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Filename match with Python regex
Calling an external command in PythonWhat are metaclasses in Python?Finding the index of an item given a list containing it in PythonDifference between append vs. extend list methods in PythonHow can I safely create a nested directory in Python?Does Python have a ternary conditional operator?Regular expression to match a line that doesn't contain a word?How to get the current time in PythonRegEx match open tags except XHTML self-contained tagsDoes Python have a string 'contains' substring method?
I have a text file scrapped from my email which contains 1 attachment/mail. The attachment is present under different names with totally different formats, ex.:
filename="John_wheeler 11041997 resume.pdf";
filename="Kujal_newResume(1).pdf";
filename=JohnKrasinski_Resume.pdf
My question is: is there any way to find a RegEx pattern that would start searching from filename= and go until the dot character (that separates from file extension)? Getting file extension would be next task, but I can hold that for now. Please help me figure this out.
python regex python-3.x
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
add a comment |
I have a text file scrapped from my email which contains 1 attachment/mail. The attachment is present under different names with totally different formats, ex.:
filename="John_wheeler 11041997 resume.pdf";
filename="Kujal_newResume(1).pdf";
filename=JohnKrasinski_Resume.pdf
My question is: is there any way to find a RegEx pattern that would start searching from filename= and go until the dot character (that separates from file extension)? Getting file extension would be next task, but I can hold that for now. Please help me figure this out.
python regex python-3.x
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
1
Your question is unclear. Please provide the data/input you have, the code that you have tried, the expected output and the error you got.
– Yusufsn
Mar 8 at 7:13
add a comment |
I have a text file scrapped from my email which contains 1 attachment/mail. The attachment is present under different names with totally different formats, ex.:
filename="John_wheeler 11041997 resume.pdf";
filename="Kujal_newResume(1).pdf";
filename=JohnKrasinski_Resume.pdf
My question is: is there any way to find a RegEx pattern that would start searching from filename= and go until the dot character (that separates from file extension)? Getting file extension would be next task, but I can hold that for now. Please help me figure this out.
python regex python-3.x
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
I have a text file scrapped from my email which contains 1 attachment/mail. The attachment is present under different names with totally different formats, ex.:
filename="John_wheeler 11041997 resume.pdf";
filename="Kujal_newResume(1).pdf";
filename=JohnKrasinski_Resume.pdf
My question is: is there any way to find a RegEx pattern that would start searching from filename= and go until the dot character (that separates from file extension)? Getting file extension would be next task, but I can hold that for now. Please help me figure this out.
python regex python-3.x
python regex python-3.x
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
edited Mar 8 at 8:13
Michał Turczyn
15.5k132241
15.5k132241
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
asked Mar 8 at 7:07
Srinath RadhakrishnanSrinath Radhakrishnan
42
42
1
Your question is unclear. Please provide the data/input you have, the code that you have tried, the expected output and the error you got.
– Yusufsn
Mar 8 at 7:13
add a comment |
1
Your question is unclear. Please provide the data/input you have, the code that you have tried, the expected output and the error you got.
– Yusufsn
Mar 8 at 7:13
1
1
Your question is unclear. Please provide the data/input you have, the code that you have tried, the expected output and the error you got.
– Yusufsn
Mar 8 at 7:13
Your question is unclear. Please provide the data/input you have, the code that you have tried, the expected output and the error you got.
– Yusufsn
Mar 8 at 7:13
add a comment |
3 Answers
3
active
oldest
votes
You could try this pattern: filename="?([^.]+)
It assumes that dot separates filename from extension.
Explanation:
filename="? - match filename= literally and tehn match 0 or 1 apostrophe "
([^.]+) - match one or more characters that is not a dot (match everything until dot) and store it in capturing group
Your desired filename will be stored in capturing group.
Demo
EXTRA: to capture also file extension, you could use such pattern: filename="?([^.]+).([^";]+)
Additional thing here is .([^";]+): matches dot literally with .. Then it matches one or more characters other than " or ; with pattern [^";]+ and stores it in second capturing gropup.
Another demo
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
add a comment |
How about the following:
(?:filename=)([^.]*).(w*)
This REGEX returns different groups containing the different elements you're interested in.
answered Mar 8 at 7:15
tk78tk78
547310
add a comment |
I'm not sure the output you expect. But this may help. RegexDemo
(?<=filename=)["]?(w.*[.].*)(?<=w)["]?
Or if you want to ignore the file extension:
(?<=filename=)["]?(w.*)[.]
answered Mar 8 at 7:26
YusufsnYusufsn
392215
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could try this pattern: filename="?([^.]+)
It assumes that dot separates filename from extension.
Explanation:
filename="? - match filename= literally and tehn match 0 or 1 apostrophe "
([^.]+) - match one or more characters that is not a dot (match everything until dot) and store it in capturing group
Your desired filename will be stored in capturing group.
Demo
EXTRA: to capture also file extension, you could use such pattern: filename="?([^.]+).([^";]+)
Additional thing here is .([^";]+): matches dot literally with .. Then it matches one or more characters other than " or ; with pattern [^";]+ and stores it in second capturing gropup.
Another demo
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
add a comment |
You could try this pattern: filename="?([^.]+)
It assumes that dot separates filename from extension.
Explanation:
filename="? - match filename= literally and tehn match 0 or 1 apostrophe "
([^.]+) - match one or more characters that is not a dot (match everything until dot) and store it in capturing group
Your desired filename will be stored in capturing group.
Demo
EXTRA: to capture also file extension, you could use such pattern: filename="?([^.]+).([^";]+)
Additional thing here is .([^";]+): matches dot literally with .. Then it matches one or more characters other than " or ; with pattern [^";]+ and stores it in second capturing gropup.
Another demo
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
add a comment |
You could try this pattern: filename="?([^.]+)
It assumes that dot separates filename from extension.
Explanation:
filename="? - match filename= literally and tehn match 0 or 1 apostrophe "
([^.]+) - match one or more characters that is not a dot (match everything until dot) and store it in capturing group
Your desired filename will be stored in capturing group.
Demo
EXTRA: to capture also file extension, you could use such pattern: filename="?([^.]+).([^";]+)
Additional thing here is .([^";]+): matches dot literally with .. Then it matches one or more characters other than " or ; with pattern [^";]+ and stores it in second capturing gropup.
Another demo
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
You could try this pattern: filename="?([^.]+)
It assumes that dot separates filename from extension.
Explanation:
filename="? - match filename= literally and tehn match 0 or 1 apostrophe "
([^.]+) - match one or more characters that is not a dot (match everything until dot) and store it in capturing group
Your desired filename will be stored in capturing group.
Demo
EXTRA: to capture also file extension, you could use such pattern: filename="?([^.]+).([^";]+)
Additional thing here is .([^";]+): matches dot literally with .. Then it matches one or more characters other than " or ; with pattern [^";]+ and stores it in second capturing gropup.
Another demo
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
edited Mar 8 at 8:20
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
answered Mar 8 at 8:12
Michał TurczynMichał Turczyn
15.5k132241
15.5k132241
add a comment |
add a comment |
How about the following:
(?:filename=)([^.]*).(w*)
This REGEX returns different groups containing the different elements you're interested in.
answered Mar 8 at 7:15
tk78tk78
547310
add a comment |
How about the following:
(?:filename=)([^.]*).(w*)
This REGEX returns different groups containing the different elements you're interested in.
answered Mar 8 at 7:15
tk78tk78
547310
add a comment |
How about the following:
(?:filename=)([^.]*).(w*)
This REGEX returns different groups containing the different elements you're interested in.
answered Mar 8 at 7:15
tk78tk78
547310
How about the following:
(?:filename=)([^.]*).(w*)
This REGEX returns different groups containing the different elements you're interested in.
answered Mar 8 at 7:15
tk78tk78
547310
answered Mar 8 at 7:15
tk78tk78
547310
answered Mar 8 at 7:15
tk78tk78
547310
answered Mar 8 at 7:15
tk78tk78
547310
547310
add a comment |
add a comment |
I'm not sure the output you expect. But this may help. RegexDemo
(?<=filename=)["]?(w.*[.].*)(?<=w)["]?
Or if you want to ignore the file extension:
(?<=filename=)["]?(w.*)[.]
answered Mar 8 at 7:26
YusufsnYusufsn
392215
add a comment |
I'm not sure the output you expect. But this may help. RegexDemo
(?<=filename=)["]?(w.*[.].*)(?<=w)["]?
Or if you want to ignore the file extension:
(?<=filename=)["]?(w.*)[.]
answered Mar 8 at 7:26
YusufsnYusufsn
392215
add a comment |
I'm not sure the output you expect. But this may help. RegexDemo
(?<=filename=)["]?(w.*[.].*)(?<=w)["]?
Or if you want to ignore the file extension:
(?<=filename=)["]?(w.*)[.]
answered Mar 8 at 7:26
YusufsnYusufsn
392215
I'm not sure the output you expect. But this may help. RegexDemo
(?<=filename=)["]?(w.*[.].*)(?<=w)["]?
Or if you want to ignore the file extension:
(?<=filename=)["]?(w.*)[.]
answered Mar 8 at 7:26
YusufsnYusufsn
392215
answered Mar 8 at 7:26
YusufsnYusufsn
392215
answered Mar 8 at 7:26
YusufsnYusufsn
392215
answered Mar 8 at 7:26
YusufsnYusufsn
392215
392215
add a comment |
add a comment |
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1
Your question is unclear. Please provide the data/input you have, the code that you have tried, the expected output and the error you got.
– Yusufsn
Mar 8 at 7:13