This uses scope resolution to select specific versions of foo.
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
edited Mar 17 '11 at 21:40
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
answered Mar 17 '11 at 21:35
ErikErik
67.8k9173174
67.8k9173174
add a comment |
add a comment |
In C++ the :: is called the Scope Resolution Operator. It makes it clear to which namespace or class a symbol belongs.
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
add a comment |
In C++ the :: is called the Scope Resolution Operator. It makes it clear to which namespace or class a symbol belongs.
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
add a comment |
In C++ the :: is called the Scope Resolution Operator. It makes it clear to which namespace or class a symbol belongs.
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
In C++ the :: is called the Scope Resolution Operator. It makes it clear to which namespace or class a symbol belongs.
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
answered Mar 17 '11 at 21:36
maericsmaerics
106k29203251
106k29203251
add a comment |
add a comment |
It declares a namespace. So in AirlineTicket:: you can call all public functions of the AirlineTicket class and AirlineTicket() is the function in that namespace (in this case the constructor).
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
add a comment |
It declares a namespace. So in AirlineTicket:: you can call all public functions of the AirlineTicket class and AirlineTicket() is the function in that namespace (in this case the constructor).
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
add a comment |
It declares a namespace. So in AirlineTicket:: you can call all public functions of the AirlineTicket class and AirlineTicket() is the function in that namespace (in this case the constructor).
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
It declares a namespace. So in AirlineTicket:: you can call all public functions of the AirlineTicket class and AirlineTicket() is the function in that namespace (in this case the constructor).
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
answered Mar 17 '11 at 21:36
Benedikt WutziBenedikt Wutzi
153518
153518
add a comment |
add a comment |
AirlineTicket is like a namespace for your class. You have to use it in the implementation of the constructor.
answered Mar 17 '11 at 21:35
ChrisChris
3542416
add a comment |
AirlineTicket is like a namespace for your class. You have to use it in the implementation of the constructor.
answered Mar 17 '11 at 21:35
ChrisChris
3542416
add a comment |
AirlineTicket is like a namespace for your class. You have to use it in the implementation of the constructor.
answered Mar 17 '11 at 21:35
ChrisChris
3542416
AirlineTicket is like a namespace for your class. You have to use it in the implementation of the constructor.
answered Mar 17 '11 at 21:35
ChrisChris
3542416
answered Mar 17 '11 at 21:35
ChrisChris
3542416
answered Mar 17 '11 at 21:35
ChrisChris
3542416
answered Mar 17 '11 at 21:35
ChrisChris
3542416
3542416
add a comment |
add a comment |
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6
The fact that you're asking the question suggests that you have not yet read a basic introductory book on C++ - you should probably make it a priority to do so before you get much further with learning the language.
– Paul R
Mar 17 '11 at 21:38
2
@Paul R: Exactly. Here's the book list: stackoverflow.com/questions/388242/…
– Fred Larson
Mar 17 '11 at 21:42
thanks @Fred Larson
– Milad Sobhkhiz
Mar 17 '11 at 21:47
2
@PaulR Not everyone who arrives upon this question is looking to learn C++. I, for example, just happened to be skimming some C++ code and wanted to get the general idea of what the program is doing and needed a quick reference :)
– Ebony Maw
Dec 16 '18 at 18:34