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How can I remove all elements to the left of an index?
2019 Community Moderator ElectionHow can I concatenate two arrays in Java?Remove empty elements from an array in JavascriptHow can I pad an integer with zeros on the left?How can I create an executable JAR with dependencies using Maven?How to insert an item into an array at a specific index (JavaScript)?Get all unique values in a JavaScript array (remove duplicates)Remove empty array elementsHow do I remove a particular element from an array in JavaScript?How can I add new array elements at the beginning of an array in Javascript?swift for loop: for index, element in array?
So I am currently working on an assignment and I am currently stuck. I cannot figure out how to get all elements that are to the left of an index and remove them from an Arraylist.
These are the exact instructions:
For this program, given the sequence, remove all the zeros, if any, and all the digits to their left. Then find
the largest remaining digit and if it is even subtract 2 from it or if it is odd subtract 1 from it. If two or
more digits become tied as the largest digit, use the rightmost digit as the largest. Repeat the application of
the rules to the sequence. How many moves were required to delete the sequence?
This is what I have so far:
(Sorry if the code is a bit messy)
import java.io.*;
import java.util.*;
public class Main
public static void main(String[] args) throws FileNotFoundException
File inputFile = new File("input.txt");
Scanner scanFile = new Scanner(inputFile);
String input;
int testCase;
String testCaseS = "";
int zero;
//testCase = scanFile.nextInt();
//System.out.println(testCase);
input = scanFile.next();
//System.out.println(input);
//input = input.replaceAll(",", "");
String arr = input;
String[] items = arr.replaceAll("\[", "").replaceAll("\]", "").replaceAll("\s", "").split(",");
int[] results = new int[items.length];
for (int i = 0; i < items.length; i++)
try
results[i] = Integer.parseInt(items[i]);
catch (NumberFormatException nfe)
;
//for (int o = 0; o <= items.length; o++)
//System.out.println(results[o]);
boolean choice = false;
int counter = 0;
List<Integer> intList = new ArrayList<Integer>();
for (int i : results)
intList.add(i);
if (!choice)
for (int u = 0; u < items.length; u++)
if (results[u] == 0)
counter++;
//intList.removeAll(Arrays.asList(0 ));
int zeroindex = intList.indexOf(0);
System.out.println(intList);
java arrays arraylist
add a comment |
So I am currently working on an assignment and I am currently stuck. I cannot figure out how to get all elements that are to the left of an index and remove them from an Arraylist.
These are the exact instructions:
For this program, given the sequence, remove all the zeros, if any, and all the digits to their left. Then find
the largest remaining digit and if it is even subtract 2 from it or if it is odd subtract 1 from it. If two or
more digits become tied as the largest digit, use the rightmost digit as the largest. Repeat the application of
the rules to the sequence. How many moves were required to delete the sequence?
This is what I have so far:
(Sorry if the code is a bit messy)
import java.io.*;
import java.util.*;
public class Main
public static void main(String[] args) throws FileNotFoundException
File inputFile = new File("input.txt");
Scanner scanFile = new Scanner(inputFile);
String input;
int testCase;
String testCaseS = "";
int zero;
//testCase = scanFile.nextInt();
//System.out.println(testCase);
input = scanFile.next();
//System.out.println(input);
//input = input.replaceAll(",", "");
String arr = input;
String[] items = arr.replaceAll("\[", "").replaceAll("\]", "").replaceAll("\s", "").split(",");
int[] results = new int[items.length];
for (int i = 0; i < items.length; i++)
try
results[i] = Integer.parseInt(items[i]);
catch (NumberFormatException nfe)
;
//for (int o = 0; o <= items.length; o++)
//System.out.println(results[o]);
boolean choice = false;
int counter = 0;
List<Integer> intList = new ArrayList<Integer>();
for (int i : results)
intList.add(i);
if (!choice)
for (int u = 0; u < items.length; u++)
if (results[u] == 0)
counter++;
//intList.removeAll(Arrays.asList(0 ));
int zeroindex = intList.indexOf(0);
System.out.println(intList);
java arrays arraylist
add a comment |
So I am currently working on an assignment and I am currently stuck. I cannot figure out how to get all elements that are to the left of an index and remove them from an Arraylist.
These are the exact instructions:
For this program, given the sequence, remove all the zeros, if any, and all the digits to their left. Then find
the largest remaining digit and if it is even subtract 2 from it or if it is odd subtract 1 from it. If two or
more digits become tied as the largest digit, use the rightmost digit as the largest. Repeat the application of
the rules to the sequence. How many moves were required to delete the sequence?
This is what I have so far:
(Sorry if the code is a bit messy)
import java.io.*;
import java.util.*;
public class Main
public static void main(String[] args) throws FileNotFoundException
File inputFile = new File("input.txt");
Scanner scanFile = new Scanner(inputFile);
String input;
int testCase;
String testCaseS = "";
int zero;
//testCase = scanFile.nextInt();
//System.out.println(testCase);
input = scanFile.next();
//System.out.println(input);
//input = input.replaceAll(",", "");
String arr = input;
String[] items = arr.replaceAll("\[", "").replaceAll("\]", "").replaceAll("\s", "").split(",");
int[] results = new int[items.length];
for (int i = 0; i < items.length; i++)
try
results[i] = Integer.parseInt(items[i]);
catch (NumberFormatException nfe)
;
//for (int o = 0; o <= items.length; o++)
//System.out.println(results[o]);
boolean choice = false;
int counter = 0;
List<Integer> intList = new ArrayList<Integer>();
for (int i : results)
intList.add(i);
if (!choice)
for (int u = 0; u < items.length; u++)
if (results[u] == 0)
counter++;
//intList.removeAll(Arrays.asList(0 ));
int zeroindex = intList.indexOf(0);
System.out.println(intList);
java arrays arraylist
So I am currently working on an assignment and I am currently stuck. I cannot figure out how to get all elements that are to the left of an index and remove them from an Arraylist.
These are the exact instructions:
For this program, given the sequence, remove all the zeros, if any, and all the digits to their left. Then find
the largest remaining digit and if it is even subtract 2 from it or if it is odd subtract 1 from it. If two or
more digits become tied as the largest digit, use the rightmost digit as the largest. Repeat the application of
the rules to the sequence. How many moves were required to delete the sequence?
This is what I have so far:
(Sorry if the code is a bit messy)
import java.io.*;
import java.util.*;
public class Main
public static void main(String[] args) throws FileNotFoundException
File inputFile = new File("input.txt");
Scanner scanFile = new Scanner(inputFile);
String input;
int testCase;
String testCaseS = "";
int zero;
//testCase = scanFile.nextInt();
//System.out.println(testCase);
input = scanFile.next();
//System.out.println(input);
//input = input.replaceAll(",", "");
String arr = input;
String[] items = arr.replaceAll("\[", "").replaceAll("\]", "").replaceAll("\s", "").split(",");
int[] results = new int[items.length];
for (int i = 0; i < items.length; i++)
try
results[i] = Integer.parseInt(items[i]);
catch (NumberFormatException nfe)
;
//for (int o = 0; o <= items.length; o++)
//System.out.println(results[o]);
boolean choice = false;
int counter = 0;
List<Integer> intList = new ArrayList<Integer>();
for (int i : results)
intList.add(i);
if (!choice)
for (int u = 0; u < items.length; u++)
if (results[u] == 0)
counter++;
//intList.removeAll(Arrays.asList(0 ));
int zeroindex = intList.indexOf(0);
System.out.println(intList);
java arrays arraylist
java arrays arraylist
asked Mar 7 at 5:09
LLK-11LLK-11
204
204
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
If you only want to delete all the elements left from particular index then
list.subList(0, index).clear();
this is the way.
add a comment |
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1 Answer
1
active
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you only want to delete all the elements left from particular index then
list.subList(0, index).clear();
this is the way.
add a comment |
If you only want to delete all the elements left from particular index then
list.subList(0, index).clear();
this is the way.
add a comment |
If you only want to delete all the elements left from particular index then
list.subList(0, index).clear();
this is the way.
If you only want to delete all the elements left from particular index then
list.subList(0, index).clear();
this is the way.
answered Mar 7 at 5:15
Khalid ShahKhalid Shah
1,4541921
1,4541921
add a comment |
add a comment |
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