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Ruby regex to replace character sequence



2019 Community Moderator ElectionEscaping regex string in PythonHow to write a switch statement in RubyHow to replace all occurrences of a string in JavaScriptRegEx match open tags except XHTML self-contained tagsCheck if a value exists in an array in RubyWhat is attr_accessor in Ruby?Replace only some groups with RegexHow to remove all line breaks from a stringRegex for string not ending with given suffixHow to use Regular Expressions (Regex) in Microsoft Excel both in-cell and loops










0















So I have this string



x = ""1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"" 


and I want to replace the rocket symbol that is beside a character to a pipe symbol. so the result is



x = "Test","3"=>"Another" 


I have this code right now



if x =~ /(=>w)/).present?
x.match(/=>w/) do |match|
#loop through matches and replace => with |
end
end


So basically my question is how do I loop through a matched by regex and replace the rocket sign to a pipe?










share|improve this question

















  • 3





    That string looks like the string representation of a Ruby hash. Where do you get the string from? I did you consider working on the original Ruby hash?

    – spickermann
    Mar 7 at 17:26











  • gsub will let you replace parts of string by regex

    – Sergio Tulentsev
    Mar 7 at 17:26











  • @SergioTulentsev yes but I dont want to replace =>T to | I just wanted to replace => to a | if it matches the regex /=>w/

    – stuckoverflow24
    Mar 7 at 17:30












  • @stuckoverflow24: ah, I see. In this case, you could use a positive lookahead (assert presence without including it in the match). Look it up.

    – Sergio Tulentsev
    Mar 7 at 17:31







  • 1





    I'm specifically asking for the code in your question to match, exactly, what you're trying to deal with. Right now that's not valid Ruby code.

    – tadman
    Mar 7 at 18:01















0















So I have this string



x = ""1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"" 


and I want to replace the rocket symbol that is beside a character to a pipe symbol. so the result is



x = "Test","3"=>"Another" 


I have this code right now



if x =~ /(=>w)/).present?
x.match(/=>w/) do |match|
#loop through matches and replace => with |
end
end


So basically my question is how do I loop through a matched by regex and replace the rocket sign to a pipe?










share|improve this question

















  • 3





    That string looks like the string representation of a Ruby hash. Where do you get the string from? I did you consider working on the original Ruby hash?

    – spickermann
    Mar 7 at 17:26











  • gsub will let you replace parts of string by regex

    – Sergio Tulentsev
    Mar 7 at 17:26











  • @SergioTulentsev yes but I dont want to replace =>T to | I just wanted to replace => to a | if it matches the regex /=>w/

    – stuckoverflow24
    Mar 7 at 17:30












  • @stuckoverflow24: ah, I see. In this case, you could use a positive lookahead (assert presence without including it in the match). Look it up.

    – Sergio Tulentsev
    Mar 7 at 17:31







  • 1





    I'm specifically asking for the code in your question to match, exactly, what you're trying to deal with. Right now that's not valid Ruby code.

    – tadman
    Mar 7 at 18:01













0












0








0








So I have this string



x = ""1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"" 


and I want to replace the rocket symbol that is beside a character to a pipe symbol. so the result is



x = "Test","3"=>"Another" 


I have this code right now



if x =~ /(=>w)/).present?
x.match(/=>w/) do |match|
#loop through matches and replace => with |
end
end


So basically my question is how do I loop through a matched by regex and replace the rocket sign to a pipe?










share|improve this question














So I have this string



x = ""1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"" 


and I want to replace the rocket symbol that is beside a character to a pipe symbol. so the result is



x = "Test","3"=>"Another" 


I have this code right now



if x =~ /(=>w)/).present?
x.match(/=>w/) do |match|
#loop through matches and replace => with |
end
end


So basically my question is how do I loop through a matched by regex and replace the rocket sign to a pipe?







regex ruby






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Mar 7 at 17:22









stuckoverflow24stuckoverflow24

317




317







  • 3





    That string looks like the string representation of a Ruby hash. Where do you get the string from? I did you consider working on the original Ruby hash?

    – spickermann
    Mar 7 at 17:26











  • gsub will let you replace parts of string by regex

    – Sergio Tulentsev
    Mar 7 at 17:26











  • @SergioTulentsev yes but I dont want to replace =>T to | I just wanted to replace => to a | if it matches the regex /=>w/

    – stuckoverflow24
    Mar 7 at 17:30












  • @stuckoverflow24: ah, I see. In this case, you could use a positive lookahead (assert presence without including it in the match). Look it up.

    – Sergio Tulentsev
    Mar 7 at 17:31







  • 1





    I'm specifically asking for the code in your question to match, exactly, what you're trying to deal with. Right now that's not valid Ruby code.

    – tadman
    Mar 7 at 18:01












  • 3





    That string looks like the string representation of a Ruby hash. Where do you get the string from? I did you consider working on the original Ruby hash?

    – spickermann
    Mar 7 at 17:26











  • gsub will let you replace parts of string by regex

    – Sergio Tulentsev
    Mar 7 at 17:26











  • @SergioTulentsev yes but I dont want to replace =>T to | I just wanted to replace => to a | if it matches the regex /=>w/

    – stuckoverflow24
    Mar 7 at 17:30












  • @stuckoverflow24: ah, I see. In this case, you could use a positive lookahead (assert presence without including it in the match). Look it up.

    – Sergio Tulentsev
    Mar 7 at 17:31







  • 1





    I'm specifically asking for the code in your question to match, exactly, what you're trying to deal with. Right now that's not valid Ruby code.

    – tadman
    Mar 7 at 18:01







3




3





That string looks like the string representation of a Ruby hash. Where do you get the string from? I did you consider working on the original Ruby hash?

– spickermann
Mar 7 at 17:26





That string looks like the string representation of a Ruby hash. Where do you get the string from? I did you consider working on the original Ruby hash?

– spickermann
Mar 7 at 17:26













gsub will let you replace parts of string by regex

– Sergio Tulentsev
Mar 7 at 17:26





gsub will let you replace parts of string by regex

– Sergio Tulentsev
Mar 7 at 17:26













@SergioTulentsev yes but I dont want to replace =>T to | I just wanted to replace => to a | if it matches the regex /=>w/

– stuckoverflow24
Mar 7 at 17:30






@SergioTulentsev yes but I dont want to replace =>T to | I just wanted to replace => to a | if it matches the regex /=>w/

– stuckoverflow24
Mar 7 at 17:30














@stuckoverflow24: ah, I see. In this case, you could use a positive lookahead (assert presence without including it in the match). Look it up.

– Sergio Tulentsev
Mar 7 at 17:31






@stuckoverflow24: ah, I see. In this case, you could use a positive lookahead (assert presence without including it in the match). Look it up.

– Sergio Tulentsev
Mar 7 at 17:31





1




1





I'm specifically asking for the code in your question to match, exactly, what you're trying to deal with. Right now that's not valid Ruby code.

– tadman
Mar 7 at 18:01





I'm specifically asking for the code in your question to match, exactly, what you're trying to deal with. Right now that's not valid Ruby code.

– tadman
Mar 7 at 18:01












1 Answer
1






active

oldest

votes


















2














gsub with a positive look-ahead will do it.



x = %q["1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"]
x.gsub!(%r=>(?=w), '|')
puts x


A look-ahead (or look-behind) matches, but does not include that bit in the match.



Though I think %r=>(?=[^"]), a => which is not in front of a quote, is more correct.



x = %q["1"=>"what about => a space?","2"=>"Or=>(this)"]
x.gsub!(%r=>(?=[^"]), '|')
puts x





share|improve this answer


















  • 1





    thanks alot mate

    – stuckoverflow24
    Mar 8 at 10:39










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









2














gsub with a positive look-ahead will do it.



x = %q["1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"]
x.gsub!(%r=>(?=w), '|')
puts x


A look-ahead (or look-behind) matches, but does not include that bit in the match.



Though I think %r=>(?=[^"]), a => which is not in front of a quote, is more correct.



x = %q["1"=>"what about => a space?","2"=>"Or=>(this)"]
x.gsub!(%r=>(?=[^"]), '|')
puts x





share|improve this answer


















  • 1





    thanks alot mate

    – stuckoverflow24
    Mar 8 at 10:39















2














gsub with a positive look-ahead will do it.



x = %q["1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"]
x.gsub!(%r=>(?=w), '|')
puts x


A look-ahead (or look-behind) matches, but does not include that bit in the match.



Though I think %r=>(?=[^"]), a => which is not in front of a quote, is more correct.



x = %q["1"=>"what about => a space?","2"=>"Or=>(this)"]
x.gsub!(%r=>(?=[^"]), '|')
puts x





share|improve this answer


















  • 1





    thanks alot mate

    – stuckoverflow24
    Mar 8 at 10:39













2












2








2







gsub with a positive look-ahead will do it.



x = %q["1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"]
x.gsub!(%r=>(?=w), '|')
puts x


A look-ahead (or look-behind) matches, but does not include that bit in the match.



Though I think %r=>(?=[^"]), a => which is not in front of a quote, is more correct.



x = %q["1"=>"what about => a space?","2"=>"Or=>(this)"]
x.gsub!(%r=>(?=[^"]), '|')
puts x





share|improve this answer













gsub with a positive look-ahead will do it.



x = %q["1"=>"test","2"=>"Another=>Test","3"=>"Another=>One"]
x.gsub!(%r=>(?=w), '|')
puts x


A look-ahead (or look-behind) matches, but does not include that bit in the match.



Though I think %r=>(?=[^"]), a => which is not in front of a quote, is more correct.



x = %q["1"=>"what about => a space?","2"=>"Or=>(this)"]
x.gsub!(%r=>(?=[^"]), '|')
puts x






share|improve this answer












share|improve this answer



share|improve this answer










answered Mar 7 at 18:59









SchwernSchwern

90.8k17104238




90.8k17104238







  • 1





    thanks alot mate

    – stuckoverflow24
    Mar 8 at 10:39












  • 1





    thanks alot mate

    – stuckoverflow24
    Mar 8 at 10:39







1




1





thanks alot mate

– stuckoverflow24
Mar 8 at 10:39





thanks alot mate

– stuckoverflow24
Mar 8 at 10:39



















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