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UNIX Not in condition to file files
2019 Community Moderator ElectionUse grep --exclude/--include syntax to not grep through certain filesUnix shell script find out which directory the script file resides?Why should text files end with a newline?How to count all the lines of code in a directory recursively?Looping through the content of a file in BashDelete lines in a text file that contain a specific stringHow can I recursively find all files in current and subfolders based on wildcard matching?Argument list too long error for rm, cp, mv commandsgrep, but only certain file extensionsHow to permanently set $PATH on Linux/Unix?
I have following files under one directory.
ABC_2019-01-01.zip
ABC_2019-01-02.zip
ABC_2019-01-03.zip
.
.
.
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
suppose today's date is 2019-01-31 then I just want to retain today's ABC file i.e. ABC_2019-01-31.zip, retain all XYZ file (irrespective of date) and delete all ABC files which doesn't hold today's date.
Output should be:
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
shell unix
edited Mar 7 at 19:27
John Kugelman
246k54406459
asked Mar 7 at 15:29
vkasevkase
204
add a comment |
I have following files under one directory.
ABC_2019-01-01.zip
ABC_2019-01-02.zip
ABC_2019-01-03.zip
.
.
.
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
suppose today's date is 2019-01-31 then I just want to retain today's ABC file i.e. ABC_2019-01-31.zip, retain all XYZ file (irrespective of date) and delete all ABC files which doesn't hold today's date.
Output should be:
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
shell unix
edited Mar 7 at 19:27
John Kugelman
246k54406459
asked Mar 7 at 15:29
vkasevkase
204
I think the question is "how do I remove all files named ABC_....zip except for ABC_2019-01-31.zip"? But perhaps the question is "How do I make a glob that matches all files named ABC_....zip except for ABC_2019-01-31.zip"? The former is easy, the latter is hard. I'd be interested to see an answer for the second question.
– William Pursell
Mar 7 at 16:33
add a comment |
I have following files under one directory.
ABC_2019-01-01.zip
ABC_2019-01-02.zip
ABC_2019-01-03.zip
.
.
.
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
suppose today's date is 2019-01-31 then I just want to retain today's ABC file i.e. ABC_2019-01-31.zip, retain all XYZ file (irrespective of date) and delete all ABC files which doesn't hold today's date.
Output should be:
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
shell unix
edited Mar 7 at 19:27
John Kugelman
246k54406459
asked Mar 7 at 15:29
vkasevkase
204
I have following files under one directory.
ABC_2019-01-01.zip
ABC_2019-01-02.zip
ABC_2019-01-03.zip
.
.
.
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
suppose today's date is 2019-01-31 then I just want to retain today's ABC file i.e. ABC_2019-01-31.zip, retain all XYZ file (irrespective of date) and delete all ABC files which doesn't hold today's date.
Output should be:
ABC_2019-01-31.zip
.
.
XYZ_2019-01-01.zip
XYZ_2019-01-02.zip
XYZ_2019-01-03.zip
.
.
.
XYZ_2019-01-31.zip
shell unix
shell unix
edited Mar 7 at 19:27
John Kugelman
246k54406459
asked Mar 7 at 15:29
vkasevkase
204
edited Mar 7 at 19:27
John Kugelman
246k54406459
asked Mar 7 at 15:29
vkasevkase
204
edited Mar 7 at 19:27
John Kugelman
246k54406459
edited Mar 7 at 19:27
John Kugelman
246k54406459
edited Mar 7 at 19:27
John Kugelman
246k54406459
246k54406459
asked Mar 7 at 15:29
vkasevkase
204
asked Mar 7 at 15:29
vkasevkase
204
asked Mar 7 at 15:29
vkasevkase
204
204
I think the question is "how do I remove all files named ABC_....zip except for ABC_2019-01-31.zip"? But perhaps the question is "How do I make a glob that matches all files named ABC_....zip except for ABC_2019-01-31.zip"? The former is easy, the latter is hard. I'd be interested to see an answer for the second question.
– William Pursell
Mar 7 at 16:33
add a comment |
I think the question is "how do I remove all files named ABC_....zip except for ABC_2019-01-31.zip"? But perhaps the question is "How do I make a glob that matches all files named ABC_....zip except for ABC_2019-01-31.zip"? The former is easy, the latter is hard. I'd be interested to see an answer for the second question.
– William Pursell
Mar 7 at 16:33
I think the question is "how do I remove all files named ABC_....zip except for ABC_2019-01-31.zip"? But perhaps the question is "How do I make a glob that matches all files named ABC_....zip except for ABC_2019-01-31.zip"? The former is easy, the latter is hard. I'd be interested to see an answer for the second question.
– William Pursell
Mar 7 at 16:33
I think the question is "how do I remove all files named ABC_....zip except for ABC_2019-01-31.zip"? But perhaps the question is "How do I make a glob that matches all files named ABC_....zip except for ABC_2019-01-31.zip"? The former is easy, the latter is hard. I'd be interested to see an answer for the second question.
– William Pursell
Mar 7 at 16:33
add a comment |
1 Answer
1
active
oldest
votes
Assuming you have $date filled out:
date=$(date %+m-%d-%Y)
In bash you can use extended globs to exclude matches:
shopt -s extglob
rm ABC_!("$date").zip
Or in any shell you can use find:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -delete
If -delete isn't available on your platform then use:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -exec rm ;
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Assuming you have $date filled out:
date=$(date %+m-%d-%Y)
In bash you can use extended globs to exclude matches:
shopt -s extglob
rm ABC_!("$date").zip
Or in any shell you can use find:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -delete
If -delete isn't available on your platform then use:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -exec rm ;
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
add a comment |
Assuming you have $date filled out:
date=$(date %+m-%d-%Y)
In bash you can use extended globs to exclude matches:
shopt -s extglob
rm ABC_!("$date").zip
Or in any shell you can use find:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -delete
If -delete isn't available on your platform then use:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -exec rm ;
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
add a comment |
Assuming you have $date filled out:
date=$(date %+m-%d-%Y)
In bash you can use extended globs to exclude matches:
shopt -s extglob
rm ABC_!("$date").zip
Or in any shell you can use find:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -delete
If -delete isn't available on your platform then use:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -exec rm ;
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
Assuming you have $date filled out:
date=$(date %+m-%d-%Y)
In bash you can use extended globs to exclude matches:
shopt -s extglob
rm ABC_!("$date").zip
Or in any shell you can use find:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -delete
If -delete isn't available on your platform then use:
find dir/ -name 'ABC_*.zip' ! -name "ABC_$date.zip" -exec rm ;
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
edited Mar 7 at 19:28
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
answered Mar 7 at 17:21
John KugelmanJohn Kugelman
246k54406459
246k54406459
add a comment |
add a comment |
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I think the question is "how do I remove all files named ABC_....zip except for ABC_2019-01-31.zip"? But perhaps the question is "How do I make a glob that matches all files named ABC_....zip except for ABC_2019-01-31.zip"? The former is easy, the latter is hard. I'd be interested to see an answer for the second question.
– William Pursell
Mar 7 at 16:33