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How to cancel a setInterval in python?
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I am using this code to call a function doSomething every 3 seconds. but I want that when numeroPeticiones== 3, stop doing it. I have looked for many examples, but none works. In my case, my function continues to be executed eternally, even though the condition of numeroPeticiones== 3 is fulfilled. how can I solve that?
import threading
from threading import Timer
numeroPeticiones=0
def doSomething():
global numeroPeticiones
numeroPeticiones=numeroPeticiones+1
print ("hello, world",numeroPeticiones)
if numeroPeticiones == 3:
print("cancel")
t.cancel()
def set_interval(func, sec):
def func_wrapper():
set_interval(func, sec)
func()
t = threading.Timer(sec, func_wrapper)
t.start()
return t
python
asked Mar 8 at 14:36
unusuariounusuario
4911
add a comment |
I am using this code to call a function doSomething every 3 seconds. but I want that when numeroPeticiones== 3, stop doing it. I have looked for many examples, but none works. In my case, my function continues to be executed eternally, even though the condition of numeroPeticiones== 3 is fulfilled. how can I solve that?
import threading
from threading import Timer
numeroPeticiones=0
def doSomething():
global numeroPeticiones
numeroPeticiones=numeroPeticiones+1
print ("hello, world",numeroPeticiones)
if numeroPeticiones == 3:
print("cancel")
t.cancel()
def set_interval(func, sec):
def func_wrapper():
set_interval(func, sec)
func()
t = threading.Timer(sec, func_wrapper)
t.start()
return t
python
asked Mar 8 at 14:36
unusuariounusuario
4911
Because t is in the set_interval function scope and can't be accessed in the doSomething function
– Ghanima
Mar 8 at 14:38
@AGhanima Thanks for answering, I'm new to python, I'm not sure what I should do. my strong is javascript.
– unusuario
Mar 8 at 14:40
add a comment |
I am using this code to call a function doSomething every 3 seconds. but I want that when numeroPeticiones== 3, stop doing it. I have looked for many examples, but none works. In my case, my function continues to be executed eternally, even though the condition of numeroPeticiones== 3 is fulfilled. how can I solve that?
import threading
from threading import Timer
numeroPeticiones=0
def doSomething():
global numeroPeticiones
numeroPeticiones=numeroPeticiones+1
print ("hello, world",numeroPeticiones)
if numeroPeticiones == 3:
print("cancel")
t.cancel()
def set_interval(func, sec):
def func_wrapper():
set_interval(func, sec)
func()
t = threading.Timer(sec, func_wrapper)
t.start()
return t
python
asked Mar 8 at 14:36
unusuariounusuario
4911
I am using this code to call a function doSomething every 3 seconds. but I want that when numeroPeticiones== 3, stop doing it. I have looked for many examples, but none works. In my case, my function continues to be executed eternally, even though the condition of numeroPeticiones== 3 is fulfilled. how can I solve that?
import threading
from threading import Timer
numeroPeticiones=0
def doSomething():
global numeroPeticiones
numeroPeticiones=numeroPeticiones+1
print ("hello, world",numeroPeticiones)
if numeroPeticiones == 3:
print("cancel")
t.cancel()
def set_interval(func, sec):
def func_wrapper():
set_interval(func, sec)
func()
t = threading.Timer(sec, func_wrapper)
t.start()
return t
python
python
asked Mar 8 at 14:36
unusuariounusuario
4911
asked Mar 8 at 14:36
unusuariounusuario
4911
asked Mar 8 at 14:36
unusuariounusuario
4911
asked Mar 8 at 14:36
unusuariounusuario
4911
asked Mar 8 at 14:36
unusuariounusuario
4911
4911
Because t is in the set_interval function scope and can't be accessed in the doSomething function
– Ghanima
Mar 8 at 14:38
@AGhanima Thanks for answering, I'm new to python, I'm not sure what I should do. my strong is javascript.
– unusuario
Mar 8 at 14:40
add a comment |
Because t is in the set_interval function scope and can't be accessed in the doSomething function
– Ghanima
Mar 8 at 14:38
@AGhanima Thanks for answering, I'm new to python, I'm not sure what I should do. my strong is javascript.
– unusuario
Mar 8 at 14:40
Because t is in the set_interval function scope and can't be accessed in the doSomething function
– Ghanima
Mar 8 at 14:38
Because t is in the set_interval function scope and can't be accessed in the doSomething function
– Ghanima
Mar 8 at 14:38
@AGhanima Thanks for answering, I'm new to python, I'm not sure what I should do. my strong is javascript.
– unusuario
Mar 8 at 14:40
@AGhanima Thanks for answering, I'm new to python, I'm not sure what I should do. my strong is javascript.
– unusuario
Mar 8 at 14:40
add a comment |
1 Answer
1
active
oldest
votes
You can do the following, if num is equal to the 3, it wont start the timer
from threading import Timer
num = 0
def hello():
global num
num += 1
print("hello, world")
if (num < 3):
Timer(3, hello).start()
Timer(3, hello).start()
answered Mar 8 at 14:50
GhanimaGhanima
5881216
Timer(3, hello).start() in this line stops the interval... why?
– unusuario
Mar 8 at 14:53
The if condition is what controls whether the next timer starts or not
– Ghanima
Mar 8 at 14:54
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can do the following, if num is equal to the 3, it wont start the timer
from threading import Timer
num = 0
def hello():
global num
num += 1
print("hello, world")
if (num < 3):
Timer(3, hello).start()
Timer(3, hello).start()
answered Mar 8 at 14:50
GhanimaGhanima
5881216
Timer(3, hello).start() in this line stops the interval... why?
– unusuario
Mar 8 at 14:53
The if condition is what controls whether the next timer starts or not
– Ghanima
Mar 8 at 14:54
add a comment |
You can do the following, if num is equal to the 3, it wont start the timer
from threading import Timer
num = 0
def hello():
global num
num += 1
print("hello, world")
if (num < 3):
Timer(3, hello).start()
Timer(3, hello).start()
answered Mar 8 at 14:50
GhanimaGhanima
5881216
Timer(3, hello).start() in this line stops the interval... why?
– unusuario
Mar 8 at 14:53
The if condition is what controls whether the next timer starts or not
– Ghanima
Mar 8 at 14:54
add a comment |
You can do the following, if num is equal to the 3, it wont start the timer
from threading import Timer
num = 0
def hello():
global num
num += 1
print("hello, world")
if (num < 3):
Timer(3, hello).start()
Timer(3, hello).start()
answered Mar 8 at 14:50
GhanimaGhanima
5881216
You can do the following, if num is equal to the 3, it wont start the timer
from threading import Timer
num = 0
def hello():
global num
num += 1
print("hello, world")
if (num < 3):
Timer(3, hello).start()
Timer(3, hello).start()
answered Mar 8 at 14:50
GhanimaGhanima
5881216
answered Mar 8 at 14:50
GhanimaGhanima
5881216
answered Mar 8 at 14:50
GhanimaGhanima
5881216
answered Mar 8 at 14:50
GhanimaGhanima
5881216
5881216
Timer(3, hello).start() in this line stops the interval... why?
– unusuario
Mar 8 at 14:53
The if condition is what controls whether the next timer starts or not
– Ghanima
Mar 8 at 14:54
add a comment |
Timer(3, hello).start() in this line stops the interval... why?
– unusuario
Mar 8 at 14:53
The if condition is what controls whether the next timer starts or not
– Ghanima
Mar 8 at 14:54
Timer(3, hello).start() in this line stops the interval... why?
– unusuario
Mar 8 at 14:53
Timer(3, hello).start() in this line stops the interval... why?
– unusuario
Mar 8 at 14:53
The if condition is what controls whether the next timer starts or not
– Ghanima
Mar 8 at 14:54
The if condition is what controls whether the next timer starts or not
– Ghanima
Mar 8 at 14:54
add a comment |
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Because t is in the set_interval function scope and can't be accessed in the doSomething function
– Ghanima
Mar 8 at 14:38
@AGhanima Thanks for answering, I'm new to python, I'm not sure what I should do. my strong is javascript.
– unusuario
Mar 8 at 14:40